Integrand size = 317, antiderivative size = 36 \[ \int \frac {-9 x^2+6 x^3-16 x^4+8 x^5-8 x^6+2 x^7-x^8+e^x \left (3 x^2-5 x^3+x^4+4 x^5-4 x^6+x^7\right )+\left (-9 x^2+6 x^3+2 x^4-4 x^5+6 x^6-2 x^7+x^8+e^x \left (6 x-10 x^2+2 x^3+8 x^4-8 x^5+2 x^6\right )\right ) \log \left (\frac {-1+x^2}{x}\right )+e^x \left (3-5 x+x^2+4 x^3-4 x^4+x^5\right ) \log ^2\left (\frac {-1+x^2}{x}\right )}{-36 x^4+24 x^5+8 x^6-16 x^7+24 x^8-8 x^9+4 x^{10}+\left (-72 x^3+48 x^4+16 x^5-32 x^6+48 x^7-16 x^8+8 x^9\right ) \log \left (\frac {-1+x^2}{x}\right )+\left (-36 x^2+24 x^3+8 x^4-16 x^5+24 x^6-8 x^7+4 x^8\right ) \log ^2\left (\frac {-1+x^2}{x}\right )} \, dx=\frac {1}{4} \left (\frac {e^x}{x \left (3-x+x^2\right )}+\frac {x}{x+\log \left (-\frac {1}{x}+x\right )}\right ) \]
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Result contains higher order function than in optimal. Order 4 vs. order 3 in optimal.
Time = 4.60 (sec) , antiderivative size = 523, normalized size of antiderivative = 14.53, number of steps used = 33, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.028, Rules used = {6820, 12, 6857, 6874, 2208, 2209, 6860, 6843, 32} \[ \int \frac {-9 x^2+6 x^3-16 x^4+8 x^5-8 x^6+2 x^7-x^8+e^x \left (3 x^2-5 x^3+x^4+4 x^5-4 x^6+x^7\right )+\left (-9 x^2+6 x^3+2 x^4-4 x^5+6 x^6-2 x^7+x^8+e^x \left (6 x-10 x^2+2 x^3+8 x^4-8 x^5+2 x^6\right )\right ) \log \left (\frac {-1+x^2}{x}\right )+e^x \left (3-5 x+x^2+4 x^3-4 x^4+x^5\right ) \log ^2\left (\frac {-1+x^2}{x}\right )}{-36 x^4+24 x^5+8 x^6-16 x^7+24 x^8-8 x^9+4 x^{10}+\left (-72 x^3+48 x^4+16 x^5-32 x^6+48 x^7-16 x^8+8 x^9\right ) \log \left (\frac {-1+x^2}{x}\right )+\left (-36 x^2+24 x^3+8 x^4-16 x^5+24 x^6-8 x^7+4 x^8\right ) \log ^2\left (\frac {-1+x^2}{x}\right )} \, dx=-\frac {1}{264} \left (11+3 i \sqrt {11}\right ) e^{\frac {1}{2}+\frac {i \sqrt {11}}{2}} \operatorname {ExpIntegralEi}\left (\frac {1}{2} \left (2 x-i \sqrt {11}-1\right )\right )+\frac {1}{264} \left (1+i \sqrt {11}\right ) e^{\frac {1}{2}+\frac {i \sqrt {11}}{2}} \operatorname {ExpIntegralEi}\left (\frac {1}{2} \left (2 x-i \sqrt {11}-1\right )\right )+\frac {i e^{\frac {1}{2}+\frac {i \sqrt {11}}{2}} \operatorname {ExpIntegralEi}\left (\frac {1}{2} \left (2 x-i \sqrt {11}-1\right )\right )}{12 \sqrt {11}}+\frac {5}{132} e^{\frac {1}{2}+\frac {i \sqrt {11}}{2}} \operatorname {ExpIntegralEi}\left (\frac {1}{2} \left (2 x-i \sqrt {11}-1\right )\right )-\frac {1}{264} \left (11-3 i \sqrt {11}\right ) e^{\frac {1}{2}-\frac {i \sqrt {11}}{2}} \operatorname {ExpIntegralEi}\left (\frac {1}{2} \left (2 x+i \sqrt {11}-1\right )\right )+\frac {1}{264} \left (1-i \sqrt {11}\right ) e^{\frac {1}{2}-\frac {i \sqrt {11}}{2}} \operatorname {ExpIntegralEi}\left (\frac {1}{2} \left (2 x+i \sqrt {11}-1\right )\right )-\frac {i e^{\frac {1}{2}-\frac {i \sqrt {11}}{2}} \operatorname {ExpIntegralEi}\left (\frac {1}{2} \left (2 x+i \sqrt {11}-1\right )\right )}{12 \sqrt {11}}+\frac {5}{132} e^{\frac {1}{2}-\frac {i \sqrt {11}}{2}} \operatorname {ExpIntegralEi}\left (\frac {1}{2} \left (2 x+i \sqrt {11}-1\right )\right )+\frac {\left (1-i \sqrt {11}\right ) e^x}{132 \left (-2 x-i \sqrt {11}+1\right )}+\frac {5 e^x}{66 \left (-2 x-i \sqrt {11}+1\right )}+\frac {\left (1+i \sqrt {11}\right ) e^x}{132 \left (-2 x+i \sqrt {11}+1\right )}+\frac {5 e^x}{66 \left (-2 x+i \sqrt {11}+1\right )}+\frac {e^x}{12 x}-\frac {1}{4 \left (\frac {x}{\log \left (x-\frac {1}{x}\right )}+1\right )} \]
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Rule 12
Rule 32
Rule 2208
Rule 2209
Rule 6820
Rule 6843
Rule 6857
Rule 6860
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \frac {x^2 \left (\left (1+x^2\right ) \left (3-x+x^2\right )^2-e^x \left (3-5 x+x^2+4 x^3-4 x^4+x^5\right )\right )-x \left (-1+x^2\right ) \left (x \left (3-x+x^2\right )^2+2 e^x \left (-3+5 x-4 x^2+x^3\right )\right ) \log \left (-\frac {1}{x}+x\right )-e^x \left (3-5 x+x^2+4 x^3-4 x^4+x^5\right ) \log ^2\left (-\frac {1}{x}+x\right )}{4 x^2 \left (1-x^2\right ) \left (3-x+x^2\right )^2 \left (x+\log \left (-\frac {1}{x}+x\right )\right )^2} \, dx \\ & = \frac {1}{4} \int \frac {x^2 \left (\left (1+x^2\right ) \left (3-x+x^2\right )^2-e^x \left (3-5 x+x^2+4 x^3-4 x^4+x^5\right )\right )-x \left (-1+x^2\right ) \left (x \left (3-x+x^2\right )^2+2 e^x \left (-3+5 x-4 x^2+x^3\right )\right ) \log \left (-\frac {1}{x}+x\right )-e^x \left (3-5 x+x^2+4 x^3-4 x^4+x^5\right ) \log ^2\left (-\frac {1}{x}+x\right )}{x^2 \left (1-x^2\right ) \left (3-x+x^2\right )^2 \left (x+\log \left (-\frac {1}{x}+x\right )\right )^2} \, dx \\ & = \frac {1}{4} \int \left (\frac {e^x \left (-3+5 x-4 x^2+x^3\right )}{x^2 \left (3-x+x^2\right )^2}+\frac {-1-x^2-\log \left (-\frac {1}{x}+x\right )+x^2 \log \left (-\frac {1}{x}+x\right )}{\left (-1+x^2\right ) \left (x+\log \left (-\frac {1}{x}+x\right )\right )^2}\right ) \, dx \\ & = \frac {1}{4} \int \frac {e^x \left (-3+5 x-4 x^2+x^3\right )}{x^2 \left (3-x+x^2\right )^2} \, dx+\frac {1}{4} \int \frac {-1-x^2-\log \left (-\frac {1}{x}+x\right )+x^2 \log \left (-\frac {1}{x}+x\right )}{\left (-1+x^2\right ) \left (x+\log \left (-\frac {1}{x}+x\right )\right )^2} \, dx \\ & = \frac {1}{4} \int \left (-\frac {e^x}{3 x^2}+\frac {e^x}{3 x}+\frac {e^x (-5-x)}{3 \left (3-x+x^2\right )^2}+\frac {e^x (2-x)}{3 \left (3-x+x^2\right )}\right ) \, dx+\frac {1}{4} \text {Subst}\left (\int \frac {1}{(1+x)^2} \, dx,x,\frac {x}{\log \left (-\frac {1}{x}+x\right )}\right ) \\ & = -\frac {1}{4 \left (1+\frac {x}{\log \left (-\frac {1}{x}+x\right )}\right )}-\frac {1}{12} \int \frac {e^x}{x^2} \, dx+\frac {1}{12} \int \frac {e^x}{x} \, dx+\frac {1}{12} \int \frac {e^x (-5-x)}{\left (3-x+x^2\right )^2} \, dx+\frac {1}{12} \int \frac {e^x (2-x)}{3-x+x^2} \, dx \\ & = \frac {e^x}{12 x}+\frac {\text {Ei}(x)}{12}-\frac {1}{4 \left (1+\frac {x}{\log \left (-\frac {1}{x}+x\right )}\right )}-\frac {1}{12} \int \frac {e^x}{x} \, dx+\frac {1}{12} \int \left (\frac {\left (-1-\frac {3 i}{\sqrt {11}}\right ) e^x}{-1-i \sqrt {11}+2 x}+\frac {\left (-1+\frac {3 i}{\sqrt {11}}\right ) e^x}{-1+i \sqrt {11}+2 x}\right ) \, dx+\frac {1}{12} \int \left (-\frac {5 e^x}{\left (3-x+x^2\right )^2}-\frac {e^x x}{\left (3-x+x^2\right )^2}\right ) \, dx \\ & = \frac {e^x}{12 x}-\frac {1}{4 \left (1+\frac {x}{\log \left (-\frac {1}{x}+x\right )}\right )}-\frac {1}{12} \int \frac {e^x x}{\left (3-x+x^2\right )^2} \, dx-\frac {5}{12} \int \frac {e^x}{\left (3-x+x^2\right )^2} \, dx+\frac {1}{132} \left (-11+3 i \sqrt {11}\right ) \int \frac {e^x}{-1+i \sqrt {11}+2 x} \, dx-\frac {1}{132} \left (11+3 i \sqrt {11}\right ) \int \frac {e^x}{-1-i \sqrt {11}+2 x} \, dx \\ & = \frac {e^x}{12 x}-\frac {1}{264} \left (11+3 i \sqrt {11}\right ) e^{\frac {1}{2}+\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1-i \sqrt {11}+2 x\right )\right )-\frac {1}{264} \left (11-3 i \sqrt {11}\right ) e^{\frac {1}{2}-\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1+i \sqrt {11}+2 x\right )\right )-\frac {1}{4 \left (1+\frac {x}{\log \left (-\frac {1}{x}+x\right )}\right )}-\frac {1}{12} \int \left (-\frac {2 \left (1+i \sqrt {11}\right ) e^x}{11 \left (1+i \sqrt {11}-2 x\right )^2}+\frac {2 i e^x}{11 \sqrt {11} \left (1+i \sqrt {11}-2 x\right )}-\frac {2 \left (1-i \sqrt {11}\right ) e^x}{11 \left (-1+i \sqrt {11}+2 x\right )^2}+\frac {2 i e^x}{11 \sqrt {11} \left (-1+i \sqrt {11}+2 x\right )}\right ) \, dx-\frac {5}{12} \int \left (-\frac {4 e^x}{11 \left (1+i \sqrt {11}-2 x\right )^2}+\frac {4 i e^x}{11 \sqrt {11} \left (1+i \sqrt {11}-2 x\right )}-\frac {4 e^x}{11 \left (-1+i \sqrt {11}+2 x\right )^2}+\frac {4 i e^x}{11 \sqrt {11} \left (-1+i \sqrt {11}+2 x\right )}\right ) \, dx \\ & = \frac {e^x}{12 x}-\frac {1}{264} \left (11+3 i \sqrt {11}\right ) e^{\frac {1}{2}+\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1-i \sqrt {11}+2 x\right )\right )-\frac {1}{264} \left (11-3 i \sqrt {11}\right ) e^{\frac {1}{2}-\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1+i \sqrt {11}+2 x\right )\right )-\frac {1}{4 \left (1+\frac {x}{\log \left (-\frac {1}{x}+x\right )}\right )}+\frac {5}{33} \int \frac {e^x}{\left (1+i \sqrt {11}-2 