\(\int \frac {e^{2 e^x} (6-3 e^4)+12 x^2-3 e^4 x^2-3 x^2 \log (2)+(-16 x+6 e^4 x+2 x \log (2)) \log (3)+(6-3 e^4) \log ^2(3)+e^{e^x} (-16 x+6 e^4 x+2 x \log (2)+e^x (-2 x^2+x^2 \log (2))+(12-6 e^4) \log (3))}{e^{2 e^x} x^4+x^6-2 x^5 \log (3)+x^4 \log ^2(3)+e^{e^x} (-2 x^5+2 x^4 \log (3))} \, dx\) [414]

Optimal result

Integrand size = 165, antiderivative size = 30 \[ \int \frac {e^{2 e^x} \left (6-3 e^4\right )+12 x^2-3 e^4 x^2-3 x^2 \log (2)+\left (-16 x+6 e^4 x+2 x \log (2)\right ) \log (3)+\left (6-3 e^4\right ) \log ^2(3)+e^{e^x} \left (-16 x+6 e^4 x+2 x \log (2)+e^x \left (-2 x^2+x^2 \log (2)\right )+\left (12-6 e^4\right ) \log (3)\right )}{e^{2 e^x} x^4+x^6-2 x^5 \log (3)+x^4 \log ^2(3)+e^{e^x} \left (-2 x^5+2 x^4 \log (3)\right )} \, dx=\frac {-2+e^4+\frac {x (2-\log (2))}{e^{e^x}-x+\log (3)}}{x^3} \]

[Out]

((2-ln(2))*x/(ln(3)+exp(exp(x))-x)+exp(4)-2)/x^3

Rubi [F]

\[ \int \frac {e^{2 e^x} \left (6-3 e^4\right )+12 x^2-3 e^4 x^2-3 x^2 \log (2)+\left (-16 x+6 e^4 x+2 x \log (2)\right ) \log (3)+\left (6-3 e^4\right ) \log ^2(3)+e^{e^x} \left (-16 x+6 e^4 x+2 x \log (2)+e^x \left (-2 x^2+x^2 \log (2)\right )+\left (12-6 e^4\right ) \log (3)\right )}{e^{2 e^x} x^4+x^6-2 x^5 \log (3)+x^4 \log ^2(3)+e^{e^x} \left (-2 x^5+2 x^4 \log (3)\right )} \, dx=\int \frac {e^{2 e^x} \left (6-3 e^4\right )+12 x^2-3 e^4 x^2-3 x^2 \log (2)+\left (-16 x+6 e^4 x+2 x \log (2)\right ) \log (3)+\left (6-3 e^4\right ) \log ^2(3)+e^{e^x} \left (-16 x+6 e^4 x+2 x \log (2)+e^x \left (-2 x^2+x^2 \log (2)\right )+\left (12-6 e^4\right ) \log (3)\right )}{e^{2 e^x} x^4+x^6-2 x^5 \log (3)+x^4 \log ^2(3)+e^{e^x} \left (-2 x^5+2 x^4 \log (3)\right )} \, dx \]

[In]

Int[(E^(2*E^x)*(6 - 3*E^4) + 12*x^2 - 3*E^4*x^2 - 3*x^2*Log[2] + (-16*x + 6*E^4*x + 2*x*Log[2])*Log[3] + (6 -
3*E^4)*Log[3]^2 + E^E^x*(-16*x + 6*E^4*x + 2*x*Log[2] + E^x*(-2*x^2 + x^2*Log[2]) + (12 - 6*E^4)*Log[3]))/(E^(
2*E^x)*x^4 + x^6 - 2*x^5*Log[3] + x^4*Log[3]^2 + E^E^x*(-2*x^5 + 2*x^4*Log[3])),x]

[Out]

