Integrand size = 180, antiderivative size = 31 \[ \int \frac {96+96 x-36 x^2+12 x^2 \log (5)+e^x \left (-96-96 x+30 x^2-6 x^3-3 x^4-12 x^2 \log (5)\right )+e^{2 x} \left (24+24 x-6 x^2+3 x^2 \log (5)\right )}{64+48 x^2+9 x^4+\left (32 x+12 x^3\right ) \log (5)+4 x^2 \log ^2(5)+e^x \left (-64-40 x^2-6 x^4+\left (-32 x-10 x^3\right ) \log (5)-4 x^2 \log ^2(5)\right )+e^{2 x} \left (16+8 x^2+x^4+\left (8 x+2 x^3\right ) \log (5)+x^2 \log ^2(5)\right )} \, dx=9+\frac {3 x (2+x)}{4+x^2+x \left (\frac {x}{2-e^x}+\log (5)\right )} \]
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\[ \int \frac {96+96 x-36 x^2+12 x^2 \log (5)+e^x \left (-96-96 x+30 x^2-6 x^3-3 x^4-12 x^2 \log (5)\right )+e^{2 x} \left (24+24 x-6 x^2+3 x^2 \log (5)\right )}{64+48 x^2+9 x^4+\left (32 x+12 x^3\right ) \log (5)+4 x^2 \log ^2(5)+e^x \left (-64-40 x^2-6 x^4+\left (-32 x-10 x^3\right ) \log (5)-4 x^2 \log ^2(5)\right )+e^{2 x} \left (16+8 x^2+x^4+\left (8 x+2 x^3\right ) \log (5)+x^2 \log ^2(5)\right )} \, dx=\int \frac {96+96 x-36 x^2+12 x^2 \log (5)+e^x \left (-96-96 x+30 x^2-6 x^3-3 x^4-12 x^2 \log (5)\right )+e^{2 x} \left (24+24 x-6 x^2+3 x^2 \log (5)\right )}{64+48 x^2+9 x^4+\left (32 x+12 x^3\right ) \log (5)+4 x^2 \log ^2(5)+e^x \left (-64-40 x^2-6 x^4+\left (-32 x-10 x^3\right ) \log (5)-4 x^2 \log ^2(5)\right )+e^{2 x} \left (16+8 x^2+x^4+\left (8 x+2 x^3\right ) \log (5)+x^2 \log ^2(5)\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {96+96 x+x^2 (-36+12 \log (5))+e^x \left (-96-96 x+30 x^2-6 x^3-3 x^4-12 x^2 \log (5)\right )+e^{2 x} \left (24+24 x-6 x^2+3 x^2 \log (5)\right )}{64+48 x^2+9 x^4+\left (32 x+12 x^3\right ) \log (5)+4 x^2 \log ^2(5)+e^x \left (-64-40 x^2-6 x^4+\left (-32 x-10 x^3\right ) \log (5)-4 x^2 \log ^2(5)\right )+e^{2 x} \left (16+8 x^2+x^4+\left (8 x+2 x^3\right ) \log (5)+x^2 \log ^2(5)\right )} \, dx \\ & = \int \frac {96+96 x+x^2 (-36+12 \log (5))+e^x \left (-96-96 x+30 x^2-6 x^3-3 x^4-12 x^2 \log (5)\right )+e^{2 x} \left (24+24 x-6 x^2+3 x^2 \log (5)\right )}{64+9 x^4+\left (32 x+12 x^3\right ) \log (5)+x^2 \left (48+4 \log ^2(5)\right )+e^x \left (-64-40 x^2-6 x^4+\left (-32 x-10 x^3\right ) \log (5)-4 x^2 \log ^2(5)\right )+e^{2 x} \left (16+8 x^2+x^4+\left (8 x+2 x^3\right ) \log (5)+x^2 \log ^2(5)\right )} \, dx \\ & = \int \frac {3 \left (4 \left (8+8 x+x^2 (-3+\log (5))\right )+e^{2 x} \left (8+8 x+x^2 (-2+\log (5))\right )-e^x \left (32+32 x+2 x^3+x^4+2 x^2 (-5+\log (25))\right )\right )}{\left (8+3 x^2-e^x \left (4+x^2+x \log (5)\right )+x \log (25)\right )^2} \, dx \\ & = 3 \int \frac {4 \left (8+8 x+x^2 (-3+\log (5))\right )+e^{2 x} \left (8+8 x+x^2 (-2+\log (5))\right )-e^x \left (32+32 x+2 x^3+x^4+2 x^2 (-5+\log (25))\right )}{\left (8+3 x^2-e^x \left (4+x^2+x \log (5)\right )+x \log (25)\right )^2} \, dx \\ & = 3 \int \left (\frac {8+8 x-x^2 (2-\log (5))}{\left (4+x^2+x \log (5)\right )^2}+\frac {x^2 \left (-24+6 x^2+x^4+x^3 (2+\log (5))-x (8+\log (25))\right )}{\left (4+x^2+x \log (5)\right )^2 \left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )}+\frac {x^2 \left (-64 x-3 x^6-6 x^5 \left (1+\frac {5 \log (5)}{6}\right )+32 \log ^2(5) \left (1-\frac {\log ^2(25)}{4 \log ^2(5)}\right )-20 x^4 \left (1+\frac {1}{20} \log (5) (9+\log (25))\right )-32 x^3 \left (1+\frac {1}{32} \left (-8 \log ^2(5)+7 \log (25)+6 \log (5) \log (25)\right )\right )-16 