Integrand size = 7, antiderivative size = 14 \[ \int \frac {-2+x}{x} \, dx=-1+\frac {1}{16+e^2}+x+\log \left (\frac {1}{x^2}\right ) \]
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Time = 0.00 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.43, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {45} \[ \int \frac {-2+x}{x} \, dx=x-2 \log (x) \]
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Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \left (1-\frac {2}{x}\right ) \, dx \\ & = x-2 \log (x) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.43 \[ \int \frac {-2+x}{x} \, dx=x-2 \log (x) \]
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Time = 0.02 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.50
method | result | size |
default | \(x -2 \ln \left (x \right )\) | \(7\) |
norman | \(x -2 \ln \left (x \right )\) | \(7\) |
risch | \(x -2 \ln \left (x \right )\) | \(7\) |
parallelrisch | \(x -2 \ln \left (x \right )\) | \(7\) |
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none
Time = 0.23 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.43 \[ \int \frac {-2+x}{x} \, dx=x - 2 \, \log \left (x\right ) \]
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Time = 0.03 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.36 \[ \int \frac {-2+x}{x} \, dx=x - 2 \log {\left (x \right )} \]
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none
Time = 0.17 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.43 \[ \int \frac {-2+x}{x} \, dx=x - 2 \, \log \left (x\right ) \]
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none
Time = 0.26 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.50 \[ \int \frac {-2+x}{x} \, dx=x - 2 \, \log \left ({\left | x \right |}\right ) \]
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Time = 0.02 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.43 \[ \int \frac {-2+x}{x} \, dx=x-2\,\ln \left (x\right ) \]
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