6*Log[3]^2*Defer[Int][1/(x^4*(-E^E^x + x - Log[3])^2), x] - 3*E^4*Log[3]^2*Defer[Int][1/(x^4*(-E^E^x + x - Log
[3])^2), x] + 12*Log[3]*Defer[Int][E^E^x/(x^4*(-E^E^x + x - Log[3])^2), x] - 6*Log[3]*Defer[Int][E^(4 + E^x)/(
x^4*(-E^E^x + x - Log[3])^2), x] - Log[3]*(16 - Log[4])*Defer[Int][1/(x^3*(-E^E^x + x - Log[3])^2), x] + 3*E^4
*Log[9]*Defer[Int][1/(x^3*(-E^E^x + x - Log[3])^2), x] - (16 - Log[4])*Defer[Int][E^E^x/(x^3*(-E^E^x + x - Log
[3])^2), x] + 6*Defer[Int][E^(4 + E^x)/(x^3*(-E^E^x + x - Log[3])^2), x] - 3*E^4*Defer[Int][1/(x^2*(-E^E^x + x
- Log[3])^2), x] + (12 - Log[8])*Defer[Int][1/(x^2*(-E^E^x + x - Log[3])^2), x] + 3*(2 - E^4)*Defer[Int][E^(2
*E^x)/(x^4*(E^E^x - x + Log[3])^2), x] - (2 - Log[2])*Defer[Int][E^(E^x + x)/(x^2*(E^E^x - x + Log[3])^2), x]

Rubi steps \begin{align*} \text {integral}& = \int \frac {e^{2 e^x} \left (6-3 e^4\right )+\left (12-3 e^4\right ) x^2-3 x^2 \log (2)+\left (-16 x+6 e^4 x+2 x \log (2)\right ) \log (3)+\left (6-3 e^4\right ) \log ^2(3)+e^{e^x} \left (-16 x+6 e^4 x+2 x \log (2)+e^x \left (-2 x^2+x^2 \log (2)\right )+\left (12-6 e^4\right ) \log (3)\right )}{e^{2 e^x} x^4+x^6-2 x^5 \log (3)+x^4 \log ^2(3)+e^{e^x} \left (-2 x^5+2 x^4 \log (3)\right )} \, dx \\ & = \int \frac {e^{2 e^x} \left (6-3 e^4\right )+x^2 \left (12-3 e^4-3 \log (2)\right )+\left (-16 x+6 e^4 x+2 x \log (2)\right ) \log (3)+\left (6-3 e^4\right ) \log ^2(3)+e^{e^x} \left (-16 x+6 e^4 x+2 x \log (2)+e^x \left (-2 x^2+x^2 \log (2)\right )+\left (12-6 e^4\right ) \log (3)\right )}{e^{2 e^x} x^4+x^6-2 x^5 \log (3)+x^4 \log ^2(3)+e^{e^x} \left (-2 x^5+2 x^4 \log (3)\right )} \, dx \\ & = \int \frac {6 e^{2 e^x} \left (1-\frac {e^4}{2}\right )+e^{e^x+x} x^2 (-2+\log (2))+6 e^{4+e^x} (x-\log (3))-3 e^4 (x-\log (3))^2+6 \log ^2(3)+e^{e^x} (12 \log (3)+x (-16+\log (4)))+x \log (3) (-16+\log (4))-x^2 (-12+\log (8))}{x^4 \left (e^{e^x}-x+\log (3)\right )^2} \, dx \\ & = \int \left (-\frac {3 e^4 (x-\log (3))^2}{x^4 \left (-e^{e^x}+x-\log (3)\right )^2}+\frac {6 \log ^2(3)}{x^4 \left (-e^{e^x}+x-\log (3)\right )^2}-\frac {3 e^{2 e^x} \left (-2+e^4\right )}{x^4 \left (e^{e^x}-x+\log (3)\right )^2}+\frac {e^{e^x+x} (-2+\log (2))}{x^2 \left (e^{e^x}-x+\log (3)\right )^2}+\frac {6 e^{4+e^x} (x-\log (3))}{x^4 \left (e^{e^x}-x+\log (3)\right )^2}+\frac {e^{e^x} (12 \log (3)-x (16-\log (4)))}{x^4 \left (e^{e^x}-x+\log (3)\right )^2}+\frac {\log (3) (-16+\log (4))}{x^3 \left (-e^{e^x}+x-\log (3)\right )^2}-\frac {-12+\log (8)}{x^2 \left (-e^{e^x}+x-\log (3)\right )^2}\right ) \, dx \\ & = 6 \int \frac {e^{4+e^x} (x-\log (3))}{x^4 \left (e^{e^x}-x+\log (3)\right )^2} \, dx-\left (3 e^4\right ) \int \frac {(x-\log (3))^2}{x^4 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx+\left (3 \left (2-e^4\right )\right ) \int \frac {e^{2 e^x}}{x^4 \left (e^{e^x}-x+\log (3)\right )^2} \, dx+(-2+\log (2)) \int \frac {e^{e^x+x}}{x^2 \left (e^{e^x}-x+\log (3)\right )^2} \, dx+\left (6 \log ^2(3)\right ) \int \frac {1}{x^4 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx-(\log (3) (16-\log (4))) \int \frac {1}{x^3 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx+(12-\log (8)) \int \frac {1}{x^2 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx+\int \frac {e^{e^x} (12 \log (3)-x (16-\log (4)))}{x^4 \left (e^{e^x}-x+\log (3)\right )^2} \, dx \\ & = 6 \int \left (\frac {e^{4+e^x}}{x^3 \left (-e^{e^x}+x-\log (3)\right )^2}-\frac {e^{4+e^x} \log (3)}{x^4 \left (-e^{e^x}+x-\log (3)\right )^2}\right ) \, dx-\left (3 e^4\right ) \int \left (\frac {1}{x^2 \left (-e^{e^x}+x-\log (3)\right )^2}+\frac {\log ^2(3)}{x^4 \left (-e^{e^x}+x-\log (3)\right )^2}-\frac {\log (9)}{x^3 \left (-e^{e^x}+x-\log (3)\right )^2}\right ) \, dx+\left (3 \left (2-e^4\right )\right ) \int \frac {e^{2 e^x}}{x^4 \left (e^{e^x}-x+\log (3)\right )^2} \, dx+(-2+\log (2)) \int \frac {e^{e^x+x}}{x^2 \left (e^{e^x}-x+\log (3)\right )^2} \, dx+\left (6 \log ^2(3)\right ) \int \frac {1}{x^4 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx-(\log (3) (16-\log (4))) \int \frac {1}{x^3 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx+(12-\log (8)) \int \frac {1}{x^2 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx+\int \left (\frac {12 e^{e^x} \log (3)}{x^4 \left (-e^{e^x}+x-\log (3)\right )^2}+\frac {e^{e^x} (-16+\log (4))}{x^3 \left (-e^{e^x}+x-\log (3)\right )^2}\right ) \, dx \\ & = 6 \int \frac {e^{4+e^x}}{x^3 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx-\left (3 e^4\right ) \int \frac {1}{x^2 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx+\left (3 \left (2-e^4\right )\right ) \int \frac {e^{2 e^x}}{x^4 \left (e^{e^x}-x+\log (3)\right )^2} \, dx+(-2+\log (2)) \int \frac {e^{e^x+x}}{x^2 \left (e^{e^x}-x+\log (3)\right )^2} \, dx-(6 \log (3)) \int \frac {e^{4+e^x}}{x^4 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx+(12 \log (3)) \int \frac {e^{e^x}}{x^4 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx+\left (6 \log ^2(3)\right ) \int \frac {1}{x^4 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx-\left (3 e^4 \log ^2(3)\right ) \int \frac {1}{x^4 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx-(\log (3) (16-\log (4))) \int \frac {1}{x^3 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx+(-16+\log (4)) \int \frac {e^{e^x}}{x^3 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx+(12-\log (8)) \int \frac {1}{x^2 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx+\left (3 e^4 \log (9)\right ) \int \frac {1}{x^3 \left (-e^{e^x}+x-\log (3)\right )^2} \, dx \\ \end{align*}

