Integrand size = 31, antiderivative size = 19 \[ \int \frac {1}{3} e^{\frac {1}{3} \left (8-10 x-3 x^2+e (4+x)\right )} (-10+e-6 x) \, dx=e^{\frac {1}{3} (-4-x) (-2-e+3 x)} \]
[Out]
Time = 0.07 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.32, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.097, Rules used = {12, 2276, 2268} \[ \int \frac {1}{3} e^{\frac {1}{3} \left (8-10 x-3 x^2+e (4+x)\right )} (-10+e-6 x) \, dx=e^{-x^2-\frac {1}{3} (10-e) x+\frac {4 (2+e)}{3}} \]
[In]
[Out]
Rule 12
Rule 2268
Rule 2276
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \int e^{\frac {1}{3} \left (8-10 x-3 x^2+e (4+x)\right )} (-10+e-6 x) \, dx \\ & = \frac {1}{3} \int e^{\frac {4 (2+e)}{3}+\frac {1}{3} (-10+e) x-x^2} (-10+e-6 x) \, dx \\ & = e^{\frac {4 (2+e)}{3}-\frac {1}{3} (10-e) x-x^2} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.79 \[ \int \frac {1}{3} e^{\frac {1}{3} \left (8-10 x-3 x^2+e (4+x)\right )} (-10+e-6 x) \, dx=e^{\frac {1}{3} (2+e-3 x) (4+x)} \]
[In]
[Out]
Time = 0.07 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.74
method | result | size |
risch | \({\mathrm e}^{\frac {\left (4+x \right ) \left (-3 x +{\mathrm e}+2\right )}{3}}\) | \(14\) |
norman | \({\mathrm e}^{\frac {\left (4+x \right ) {\mathrm e}}{3}-x^{2}-\frac {10 x}{3}+\frac {8}{3}}\) | \(19\) |
parallelrisch | \({\mathrm e}^{\frac {\left (4+x \right ) {\mathrm e}}{3}-x^{2}-\frac {10 x}{3}+\frac {8}{3}}\) | \(19\) |
gosper | \({\mathrm e}^{\frac {x \,{\mathrm e}}{3}+\frac {4 \,{\mathrm e}}{3}-x^{2}-\frac {10 x}{3}+\frac {8}{3}}\) | \(21\) |
default | \(\frac {{\mathrm e}^{\frac {4 \,{\mathrm e}}{3}} {\mathrm e}^{\frac {8}{3}} {\mathrm e} \sqrt {\pi }\, {\mathrm e}^{\frac {\left (\frac {{\mathrm e}}{3}-\frac {10}{3}\right )^{2}}{4}} \operatorname {erf}\left (x -\frac {{\mathrm e}}{6}+\frac {5}{3}\right )}{6}-\frac {5 \,{\mathrm e}^{\frac {4 \,{\mathrm e}}{3}} {\mathrm e}^{\frac {8}{3}} \sqrt {\pi }\, {\mathrm e}^{\frac {\left (\frac {{\mathrm e}}{3}-\frac {10}{3}\right )^{2}}{4}} \operatorname {erf}\left (x -\frac {{\mathrm e}}{6}+\frac {5}{3}\right )}{3}-2 \,{\mathrm e}^{\frac {4 \,{\mathrm e}}{3}} {\mathrm e}^{\frac {8}{3}} \left (-\frac {{\mathrm e}^{-x^{2}+\left (\frac {{\mathrm e}}{3}-\frac {10}{3}\right ) x}}{2}+\frac {\left (\frac {{\mathrm e}}{3}-\frac {10}{3}\right ) \sqrt {\pi }\, {\mathrm e}^{\frac {\left (\frac {{\mathrm e}}{3}-\frac {10}{3}\right )^{2}}{4}} \operatorname {erf}\left (x -\frac {{\mathrm e}}{6}+\frac {5}{3}\right )}{4}\right )\) | \(123\) |
