Integrand size = 61, antiderivative size = 23 \[ \int \frac {5+9 x+8 x^2-2 x^3+(5-x)^4 \left (-10 x^2-9 x^3+7 x^4\right )+\left (5 x-x^2\right ) \log (x)}{-5 x+x^2} \, dx=(1+x) \left (-x+(5-x)^4 x^2-\log (x)\right ) \]
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Time = 0.12 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.78, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.049, Rules used = {1607, 6820, 2332} \[ \int \frac {5+9 x+8 x^2-2 x^3+(5-x)^4 \left (-10 x^2-9 x^3+7 x^4\right )+\left (5 x-x^2\right ) \log (x)}{-5 x+x^2} \, dx=x^7-19 x^6+130 x^5-350 x^4+125 x^3+624 x^2-x-x \log (x)-\log (x) \]
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Rule 1607
Rule 2332
Rule 6820
Rubi steps \begin{align*} \text {integral}& = \int \frac {5+9 x+8 x^2-2 x^3+(5-x)^4 \left (-10 x^2-9 x^3+7 x^4\right )+\left (5 x-x^2\right ) \log (x)}{(-5+x) x} \, dx \\ & = \int \left (-2-\frac {1}{x}+1248 x+375 x^2-1400 x^3+650 x^4-114 x^5+7 x^6-\log (x)\right ) \, dx \\ & = -2 x+624 x^2+125 x^3-350 x^4+130 x^5-19 x^6+x^7-\log (x)-\int \log (x) \, dx \\ & = -x+624 x^2+125 x^3-350 x^4+130 x^5-19 x^6+x^7-\log (x)-x \log (x) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.78 \[ \int \frac {5+9 x+8 x^2-2 x^3+(5-x)^4 \left (-10 x^2-9 x^3+7 x^4\right )+\left (5 x-x^2\right ) \log (x)}{-5 x+x^2} \, dx=-x+624 x^2+125 x^3-350 x^4+130 x^5-19 x^6+x^7-\log (x)-x \log (x) \]
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Time = 0.53 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.83
method | result | size |
default | \(x^{7}-19 x^{6}+130 x^{5}-350 x^{4}+125 x^{3}-x -x \ln \left (x \right )+624 x^{2}-\ln \left (x \right )\) | \(42\) |
norman | \(x^{7}-19 x^{6}+130 x^{5}-350 x^{4}+125 x^{3}-x -x \ln \left (x \right )+624 x^{2}-\ln \left (x \right )\) | \(42\) |
risch | \(x^{7}-19 x^{6}+130 x^{5}-350 x^{4}+125 x^{3}-x -x \ln \left (x \right )+624 x^{2}-\ln \left (x \right )\) | \(42\) |
parallelrisch | \(x^{7}-19 x^{6}+130 x^{5}-350 x^{4}+125 x^{3}-x -x \ln \left (x \right )+624 x^{2}-\ln \left (x \right )\) | \(42\) |
parts | \(x^{7}-19 x^{6}+130 x^{5}-350 x^{4}+125 x^{3}-x -x \ln \left (x \right )+624 x^{2}-\ln \left (x \right )\) | \(42\) |
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Time = 0.25 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.70 \[ \int \frac {5+9 x+8 x^2-2 x^3+(5-x)^4 \left (-10 x^2-9 x^3+7 x^4\right )+\left (5 x-x^2\right ) \log (x)}{-5 x+x^2} \, dx=x^{7} - 19 \, x^{6} + 130 \, x^{5} - 350 \, x^{4} + 125 \, x^{3} + 624 \, x^{2} - {\left (x + 1\right )} \log \left (x\right ) - x \]
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Leaf count of result is larger than twice the leaf count of optimal. 37 vs. \(2 (15) = 30\).
Time = 0.09 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.61 \[ \int \frac {5+9 x+8 x^2-2 x^3+(5-x)^4 \left (-10 x^2-9 x^3+7 x^4\right )+\left (5 x-x^2\right ) \log (x)}{-5 x+x^2} \, dx=x^{7} - 19 x^{6} + 130 x^{5} - 350 x^{4} + 125 x^{3} + 624 x^{2} - x \log {\left (x \right )} - x - \log {\left (x \right )} \]
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Time = 0.24 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.78 \[ \int \frac {5+9 x+8 x^2-2 x^3+(5-x)^4 \left (-10 x^2-9 x^3+7 x^4\right )+\left (5 x-x^2\right ) \log (x)}{-5 x+x^2} \, dx=x^{7} - 19 \, x^{6} + 130 \, x^{5} - 350 \, x^{4} + 125 \, x^{3} + 624 \, x^{2} - x \log \left (x\right ) - x - \log \left (x\right ) \]
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Time = 0.28 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.78 \[ \int \frac {5+9 x+8 x^2-2 x^3+(5-x)^4 \left (-10 x^2-9 x^3+7 x^4\right )+\left (5 x-x^2\right ) \log (x)}{-5 x+x^2} \, dx=x^{7} - 19 \, x^{6} + 130 \, x^{5} - 350 \, x^{4} + 125 \, x^{3} + 624 \, x^{2} - x \log \left (x\right ) - x - \log \left (x\right ) \]
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Time = 11.22 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.48 \[ \int \frac {5+9 x+8 x^2-2 x^3+(5-x)^4 \left (-10 x^2-9 x^3+7 x^4\right )+\left (5 x-x^2\right ) \log (x)}{-5 x+x^2} \, dx=-\left (x+1\right )\,\left (x+\ln \left (x\right )-625\,x^2+500\,x^3-150\,x^4+20\,x^5-x^6\right ) \]
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