Integrand size = 127, antiderivative size = 33 \[ \int \frac {e^{e^{\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}}+e^{e^{-x} x}+\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}+\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}} \left (-1+e^{-x+e^{-x} x} (1-x) x\right )}{8 x^2} \, dx=\frac {1}{4} e^{e^{\frac {1}{4} e^{\frac {e^{e^{e^{-x} x}}+3 x}{x}}}} \]
[Out]
\[ \int \frac {e^{e^{\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}}+e^{e^{-x} x}+\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}+\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}} \left (-1+e^{-x+e^{-x} x} (1-x) x\right )}{8 x^2} \, dx=\int \frac {\exp \left (e^{\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}}+e^{e^{-x} x}+\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}+\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}\right ) \left (-1+e^{-x+e^{-x} x} (1-x) x\right )}{8 x^2} \, dx \]
[In]
[Out]
Rubi steps \begin{align*} \text {integral}& = \frac {1}{8} \int \frac {\exp \left (e^{\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}}+e^{e^{-x} x}+\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}+\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}\right ) \left (-1+e^{-x+e^{-x} x} (1-x) x\right )}{x^2} \, dx \\ & = \frac {1}{8} \int \frac {\exp \left (\frac {4 e^{e^{e^{-x} x}}+4 e^{\frac {1}{4} e^{3+\frac {e^{e^{e^{-x} x}}}{x}}} x+e^{3+\frac {e^{e^{e^{-x} x}}}{x}} x+4 e^{e^{-x} x} x+12 x \left (1-\frac {\log (2)}{3}\right )}{4 x}\right ) \left (-1+e^{-x+e^{-x} x} (1-x) x\right )}{x^2} \, dx \\ & = \frac {1}{8} \int \left (-\frac {\exp \left (\frac {4 e^{e^{e^{-x} x}}+4 e^{\frac {1}{4} e^{3+\frac {e^{e^{e^{-x} x}}}{x}}} x+e^{3+\frac {e^{e^{e^{-x} x}}}{x}} x+4 e^{e^{-x} x} x+12 x \left (1-\frac {\log (2)}{3}\right )}{4 x}\right )}{x^2}+\frac {\exp \left (-e^{-x} \left (-1+e^x\right ) x+\frac {4 e^{e^{e^{-x} x}}+4 e^{\frac {1}{4} e^{3+\frac {e^{e^{e^{-x} x}}}{x}}} x+e^{3+\frac {e^{e^{e^{-x} x}}}{x}} x+4 e^{e^{-x} x} x+12 x \left (1-\frac {\log (2)}{3}\right )}{4 x}\right ) (1-x)}{x}\right ) \, dx \\ & = -\left (\frac {1}{8} \int \frac {\exp \left (\frac {4 e^{e^{e^{-x} x}}+4 e^{\frac {1}{4} e^{3+\frac {e^{e^{e^{-x} x}}}{x}}} x+e^{3+\frac {e^{e^{e^{-x} x}}}{x}} x+4 e^{e^{-x} x} x+12 x \left (1-\frac {\log (2)}{3}\right )}{4 x}\right )}{x^2} \, dx\right )+\frac {1}{8} \int \frac {\exp \left (-e^{-x} \left (-1+e^x\right ) x+\frac {4 e^{e^{e^{-x} x}}+4 