Mathematica [F(-1)]

Timed out. \[ \int \frac {e^{2 e^x} \left (6-3 e^4\right )+12 x^2-3 e^4 x^2-3 x^2 \log (2)+\left (-16 x+6 e^4 x+2 x \log (2)\right ) \log (3)+\left (6-3 e^4\right ) \log ^2(3)+e^{e^x} \left (-16 x+6 e^4 x+2 x \log (2)+e^x \left (-2 x^2+x^2 \log (2)\right )+\left (12-6 e^4\right ) \log (3)\right )}{e^{2 e^x} x^4+x^6-2 x^5 \log (3)+x^4 \log ^2(3)+e^{e^x} \left (-2 x^5+2 x^4 \log (3)\right )} \, dx=\text {\$Aborted} \]

[In]

Integrate[(E^(2*E^x)*(6 - 3*E^4) + 12*x^2 - 3*E^4*x^2 - 3*x^2*Log[2] + (-16*x + 6*E^4*x + 2*x*Log[2])*Log[3] +
(6 - 3*E^4)*Log[3]^2 + E^E^x*(-16*x + 6*E^4*x + 2*x*Log[2] + E^x*(-2*x^2 + x^2*Log[2]) + (12 - 6*E^4)*Log[3])
)/(E^(2*E^x)*x^4 + x^6 - 2*x^5*Log[3] + x^4*Log[3]^2 + E^E^x*(-2*x^5 + 2*x^4*Log[3])),x]

