Integrand size = 34, antiderivative size = 20 \[ \int \frac {-5-15 x+30 x^2+14 x^3+x^4}{10-15 x+10 x^3+x^4} \, dx=x+\log \left (-2+3 x-\left (2+\frac {x}{5}\right ) x^3\right ) \]
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Time = 0.04 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.059, Rules used = {6874, 1601} \[ \int \frac {-5-15 x+30 x^2+14 x^3+x^4}{10-15 x+10 x^3+x^4} \, dx=\log \left (x^4+10 x^3-15 x+10\right )+x \]
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Rule 1601
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \left (1-\frac {15-30 x^2-4 x^3}{10-15 x+10 x^3+x^4}\right ) \, dx \\ & = x-\int \frac {15-30 x^2-4 x^3}{10-15 x+10 x^3+x^4} \, dx \\ & = x+\log \left (10-15 x+10 x^3+x^4\right ) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80 \[ \int \frac {-5-15 x+30 x^2+14 x^3+x^4}{10-15 x+10 x^3+x^4} \, dx=x+\log \left (10-15 x+10 x^3+x^4\right ) \]
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Time = 0.02 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.85
method | result | size |
default | \(x +\ln \left (x^{4}+10 x^{3}-15 x +10\right )\) | \(17\) |
norman | \(x +\ln \left (x^{4}+10 x^{3}-15 x +10\right )\) | \(17\) |
risch | \(x +\ln \left (x^{4}+10 x^{3}-15 x +10\right )\) | \(17\) |
parallelrisch | \(x +\ln \left (x^{4}+10 x^{3}-15 x +10\right )\) | \(17\) |
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none
Time = 0.26 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80 \[ \int \frac {-5-15 x+30 x^2+14 x^3+x^4}{10-15 x+10 x^3+x^4} \, dx=x + \log \left (x^{4} + 10 \, x^{3} - 15 \, x + 10\right ) \]
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Time = 0.05 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.75 \[ \int \frac {-5-15 x+30 x^2+14 x^3+x^4}{10-15 x+10 x^3+x^4} \, dx=x + \log {\left (x^{4} + 10 x^{3} - 15 x + 10 \right )} \]
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none
Time = 0.27 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80 \[ \int \frac {-5-15 x+30 x^2+14 x^3+x^4}{10-15 x+10 x^3+x^4} \, dx=x + \log \left (x^{4} + 10 \, x^{3} - 15 \, x + 10\right ) \]
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none
Time = 0.26 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.85 \[ \int \frac {-5-15 x+30 x^2+14 x^3+x^4}{10-15 x+10 x^3+x^4} \, dx=x + \log \left ({\left | x^{4} + 10 \, x^{3} - 15 \, x + 10 \right |}\right ) \]
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Time = 12.11 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80 \[ \int \frac {-5-15 x+30 x^2+14 x^3+x^4}{10-15 x+10 x^3+x^4} \, dx=x+\ln \left (x^4+10\,x^3-15\,x+10\right ) \]
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