e^{\frac {1}{4} e^{3+\frac {e^{e^{e^{-x} x}}}{x}}} x+e^{3+\frac {e^{e^{e^{-x} x}}}{x}} x+4 e^{e^{-x} x} x+12 x \left (1-\frac {\log (2)}{3}\right )}{4 x}\right ) (1-x)}{x} \, dx \\ & = \frac {1}{8} \int \left (-\exp \left (-e^{-x} \left (-1+e^x\right ) x+\frac {4 e^{e^{e^{-x} x}}+4 e^{\frac {1}{4} e^{3+\frac {e^{e^{e^{-x} x}}}{x}}} x+e^{3+\frac {e^{e^{e^{-x} x}}}{x}} x+4 e^{e^{-x} x} x+12 x \left (1-\frac {\log (2)}{3}\right )}{4 x}\right )+\frac {\exp \left (-e^{-x} \left (-1+e^x\right ) x+\frac {4 e^{e^{e^{-x} x}}+4 e^{\frac {1}{4} e^{3+\frac {e^{e^{e^{-x} x}}}{x}}} x+e^{3+\frac {e^{e^{e^{-x} x}}}{x}} x+4 e^{e^{-x} x} x+12 x \left (1-\frac {\log (2)}{3}\right )}{4 x}\right )}{x}\right ) \, dx-\frac {1}{8} \int \frac {\exp \left (\frac {4 e^{e^{e^{-x} x}}+4 e^{\frac {1}{4} e^{3+\frac {e^{e^{e^{-x} x}}}{x}}} x+e^{3+\frac {e^{e^{e^{-x} x}}}{x}} x+4 e^{e^{-x} x} x+12 x \left (1-\frac {\log (2)}{3}\right )}{4 x}\right )}{x^2} \, dx \\ & = -\left (\frac {1}{8} \int \exp \left (-e^{-x} \left (-1+e^x\right ) x+\frac {4 e^{e^{e^{-x} x}}+4 e^{\frac {1}{4} e^{3+\frac {e^{e^{e^{-x} x}}}{x}}} x+e^{3+\frac {e^{e^{e^{-x} x}}}{x}} x+4 e^{e^{-x} x} x+12 x \left (1-\frac {\log (2)}{3}\right )}{4 x}\right ) \, dx\right )-\frac {1}{8} \int \frac {\exp \left (\frac {4 e^{e^{e^{-x} x}}+4 e^{\frac {1}{4} e^{3+\frac {e^{e^{e^{-x} x}}}{x}}} x+e^{3+\frac {e^{e^{e^{-x} x}}}{x}} x+4 e^{e^{-x} x} x+12 x \left (1-\frac {\log (2)}{3}\right )}{4 x}\right )}{x^2} \, dx+\frac {1}{8} \int \frac {\exp \left (-e^{-x} \left (-1+e^x\right ) x+\frac {4 e^{e^{e^{-x} x}}+4 e^{\frac {1}{4} e^{3+\frac {e^{e^{e^{-x} x}}}{x}}} x+e^{3+\frac {e^{e^{e^{-x} x}}}{x}} x+4 e^{e^{-x} x} x+12 x \left (1-\frac {\log (2)}{3}\right )}{4 x}\right )}{x} \, dx \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.94 \[ \int \frac {e^{e^{\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}}+e^{e^{-x} x}+\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}+\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}} \left (-1+e^{-x+e^{-x} x} (1-x) x\right )}{8 x^2} \, dx=\frac {1}{4} e^{e^{\frac {1}{4} e^{3+\frac {e^{e^{e^{-x} x}}}{x}}}} \]
[In]
[Out]
Time = 0.18 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.73
\[\frac {{\mathrm e}^{{\mathrm e}^{\frac {{\mathrm e}^{\frac {{\mathrm e}^{{\mathrm e}^{x \,{\mathrm e}^{-x}}}+3 x}{x}}}{4}}}}{4}\]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 198 vs. \(2 (29) = 58\).