[Out]

$Aborted

Maple [A] (verified)

Time = 0.34 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.10

method	result	size
risch	\(\frac {{\mathrm e}^{4}}{x^{3}}-\frac {2}{x^{3}}-\frac {\ln \left (2\right )-2}{x^{2} \left (\ln \left (3\right )+{\mathrm e}^{{\mathrm e}^{x}}-x \right )}\)	\(33\)
parallelrisch	\(\frac {{\mathrm e}^{4} \ln \left (3\right )+{\mathrm e}^{4} {\mathrm e}^{{\mathrm e}^{x}}-x \,{\mathrm e}^{4}-x \ln \left (2\right )-2 \ln \left (3\right )-2 \,{\mathrm e}^{{\mathrm e}^{x}}+4 x}{x^{3} \left (\ln \left (3\right )+{\mathrm e}^{{\mathrm e}^{x}}-x \right )}\)	\(50\)

[In]

int(((-3*exp(4)+6)*exp(exp(x))^2+((x^2*ln(2)-2*x^2)*exp(x)+(-6*exp(4)+12)*ln(3)+2*x*ln(2)+6*x*exp(4)-16*x)*exp
(exp(x))+(-3*exp(4)+6)*ln(3)^2+(2*x*ln(2)+6*x*exp(4)-16*x)*ln(3)-3*x^2*ln(2)-3*x^2*exp(4)+12*x^2)/(x^4*exp(exp
(x))^2+(2*x^4*ln(3)-2*x^5)*exp(exp(x))+x^4*ln(3)^2-2*x^5*ln(3)+x^6),x,method=_RETURNVERBOSE)

[Out]

exp(4)/x^3-2/x^3-(ln(2)-2)/x^2/(ln(3)+exp(exp(x))-x)

Fricas [A] (verification not implemented)

none

Time = 0.26 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.70 \[ \int \frac {e^{2 e^x} \left (6-3 e^4\right )+12 x^2-3 e^4 x^2-3 x^2 \log (2)+\left (-16 x+6 e^4 x+2 x \log (2)\right ) \log (3)+\left (6-3 e^4\right ) \log ^2(3)+e^{e^x} \left (-16 x+6 e^4 x+2 x \log (2)+e^x \left (-2 x^2+x^2 \log (2)\right )+\left (12-6 e^4\right ) \log (3)\right )}{e^{2 e^x} x^4+x^6-2 x^5 \log (3)+x^4 \log ^2(3)+e^{e^x} \left (-2 x^5+2 x^4 \log (3)\right )} \, dx=\frac {x e^{4} - {\left (e^{4} - 2\right )} e^{\left (e^{x}\right )} - {\left (e^{4} - 2\right )} \log \left (3\right ) + x \log \left (2\right ) - 4 \, x}{x^{4} - x^{3} e^{\left (e^{x}\right )} - x^{3} \log \left (3\right )} \]

[In]

integrate(((-3*exp(4)+6)*exp(exp(x))^2+((x^2*log(2)-2*x^2)*exp(x)+(-6*exp(4)+12)*log(3)+2*x*log(2)+6*x*exp(4)-
16*x)*exp(exp(x))+(-3*exp(4)+6)*log(3)^2+(2*x*log(2)+6*x*exp(4)-16*x)*log(3)-3*x^2*log(2)-3*x^2*exp(4)+12*x^2)
/(x^4*exp(exp(x))^2+(2*x^4*log(3)-2*x^5)*exp(exp(x))+x^4*log(3)^2-2*x^5*log(3)+x^6),x, algorithm="fricas")

[Out]

(x*e^4 - (e^4 - 2)*e^(e^x) - (e^4 - 2)*log(3) + x*log(2) - 4*x)/(x^4 - x^3*e^(e^x) - x^3*log(3))

Sympy [A] (verification not implemented)

Time = 0.09 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.13 \[ \int \frac {e^{2 e^x} \left (6-3 e^4\right )+12 x^2-3 e^4 x^2-3 x^2 \log (2)+\left (-16 x+6 e^4 x+2 x \log (2)\right ) \log (3)+\left (6-3 e^4\right ) \log ^2(3)+e^{e^x} \left (-16 x+6 e^4 x+2 x \log (2)+e^x \left (-2 x^2+x^2 \log (2)\right )+\left (12-6 e^4\right ) \log (3)\right )}{e^{2 e^x} x^4+x^6-2 x^5 \log (3)+x^4 \log ^2(3)+e^{e^x} \left (-2 x^5+2 x^4 \log (3)\right )} \, dx=\frac {2 - \log {\left (2 \right )}}{- x^{3} + x^{2} e^{e^{x}} + x^{2} \log {\left (3 \right )}} - \frac {6 - 3 e^{4}}{3 x^{3}} \]