x\right )^2} \, dx+\frac {5}{33} \int \frac {e^x}{\left (-1+i \sqrt {11}+2 x\right )^2} \, dx-\frac {i \int \frac {e^x}{1+i \sqrt {11}-2 x} \, dx}{66 \sqrt {11}}-\frac {i \int \frac {e^x}{-1+i \sqrt {11}+2 x} \, dx}{66 \sqrt {11}}-\frac {(5 i) \int \frac {e^x}{1+i \sqrt {11}-2 x} \, dx}{33 \sqrt {11}}-\frac {(5 i) \int \frac {e^x}{-1+i \sqrt {11}+2 x} \, dx}{33 \sqrt {11}}-\frac {1}{66} \left (-1-i \sqrt {11}\right ) \int \frac {e^x}{\left (1+i \sqrt {11}-2 x\right )^2} \, dx-\frac {1}{66} \left (-1+i \sqrt {11}\right ) \int \frac {e^x}{\left (-1+i \sqrt {11}+2 x\right )^2} \, dx \\ & = \frac {5 e^x}{66 \left (1-i \sqrt {11}-2 x\right )}+\frac {\left (1-i \sqrt {11}\right ) e^x}{132 \left (1-i \sqrt {11}-2 x\right )}+\frac {5 e^x}{66 \left (1+i \sqrt {11}-2 x\right )}+\frac {\left (1+i \sqrt {11}\right ) e^x}{132 \left (1+i \sqrt {11}-2 x\right )}+\frac {e^x}{12 x}+\frac {i e^{\frac {1}{2}+\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1-i \sqrt {11}+2 x\right )\right )}{12 \sqrt {11}}-\frac {1}{264} \left (11+3 i \sqrt {11}\right ) e^{\frac {1}{2}+\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1-i \sqrt {11}+2 x\right )\right )-\frac {i e^{\frac {1}{2}-\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1+i \sqrt {11}+2 x\right )\right )}{12 \sqrt {11}}-\frac {1}{264} \left (11-3 i \sqrt {11}\right ) e^{\frac {1}{2}-\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1+i \sqrt {11}+2 x\right )\right )-\frac {1}{4 \left (1+\frac {x}{\log \left (-\frac {1}{x}+x\right )}\right )}-\frac {5}{66} \int \frac {e^x}{1+i \sqrt {11}-2 x} \, dx+\frac {5}{66} \int \frac {e^x}{-1+i \sqrt {11}+2 x} \, dx-\frac {1}{132} \left (-1+i \sqrt {11}\right ) \int \frac {e^x}{-1+i \sqrt {11}+2 x} \, dx-\frac {1}{132} \left (1+i \sqrt {11}\right ) \int \frac {e^x}{1+i \sqrt {11}-2 x} \, dx \\ & = \frac {5 e^x}{66 \left (1-i \sqrt {11}-2 x\right )}+\frac {\left (1-i \sqrt {11}\right ) e^x}{132 \left (1-i \sqrt {11}-2 x\right )}+\frac {5 e^x}{66 \left (1+i \sqrt {11}-2 x\right )}+\frac {\left (1+i \sqrt {11}\right ) e^x}{132 \left (1+i \sqrt {11}-2 x\right )}+\frac {e^x}{12 x}+\frac {5}{132} e^{\frac {1}{2}+\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1-i \sqrt {11}+2 x\right )\right )+\frac {i e^{\frac {1}{2}+\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1-i \sqrt {11}+2 x\right )\right )}{12 \sqrt {11}}+\frac {1}{264} \left (1+i \sqrt {11}\right ) e^{\frac {1}{2}+\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1-i \sqrt {11}+2 x\right )\right )-\frac {1}{264} \left (11+3 i \sqrt {11}\right ) e^{\frac {1}{2}+\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1-i \sqrt {11}+2 x\right )\right )+\frac {5}{132} e^{\frac {1}{2}-\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1+i \sqrt {11}+2 x\right )\right )-\frac {i e^{\frac {1}{2}-\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1+i \sqrt {11}+2 x\right )\right )}{12 \sqrt {11}}+\frac {1}{264} \left (1-i \sqrt {11}\right ) e^{\frac {1}{2}-\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1+i \sqrt {11}+2 x\right )\right )-\frac {1}{264} \left (11-3 i \sqrt {11}\right ) e^{\frac {1}{2}-\frac {i \sqrt {11}}{2}} \text {Ei}\left (\frac {1}{2} \left (-1+i \sqrt {11}+2 x\right )\right )-\frac {1}{4 \left (1+\frac {x}{\log \left (-\frac {1}{x}+x\right )}\right )} \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.03 \[ \int \frac {-9 x^2+6 x^3-16 x^4+8 x^5-8 x^6+2 x^7-x^8+e^x \left (3 x^2-5 x^3+x^4+4 x^5-4 x^6+x^7\right )+\left (-9 x^2+6 x^3+2 x^4-4 x^5+6 x^6-2 x^7+x^8+e^x \left (6 x-10 x^2+2 x^3+8 x^4-8 x^5+2 x^6\right )\right ) \log \left (\frac {-1+x^2}{x}\right )+e^x \left (3-5 x+x^2+4 x^3-4 x^4+x^5\right ) \log ^2\left (\frac {-1+x^2}{x}\right )}{-36 x^4+24 x^5+8 x^6-16 x^7+24 x^8-8 x^9+4 x^{10}+\left (-72 x^3+48 x^4+16 x^5-32 x^6+48 x^7-16 x^8+8 x^9\right ) \log \left (\frac {-1+x^2}{x}\right )+\left (-36 x^2+24 x^3+8 x^4-16 x^5+24 x^6-8 x^7+4 x^8\right ) \log ^2\left (\frac {-1+x^2}{x}\right )} \, dx=\frac {1}{4} \left (\frac {e^x}{3 x-x^2+x^3}+\frac {x}{x+\log \left (-\frac {1}{x}+x\right )}\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. \(93\) vs. \(2(33)=66\).
Time = 32.37 (sec) , antiderivative size = 94, normalized size of antiderivative = 2.61
method | result | size |
parallelrisch | \(-\frac {-9 \,{\mathrm e}^{x} x -9 x^{4}+9 x^{3}-27 x^{2}-9 \,{\mathrm e}^{x} \ln \left (\frac {x^{2}-1}{x}\right )}{36 x \left (\ln \left (\frac {x^{2}-1}{x}\right ) x^{2}+x^{3}-\ln \left (\frac {x^{2}-1}{x}\right ) x -x^{2}+3 \ln \left (\frac {x^{2}-1}{x}\right )+3 x \right )}\) | \(94\) |
risch | \(\frac {{\mathrm e}^{x}}{4 x \left (x^{2}-x +3\right )}+\frac {x}{-2 i \pi \,\operatorname {csgn}\left (\frac {i}{x}\right ) \operatorname {csgn}\left (i \left (x^{2}-1\right )\right ) \operatorname {csgn}\left (\frac {i \left (x^{2}-1\right )}{x}\right )+2 i \pi \,\operatorname {csgn}\left (\frac {i}{x}\right ) {\operatorname {csgn}\left (\frac {i \left (x^{2}-1\right )}{x}\right )}^{2}+2 i \pi \,\operatorname {csgn}\left (i \left (x^{2}-1\right )\right ) {\operatorname {csgn}\left (\frac {i \left (x^{2}-1\right )}{x}\right )}^{2}-2 i \pi {\operatorname {csgn}\left (\frac {i \left (x^{2}-1\right )}{x}\right )}^{3}+4 x -4 \ln \left (x \right )+4 \ln \left (x^{2}-1\right )}\) | \(142\) |
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Leaf count of result is larger than twice the leaf count of optimal. 72 vs. \(2 (33) = 66\).
