\(\int (8-4 e^{2 e}-14 x-32 e^e x-48 x^2) \, dx\) [5290]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [A] (verification not implemented)
   Sympy [A] (verification not implemented)
   Maxima [A] (verification not implemented)
   Giac [A] (verification not implemented)
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 23, antiderivative size = 22 \[ \int \left (8-4 e^{2 e}-14 x-32 e^e x-48 x^2\right ) \, dx=x \left (x+4 \left (2-2 x-\left (e^e+2 x\right )^2\right )\right ) \]

[Out]

(8-4*(2*x+exp(exp(1)))^2-7*x)*x

Rubi [A] (verified)

Time = 0.01 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.36, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.043, Rules used = {6} \[ \int \left (8-4 e^{2 e}-14 x-32 e^e x-48 x^2\right ) \, dx=-16 x^3-\left (7+16 e^e\right ) x^2+4 \left (2-e^{2 e}\right ) x \]

[In]

Int[8 - 4*E^(2*E) - 14*x - 32*E^E*x - 48*x^2,x]

[Out]

4*(2 - E^(2*E))*x - (7 + 16*E^E)*x^2 - 16*x^3

Rule 6

Int[(u_.)*((w_.) + (a_.)*(v_) + (b_.)*(v_))^(p_.), x_Symbol] :> Int[u*((a + b)*v + w)^p, x] /; FreeQ[{a, b}, x
] &&  !FreeQ[v, x]

Rubi steps \begin{align*} \text {integral}& = \int \left (8-4 e^{2 e}+\left (-14-32 e^e\right ) x-48 x^2\right ) \, dx \\ & = 4 \left (2-e^{2 e}\right ) x-\left (7+16 e^e\right ) x^2-16 x^3 \\ \end{align*}

Mathematica [A] (verified)

Time = 0.00 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.36 \[ \int \left (8-4 e^{2 e}-14 x-32 e^e x-48 x^2\right ) \, dx=8 x-4 e^{2 e} x-7 x^2-16 e^e x^2-16 x^3 \]

[In]

Integrate[8 - 4*E^(2*E) - 14*x - 32*E^E*x - 48*x^2,x]

[Out]

8*x - 4*E^(2*E)*x - 7*x^2 - 16*E^E*x^2 - 16*x^3

Maple [A] (verified)

Time = 0.04 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.23

method result size
gosper \(-x \left (4 \,{\mathrm e}^{2 \,{\mathrm e}}+16 x \,{\mathrm e}^{{\mathrm e}}+16 x^{2}+7 x -8\right )\) \(27\)
norman \(\left (-4 \,{\mathrm e}^{2 \,{\mathrm e}}+8\right ) x +\left (-16 \,{\mathrm e}^{{\mathrm e}}-7\right ) x^{2}-16 x^{3}\) \(29\)
default \(-4 \,{\mathrm e}^{2 \,{\mathrm e}} x -16 x^{2} {\mathrm e}^{{\mathrm e}}-16 x^{3}-7 x^{2}+8 x\) \(31\)
risch \(-4 \,{\mathrm e}^{2 \,{\mathrm e}} x -16 x^{2} {\mathrm e}^{{\mathrm e}}-16 x^{3}-7 x^{2}+8 x\) \(31\)
parallelrisch \(-16 x^{2} {\mathrm e}^{{\mathrm e}}-16 x^{3}-7 x^{2}+\left (-4 \,{\mathrm e}^{2 \,{\mathrm e}}+8\right ) x\) \(31\)
parts \(-4 \,{\mathrm e}^{2 \,{\mathrm e}} x -16 x^{2} {\mathrm e}^{{\mathrm e}}-16 x^{3}-7 x^{2}+8 x\) \(31\)

[In]

int(-4*exp(exp(1))^2-32*x*exp(exp(1))-48*x^2-14*x+8,x,method=_RETURNVERBOSE)

[Out]

-x*(4*exp(exp(1))^2+16*x*exp(exp(1))+16*x^2+7*x-8)

Fricas [A] (verification not implemented)

none

Time = 0.23 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.36 \[ \int \left (8-4 e^{2 e}-14 x-32 e^e x-48 x^2\right ) \, dx=-16 \, x^{3} - 16 \, x^{2} e^{e} - 7 \, x^{2} - 4 \, x e^{\left (2 \, e\right )} + 8 \, x \]

[In]

integrate(-4*exp(exp(1))^2-32*x*exp(exp(1))-48*x^2-14*x+8,x, algorithm="fricas")

[Out]

-16*x^3 - 16*x^2*e^e - 7*x^2 - 4*x*e^(2*e) + 8*x

Sympy [A] (verification not implemented)

Time = 0.02 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.32 \[ \int \left (8-4 e^{2 e}-14 x-32 e^e x-48 x^2\right ) \, dx=- 16 x^{3} + x^{2} \left (- 16 e^{e} - 7\right ) + x \left (8 - 4 e^{2 e}\right ) \]

[In]

integrate(-4*exp(exp(1))**2-32*x*exp(exp(1))-48*x**2-14*x+8,x)

[Out]

-16*x**3 + x**2*(-16*exp(E) - 7) + x*(8 - 4*exp(2*E))

Maxima [A] (verification not implemented)

none

Time = 0.18 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.36 \[ \int \left (8-4 e^{2 e}-14 x-32 e^e x-48 x^2\right ) \, dx=-16 \, x^{3} - 16 \, x^{2} e^{e} - 7 \, x^{2} - 4 \, x e^{\left (2 \, e\right )} + 8 \, x \]

[In]

integrate(-4*exp(exp(1))^2-32*x*exp(exp(1))-48*x^2-14*x+8,x, algorithm="maxima")

[Out]

-16*x^3 - 16*x^2*e^e - 7*x^2 - 4*x*e^(2*e) + 8*x

Giac [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.36 \[ \int \left (8-4 e^{2 e}-14 x-32 e^e x-48 x^2\right ) \, dx=-16 \, x^{3} - 16 \, x^{2} e^{e} - 7 \, x^{2} - 4 \, x e^{\left (2 \, e\right )} + 8 \, x \]

[In]

integrate(-4*exp(exp(1))^2-32*x*exp(exp(1))-48*x^2-14*x+8,x, algorithm="giac")

[Out]

-16*x^3 - 16*x^2*e^e - 7*x^2 - 4*x*e^(2*e) + 8*x

Mupad [B] (verification not implemented)

Time = 0.04 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.36 \[ \int \left (8-4 e^{2 e}-14 x-32 e^e x-48 x^2\right ) \, dx=-16\,x^3+\left (-16\,{\mathrm {e}}^{\mathrm {e}}-7\right )\,x^2+\left (8-4\,{\mathrm {e}}^{2\,\mathrm {e}}\right )\,x \]

[In]

int(8 - 4*exp(2*exp(1)) - 32*x*exp(exp(1)) - 48*x^2 - 14*x,x)

[Out]

- x*(4*exp(2*exp(1)) - 8) - x^2*(16*exp(exp(1)) + 7) - 16*x^3