[In]

integrate(((-3*exp(4)+6)*exp(exp(x))**2+((x**2*ln(2)-2*x**2)*exp(x)+(-6*exp(4)+12)*ln(3)+2*x*ln(2)+6*x*exp(4)-
16*x)*exp(exp(x))+(-3*exp(4)+6)*ln(3)**2+(2*x*ln(2)+6*x*exp(4)-16*x)*ln(3)-3*x**2*ln(2)-3*x**2*exp(4)+12*x**2)
/(x**4*exp(exp(x))**2+(2*x**4*ln(3)-2*x**5)*exp(exp(x))+x**4*ln(3)**2-2*x**5*ln(3)+x**6),x)

[Out]

(2 - log(2))/(-x**3 + x**2*exp(exp(x)) + x**2*log(3)) - (6 - 3*exp(4))/(3*x**3)

Maxima [A] (verification not implemented)

none

Time = 0.31 (sec) , antiderivative size = 50, normalized size of antiderivative = 1.67 \[ \int \frac {e^{2 e^x} \left (6-3 e^4\right )+12 x^2-3 e^4 x^2-3 x^2 \log (2)+\left (-16 x+6 e^4 x+2 x \log (2)\right ) \log (3)+\left (6-3 e^4\right ) \log ^2(3)+e^{e^x} \left (-16 x+6 e^4 x+2 x \log (2)+e^x \left (-2 x^2+x^2 \log (2)\right )+\left (12-6 e^4\right ) \log (3)\right )}{e^{2 e^x} x^4+x^6-2 x^5 \log (3)+x^4 \log ^2(3)+e^{e^x} \left (-2 x^5+2 x^4 \log (3)\right )} \, dx=\frac {x {\left (e^{4} + \log \left (2\right ) - 4\right )} - {\left (e^{4} - 2\right )} e^{\left (e^{x}\right )} - e^{4} \log \left (3\right ) + 2 \, \log \left (3\right )}{x^{4} - x^{3} e^{\left (e^{x}\right )} - x^{3} \log \left (3\right )} \]

[In]

integrate(((-3*exp(4)+6)*exp(exp(x))^2+((x^2*log(2)-2*x^2)*exp(x)+(-6*exp(4)+12)*log(3)+2*x*log(2)+6*x*exp(4)-
16*x)*exp(exp(x))+(-3*exp(4)+6)*log(3)^2+(2*x*log(2)+6*x*exp(4)-16*x)*log(3)-3*x^2*log(2)-3*x^2*exp(4)+12*x^2)
/(x^4*exp(exp(x))^2+(2*x^4*log(3)-2*x^5)*exp(exp(x))+x^4*log(3)^2-2*x^5*log(3)+x^6),x, algorithm="maxima")

[Out]

(x*(e^4 + log(2) - 4) - (e^4 - 2)*e^(e^x) - e^4*log(3) + 2*log(3))/(x^4 - x^3*e^(e^x) - x^3*log(3))

Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 56 vs. \(2 (27) = 54\).

Time = 0.33 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.87 \[ \int \frac {e^{2 e^x} \left (6-3 e^4\right )+12 x^2-3 e^4 x^2-3 x^2 \log (2)+\left (-16 x+6 e^4 x+2 x \log (2)\right ) \log (3)+\left (6-3 e^4\right ) \log ^2(3)+e^{e^x} \left (-16 x+6 e^4 x+2 x \log (2)+e^x \left (-2 x^2+x^2 \log (2)\right )+\left (12-6 e^4\right ) \log (3)\right )}{e^{2 e^x} x^4+x^6-2 x^5 \log (3)+x^4 \log ^2(3)+e^{e^x} \left (-2 x^5+2 x^4 \log (3)\right )} \, dx=\frac {x e^{4} - e^{4} \log \left (3\right ) + x \log \left (2\right ) - 4 \, x - e^{\left (e^{x} + 4\right )} + 2 \, e^{\left (e^{x}\right )} + 2 \, \log \left (3\right )}{x^{4} - x^{3} e^{\left (e^{x}\right )} - x^{3} \log \left (3\right )} \]

