Integrand size = 82, antiderivative size = 26 \[ \int \frac {e^{-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}} \left (-4-8 x+2 x^3+x^4+e^x \left (4 x+4 x^2+x^4+x^5\right )\right )}{3 x^2+6 x^3+3 x^4} \, dx=e^{\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x (1+x)}} \]
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\[ \int \frac {e^{-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}} \left (-4-8 x+2 x^3+x^4+e^x \left (4 x+4 x^2+x^4+x^5\right )\right )}{3 x^2+6 x^3+3 x^4} \, dx=\int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) \left (-4-8 x+2 x^3+x^4+e^x \left (4 x+4 x^2+x^4+x^5\right )\right )}{3 x^2+6 x^3+3 x^4} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) \left (-4-8 x+2 x^3+x^4+e^x \left (4 x+4 x^2+x^4+x^5\right )\right )}{x^2 \left (3+6 x+3 x^2\right )} \, dx \\ & = \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) \left (-4-8 x+2 x^3+x^4+e^x \left (4 x+4 x^2+x^4+x^5\right )\right )}{3 x^2 (1+x)^2} \, dx \\ & = \frac {1}{3} \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) \left (-4-8 x+2 x^3+x^4+e^x \left (4 x+4 x^2+x^4+x^5\right )\right )}{x^2 (1+x)^2} \, dx \\ & = \frac {1}{3} \int \left (-\frac {4 \exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{x^2 (1+x)^2}-\frac {8 \exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{x (1+x)^2}+\frac {2 \exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) x}{(1+x)^2}+\frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) x^2}{(1+x)^2}+\frac {\exp \left (-5+e^x+x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) \left (4+x^3\right )}{x (1+x)}\right ) \, dx \\ & = \frac {1}{3} \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) x^2}{(1+x)^2} \, dx+\frac {1}{3} \int \frac {\exp \left (-5+e^x+x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) \left (4+x^3\right )}{x (1+x)} \, dx+\frac {2}{3} \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) x}{(1+x)^2} \, dx-\frac {4}{3} \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{x^2 (1+x)^2} \, dx-\frac {8}{3} \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{x (1+x)^2} \, dx \\ & = \frac {1}{3} \int \left (\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )+\frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{(1+x)^2}-\frac {2 \exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{1+x}\right ) \, dx+\frac {1}{3} \int \left (-\exp \left (-5+e^x+x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )+\frac {4 \exp \left (-5+e^x+x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{x}+\exp \left (-5+e^x+x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) x-\frac {3 \exp \left (-5+e^x+x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{1+x}\right ) \, dx+\frac {2}{3} \int \left (-\frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{(1+x)^2}+\frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{1+x}\right ) \, dx-\frac {4}{3} \int \left (\frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{x^2}-\frac {2 \exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{x}+\frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{(1+x)^2}+\frac {2 \exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{1+x}\right ) \, dx-\frac {8}{3} \int \left (\frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{-1-x}+\frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{x}-\frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{(1+x)^2}\right ) \, dx \\ & = \frac {1}{3} \int \exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) \, dx-\frac {1}{3} \int \exp \left (-5+e^x+x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) \, dx+\frac {1}{3} \int \exp \left (-5+e^x+x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right ) x \, dx+\frac {1}{3} \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{(1+x)^2} \, dx-\frac {2}{3} \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{(1+x)^2} \, dx-\frac {4}{3} \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{x^2} \, dx+\frac {4}{3} \int \frac {\exp \left (-5+e^x+x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{x} \, dx-\frac {4}{3} \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{(1+x)^2} \, dx-\frac {8}{3} \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{-1-x} \, dx+\frac {8}{3} \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{(1+x)^2} \, dx-\frac {8}{3} \int \frac {\exp \left (-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{1+x} \, dx-\int \frac {\exp \left (-5+e^x+x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}\right )}{1+x} \, dx \\ \end{align*}
Time = 5.16 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.00 \[ \int \frac {e^{-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}} \left (-4-8 x+2 x^3+x^4+e^x \left (4 x+4 x^2+x^4+x^5\right )\right )}{3 x^2+6 x^3+3 x^4} \, dx=e^{\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x (1+x)}} \]
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Time = 20.70 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.85
method | result | size |
risch | \({\mathrm e}^{\frac {{\mathrm e}^{{\mathrm e}^{x}-5} \left (x^{3}+4\right )}{3 \left (1+x \right ) x}}\) | \(22\) |
parallelrisch | \({\mathrm e}^{\frac {{\mathrm e}^{{\mathrm e}^{x}-5} \left (x^{3}+4\right )}{3 \left (1+x \right ) x}}\) | \(22\) |
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Leaf count of result is larger than twice the leaf count of optimal. 46 vs. \(2 (21) = 42\).
