Integrand size = 222, antiderivative size = 29 \[ \int \frac {\left (4 e^2 x+8 x^2+e^x \left (e^2 x+2 x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right ) \left (4 e^2+4 x+e^x \left (x+x^2+e^2 (1+x)\right )+\left (4 e^2+4 x+e^x \left (e^2+x\right )\right ) \log \left (4 x+e^x x\right )+\left (4 x-4 e^2 x-4 x^2+e^x \left (x-e^2 x-x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )\right )}{\left (4 x+e^x x\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )} \, dx=4+\left (e^2+x\right ) \left (x+e^{4-x} \log \left (x \log \left (\left (4+e^x\right ) x\right )\right )\right ) \]
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Leaf count is larger than twice the leaf count of optimal. \(62\) vs. \(2(29)=58\).
Time = 13.14 (sec) , antiderivative size = 62, normalized size of antiderivative = 2.14, number of steps used = 29, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.027, Rules used = {6820, 6874, 2225, 2209, 2207, 2635} \[ \int \frac {\left (4 e^2 x+8 x^2+e^x \left (e^2 x+2 x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right ) \left (4 e^2+4 x+e^x \left (x+x^2+e^2 (1+x)\right )+\left (4 e^2+4 x+e^x \left (e^2+x\right )\right ) \log \left (4 x+e^x x\right )+\left (4 x-4 e^2 x-4 x^2+e^x \left (x-e^2 x-x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )\right )}{\left (4 x+e^x x\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )} \, dx=x^2+e^2 x+e^{4-x} \log \left (x \log \left (e^x x+4 x\right )\right )-e^{4-x} \left (-x-e^2+1\right ) \log \left (x \log \left (e^x x+4 x\right )\right ) \]
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Rule 2207
Rule 2209
Rule 2225
Rule 2635
Rule 6820
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \frac {e^{-x} \left (e^6+e^4 x+e^{2+x} x+2 e^x x^2+\frac {e^4 \left (e^2+x\right ) \left (4+e^x (1+x)\right )}{\left (4+e^x\right ) \log \left (\left (4+e^x\right ) x\right )}-e^4 x \left (-1+e^2+x\right ) \log \left (x \log \left (\left (4+e^x\right ) x\right )\right )\right )}{x} \, dx \\ & = \int \left (e^2+2 x+\frac {4 e^{4-x} \left (-e^2-x\right )}{\left (4+e^x\right ) \log \left (4 x+e^x x\right )}+\frac {e^{4-x} \left (e^2+\left (1+e^2\right ) x+x^2+e^2 \log \left (\left (4+e^x\right ) x\right )+x \log \left (\left (4+e^x\right ) x\right )+\left (1-e^2\right ) x \log \left (\left (4+e^x\right ) x\right ) \log \left (x \log \left (\left (4+e^x\right ) x\right )\right )-x^2 \log \left (\left (4+e^x\right ) x\right ) \log \left (x \log \left (\left (4+e^x\right ) x\right )\right )\right )}{x \log \left (4 x+e^x x\right )}\right ) \, dx \\ & = e^2 x+x^2+4 \int \frac {e^{4-x} \left (-e^2-x\right )}{\left (4+e^x\right ) \log \left (4 x+e^x x\right )} \, dx+\int \frac {e^{4-x} \left (e^2+\left (1+e^2\right ) x+x^2+e^2 \log \left (\left (4+e^x\right ) x\right )+x \log \left (\left (4+e^x\right ) x\right )+\left (1-e^2\right ) x \log \left (\left (4+e^x\right ) x\right ) \log \left (x \log \left (\left (4+e^x\right ) x\right )\right )-x^2 \log \left (\left (4+e^x\right ) x\right ) \log \left (x \log \left (\left (4+e^x\right ) x\right )\right )\right )}{x \log \left (4 x+e^x x\right )} \, dx \\ & = e^2 x+x^2+4 \int \left (\frac {e^{6-x}}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )}+\frac {e^{4-x} x}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )}\right ) \, dx+\int \frac {e^{4-x} \left ((1+x) \left (e^2+x\right )-\log \left (\left (4+e^x\right ) x\right ) \left (-e^2-x+x \left (-1+e^2+x\right ) \log \left (x \log \left (\left (4+e^x\right ) x\right )\right )\right )\right )}{x \log \left (4 x+e^x x\right )} \, dx \\ & = e^2 x+x^2+4 \int \frac {e^{6-x}}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )} \, dx+4 \int \frac {e^{4-x} x}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )} \, dx+\int \left (\frac {e^{4-x} \left (e^2+x\right ) \left (1+x+\log \left (\left (4+e^x\right ) x\right )\right )}{x \log \left (4 x+e^x x\right )}+e^{4-x} \left (1-e^2-x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )\right ) \, dx \\ & = e^2 x+x^2+4 \int \frac {e^{6-x}}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )} \, dx+4 \int \frac {e^{4-x} x}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )} \, dx+\int \frac {e^{4-x} \left (e^2+x\right ) \left (1+x+\log \left (\left (4+e^x\right ) x\right )\right )}{x \log \left (4 x+e^x x\right )} \, dx+\int e^{4-x} \left (1-e^2-x\right ) \log \left (x \log \left (4 x+e^x x\right )\right ) \, dx \\ & = e^2 x+x^2+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right )-e^{4-x} \left (1-e^2-x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )+4 \int \frac {e^{6-x}}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )} \, dx+4 \int \frac {e^{4-x} x}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )} \, dx+\int \left (\frac {e^{4-x} \left (1+x+\log \left (\left (4+e^x\right ) x\right )\right )}{\log \left (4 x+e^x x\right )}+\frac {e^{6-x} \left (1+x+\log \left (\left (4+e^x\right ) x\right )\right )}{x \log \left (4 x+e^x x\right )}\right ) \, dx-\int \frac {e^{4-x} \left (e^2+x\right ) \left (4+e^x (1+x)+\left (4+e^x\right ) \log \left (\left (4+e^x\right ) x\right )\right )}{\left (4+e^x\right ) x \log \left (4 x+e^x x\right )} \, dx \\ & = e^2 x+x^2+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right )-e^{4-x} \left (1-e^2-x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )+4 \int \frac {e^{6-x}}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )} \, dx+4 \int \frac {e^{4-x} x}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )} \, dx-\int \left (\frac {4 e^{4-x} \left (-e^2-x\right )}{\left (4+e^x\right ) \log \left (4 x+e^x x\right )}+\frac {e^{4-x} \left (e^2+x\right ) \left (1+x+\log \left (\left (4+e^x\right ) x\right )\right )}{x \log \left (4 x+e^x x\right )}\right ) \, dx+\int \frac {e^{4-x} \left (1+x+\log \left (\left (4+e^x\right ) x\right )\right )}{\log \left (4 x+e^x x\right )} \, dx+\int \frac {e^{6-x} \left (1+x+\log \left (\left (4+e^x\right ) x\right )\right )}{x \log \left (4 x+e^x x\right )} \, dx \\ & = e^2 x+x^2+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right )-e^{4-x} \left (1-e^2-x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )+4 \int \frac {e^{6-x}}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )} \, dx-4 \int \frac {e^{4-x} \left (-e^2-x\right )}{\left (4+e^x\right ) \log \left (4 x+e^x x\right )} \, dx+4 \int \frac {e^{4-x} x}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )} \, dx+\int \left (\frac {e^{6-x}}{x}+\frac {e^{6-x}}{\log \left (4 x+e^x x\right )}+\frac {e^{6-x}}{x \log \left (4 x+e^x x\right )}\right ) \, dx+\int \left (e^{4-x}+\frac {e^{4-x}}{\log \left (4 x+e^x x\right )}+\frac {e^{4-x} x}{\log \left (4 x+e^x x\right )}\right ) \, dx-\int \frac {e^{4-x} \left (e^2+x\right ) \left (1+x+\log \left (\left (4+e^x\right ) x\right )\right )}{x \log \left (4 x+e^x x\right )} \, dx \\ & = e^2 x+x^2+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right )-e^{4-x} \left (1-e^2-x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )-4 \int \left (\frac {e^{6-x}}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )}+\frac {e^{4-x} x}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )}\right ) \, dx+4 \int \frac {e^{6-x}}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )} \, dx+4 \int \frac {e^{4-x} x}{\left (-4-e^x\right ) \log \left (4 x+e^x x\right )} \, dx+\int e^{4-x} \, dx+\int \frac {e^{6-x}}{x} \, dx-\int \left (\frac {e^{4-x} \left (1+x+\log \left (\left (4+e^x\right ) x\right )\right )}{\log \left (4 x+e^x x\right )}+\frac {e^{6-x} \left (1+x+\log \left (\left (4+e^x\right ) x\right )\right )}{x \log \left (4 x+e^x x\right )}\right ) \, dx+\int \frac {e^{4-x}}{\log \left (4 x+e^x x\right )} \, dx+\int \frac {e^{6-x}}{\log \left (4 x+e^x x\right )} \, dx+\int \frac {e^{6-x}}{x \log \left (4 x+e^x x\right )} \, dx+\int \frac {e^{4-x} x}{\log \left (4 x+e^x x\right )} \, dx \\ & = -e^{4-x}+e^2 x+x^2+e^6 \text {Ei}(-x)+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right )-e^{4-x} \left (1-e^2-x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )+\int \frac {e^{4-x}}{\log \left (4 x+e^x x\right )} \, dx+\int \frac {e^{6-x}}{\log \left (4 x+e^x x\right )} \, dx+\int \frac {e^{6-x}}{x \log \left (4 x+e^x x\right )} \, dx+\int \frac {e^{4-x} x}{\log \left (4 x+e^x x\right )} \, dx-\int \frac {e^{4-x} \left (1+x+\log \left (\left (4+e^x\right ) x\right )\right )}{\log \left (4 x+e^x x\right )} \, dx-\int \frac {e^{6-x} \left (1+x+\log \left (\left (4+e^x\right ) x\right )\right )}{x \log \left (4 x+e^x x\right )} \, dx \\ & = -e^{4-x}+e^2 x+x^2+e^6 \text {Ei}(-x)+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right )-e^{4-x} \left (1-e^2-x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )-\int \left (\frac {e^{6-x}}{x}+\frac {e^{6-x}}{\log \left (4 x+e^x x\right )}+\frac {e^{6-x}}{x \log \left (4 x+e^x x\right )}\right ) \, dx-\int \left (e^{4-x}+\frac {e^{4-x}}{\log \left (4 x+e^x x\right )}+\frac {e^{4-x} x}{\log \left (4 x+e^x x\right )}\right ) \, dx+\int \frac {e^{4-x}}{\log \left (4 x+e^x x\right )} \, dx+\int \frac {e^{6-x}}{\log \left (4 x+e^x x\right )} \, dx+\int \frac {e^{6-x}}{x \log \left (4 x+e^x x\right )} \, dx+\int \frac {e^{4-x} x}{\log \left (4 x+e^x x\right )} \, dx \\ & = -e^{4-x}+e^2 x+x^2+e^6 \text {Ei}(-x)+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right )-e^{4-x} \left (1-e^2-x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )-\int e^{4-x} \, dx-\int \frac {e^{6-x}}{x} \, dx \\ & = e^2 x+x^2+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right )-e^{4-x} \left (1-e^2-x\right ) \log \left (x \log \left (4 x+e^x x\right )\right ) \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.14 \[ \int \frac {\left (4 e^2 x+8 x^2+e^x \left (e^2 x+2 x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right ) \left (4 e^2+4 x+e^x \left (x+x^2+e^2 (1+x)\right )+\left (4 e^2+4 x+e^x \left (e^2+x\right )\right ) \log \left (4 x+e^x x\right )+\left (4 x-4 e^2 x-4 x^2+e^x \left (x-e^2 x-x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )\right )}{\left (4 x+e^x x\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )} \, dx=e^2 x+x^2+e^{4-x} \left (e^2+x\right ) \log \left (x \log \left (\left (4+e^x\right ) x\right )\right ) \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 0.10 (sec) , antiderivative size = 2626, normalized size of antiderivative = 90.55
\[\text {Expression too large to display}\]
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Time = 0.27 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.28 \[ \int \frac {\left (4 e^2 x+8 x^2+e^x \left (e^2 x+2 x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right ) \left (4 e^2+4 x+e^x \left (x+x^2+e^2 (1+x)\right )+\left (4 e^2+4 x+e^x \left (e^2+x\right )\right ) \log \left (4 x+e^x x\right )+\left (4 x-4 e^2 x-4 x^2+e^x \left (x-e^2 x-x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )\right )}{\left (4 x+e^x x\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )} \, dx={\left ({\left (x^{2} + x e^{2}\right )} e^{x} + {\left (x e^{4} + e^{6}\right )} \log \left (x \log \left (x e^{x} + 4 \, x\right )\right )\right )} e^{\left (-x\right )} \]
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Time = 0.68 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.10 \[ \int \frac {\left (4 e^2 x+8 x^2+e^x \left (e^2 x+2 x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right ) \left (4 e^2+4 x+e^x \left (x+x^2+e^2 (1+x)\right )+\left (4 e^2+4 x+e^x \left (e^2+x\right )\right ) \log \left (4 x+e^x x\right )+\left (4 x-4 e^2 x-4 x^2+e^x \left (x-e^2 x-x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )\right )}{\left (4 x+e^x x\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )} \, dx=x^{2} + x e^{2} + \left (x e^{4} + e^{6}\right ) e^{- x} \log {\left (x \log {\left (x e^{x} + 4 x \right )} \right )} \]
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Time = 0.29 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.48 \[ \int \frac {\left (4 e^2 x+8 x^2+e^x \left (e^2 x+2 x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right ) \left (4 e^2+4 x+e^x \left (x+x^2+e^2 (1+x)\right )+\left (4 e^2+4 x+e^x \left (e^2+x\right )\right ) \log \left (4 x+e^x x\right )+\left (4 x-4 e^2 x-4 x^2+e^x \left (x-e^2 x-x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )\right )}{\left (4 x+e^x x\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )} \, dx={\left (x e^{4} + e^{6}\right )} e^{\left (-x\right )} \log \left (x\right ) + {\left (x e^{4} + e^{6}\right )} e^{\left (-x\right )} \log \left (\log \left (x\right ) + \log \left (e^{x} + 4\right )\right ) + x^{2} + x e^{2} \]
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Leaf count of result is larger than twice the leaf count of optimal. 54 vs. \(2 (26) = 52\).