[In]

integrate(((-3*exp(4)+6)*exp(exp(x))^2+((x^2*log(2)-2*x^2)*exp(x)+(-6*exp(4)+12)*log(3)+2*x*log(2)+6*x*exp(4)-
16*x)*exp(exp(x))+(-3*exp(4)+6)*log(3)^2+(2*x*log(2)+6*x*exp(4)-16*x)*log(3)-3*x^2*log(2)-3*x^2*exp(4)+12*x^2)
/(x^4*exp(exp(x))^2+(2*x^4*log(3)-2*x^5)*exp(exp(x))+x^4*log(3)^2-2*x^5*log(3)+x^6),x, algorithm="giac")

[Out]

(x*e^4 - e^4*log(3) + x*log(2) - 4*x - e^(e^x + 4) + 2*e^(e^x) + 2*log(3))/(x^4 - x^3*e^(e^x) - x^3*log(3))

Mupad [F(-1)]

Timed out. \[ \int \frac {e^{2 e^x} \left (6-3 e^4\right )+12 x^2-3 e^4 x^2-3 x^2 \log (2)+\left (-16 x+6 e^4 x+2 x \log (2)\right ) \log (3)+\left (6-3 e^4\right ) \log ^2(3)+e^{e^x} \left (-16 x+6 e^4 x+2 x \log (2)+e^x \left (-2 x^2+x^2 \log (2)\right )+\left (12-6 e^4\right ) \log (3)\right )}{e^{2 e^x} x^4+x^6-2 x^5 \log (3)+x^4 \log ^2(3)+e^{e^x} \left (-2 x^5+2 x^4 \log (3)\right )} \, dx=-\int \frac {{\mathrm {e}}^{2\,{\mathrm {e}}^x}\,\left (3\,{\mathrm {e}}^4-6\right )+{\ln \left (3\right )}^2\,\left (3\,{\mathrm {e}}^4-6\right )-\ln \left (3\right )\,\left (6\,x\,{\mathrm {e}}^4-16\,x+2\,x\,\ln \left (2\right )\right )+3\,x^2\,{\mathrm {e}}^4+3\,x^2\,\ln \left (2\right )-{\mathrm {e}}^{{\mathrm {e}}^x}\,\left (6\,x\,{\mathrm {e}}^4-16\,x+2\,x\,\ln \left (2\right )+{\mathrm {e}}^x\,\left (x^2\,\ln \left (2\right )-2\,x^2\right )-\ln \left (3\right )\,\left (6\,{\mathrm {e}}^4-12\right )\right )-12\,x^2}{x^4\,{\ln \left (3\right )}^2-2\,x^5\,\ln \left (3\right )+x^6+x^4\,{\mathrm {e}}^{2\,{\mathrm {e}}^x}+{\mathrm {e}}^{{\mathrm {e}}^x}\,\left (2\,x^4\,\ln \left (3\right )-2\,x^5\right )} \,d x \]

[In]

int(-(exp(2*exp(x))*(3*exp(4) - 6) + log(3)^2*(3*exp(4) - 6) - log(3)*(6*x*exp(4) - 16*x + 2*x*log(2)) + 3*x^2
*exp(4) + 3*x^2*log(2) - exp(exp(x))*(6*x*exp(4) - 16*x + 2*x*log(2) + exp(x)*(x^2*log(2) - 2*x^2) - log(3)*(6
*exp(4) - 12)) - 12*x^2)/(x^4*log(3)^2 - 2*x^5*log(3) + x^6 + x^4*exp(2*exp(x)) + exp(exp(x))*(2*x^4*log(3) -
2*x^5)),x)

[Out]

-int((exp(2*exp(x))*(3*exp(4) - 6) + log(3)^2*(3*exp(4) - 6) - log(3)*(6*x*exp(4) - 16*x + 2*x*log(2)) + 3*x^2
*exp(4) + 3*x^2*log(2) - exp(exp(x))*(6*x*exp(4) - 16*x + 2*x*log(2) + exp(x)*(x^2*log(2) - 2*x^2) - log(3)*(6
*exp(4) - 12)) - 12*x^2)/(x^4*log(3)^2 - 2*x^5*log(3) + x^6 + x^4*exp(2*exp(x)) + exp(exp(x))*(2*x^4*log(3) -
2*x^5)), x)