Integrand size = 185, antiderivative size = 35 \[ \int \frac {-5 x+x^2+e^{x^2} \left (10 x^3-2 x^4+e^3 \left (-10 x^2+2 x^3\right )\right )+\left (-20 e^3+e^{x^2} \left (5 e^3-5 x\right )+20 x+\left (-5 e^3+5 x\right ) \log \left (e^3-x\right )\right ) \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}{\left (4 e^3 x^2-4 x^3+e^{x^2} \left (-e^3 x^2+x^3\right )+\left (e^3 x^2-x^3\right ) \log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx=3+\frac {5-x}{x \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \]
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\[ \int \frac {-5 x+x^2+e^{x^2} \left (10 x^3-2 x^4+e^3 \left (-10 x^2+2 x^3\right )\right )+\left (-20 e^3+e^{x^2} \left (5 e^3-5 x\right )+20 x+\left (-5 e^3+5 x\right ) \log \left (e^3-x\right )\right ) \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}{\left (4 e^3 x^2-4 x^3+e^{x^2} \left (-e^3 x^2+x^3\right )+\left (e^3 x^2-x^3\right ) \log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx=\int \frac {-5 x+x^2+e^{x^2} \left (10 x^3-2 x^4+e^3 \left (-10 x^2+2 x^3\right )\right )+\left (-20 e^3+e^{x^2} \left (5 e^3-5 x\right )+20 x+\left (-5 e^3+5 x\right ) \log \left (e^3-x\right )\right ) \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}{\left (4 e^3 x^2-4 x^3+e^{x^2} \left (-e^3 x^2+x^3\right )+\left (e^3 x^2-x^3\right ) \log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\frac {(-5+x) x \left (-1-2 e^{3+x^2} x+2 e^{x^2} x^2\right )}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right )}-5 \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}{x^2 \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx \\ & = \int \left (-\frac {(-5+x) \left (-1-8 e^3 x+8 x^2-2 e^3 x \log \left (e^3-x\right )+2 x^2 \log \left (e^3-x\right )\right )}{x \left (-e^3+x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}+\frac {10 x^2-2 x^3-5 \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}{x^2 \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}\right ) \, dx \\ & = -\int \frac {(-5+x) \left (-1-8 e^3 x+8 x^2-2 e^3 x \log \left (e^3-x\right )+2 x^2 \log \left (e^3-x\right )\right )}{x \left (-e^3+x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+\int \frac {10 x^2-2 x^3-5 \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}{x^2 \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx \\ & = -\int \left (\frac {\left (-5+e^3\right ) \left (1+8 e^3 x-8 x^2+2 e^3 x \log \left (e^3-x\right )-2 x^2 \log \left (e^3-x\right )\right )}{e^3 \left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}-\frac {5 \left (1+8 e^3 x-8 x^2+2 e^3 x \log \left (e^3-x\right )-2 x^2 \log \left (e^3-x\right )\right )}{e^3 x \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}\right ) \, dx+\int \left (-\frac {2 (-5+x)}{\log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}-\frac {5}{x^2 \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}\right ) \, dx \\ & = -\left (2 \int \frac {-5+x}{\log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx\right )-5 \int \frac {1}{x^2 \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+\frac {5 \int \frac {1+8 e^3 x-8 x^2+2 e^3 x \log \left (e^3-x\right )-2 x^2 \log \left (e^3-x\right )}{x \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}-\frac {\left (-5+e^3\right ) \int \frac {1+8 e^3 x-8 x^2+2 e^3 x \log \left (e^3-x\right )-2 x^2 \log \left (e^3-x\right )}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3} \\ & = -\left (2 \int \left (-\frac {5}{\log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}+\frac {x}{\log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}\right ) \, dx\right )-5 \int \frac {1}{x^2 \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+\frac {5 \int \left (\frac {8 e^3}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}+\frac {1}{x \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}-\frac {8 x}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}+\frac {2 e^3 \log \left (e^3-x\right )}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}-\frac {2 x \log \left (e^3-x\right )}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}\right ) \, dx}{e^3}-\frac {\left (-5+e^3\right ) \int \left (\frac {1}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}+\frac {8 e^3 x}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}-\frac {8 x^2}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}+\frac {2 e^3 x \log \left (e^3-x\right )}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}-\frac {2 x^2 \log \left (e^3-x\right )}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}\right ) \, dx}{e^3} \\ & = -\left (2 \int \frac {x}{\log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx\right )-5 \int \frac {1}{x^2 \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+10 \int \frac {1}{\log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+10 \int \frac {\log \left (e^3-x\right )}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+40 \int \frac {1}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+\frac {5 \int \frac {1}{x \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}-\frac {10 \int \frac {x \log \left (e^3-x\right )}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}-\frac {40 \int \frac {x}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}+\left (2 \left (5-e^3\right )\right ) \int \frac {x \log \left (e^3-x\right )}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+\left (8 \left (5-e^3\right )\right ) \int \frac {x}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx-\frac {\left (-5+e^3\right ) \int \frac {1}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}+\frac {\left (2 \left (-5+e^3\right )\right ) \int \frac {x^2 \log \left (e^3-x\right )}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}+\frac {\left (8 \left (-5+e^3\right )\right ) \int \frac {x^2}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3} \\ & = -\left (2 \int \frac {x}{\log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx\right )-5 \int \frac {1}{x^2 \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+10 \int \frac {1}{\log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+10 \int \frac {\log \left (e^3-x\right )}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+40 \int \frac {1}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+\frac {5 \int \frac {1}{x \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}-\frac {10 \int \frac {x \log \left (e^3-x\right )}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}-\frac {40 \int \frac {x}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}+\left (2 \left (5-e^3\right )\right ) \int \left (-\frac {\log \left (e^3-x\right )}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}+\frac {e^3 \log \left (e^3-x\right )}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}\right ) \, dx+\left (8 \left (5-e^3\right )\right ) \int \left (-\frac {1}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}+\frac {e^3}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}\right ) \, dx-\frac {\left (-5+e^3\right ) \int \frac {1}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}+\frac {\left (2 \left (-5+e^3\right )\right ) \int \left (-\frac {e^3 \log \left (e^3-x\right )}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}+\frac {e^6 \log \left (e^3-x\right )}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}-\frac {x \log \left (e^3-x\right )}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}\right ) \, dx}{e^3}+\frac {\left (8 \left (-5+e^3\right )\right ) \int \left (-\frac {e^3}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}+\frac {e^6}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}-\frac {x}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}\right ) \, dx}{e^3} \\ & = -\left (2 \int \frac {x}{\log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx\right )-5 \int \frac {1}{x^2 \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+10 \int \frac {1}{\log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+10 \int \frac {\log \left (e^3-x\right )}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+40 \int \frac {1}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx+\frac {5 \int \frac {1}{x \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}-\frac {10 \int \frac {x \log \left (e^3-x\right )}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}-\frac {40 \int \frac {x}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}-\frac {\left (-5+e^3\right ) \int \frac {1}{\left (e^3-x\right ) \left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}-\frac {\left (2 \left (-5+e^3\right )\right ) \int \frac {x \log \left (e^3-x\right )}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3}-\frac {\left (8 \left (-5+e^3\right )\right ) \int \frac {x}{\left (-4+e^{x^2}-\log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx}{e^3} \\ \end{align*}
Time = 0.17 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.94 \[ \int \frac {-5 x+x^2+e^{x^2} \left (10 x^3-2 x^4+e^3 \left (-10 x^2+2 x^3\right )\right )+\left (-20 e^3+e^{x^2} \left (5 e^3-5 x\right )+20 x+\left (-5 e^3+5 x\right ) \log \left (e^3-x\right )\right ) \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}{\left (4 e^3 x^2-4 x^3+e^{x^2} \left (-e^3 x^2+x^3\right )+\left (e^3 x^2-x^3\right ) \log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx=\frac {5-x}{x \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \]
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Time = 18.12 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.91
method | result | size |
parallelrisch | \(\frac {5-x}{\ln \left (\frac {5}{\ln \left (-x +{\mathrm e}^{3}\right )+4-{\mathrm e}^{x^{2}}}\right ) x}\) | \(32\) |
risch | \(-\frac {2 i \left (-5+x \right )}{x \left (-2 \pi {\operatorname {csgn}\left (\frac {i}{-\ln \left (-x +{\mathrm e}^{3}\right )-4+{\mathrm e}^{x^{2}}}\right )}^{3}+2 \pi {\operatorname {csgn}\left (\frac {i}{-\ln \left (-x +{\mathrm e}^{3}\right )-4+{\mathrm e}^{x^{2}}}\right )}^{2}-2 \pi +2 i \ln \left (5\right )-2 i \ln \left (-\ln \left (-x +{\mathrm e}^{3}\right )-4+{\mathrm e}^{x^{2}}\right )\right )}\) | \(92\) |
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Time = 0.25 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.86 \[ \int \frac {-5 x+x^2+e^{x^2} \left (10 x^3-2 x^4+e^3 \left (-10 x^2+2 x^3\right )\right )+\left (-20 e^3+e^{x^2} \left (5 e^3-5 x\right )+20 x+\left (-5 e^3+5 x\right ) \log \left (e^3-x\right )\right ) \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}{\left (4 e^3 x^2-4 x^3+e^{x^2} \left (-e^3 x^2+x^3\right )+\left (e^3 x^2-x^3\right ) \log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx=-\frac {x - 5}{x \log \left (-\frac {5}{e^{\left (x^{2}\right )} - \log \left (-x + e^{3}\right ) - 4}\right )} \]
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Time = 1.20 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.57 \[ \int \frac {-5 x+x^2+e^{x^2} \left (10 x^3-2 x^4+e^3 \left (-10 x^2+2 x^3\right )\right )+\left (-20 e^3+e^{x^2} \left (5 e^3-5 x\right )+20 x+\left (-5 e^3+5 x\right ) \log \left (e^3-x\right )\right ) \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}{\left (4 e^3 x^2-4 x^3+e^{x^2} \left (-e^3 x^2+x^3\right )+\left (e^3 x^2-x^3\right ) \log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx=\frac {5 - x}{x \log {\left (\frac {5}{- e^{x^{2}} + \log {\left (- x + e^{3} \right )} + 4} \right )}} \]
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Time = 0.35 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.89 \[ \int \frac {-5 x+x^2+e^{x^2} \left (10 x^3-2 x^4+e^3 \left (-10 x^2+2 x^3\right )\right )+\left (-20 e^3+e^{x^2} \left (5 e^3-5 x\right )+20 x+\left (-5 e^3+5 x\right ) \log \left (e^3-x\right )\right ) \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}{\left (4 e^3 x^2-4 x^3+e^{x^2} \left (-e^3 x^2+x^3\right )+\left (e^3 x^2-x^3\right ) \log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx=-\frac {x - 5}{x \log \left (5\right ) - x \log \left (-e^{\left (x^{2}\right )} + \log \left (-x + e^{3}\right ) + 4\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 569 vs. \(2 (32) = 64\).
