Integrand size = 131, antiderivative size = 25 \[ \int e^{-2 x^2-2 x^3} \left (32 e^{2 x^2+2 x^3} x+150 x^5-100 x^7-150 x^8+\left (250 x^4-200 x^6-300 x^7\right ) \log (5)+\left (100 x^3-100 x^5-150 x^6\right ) \log ^2(5)+e^{x^2+x^3} \left (160 x^3-80 x^5-120 x^6+\left (120 x^2-80 x^4-120 x^5\right ) \log (5)\right )\right ) \, dx=\left (4 x+5 e^{-x \left (x+x^2\right )} x^2 (x+\log (5))\right )^2 \]
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\[ \int e^{-2 x^2-2 x^3} \left (32 e^{2 x^2+2 x^3} x+150 x^5-100 x^7-150 x^8+\left (250 x^4-200 x^6-300 x^7\right ) \log (5)+\left (100 x^3-100 x^5-150 x^6\right ) \log ^2(5)+e^{x^2+x^3} \left (160 x^3-80 x^5-120 x^6+\left (120 x^2-80 x^4-120 x^5\right ) \log (5)\right )\right ) \, dx=\int e^{-2 x^2-2 x^3} \left (32 e^{2 x^2+2 x^3} x+150 x^5-100 x^7-150 x^8+\left (250 x^4-200 x^6-300 x^7\right ) \log (5)+\left (100 x^3-100 x^5-150 x^6\right ) \log ^2(5)+e^{x^2+x^3} \left (160 x^3-80 x^5-120 x^6+\left (120 x^2-80 x^4-120 x^5\right ) \log (5)\right )\right ) \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (32 e^{-2 x^2-2 x^3+2 x^2 (1+x)} x+150 e^{-2 x^2-2 x^3} x^5-100 e^{-2 x^2-2 x^3} x^7-150 e^{-2 x^2-2 x^3} x^8-50 e^{-2 x^2-2 x^3} x^4 \left (-5+4 x^2+6 x^3\right ) \log (5)-50 e^{-2 x^2-2 x^3} x^3 \left (-2+2 x^2+3 x^3\right ) \log ^2(5)+40 e^{-x^2-x^3} x^2 \left (4 x-3 x^4+3 \log (5)-x^2 \log (25)-x^3 (2+\log (125))\right )\right ) \, dx \\ & = 32 \int e^{-2 x^2-2 x^3+2 x^2 (1+x)} x \, dx+40 \int e^{-x^2-x^3} x^2 \left (4 x-3 x^4+3 \log (5)-x^2 \log (25)-x^3 (2+\log (125))\right ) \, dx-100 \int e^{-2 x^2-2 x^3} x^7 \, dx+150 \int e^{-2 x^2-2 x^3} x^5 \, dx-150 \int e^{-2 x^2-2 x^3} x^8 \, dx-(50 \log (5)) \int e^{-2 x^2-2 x^3} x^4 \left (-5+4 x^2+6 x^3\right ) \, dx-\left (50 \log ^2(5)\right ) \int e^{-2 x^2-2 x^3} x^3 \left (-2+2 x^2+3 x^3\right ) \, dx \\ & = \frac {50 e^{-2 x^2-2 x^3} x^4 \left (2 x^2+3 x^3\right ) \log (5)}{2 x+3 x^2}+\frac {25 e^{-2 x^2-2 x^3} x^3 \left (2 x^2+3 x^3\right ) \log ^2(5)}{2 x+3 x^2}+\frac {40 e^{-x^2-x^3} x^2 \left (3 x^4+x^2 \log (25)+x^3 (2+\log (125))\right )}{2 x+3 x^2}+32 \int x \, dx-100 \int e^{-2 x^2-2 x^3} x^7 \, dx+150 \int e^{-2 x^2-2 x^3} x^5 \, dx-150 \int e^{-2 x^2-2 x^3} x^8 \, dx \\ & = 16 x^2+\frac {50 e^{-2 x^2-2 x^3} x^4 \left (2 x^2+3 x^3\right ) \log (5)}{2 x+3 x^2}+\frac {25 e^{-2 x^2-2 x^3} x^3 \left (2 x^2+3 x^3\right ) \log ^2(5)}{2 x+3 x^2}+\frac {40 e^{-x^2-x^3} x^2 \left (3 x^4+x^2 \log (25)+x^3 (2+\log (125))\right )}{2 x+3 x^2}-100 \int e^{-2 x^2-2 x^3} x^7 \, dx+150 \int e^{-2 x^2-2 x^3} x^5 \, dx-150 \int e^{-2 x^2-2 x^3} x^8 \, dx \\ \end{align*}
\[ \int e^{-2 x^2-2 x^3} \left (32 e^{2 x^2+2 x^3} x+150 x^5-100 x^7-150 x^8+\left (250 x^4-200 x^6-300 x^7\right ) \log (5)+\left (100 x^3-100 x^5-150 x^6\right ) \log ^2(5)+e^{x^2+x^3} \left (160 x^3-80 x^5-120 x^6+\left (120 x^2-80 x^4-120 x^5\right ) \log (5)\right )\right ) \, dx=\int e^{-2 x^2-2 x^3} \left (32 e^{2 x^2+2 x^3} x+150 x^5-100 x^7-150 x^8+\left (250 x^4-200 x^6-300 x^7\right ) \log (5)+\left (100 x^3-100 x^5-150 x^6\right ) \log ^2(5)+e^{x^2+x^3} \left (160 x^3-80 x^5-120 x^6+\left (120 x^2-80 x^4-120 x^5\right ) \log (5)\right )\right ) \, dx \]
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Leaf count of result is larger than twice the leaf count of optimal. \(61\) vs. \(2(25)=50\).
