Integrand size = 31, antiderivative size = 30 \[ \int \frac {-2-2 x+3 x^2-x^3}{4-2 x-2 x^2+x^3} \, dx=-x+\log \left (\left (2+\frac {5 e^2}{2}\right ) \left (2+x-\frac {x^2}{2-x}\right )\right ) \]
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Time = 0.02 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.67, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.065, Rules used = {2099, 266} \[ \int \frac {-2-2 x+3 x^2-x^3}{4-2 x-2 x^2+x^3} \, dx=\log \left (2-x^2\right )-x-\log (2-x) \]
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Rule 266
Rule 2099
Rubi steps \begin{align*} \text {integral}& = \int \left (-1+\frac {1}{2-x}+\frac {2 x}{-2+x^2}\right ) \, dx \\ & = -x-\log (2-x)+2 \int \frac {x}{-2+x^2} \, dx \\ & = -x-\log (2-x)+\log \left (2-x^2\right ) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.67 \[ \int \frac {-2-2 x+3 x^2-x^3}{4-2 x-2 x^2+x^3} \, dx=-x-\log (2-x)+\log \left (2-x^2\right ) \]
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Time = 0.06 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.57
method | result | size |
default | \(-x +\ln \left (x^{2}-2\right )-\ln \left (-2+x \right )\) | \(17\) |
norman | \(-x +\ln \left (x^{2}-2\right )-\ln \left (-2+x \right )\) | \(17\) |
risch | \(-x +\ln \left (x^{2}-2\right )-\ln \left (-2+x \right )\) | \(17\) |
parallelrisch | \(-x +\ln \left (x^{2}-2\right )-\ln \left (-2+x \right )\) | \(17\) |
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none
Time = 0.26 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.53 \[ \int \frac {-2-2 x+3 x^2-x^3}{4-2 x-2 x^2+x^3} \, dx=-x + \log \left (x^{2} - 2\right ) - \log \left (x - 2\right ) \]
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Time = 0.05 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.40 \[ \int \frac {-2-2 x+3 x^2-x^3}{4-2 x-2 x^2+x^3} \, dx=- x - \log {\left (x - 2 \right )} + \log {\left (x^{2} - 2 \right )} \]
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none
Time = 0.28 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.53 \[ \int \frac {-2-2 x+3 x^2-x^3}{4-2 x-2 x^2+x^3} \, dx=-x + \log \left (x^{2} - 2\right ) - \log \left (x - 2\right ) \]
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none
Time = 0.30 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.60 \[ \int \frac {-2-2 x+3 x^2-x^3}{4-2 x-2 x^2+x^3} \, dx=-x + \log \left ({\left | x^{2} - 2 \right |}\right ) - \log \left ({\left | x - 2 \right |}\right ) \]
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Time = 13.64 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.53 \[ \int \frac {-2-2 x+3 x^2-x^3}{4-2 x-2 x^2+x^3} \, dx=\ln \left (x^2-2\right )-\ln \left (x-2\right )-x \]
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