Time = 0.27 (sec) , antiderivative size = 198, normalized size of antiderivative = 6.00 \[ \int \frac {e^{e^{\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}}+e^{e^{-x} x}+\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}+\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}} \left (-1+e^{-x+e^{-x} x} (1-x) x\right )}{8 x^2} \, dx=\frac {1}{4} \, e^{\left (\frac {{\left (x e^{\left (-x - \frac {x \log \left (2\right ) - 3 \, x - e^{\left (e^{\left (e^{\left (-x + \log \left (x\right )\right )}\right )}\right )}}{x} + \log \left (x\right )\right )} + 2 \, x e^{\left (-x + e^{\left (-x + \log \left (x\right )\right )} + \log \left (x\right )\right )} + 2 \, x e^{\left (-x + \frac {1}{2} \, e^{\left (-\frac {x \log \left (2\right ) - 3 \, x - e^{\left (e^{\left (e^{\left (-x + \log \left (x\right )\right )}\right )}\right )}}{x}\right )} + \log \left (x\right )\right )} - 2 \, {\left (x \log \left (2\right ) - 3 \, x\right )} e^{\left (-x + \log \left (x\right )\right )} + 2 \, e^{\left (-x + e^{\left (e^{\left (-x + \log \left (x\right )\right )}\right )} + \log \left (x\right )\right )}\right )} e^{\left (x - \log \left (x\right )\right )}}{2 \, x} + \frac {x \log \left (2\right ) - 3 \, x - e^{\left (e^{\left (e^{\left (-x + \log \left (x\right )\right )}\right )}\right )}}{x} - \frac {1}{2} \, e^{\left (-\frac {x \log \left (2\right ) - 3 \, x - e^{\left (e^{\left (e^{\left (-x + \log \left (x\right )\right )}\right )}\right )}}{x}\right )} - e^{\left (e^{\left (-x + \log \left (x\right )\right )}\right )}\right )} \]
[In]
[Out]
Timed out. \[ \int \frac {e^{e^{\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}}+e^{e^{-x} x}+\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}+\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}} \left (-1+e^{-x+e^{-x} x} (1-x) x\right )}{8 x^2} \, dx=\text {Timed out} \]
[In]
[Out]
none
Time = 1.31 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.64 \[ \int \frac {e^{e^{\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}}+e^{e^{-x} x}+\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}+\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}} \left (-1+e^{-x+e^{-x} x} (1-x) x\right )}{8 x^2} \, dx=\frac {1}{4} \, e^{\left (e^{\left (\frac {1}{4} \, e^{\left (\frac {e^{\left (e^{\left (x e^{\left (-x\right )}\right )}\right )}}{x} + 3\right )}\right )}\right )} \]
[In]
[Out]
\[ \int \frac {e^{e^{\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}}+e^{e^{-x} x}+\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}+\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}} \left (-1+e^{-x+e^{-x} x} (1-x) x\right )}{8 x^2} \, dx=\int { -\frac {{\left ({\left (x - 1\right )} e^{\left (-x + e^{\left (-x + \log \left (x\right )\right )} + \log \left (x\right )\right )} + 1\right )} e^{\left (-\frac {x \log \left (2\right ) - 3 \, x - e^{\left (e^{\left (e^{\left (-x + \log \left (x\right )\right )}\right )}\right )}}{x} + e^{\left (\frac {1}{2} \, e^{\left (-\frac {x \log \left (2\right ) - 3 \, x - e^{\left (e^{\left (e^{\left (-x + \log \left (x\right )\right )}\right )}\right )}}{x}\right )}\right )} + \frac {1}{2} \, e^{\left (-\frac {x \log \left (2\right ) - 3 \, x - e^{\left (e^{\left (e^{\left (-x + \log \left (x\right )\right )}\right )}\right )}}{x}\right )} + e^{\left (e^{\left (-x + \log \left (x\right )\right )}\right )}\right )}}{8 \, x^{2}} \,d x } \]
[In]
[Out]
Time = 12.15 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.64 \[ \int \frac {e^{e^{\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}}+e^{e^{-x} x}+\frac {1}{2} e^{\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}}+\frac {e^{e^{e^{-x} x}}+3 x-x \log (2)}{x}} \left (-1+e^{-x+e^{-x} x} (1-x) x\right )}{8 x^2} \, dx=\frac {{\mathrm {e}}^{{\mathrm {e}}^{\frac {{\mathrm {e}}^3\,{\mathrm {e}}^{\frac {{\mathrm {e}}^{{\mathrm {e}}^{x\,{\mathrm {e}}^{-x}}}}{x}}}{4}}}}{4} \]
[In]
[Out]