Time = 0.22 (sec) , antiderivative size = 62, normalized size of antiderivative = 2.48
method | result | size |
risch | \(16 x^{2}+\left (40 x^{3} \ln \left (5\right )+40 x^{4}\right ) {\mathrm e}^{-x^{2} \left (1+x \right )}+\left (25 x^{4} \ln \left (5\right )^{2}+50 x^{5} \ln \left (5\right )+25 x^{6}\right ) {\mathrm e}^{-2 x^{2} \left (1+x \right )}\) | \(62\) |
parts | \(16 x^{2}+\left (40 x^{3} \ln \left (5\right )+40 x^{4}\right ) {\mathrm e}^{-x^{3}-x^{2}}+\left (25 x^{4} \ln \left (5\right )^{2}+50 x^{5} \ln \left (5\right )+25 x^{6}\right ) {\mathrm e}^{-2 x^{3}-2 x^{2}}\) | \(64\) |
norman | \(\left (25 x^{6}+16 x^{2} {\mathrm e}^{2 x^{3}+2 x^{2}}+25 x^{4} \ln \left (5\right )^{2}+50 x^{5} \ln \left (5\right )+40 \,{\mathrm e}^{x^{3}+x^{2}} x^{4}+40 \ln \left (5\right ) {\mathrm e}^{x^{3}+x^{2}} x^{3}\right ) {\mathrm e}^{-2 x^{3}-2 x^{2}}\) | \(77\) |
parallelrisch | \(\left (25 x^{4} \ln \left (5\right )^{2}+50 x^{5} \ln \left (5\right )+25 x^{6}+40 \,{\mathrm e}^{x^{2} \left (1+x \right )} \ln \left (5\right ) x^{3}+40 \,{\mathrm e}^{x^{2} \left (1+x \right )} x^{4}+16 x^{2} {\mathrm e}^{2 x^{2} \left (1+x \right )}\right ) {\mathrm e}^{-2 x^{2} \left (1+x \right )}\) | \(77\) |
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Leaf count of result is larger than twice the leaf count of optimal. 72 vs. \(2 (24) = 48\).
Time = 0.24 (sec) , antiderivative size = 72, normalized size of antiderivative = 2.88 \[ \int e^{-2 x^2-2 x^3} \left (32 e^{2 x^2+2 x^3} x+150 x^5-100 x^7-150 x^8+\left (250 x^4-200 x^6-300 x^7\right ) \log (5)+\left (100 x^3-100 x^5-150 x^6\right ) \log ^2(5)+e^{x^2+x^3} \left (160 x^3-80 x^5-120 x^6+\left (120 x^2-80 x^4-120 x^5\right ) \log (5)\right )\right ) \, dx={\left (25 \, x^{6} + 50 \, x^{5} \log \left (5\right ) + 25 \, x^{4} \log \left (5\right )^{2} + 16 \, x^{2} e^{\left (2 \, x^{3} + 2 \, x^{2}\right )} + 40 \, {\left (x^{4} + x^{3} \log \left (5\right )\right )} e^{\left (x^{3} + x^{2}\right )}\right )} e^{\left (-2 \, x^{3} - 2 \, x^{2}\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 65 vs. \(2 (24) = 48\).