parts | \(\frac {\sqrt {\pi }\, {\mathrm e}^{\frac {4 \,{\mathrm e}}{3}+\frac {8}{3}+\frac {\left (\frac {{\mathrm e}}{3}-\frac {10}{3}\right )^{2}}{4}} \operatorname {erf}\left (x -\frac {{\mathrm e}}{6}+\frac {5}{3}\right ) {\mathrm e}}{6}-\sqrt {\pi }\, {\mathrm e}^{\frac {4 \,{\mathrm e}}{3}+\frac {8}{3}+\frac {\left (\frac {{\mathrm e}}{3}-\frac {10}{3}\right )^{2}}{4}} \operatorname {erf}\left (x -\frac {{\mathrm e}}{6}+\frac {5}{3}\right ) x -\frac {5 \sqrt {\pi }\, {\mathrm e}^{\frac {4 \,{\mathrm e}}{3}+\frac {8}{3}+\frac {\left (\frac {{\mathrm e}}{3}-\frac {10}{3}\right )^{2}}{4}} \operatorname {erf}\left (x -\frac {{\mathrm e}}{6}+\frac {5}{3}\right )}{3}-\frac {{\mathrm e}^{\frac {4 \,{\mathrm e}}{3}+\frac {8}{3}+\frac {\left (\frac {{\mathrm e}}{3}-\frac {10}{3}\right )^{2}}{4}} \left (\operatorname {erf}\left (x -\frac {{\mathrm e}}{6}+\frac {5}{3}\right ) \sqrt {\pi }\, {\mathrm e}-6 x \,\operatorname {erf}\left (x -\frac {{\mathrm e}}{6}+\frac {5}{3}\right ) \sqrt {\pi }-10 \,\operatorname {erf}\left (x -\frac {{\mathrm e}}{6}+\frac {5}{3}\right ) \sqrt {\pi }-6 \,{\mathrm e}^{-\left (x -\frac {{\mathrm e}}{6}+\frac {5}{3}\right )^{2}}\right )}{6}\) | \(170\) |
[In]
[Out]
none
Time = 0.26 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.95 \[ \int \frac {1}{3} e^{\frac {1}{3} \left (8-10 x-3 x^2+e (4+x)\right )} (-10+e-6 x) \, dx=e^{\left (-x^{2} + \frac {1}{3} \, {\left (x + 4\right )} e - \frac {10}{3} \, x + \frac {8}{3}\right )} \]
[In]
[Out]
Time = 0.06 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.16 \[ \int \frac {1}{3} e^{\frac {1}{3} \left (8-10 x-3 x^2+e (4+x)\right )} (-10+e-6 x) \, dx=e^{- x^{2} - \frac {10 x}{3} + e \left (\frac {x}{3} + \frac {4}{3}\right ) + \frac {8}{3}} \]
[In]
[Out]
none
Time = 0.18 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.95 \[ \int \frac {1}{3} e^{\frac {1}{3} \left (8-10 x-3 x^2+e (4+x)\right )} (-10+e-6 x) \, dx=e^{\left (-x^{2} + \frac {1}{3} \, {\left (x + 4\right )} e - \frac {10}{3} \, x + \frac {8}{3}\right )} \]
[In]
[Out]
none
Time = 0.27 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.05 \[ \int \frac {1}{3} e^{\frac {1}{3} \left (8-10 x-3 x^2+e (4+x)\right )} (-10+e-6 x) \, dx=e^{\left (-x^{2} + \frac {1}{3} \, x e - \frac {10}{3} \, x + \frac {4}{3} \, e + \frac {8}{3}\right )} \]
[In]
[Out]
Time = 0.18 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.26 \[ \int \frac {1}{3} e^{\frac {1}{3} \left (8-10 x-3 x^2+e (4+x)\right )} (-10+e-6 x) \, dx={\mathrm {e}}^{\frac {4\,\mathrm {e}}{3}}\,{\mathrm {e}}^{-\frac {10\,x}{3}}\,{\mathrm {e}}^{8/3}\,{\mathrm {e}}^{-x^2}\,{\mathrm {e}}^{\frac {x\,\mathrm {e}}{3}} \]
[In]
[Out]