Time = 0.25 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.77 \[ \int \frac {e^{-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}} \left (-4-8 x+2 x^3+x^4+e^x \left (4 x+4 x^2+x^4+x^5\right )\right )}{3 x^2+6 x^3+3 x^4} \, dx=e^{\left (-\frac {15 \, x^{2} - 3 \, {\left (x^{2} + x\right )} e^{x} - {\left (x^{3} + 4\right )} e^{\left (e^{x} - 5\right )} + 15 \, x}{3 \, {\left (x^{2} + x\right )}} - e^{x} + 5\right )} \]
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Time = 0.48 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.77 \[ \int \frac {e^{-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}} \left (-4-8 x+2 x^3+x^4+e^x \left (4 x+4 x^2+x^4+x^5\right )\right )}{3 x^2+6 x^3+3 x^4} \, dx=e^{\frac {\left (x^{3} + 4\right ) e^{e^{x} - 5}}{3 x^{2} + 3 x}} \]
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none
Time = 0.42 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.58 \[ \int \frac {e^{-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}} \left (-4-8 x+2 x^3+x^4+e^x \left (4 x+4 x^2+x^4+x^5\right )\right )}{3 x^2+6 x^3+3 x^4} \, dx=e^{\left (\frac {1}{3} \, x e^{\left (e^{x} - 5\right )} + \frac {4 \, e^{\left (e^{x} - 5\right )}}{3 \, x} - \frac {e^{\left (e^{x}\right )}}{x e^{5} + e^{5}} - \frac {1}{3} \, e^{\left (e^{x} - 5\right )}\right )} \]
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\[ \int \frac {e^{-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}} \left (-4-8 x+2 x^3+x^4+e^x \left (4 x+4 x^2+x^4+x^5\right )\right )}{3 x^2+6 x^3+3 x^4} \, dx=\int { \frac {{\left (x^{4} + 2 \, x^{3} + {\left (x^{5} + x^{4} + 4 \, x^{2} + 4 \, x\right )} e^{x} - 8 \, x - 4\right )} e^{\left (\frac {{\left (x^{3} + 4\right )} e^{\left (e^{x} - 5\right )}}{3 \, {\left (x^{2} + x\right )}} + e^{x} - 5\right )}}{3 \, {\left (x^{4} + 2 \, x^{3} + x^{2}\right )}} \,d x } \]
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Time = 11.02 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.58 \[ \int \frac {e^{-5+e^x+\frac {e^{-5+e^x} \left (4+x^3\right )}{3 x+3 x^2}} \left (-4-8 x+2 x^3+x^4+e^x \left (4 x+4 x^2+x^4+x^5\right )\right )}{3 x^2+6 x^3+3 x^4} \, dx={\mathrm {e}}^{\frac {x^3\,{\mathrm {e}}^{{\mathrm {e}}^x}\,{\mathrm {e}}^{-5}}{3\,x^2+3\,x}}\,{\mathrm {e}}^{\frac {4\,{\mathrm {e}}^{{\mathrm {e}}^x}\,{\mathrm {e}}^{-5}}{3\,x^2+3\,x}} \]
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