Time = 0.13 (sec) , antiderivative size = 65, normalized size of antiderivative = 2.60 \[ \int e^{-2 x^2-2 x^3} \left (32 e^{2 x^2+2 x^3} x+150 x^5-100 x^7-150 x^8+\left (250 x^4-200 x^6-300 x^7\right ) \log (5)+\left (100 x^3-100 x^5-150 x^6\right ) \log ^2(5)+e^{x^2+x^3} \left (160 x^3-80 x^5-120 x^6+\left (120 x^2-80 x^4-120 x^5\right ) \log (5)\right )\right ) \, dx=16 x^{2} + \left (40 x^{4} + 40 x^{3} \log {\left (5 \right )}\right ) e^{- x^{3} - x^{2}} + \left (25 x^{6} + 50 x^{5} \log {\left (5 \right )} + 25 x^{4} \log {\left (5 \right )}^{2}\right ) e^{- 2 x^{3} - 2 x^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 64 vs. \(2 (24) = 48\).
Time = 0.32 (sec) , antiderivative size = 64, normalized size of antiderivative = 2.56 \[ \int e^{-2 x^2-2 x^3} \left (32 e^{2 x^2+2 x^3} x+150 x^5-100 x^7-150 x^8+\left (250 x^4-200 x^6-300 x^7\right ) \log (5)+\left (100 x^3-100 x^5-150 x^6\right ) \log ^2(5)+e^{x^2+x^3} \left (160 x^3-80 x^5-120 x^6+\left (120 x^2-80 x^4-120 x^5\right ) \log (5)\right )\right ) \, dx=16 \, x^{2} + 5 \, {\left (5 \, {\left (x^{6} + 2 \, x^{5} \log \left (5\right ) + x^{4} \log \left (5\right )^{2}\right )} e^{\left (-2 \, x^{3}\right )} + 8 \, {\left (x^{4} + x^{3} \log \left (5\right )\right )} e^{\left (-x^{3} + x^{2}\right )}\right )} e^{\left (-2 \, x^{2}\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 99 vs. \(2 (24) = 48\).
Time = 0.29 (sec) , antiderivative size = 99, normalized size of antiderivative = 3.96 \[ \int e^{-2 x^2-2 x^3} \left (32 e^{2 x^2+2 x^3} x+150 x^5-100 x^7-150 x^8+\left (250 x^4-200 x^6-300 x^7\right ) \log (5)+\left (100 x^3-100 x^5-150 x^6\right ) \log ^2(5)+e^{x^2+x^3} \left (160 x^3-80 x^5-120 x^6+\left (120 x^2-80 x^4-120 x^5\right ) \log (5)\right )\right ) \, dx=25 \, x^{6} e^{\left (-2 \, x^{3} - 2 \, x^{2}\right )} + 50 \, x^{5} e^{\left (-2 \, x^{3} - 2 \, x^{2}\right )} \log \left (5\right ) + 25 \, x^{4} e^{\left (-2 \, x^{3} - 2 \, x^{2}\right )} \log \left (5\right )^{2} + 40 \, x^{4} e^{\left (-x^{3} - x^{2}\right )} + 40 \, x^{3} e^{\left (-x^{3} - x^{2}\right )} \log \left (5\right ) + 16 \, x^{2} \]
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Timed out. \[ \int e^{-2 x^2-2 x^3} \left (32 e^{2 x^2+2 x^3} x+150 x^5-100 x^7-150 x^8+\left (250 x^4-200 x^6-300 x^7\right ) \log (5)+\left (100 x^3-100 x^5-150 x^6\right ) \log ^2(5)+e^{x^2+x^3} \left (160 x^3-80 x^5-120 x^6+\left (120 x^2-80 x^4-120 x^5\right ) \log (5)\right )\right ) \, dx=\int -{\mathrm {e}}^{-2\,x^3-2\,x^2}\,\left ({\ln \left (5\right )}^2\,\left (150\,x^6+100\,x^5-100\,x^3\right )-32\,x\,{\mathrm {e}}^{2\,x^3+2\,x^2}+{\mathrm {e}}^{x^3+x^2}\,\left (\ln \left (5\right )\,\left (120\,x^5+80\,x^4-120\,x^2\right )-160\,x^3+80\,x^5+120\,x^6\right )+\ln \left (5\right )\,\left (300\,x^7+200\,x^6-250\,x^4\right )-150\,x^5+100\,x^7+150\,x^8\right ) \,d x \]
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