Time = 0.67 (sec) , antiderivative size = 569, normalized size of antiderivative = 16.26 \[ \int \frac {-5 x+x^2+e^{x^2} \left (10 x^3-2 x^4+e^3 \left (-10 x^2+2 x^3\right )\right )+\left (-20 e^3+e^{x^2} \left (5 e^3-5 x\right )+20 x+\left (-5 e^3+5 x\right ) \log \left (e^3-x\right )\right ) \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}{\left (4 e^3 x^2-4 x^3+e^{x^2} \left (-e^3 x^2+x^3\right )+\left (e^3 x^2-x^3\right ) \log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx=\frac {2 \, {\left (2 \, x \log \left (5\right ) - x \log \left (\frac {1}{2} \, \pi ^{2} \mathrm {sgn}\left (x - e^{3}\right ) + \frac {1}{2} \, \pi ^{2} - 2 \, e^{\left (x^{2}\right )} \log \left ({\left | x - e^{3} \right |}\right ) + \log \left ({\left | x - e^{3} \right |}\right )^{2} + e^{\left (2 \, x^{2}\right )} - 8 \, e^{\left (x^{2}\right )} + 8 \, \log \left ({\left | x - e^{3} \right |}\right ) + 16\right ) - 10 \, \log \left (5\right ) + 5 \, \log \left (\frac {1}{2} \, \pi ^{2} \mathrm {sgn}\left (x - e^{3}\right ) + \frac {1}{2} \, \pi ^{2} - 2 \, e^{\left (x^{2}\right )} \log \left ({\left | x - e^{3} \right |}\right ) + \log \left ({\left | x - e^{3} \right |}\right )^{2} + e^{\left (2 \, x^{2}\right )} - 8 \, e^{\left (x^{2}\right )} + 8 \, \log \left ({\left | x - e^{3} \right |}\right ) + 16\right )\right )}}{4 \, \pi ^{2} x \mathrm {sgn}\left (\pi + \pi \mathrm {sgn}\left (x - e^{3}\right )\right ) \mathrm {sgn}\left (e^{\left (x^{2}\right )} - \log \left ({\left | x - e^{3} \right |}\right ) - 4\right ) + 4 \, \pi x \arctan \left (\frac {\pi + \pi \mathrm {sgn}\left (x - e^{3}\right )}{2 \, {\left (e^{\left (x^{2}\right )} - \log \left ({\left | x - e^{3} \right |}\right ) - 4\right )}}\right ) \mathrm {sgn}\left (\pi + \pi \mathrm {sgn}\left (x - e^{3}\right )\right ) \mathrm {sgn}\left (e^{\left (x^{2}\right )} - \log \left ({\left | x - e^{3} \right |}\right ) - 4\right ) - 4 \, \pi ^{2} x \mathrm {sgn}\left (\pi + \pi \mathrm {sgn}\left (x - e^{3}\right )\right ) - 4 \, \pi x \arctan \left (\frac {\pi + \pi \mathrm {sgn}\left (x - e^{3}\right )}{2 \, {\left (e^{\left (x^{2}\right )} - \log \left ({\left | x - e^{3} \right |}\right ) - 4\right )}}\right ) \mathrm {sgn}\left (\pi + \pi \mathrm {sgn}\left (x - e^{3}\right )\right ) + 2 \, \pi ^{2} x \mathrm {sgn}\left (e^{\left (x^{2}\right )} - \log \left ({\left | x - e^{3} \right |}\right ) - 4\right ) - 6 \, \pi ^{2} x - 8 \, \pi x \arctan \left (\frac {\pi + \pi \mathrm {sgn}\left (x - e^{3}\right )}{2 \, {\left (e^{\left (x^{2}\right )} - \log \left ({\left | x - e^{3} \right |}\right ) - 4\right )}}\right ) - 4 \, x \arctan \left (\frac {\pi + \pi \mathrm {sgn}\left (x - e^{3}\right )}{2 \, {\left (e^{\left (x^{2}\right )} - \log \left ({\left | x - e^{3} \right |}\right ) - 4\right )}}\right )^{2} - 4 \, x \log \left (5\right )^{2} + 4 \, x \log \left (5\right ) \log \left (\frac {1}{2} \, \pi ^{2} \mathrm {sgn}\left (x - e^{3}\right ) + \frac {1}{2} \, \pi ^{2} - 2 \, e^{\left (x^{2}\right )} \log \left ({\left | x - e^{3} \right |}\right ) + \log \left ({\left | x - e^{3} \right |}\right )^{2} + e^{\left (2 \, x^{2}\right )} - 8 \, e^{\left (x^{2}\right )} + 8 \, \log \left ({\left | x - e^{3} \right |}\right ) + 16\right ) - x \log \left (\frac {1}{2} \, \pi ^{2} \mathrm {sgn}\left (x - e^{3}\right ) + \frac {1}{2} \, \pi ^{2} - 2 \, e^{\left (x^{2}\right )} \log \left ({\left | x - e^{3} \right |}\right ) + \log \left ({\left | x - e^{3} \right |}\right )^{2} + e^{\left (2 \, x^{2}\right )} - 8 \, e^{\left (x^{2}\right )} + 8 \, \log \left ({\left | x - e^{3} \right |}\right ) + 16\right )^{2}} \]
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Timed out. \[ \int \frac {-5 x+x^2+e^{x^2} \left (10 x^3-2 x^4+e^3 \left (-10 x^2+2 x^3\right )\right )+\left (-20 e^3+e^{x^2} \left (5 e^3-5 x\right )+20 x+\left (-5 e^3+5 x\right ) \log \left (e^3-x\right )\right ) \log \left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )}{\left (4 e^3 x^2-4 x^3+e^{x^2} \left (-e^3 x^2+x^3\right )+\left (e^3 x^2-x^3\right ) \log \left (e^3-x\right )\right ) \log ^2\left (\frac {5}{4-e^{x^2}+\log \left (e^3-x\right )}\right )} \, dx=\text {Hanged} \]
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