Time = 0.26 (sec) , antiderivative size = 72, normalized size of antiderivative = 2.00 \[ \int \frac {-9 x^2+6 x^3-16 x^4+8 x^5-8 x^6+2 x^7-x^8+e^x \left (3 x^2-5 x^3+x^4+4 x^5-4 x^6+x^7\right )+\left (-9 x^2+6 x^3+2 x^4-4 x^5+6 x^6-2 x^7+x^8+e^x \left (6 x-10 x^2+2 x^3+8 x^4-8 x^5+2 x^6\right )\right ) \log \left (\frac {-1+x^2}{x}\right )+e^x \left (3-5 x+x^2+4 x^3-4 x^4+x^5\right ) \log ^2\left (\frac {-1+x^2}{x}\right )}{-36 x^4+24 x^5+8 x^6-16 x^7+24 x^8-8 x^9+4 x^{10}+\left (-72 x^3+48 x^4+16 x^5-32 x^6+48 x^7-16 x^8+8 x^9\right ) \log \left (\frac {-1+x^2}{x}\right )+\left (-36 x^2+24 x^3+8 x^4-16 x^5+24 x^6-8 x^7+4 x^8\right ) \log ^2\left (\frac {-1+x^2}{x}\right )} \, dx=\frac {x^{4} - x^{3} + 3 \, x^{2} + x e^{x} + e^{x} \log \left (\frac {x^{2} - 1}{x}\right )}{4 \, {\left (x^{4} - x^{3} + 3 \, x^{2} + {\left (x^{3} - x^{2} + 3 \, x\right )} \log \left (\frac {x^{2} - 1}{x}\right )\right )}} \]
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Time = 0.28 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.86 \[ \int \frac {-9 x^2+6 x^3-16 x^4+8 x^5-8 x^6+2 x^7-x^8+e^x \left (3 x^2-5 x^3+x^4+4 x^5-4 x^6+x^7\right )+\left (-9 x^2+6 x^3+2 x^4-4 x^5+6 x^6-2 x^7+x^8+e^x \left (6 x-10 x^2+2 x^3+8 x^4-8 x^5+2 x^6\right )\right ) \log \left (\frac {-1+x^2}{x}\right )+e^x \left (3-5 x+x^2+4 x^3-4 x^4+x^5\right ) \log ^2\left (\frac {-1+x^2}{x}\right )}{-36 x^4+24 x^5+8 x^6-16 x^7+24 x^8-8 x^9+4 x^{10}+\left (-72 x^3+48 x^4+16 x^5-32 x^6+48 x^7-16 x^8+8 x^9\right ) \log \left (\frac {-1+x^2}{x}\right )+\left (-36 x^2+24 x^3+8 x^4-16 x^5+24 x^6-8 x^7+4 x^8\right ) \log ^2\left (\frac {-1+x^2}{x}\right )} \, dx=\frac {x}{4 x + 4 \log {\left (\frac {x^{2} - 1}{x} \right )}} + \frac {e^{x}}{4 x^{3} - 4 x^{2} + 12 x} \]
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Leaf count of result is larger than twice the leaf count of optimal. 105 vs. \(2 (33) = 66\).
Time = 0.27 (sec) , antiderivative size = 105, normalized size of antiderivative = 2.92 \[ \int \frac {-9 x^2+6 x^3-16 x^4+8 x^5-8 x^6+2 x^7-x^8+e^x \left (3 x^2-5 x^3+x^4+4 x^5-4 x^6+x^7\right )+\left (-9 x^2+6 x^3+2 x^4-4 x^5+6 x^6-2 x^7+x^8+e^x \left (6 x-10 x^2+2 x^3+8 x^4-8 x^5+2 x^6\right )\right ) \log \left (\frac {-1+x^2}{x}\right )+e^x \left (3-5 x+x^2+4 x^3-4 x^4+x^5\right ) \log ^2\left (\frac {-1+x^2}{x}\right )}{-36 x^4+24 x^5+8 x^6-16 x^7+24 x^8-8 x^9+4 x^{10}+\left (-72 x^3+48 x^4+16 x^5-32 x^6+48 x^7-16 x^8+8 x^9\right ) \log \left (\frac {-1+x^2}{x}\right )+\left (-36 x^2+24 x^3+8 x^4-16 x^5+24 x^6-8 x^7+4 x^8\right ) \log ^2\left (\frac {-1+x^2}{x}\right )} \, dx=\frac {x^{4} - x^{3} + 3 \, x^{2} + {\left (x - \log \left (x\right )\right )} e^{x} + e^{x} \log \left (x + 1\right ) + e^{x} \log \left (x - 1\right )}{4 \, {\left (x^{4} - x^{3} + 3 \, x^{2} + {\left (x^{3} - x^{2} + 3 \, x\right )} \log \left (x + 1\right ) + {\left (x^{3} - x^{2} + 3 \, x\right )} \log \left (x - 1\right ) - {\left (x^{3} - x^{2} + 3 \, x\right )} \log \left (x\right )\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 91 vs. \(2 (33) = 66\).
