Integrand size = 52, antiderivative size = 26 \[ \int \frac {-184-64 x-4 x^2+e^{625 e^{5-x}} \left (8+e^{5-x} \left (-5000 x-625 x^2\right )\right )}{64+16 x+x^2} \, dx=x \left (-3+\frac {1+e^{625 e^{5-x}}-x}{8+x}\right ) \]
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\[ \int \frac {-184-64 x-4 x^2+e^{625 e^{5-x}} \left (8+e^{5-x} \left (-5000 x-625 x^2\right )\right )}{64+16 x+x^2} \, dx=\int \frac {-184-64 x-4 x^2+e^{625 e^{5-x}} \left (8+e^{5-x} \left (-5000 x-625 x^2\right )\right )}{64+16 x+x^2} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {-184-64 x-4 x^2+e^{625 e^{5-x}} \left (8+e^{5-x} \left (-5000 x-625 x^2\right )\right )}{(8+x)^2} \, dx \\ & = \int \left (-\frac {184}{(8+x)^2}+\frac {8 e^{625 e^{5-x}}}{(8+x)^2}-\frac {64 x}{(8+x)^2}-\frac {4 x^2}{(8+x)^2}-\frac {625 e^{5+625 e^{5-x}-x} x}{8+x}\right ) \, dx \\ & = \frac {184}{8+x}-4 \int \frac {x^2}{(8+x)^2} \, dx+8 \int \frac {e^{625 e^{5-x}}}{(8+x)^2} \, dx-64 \int \frac {x}{(8+x)^2} \, dx-625 \int \frac {e^{5+625 e^{5-x}-x} x}{8+x} \, dx \\ & = \frac {184}{8+x}-4 \int \left (1+\frac {64}{(8+x)^2}-\frac {16}{8+x}\right ) \, dx+8 \int \frac {e^{625 e^{5-x}}}{(8+x)^2} \, dx-64 \int \left (-\frac {8}{(8+x)^2}+\frac {1}{8+x}\right ) \, dx-625 \int \left (e^{5+625 e^{5-x}-x}-\frac {8 e^{5+625 e^{5-x}-x}}{8+x}\right ) \, dx \\ & = -4 x-\frac {72}{8+x}+8 \int \frac {e^{625 e^{5-x}}}{(8+x)^2} \, dx-625 \int e^{5+625 e^{5-x}-x} \, dx+5000 \int \frac {e^{5+625 e^{5-x}-x}}{8+x} \, dx \\ & = -4 x-\frac {72}{8+x}+8 \int \frac {e^{625 e^{5-x}}}{(8+x)^2} \, dx+625 \text {Subst}\left (\int e^{5+625 e^5 x} \, dx,x,e^{-x}\right )+5000 \int \frac {e^{5+625 e^{5-x}-x}}{8+x} \, dx \\ & = e^{625 e^{5-x}}-4 x-\frac {72}{8+x}+8 \int \frac {e^{625 e^{5-x}}}{(8+x)^2} \, dx+5000 \int \frac {e^{5+625 e^{5-x}-x}}{8+x} \, dx \\ \end{align*}
Time = 3.03 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.08 \[ \int \frac {-184-64 x-4 x^2+e^{625 e^{5-x}} \left (8+e^{5-x} \left (-5000 x-625 x^2\right )\right )}{64+16 x+x^2} \, dx=\frac {-72+\left (-32+e^{625 e^{5-x}}\right ) x-4 x^2}{8+x} \]
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Time = 0.42 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.96
method | result | size |
norman | \(\frac {x \,{\mathrm e}^{625 \,{\mathrm e}^{5-x}}-4 x^{2}+184}{x +8}\) | \(25\) |
parallelrisch | \(-\frac {4 x^{2}-x \,{\mathrm e}^{625 \,{\mathrm e}^{5-x}}-184}{x +8}\) | \(27\) |
risch | \(-\frac {72}{x +8}-4 x +\frac {x \,{\mathrm e}^{625 \,{\mathrm e}^{5-x}}}{x +8}\) | \(28\) |
parts | \(\frac {x^{2} {\mathrm e}^{625 \,{\mathrm e}^{5-x}}+8 x \,{\mathrm e}^{625 \,{\mathrm e}^{5-x}}}{\left (x +8\right )^{2}}-\frac {72}{x +8}-4 x\) | \(44\) |
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Time = 0.26 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.12 \[ \int \frac {-184-64 x-4 x^2+e^{625 e^{5-x}} \left (8+e^{5-x} \left (-5000 x-625 x^2\right )\right )}{64+16 x+x^2} \, dx=-\frac {4 \, x^{2} - x e^{\left (625 \, e^{\left (-x + 5\right )}\right )} + 32 \, x + 72}{x + 8} \]
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Time = 0.10 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.77 \[ \int \frac {-184-64 x-4 x^2+e^{625 e^{5-x}} \left (8+e^{5-x} \left (-5000 x-625 x^2\right )\right )}{64+16 x+x^2} \, dx=- 4 x + \frac {x e^{625 e^{5 - x}}}{x + 8} - \frac {72}{x + 8} \]
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\[ \int \frac {-184-64 x-4 x^2+e^{625 e^{5-x}} \left (8+e^{5-x} \left (-5000 x-625 x^2\right )\right )}{64+16 x+x^2} \, dx=\int { -\frac {4 \, x^{2} + {\left (625 \, {\left (x^{2} + 8 \, x\right )} e^{\left (-x + 5\right )} - 8\right )} e^{\left (625 \, e^{\left (-x + 5\right )}\right )} + 64 \, x + 184}{x^{2} + 16 \, x + 64} \,d x } \]
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Time = 0.27 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.12 \[ \int \frac {-184-64 x-4 x^2+e^{625 e^{5-x}} \left (8+e^{5-x} \left (-5000 x-625 x^2\right )\right )}{64+16 x+x^2} \, dx=-\frac {4 \, x^{2} - x e^{\left (625 \, e^{\left (-x + 5\right )}\right )} + 32 \, x + 72}{x + 8} \]
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Time = 11.64 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.08 \[ \int \frac {-184-64 x-4 x^2+e^{625 e^{5-x}} \left (8+e^{5-x} \left (-5000 x-625 x^2\right )\right )}{64+16 x+x^2} \, dx=-\frac {23\,x-x\,{\mathrm {e}}^{625\,{\mathrm {e}}^{-x}\,{\mathrm {e}}^5}+4\,x^2}{x+8} \]
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