Integrand size = 213, antiderivative size = 31 \[ \int \frac {5 x-x^3+e^2 \left (5-x^2\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x+e^{2 e^{\log (x) \log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )} \left (-4 x \log (x)+\left (-4 e^2-4 x\right ) \log \left (e^2+x\right )\right )\right )}{25 x-10 x^2+11 x^3-2 x^4+x^5+e^{4 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x\right )+e^2 \left (25-10 x+11 x^2-2 x^3+x^4\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (10 x-2 x^2+2 x^3+e^2 \left (10-2 x+2 x^2\right )\right )} \, dx=\frac {x}{5+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}}-x+x^2} \]
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\[ \int \frac {5 x-x^3+e^2 \left (5-x^2\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x+e^{2 e^{\log (x) \log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )} \left (-4 x \log (x)+\left (-4 e^2-4 x\right ) \log \left (e^2+x\right )\right )\right )}{25 x-10 x^2+11 x^3-2 x^4+x^5+e^{4 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x\right )+e^2 \left (25-10 x+11 x^2-2 x^3+x^4\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (10 x-2 x^2+2 x^3+e^2 \left (10-2 x+2 x^2\right )\right )} \, dx=\int \frac {5 x-x^3+e^2 \left (5-x^2\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x+\exp \left (2 e^{\log (x) \log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) \left (-4 x \log (x)+\left (-4 e^2-4 x\right ) \log \left (e^2+x\right )\right )\right )}{25 x-10 x^2+11 x^3-2 x^4+x^5+e^{4 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x\right )+e^2 \left (25-10 x+11 x^2-2 x^3+x^4\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (10 x-2 x^2+2 x^3+e^2 \left (10-2 x+2 x^2\right )\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {-4 \exp \left (2 \left (e^{2 x^{\log \left (e^2+x\right )}}+x^{\log \left (e^2+x\right )}\right )+\log (x) \log \left (e^2+x\right )\right ) x \log (x)-\left (e^2+x\right ) \left (-5-e^{2 e^{2 x^{\log \left (e^2+x\right )}}}+x^2+4 \exp \left (2 \left (e^{2 x^{\log \left (e^2+x\right )}}+x^{\log \left (e^2+x\right )}\right )+\log (x) \log \left (e^2+x\right )\right ) \log \left (e^2+x\right )\right )}{\left (e^2+x\right ) \left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx \\ & = \int \left (\frac {5}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2}+\frac {e^{2 e^{2 x^{\log \left (e^2+x\right )}}}}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2}-\frac {x^2}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2}-\frac {4 \exp \left (2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) \left (x \log (x)+e^2 \log \left (e^2+x\right )+x \log \left (e^2+x\right )\right )}{\left (e^2+x\right ) \left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2}\right ) \, dx \\ & = -\left (4 \int \frac {\exp \left (2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) \left (x \log (x)+e^2 \log \left (e^2+x\right )+x \log \left (e^2+x\right )\right )}{\left (e^2+x\right ) \left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx\right )+5 \int \frac {1}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx+\int \frac {e^{2 e^{2 x^{\log \left (e^2+x\right )}}}}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx-\int \frac {x^2}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx \\ & = -\left (4 \int \left (\frac {\exp \left (2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) x \log (x)}{\left (e^2+x\right ) \left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2}+\frac {\exp \left (2+2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) \log \left (e^2+x\right )}{\left (e^2+x\right ) \left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2}+\frac {\exp \left (2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) x \log \left (e^2+x\right )}{\left (e^2+x\right ) \left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2}\right ) \, dx\right )+5 \int \frac {1}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx+\int \frac {e^{2 e^{2 x^{\log \left (e^2+x\right )}}}}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx-\int \frac {x^2}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx \\ & = -\left (4 \int \frac {\exp \left (2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) x \log (x)}{\left (e^2+x\right ) \left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx\right )-4 \int \frac {\exp \left (2+2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) \log \left (e^2+x\right )}{\left (e^2+x\right ) \left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx-4 \int \frac {\exp \left (2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) x \log \left (e^2+x\right )}{\left (e^2+x\right ) \left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx+5 \int \frac {1}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx+\int \frac {e^{2 e^{2 x^{\log \left (e^2+x\right )}}}}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx-\int \frac {x^2}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx \\ & = -\left (4 \int \left (\frac {\exp \left (2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) \log (x)}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2}-\frac {\exp \left (2+2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) \log (x)}{\left (e^2+x\right ) \left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2}\right ) \, dx\right )-4 \int \frac {\exp \left (2+2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) \log \left (e^2+x\right )}{\left (e^2+x\right ) \left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx-4 \int \left (\frac {\exp \left (2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) \log \left (e^2+x\right )}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2}-\frac {\exp \left (2+2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) \log \left (e^2+x\right )}{\left (e^2+x\right ) \left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2}\right ) \, dx+5 \int \frac {1}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx+\int \frac {e^{2 e^{2 x^{\log \left (e^2+x\right )}}}}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx-\int \frac {x^2}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx \\ & = -\left (4 \int \frac {\exp \left (2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) \log (x)}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx\right )+4 \int \frac {\exp \left (2+2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) \log (x)}{\left (e^2+x\right ) \left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx-4 \int \frac {\exp \left (2 e^{2 x^{\log \left (e^2+x\right )}}+2 x^{\log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )\right ) \log \left (e^2+x\right )}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx+5 \int \frac {1}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx+\int \frac {e^{2 e^{2 x^{\log \left (e^2+x\right )}}}}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx-\int \frac {x^2}{\left (5+e^{2 e^{2 x^{\log \left (e^2+x\right )}}}-x+x^2\right )^2} \, dx \\ \end{align*}
\[ \int \frac {5 x-x^3+e^2 \left (5-x^2\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x+e^{2 e^{\log (x) \log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )} \left (-4 x \log (x)+\left (-4 e^2-4 x\right ) \log \left (e^2+x\right )\right )\right )}{25 x-10 x^2+11 x^3-2 x^4+x^5+e^{4 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x\right )+e^2 \left (25-10 x+11 x^2-2 x^3+x^4\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (10 x-2 x^2+2 x^3+e^2 \left (10-2 x+2 x^2\right )\right )} \, dx=\int \frac {5 x-x^3+e^2 \left (5-x^2\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x+e^{2 e^{\log (x) \log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )} \left (-4 x \log (x)+\left (-4 e^2-4 x\right ) \log \left (e^2+x\right )\right )\right )}{25 x-10 x^2+11 x^3-2 x^4+x^5+e^{4 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x\right )+e^2 \left (25-10 x+11 x^2-2 x^3+x^4\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (10 x-2 x^2+2 x^3+e^2 \left (10-2 x+2 x^2\right )\right )} \, dx \]
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Time = 0.12 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.84
\[\frac {x}{x^{2}-x +{\mathrm e}^{2 \,{\mathrm e}^{2 \left (x +{\mathrm e}^{2}\right )^{\ln \left (x \right )}}}+5}\]
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Time = 0.26 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.87 \[ \int \frac {5 x-x^3+e^2 \left (5-x^2\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x+e^{2 e^{\log (x) \log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )} \left (-4 x \log (x)+\left (-4 e^2-4 x\right ) \log \left (e^2+x\right )\right )\right )}{25 x-10 x^2+11 x^3-2 x^4+x^5+e^{4 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x\right )+e^2 \left (25-10 x+11 x^2-2 x^3+x^4\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (10 x-2 x^2+2 x^3+e^2 \left (10-2 x+2 x^2\right )\right )} \, dx=\frac {x}{x^{2} - x + e^{\left (2 \, e^{\left (2 \, e^{\left (\log \left (x + e^{2}\right ) \log \left (x\right )\right )}\right )}\right )} + 5} \]
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Timed out. \[ \int \frac {5 x-x^3+e^2 \left (5-x^2\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x+e^{2 e^{\log (x) \log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )} \left (-4 x \log (x)+\left (-4 e^2-4 x\right ) \log \left (e^2+x\right )\right )\right )}{25 x-10 x^2+11 x^3-2 x^4+x^5+e^{4 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x\right )+e^2 \left (25-10 x+11 x^2-2 x^3+x^4\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (10 x-2 x^2+2 x^3+e^2 \left (10-2 x+2 x^2\right )\right )} \, dx=\text {Timed out} \]
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Time = 0.45 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.87 \[ \int \frac {5 x-x^3+e^2 \left (5-x^2\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x+e^{2 e^{\log (x) \log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )} \left (-4 x \log (x)+\left (-4 e^2-4 x\right ) \log \left (e^2+x\right )\right )\right )}{25 x-10 x^2+11 x^3-2 x^4+x^5+e^{4 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x\right )+e^2 \left (25-10 x+11 x^2-2 x^3+x^4\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (10 x-2 x^2+2 x^3+e^2 \left (10-2 x+2 x^2\right )\right )} \, dx=\frac {x}{x^{2} - x + e^{\left (2 \, e^{\left (2 \, e^{\left (\log \left (x + e^{2}\right ) \log \left (x\right )\right )}\right )}\right )} + 5} \]
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Time = 27.33 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.87 \[ \int \frac {5 x-x^3+e^2 \left (5-x^2\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x+e^{2 e^{\log (x) \log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )} \left (-4 x \log (x)+\left (-4 e^2-4 x\right ) \log \left (e^2+x\right )\right )\right )}{25 x-10 x^2+11 x^3-2 x^4+x^5+e^{4 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x\right )+e^2 \left (25-10 x+11 x^2-2 x^3+x^4\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (10 x-2 x^2+2 x^3+e^2 \left (10-2 x+2 x^2\right )\right )} \, dx=\frac {x}{x^{2} - x + e^{\left (2 \, e^{\left (2 \, e^{\left (\log \left (x + e^{2}\right ) \log \left (x\right )\right )}\right )}\right )} + 5} \]
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Time = 12.43 (sec) , antiderivative size = 732, normalized size of antiderivative = 23.61 \[ \int \frac {5 x-x^3+e^2 \left (5-x^2\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x+e^{2 e^{\log (x) \log \left (e^2+x\right )}+\log (x) \log \left (e^2+x\right )} \left (-4 x \log (x)+\left (-4 e^2-4 x\right ) \log \left (e^2+x\right )\right )\right )}{25 x-10 x^2+11 x^3-2 x^4+x^5+e^{4 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (e^2+x\right )+e^2 \left (25-10 x+11 x^2-2 x^3+x^4\right )+e^{2 e^{2 e^{\log (x) \log \left (e^2+x\right )}}} \left (10 x-2 x^2+2 x^3+e^2 \left (10-2 x+2 x^2\right )\right )} \, dx=\text {Too large to display} \]
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