Time = 0.67 (sec) , antiderivative size = 91, normalized size of antiderivative = 2.53 \[ \int \frac {-9 x^2+6 x^3-16 x^4+8 x^5-8 x^6+2 x^7-x^8+e^x \left (3 x^2-5 x^3+x^4+4 x^5-4 x^6+x^7\right )+\left (-9 x^2+6 x^3+2 x^4-4 x^5+6 x^6-2 x^7+x^8+e^x \left (6 x-10 x^2+2 x^3+8 x^4-8 x^5+2 x^6\right )\right ) \log \left (\frac {-1+x^2}{x}\right )+e^x \left (3-5 x+x^2+4 x^3-4 x^4+x^5\right ) \log ^2\left (\frac {-1+x^2}{x}\right )}{-36 x^4+24 x^5+8 x^6-16 x^7+24 x^8-8 x^9+4 x^{10}+\left (-72 x^3+48 x^4+16 x^5-32 x^6+48 x^7-16 x^8+8 x^9\right ) \log \left (\frac {-1+x^2}{x}\right )+\left (-36 x^2+24 x^3+8 x^4-16 x^5+24 x^6-8 x^7+4 x^8\right ) \log ^2\left (\frac {-1+x^2}{x}\right )} \, dx=\frac {x^{4} - x^{3} + 3 \, x^{2} + x e^{x} + e^{x} \log \left (\frac {x^{2} - 1}{x}\right )}{4 \, {\left (x^{4} + x^{3} \log \left (\frac {x^{2} - 1}{x}\right ) - x^{3} - x^{2} \log \left (\frac {x^{2} - 1}{x}\right ) + 3 \, x^{2} + 3 \, x \log \left (\frac {x^{2} - 1}{x}\right )\right )}} \]
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Time = 11.43 (sec) , antiderivative size = 89, normalized size of antiderivative = 2.47 \[ \int \frac {-9 x^2+6 x^3-16 x^4+8 x^5-8 x^6+2 x^7-x^8+e^x \left (3 x^2-5 x^3+x^4+4 x^5-4 x^6+x^7\right )+\left (-9 x^2+6 x^3+2 x^4-4 x^5+6 x^6-2 x^7+x^8+e^x \left (6 x-10 x^2+2 x^3+8 x^4-8 x^5+2 x^6\right )\right ) \log \left (\frac {-1+x^2}{x}\right )+e^x \left (3-5 x+x^2+4 x^3-4 x^4+x^5\right ) \log ^2\left (\frac {-1+x^2}{x}\right )}{-36 x^4+24 x^5+8 x^6-16 x^7+24 x^8-8 x^9+4 x^{10}+\left (-72 x^3+48 x^4+16 x^5-32 x^6+48 x^7-16 x^8+8 x^9\right ) \log \left (\frac {-1+x^2}{x}\right )+\left (-36 x^2+24 x^3+8 x^4-16 x^5+24 x^6-8 x^7+4 x^8\right ) \log ^2\left (\frac {-1+x^2}{x}\right )} \, dx=\frac {x^2\,\ln \left (\frac {x^2-1}{x}\right )-x^3\,\ln \left (\frac {x^2-1}{x}\right )+{\mathrm {e}}^x\,\ln \left (\frac {x^2-1}{x}\right )-3\,x\,\ln \left (\frac {x^2-1}{x}\right )+x\,{\mathrm {e}}^x}{4\,x\,\left (x+\ln \left (\frac {x^2-1}{x}\right )\right )\,\left (x^2-x+3\right )} \]
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