Time = 0.44 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.86 \[ \int \frac {\left (4 e^2 x+8 x^2+e^x \left (e^2 x+2 x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right ) \left (4 e^2+4 x+e^x \left (x+x^2+e^2 (1+x)\right )+\left (4 e^2+4 x+e^x \left (e^2+x\right )\right ) \log \left (4 x+e^x x\right )+\left (4 x-4 e^2 x-4 x^2+e^x \left (x-e^2 x-x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )\right )}{\left (4 x+e^x x\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )} \, dx={\left (x^{2} e^{x} + x e^{4} \log \left (x\right ) + x e^{4} \log \left (\log \left (x\right ) + \log \left (e^{x} + 4\right )\right ) + x e^{\left (x + 2\right )} + e^{6} \log \left (x\right ) + e^{6} \log \left (\log \left (x\right ) + \log \left (e^{x} + 4\right )\right )\right )} e^{\left (-x\right )} \]
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Timed out. \[ \int \frac {\left (4 e^2 x+8 x^2+e^x \left (e^2 x+2 x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )+e^{4-x} \log \left (x \log \left (4 x+e^x x\right )\right ) \left (4 e^2+4 x+e^x \left (x+x^2+e^2 (1+x)\right )+\left (4 e^2+4 x+e^x \left (e^2+x\right )\right ) \log \left (4 x+e^x x\right )+\left (4 x-4 e^2 x-4 x^2+e^x \left (x-e^2 x-x^2\right )\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )\right )}{\left (4 x+e^x x\right ) \log \left (4 x+e^x x\right ) \log \left (x \log \left (4 x+e^x x\right )\right )} \, dx=\int \frac {{\mathrm {e}}^{\ln \left (\ln \left (x\,\ln \left (4\,x+x\,{\mathrm {e}}^x\right )\right )\right )-x+4}\,\left (4\,x+4\,{\mathrm {e}}^2+\ln \left (4\,x+x\,{\mathrm {e}}^x\right )\,\left (4\,x+4\,{\mathrm {e}}^2+{\mathrm {e}}^x\,\left (x+{\mathrm {e}}^2\right )\right )+{\mathrm {e}}^x\,\left (x+{\mathrm {e}}^2\,\left (x+1\right )+x^2\right )-\ln \left (4\,x+x\,{\mathrm {e}}^x\right )\,\ln \left (x\,\ln \left (4\,x+x\,{\mathrm {e}}^x\right )\right )\,\left (4\,x\,{\mathrm {e}}^2-4\,x+{\mathrm {e}}^x\,\left (x\,{\mathrm {e}}^2-x+x^2\right )+4\,x^2\right )\right )+\ln \left (4\,x+x\,{\mathrm {e}}^x\right )\,\ln \left (x\,\ln \left (4\,x+x\,{\mathrm {e}}^x\right )\right )\,\left ({\mathrm {e}}^x\,\left (2\,x^2+{\mathrm {e}}^2\,x\right )+4\,x\,{\mathrm {e}}^2+8\,x^2\right )}{\ln \left (4\,x+x\,{\mathrm {e}}^x\right )\,\ln \left (x\,\ln \left (4\,x+x\,{\mathrm {e}}^x\right )\right )\,\left (4\,x+x\,{\mathrm {e}}^x\right )} \,d x \]
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