Integrand size = 20, antiderivative size = 25 \[ \int \frac {-50 e^2-5 x+e^x x^3}{x^3} \, dx=-e+e^x+\frac {5+25 e^2 \left (\frac {1}{x}-x\right )}{x} \]
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Time = 0.01 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.92, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {14, 2225, 37} \[ \int \frac {-50 e^2-5 x+e^x x^3}{x^3} \, dx=\frac {\left (x+10 e^2\right )^2}{4 e^2 x^2}+e^x \]
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Rule 14
Rule 37
Rule 2225
Rubi steps \begin{align*} \text {integral}& = \int \left (e^x-\frac {5 \left (10 e^2+x\right )}{x^3}\right ) \, dx \\ & = -\left (5 \int \frac {10 e^2+x}{x^3} \, dx\right )+\int e^x \, dx \\ & = e^x+\frac {\left (10 e^2+x\right )^2}{4 e^2 x^2} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.68 \[ \int \frac {-50 e^2-5 x+e^x x^3}{x^3} \, dx=e^x+\frac {25 e^2}{x^2}+\frac {5}{x} \]
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Time = 0.05 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.64
method | result | size |
default | \(\frac {5}{x}+\frac {25 \,{\mathrm e}^{2}}{x^{2}}+{\mathrm e}^{x}\) | \(16\) |
risch | \(\frac {25 \,{\mathrm e}^{2}+5 x}{x^{2}}+{\mathrm e}^{x}\) | \(16\) |
parts | \(\frac {5}{x}+\frac {25 \,{\mathrm e}^{2}}{x^{2}}+{\mathrm e}^{x}\) | \(16\) |
norman | \(\frac {{\mathrm e}^{x} x^{2}+5 x +25 \,{\mathrm e}^{2}}{x^{2}}\) | \(19\) |
parallelrisch | \(\frac {{\mathrm e}^{x} x^{2}+5 x +25 \,{\mathrm e}^{2}}{x^{2}}\) | \(19\) |
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Time = 0.25 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.72 \[ \int \frac {-50 e^2-5 x+e^x x^3}{x^3} \, dx=\frac {x^{2} e^{x} + 5 \, x + 25 \, e^{2}}{x^{2}} \]
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Time = 0.08 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.60 \[ \int \frac {-50 e^2-5 x+e^x x^3}{x^3} \, dx=e^{x} - \frac {- 5 x - 25 e^{2}}{x^{2}} \]
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Time = 0.21 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.60 \[ \int \frac {-50 e^2-5 x+e^x x^3}{x^3} \, dx=\frac {5}{x} + \frac {25 \, e^{2}}{x^{2}} + e^{x} \]
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Time = 0.27 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.72 \[ \int \frac {-50 e^2-5 x+e^x x^3}{x^3} \, dx=\frac {x^{2} e^{x} + 5 \, x + 25 \, e^{2}}{x^{2}} \]
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Time = 11.35 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.60 \[ \int \frac {-50 e^2-5 x+e^x x^3}{x^3} \, dx={\mathrm {e}}^x+\frac {5\,x+25\,{\mathrm {e}}^2}{x^2} \]
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