x^2 \left (1+\frac {1}{16} \left (12 \log ^2(5)-4 \log ^3(5)+32 \log (25)+\log (5) \left (-32-6 \log (25)+\log ^2(25)\right )\right )\right )\right )}{\left (4+x^2+x \log (5)\right )^2 \left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )^2}\right ) \, dx \\ & = 3 \int \frac {8+8 x-x^2 (2-\log (5))}{\left (4+x^2+x \log (5)\right )^2} \, dx+3 \int \frac {x^2 \left (-24+6 x^2+x^4+x^3 (2+\log (5))-x (8+\log (25))\right )}{\left (4+x^2+x \log (5)\right )^2 \left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )} \, dx+3 \int \frac {x^2 \left (-64 x-3 x^6-6 x^5 \left (1+\frac {5 \log (5)}{6}\right )+32 \log ^2(5) \left (1-\frac {\log ^2(25)}{4 \log ^2(5)}\right )-20 x^4 \left (1+\frac {1}{20} \log (5) (9+\log (25))\right )-32 x^3 \left (1+\frac {1}{32} \left (-8 \log ^2(5)+7 \log (25)+6 \log (5) \log (25)\right )\right )-16 x^2 \left (1+\frac {1}{16} \left (12 \log ^2(5)-4 \log ^3(5)+32 \log (25)+\log (5) \left (-32-6 \log (25)+\log ^2(25)\right )\right )\right )\right )}{\left (4+x^2+x \log (5)\right )^2 \left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )^2} \, dx \\ & = \frac {3 \left (x (2-\log (5)) (4-\log (5)) (4+\log (5))-4 \left (16-\log ^2(5)\right )\right )}{\left (4+x^2+x \log (5)\right ) \left (16-\log ^2(5)\right )}+3 \int \left (-\frac {x^2}{-8+4 e^x-3 x^2+e^x x^2+e^x x \log (5)-x \log (25)}+\frac {x (-2+\log (5))}{-8+4 e^x-3 x^2+e^x x^2+e^x x \log (5)-x \log (25)}+\frac {2 \left (1-\frac {\log ^2(5)}{2}+\log (25)\right )}{-8+4 e^x-3 x^2+e^x x^2+e^x x \log (5)-x \log (25)}+\frac {-24-2 \log ^2(5)-2 \log ^3(5)-x \left (24-6 \log ^2(5)+\log ^3(5)-\log (25)\right )+\log (5) (40+\log (25))}{\left (4+x^2+x \log (5)\right ) \left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )}+\frac {4 \left (32-2 \log ^2(5)+2 \log ^3(5)-\log (5) (24+\log (25))\right )+x \left (40 \log (5)-2 \log ^3(5)+2 \log ^4(5)+4 (16+\log (25))-\log ^2(5) (32+\log (25))\right )}{\left (4+x^2+x \log (5)\right )^2 \left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )}\right ) \, dx+3 \int \left (-\frac {3 x^4}{\left (-8+4 e^x-3 x^2+e^x x^2+e^x x \log (5)-x \log (25)\right )^2}+\frac {x^3 (-6+\log (5))}{\left (-8+4 e^x-3 x^2+e^x x^2+e^x x \log (5)-x \log (25)\right )^2}+\frac {x^2 \left (4+\log ^2(5)+\log (5) (3-\log (25))\right )}{\left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )^2}+\frac {x \left (16-3 \log ^3(5)+\log (5) (8-6 \log (25))-7 \log (25)+2 \log ^2(5) (4+\log (25))\right )}{\left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )^2}+\frac {24 \log (5) \left (1-2 \log (5) \left (1+\frac {5}{16} \log (5) \left (1-\frac {\log (5)}{3}+\frac {\left (32-28 \log (5)-10 \log ^2(5)+3 \log ^3(5)\right ) \log (25)}{15 \log ^3(5)}\right )\right )\right )}{\left (-8+4 e^x-3 x^2+e^x x^2+e^x x \log (5)-x \log (25)\right )^2}+\frac {-x \left (2 \log ^7(5)+8 \log ^3(5) (54-13 \log (25))-16 (8-7 \log (25))-6 \log ^5(5) (10-\log (25))-\log ^6(5) (7+\log (25))-\log ^2(5) \left (560+180 \log (25)-8 \log ^2(25)\right )+\log ^4(5) \left (152+29 \log (25)-\log ^2(25)\right )-8 \log (5) \left (48-44 \log (25)+\log ^2(25)\right )\right )-4 \left (2 \log ^6(5)+\log ^2(5) (256-80 \log (25))-\log ^4(5) (52-6 \log (25))-\log ^5(5) (7+\log (25))-4 \log (5) \left (44+24 \log (25)-\log ^2(25)\right )+\log ^3(5) \left (124+25 \log (25)-\log ^2(25)\right )-8 \left (8-16 \log (25)+\log ^2(25)\right )\right )}{\left (4+x^2+x \log (5)\right )^2 \left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )^2}+\frac {2 \log ^6(5)-6 \log ^4(5) (12-\log (25))-\log ^5(5) (7+\log (25))-8 \log (5) \left (34+26 \log (25)-\log ^2(25)\right )+\log ^3(5) \left (184+37 \log (25)-\log ^2(25)\right )-8 \left (8-32 \log (25)+\log ^2(25)\right )-x \left (96+7 \log ^5(5)-2 \log ^3(5) (52-9 \log (25))+112 \log (5) (1-\log (25))-56 \log (25)-\log ^4(5) (22+4 \log (25))+\log ^2(5) \left (152+57 \log (25)-2 \log ^2(25)\right )\right )+64 \log ^2(5) (7-\log (625))}{\left (4+x^2+x \log (5)\right ) \left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )^2}\right ) \, dx+\frac {3 \int 0 \, dx}{16-\log ^2(5)} \\ & = \frac {3 \left (x (2-\log (5)) (4-\log (5)) (4+\log (5))-4 \left (16-\log ^2(5)\right )\right )}{\left (4+x^2+x \log (5)\right ) \left (16-\log ^2(5)\right )}-3 \int \frac {x^2}{-8+4 e^x-3 x^2+e^x x^2+e^x x \log (5)-x \log (25)} \, dx+3 \int \frac {-24-2 \log ^2(5)-2 \log ^3(5)-x \left (24-6 \log ^2(5)+\log ^3(5)-\log (25)\right )+\log (5) (40+\log (25))}{\left (4+x^2+x \log (5)\right ) \left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )} \, dx+3 \int \frac {4 \left (32-2 \log ^2(5)+2 \log ^3(5)-\log (5) (24+\log (25))\right )+x \left (40 \log (5)-2 \log ^3(5)+2 \log ^4(5)+4 (16+\log (25))-\log ^2(5) (32+\log (25))\right )}{\left (4+x^2+x \log (5)\right )^2 \left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )} \, dx+3 \int \frac {-x \left (2 \log ^7(5)+8 \log ^3(5) (54-13 \log (25))-16 (8-7 \log (25))-6 \log ^5(5) (10-\log (25))-\log ^6(5) (7+\log (25))-\log ^2(5) \left (560+180 \log (25)-8 \log ^2(25)\right )+\log ^4(5) \left (152+29 \log (25)-\log ^2(25)\right )-8 \log (5) \left (48-44 \log (25)+\log ^2(25)\right )\right )-4 \left (2 \log ^6(5)+\log ^2(5) (256-80 \log (25))-\log ^4(5) (52-6 \log (25))-\log ^5(5) (7+\log (25))-4 \log (5) \left (44+24 \log (25)-\log ^2(25)\right )+\log ^3(5) \left (124+25 \log (25)-\log ^2(25)\right )-8 \left (8-16 \log (25)+\log ^2(25)\right )\right )}{\left (4+x^2+x \log (5)\right )^2 \left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )^2} \, dx+3 \int \frac {2 \log ^6(5)-6 \log ^4(5) (12-\log (25))-\log ^5(5) (7+\log (25))-8 \log (5) \left (34+26 \log (25)-\log ^2(25)\right )+\log ^3(5) \left (184+37 \log (25)-\log ^2(25)\right )-8 \left (8-32 \log (25)+\log ^2(25)\right )-x \left (96+7 \log ^5(5)-2 \log ^3(5) (52-9 \log (25))+112 \log (5) (1-\log (25))-56 \log (25)-\log ^4(5) (22+4 \log (25))+\log ^2(5) \left (152+57 \log (25)-2 \log ^2(25)\right )\right )+64 \log ^2(5) (7-\log (625))}{\left (4+x^2+x \log (5)\right ) \left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )^2} \, dx-9 \int \frac {x^4}{\left (-8+4 e^x-3 x^2+e^x x^2+e^x x \log (5)-x \log (25)\right )^2} \, dx-(3 (6-\log (5))) \int \frac {x^3}{\left (-8+4 e^x-3 x^2+e^x x^2+e^x x \log (5)-x \log (25)\right )^2} \, dx+(3 (-2+\log (5))) \int \frac {x}{-8+4 e^x-3 x^2+e^x x^2+e^x x \log (5)-x \log (25)} \, dx+\left (3 \left (4+\log ^2(5)+\log (5) (3-\log (25))\right )\right ) \int \frac {x^2}{\left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )^2} \, dx+\left (3 \left (16-3 \log ^3(5)+\log (5) (8-6 \log (25))-7 \log (25)+2 \log ^2(5) (4+\log (25))\right )\right ) \int \frac {x}{\left (8-4 e^x+3 x^2-e^x x^2-e^x x \log (5)+x \log (25)\right )^2} \, dx+\left (3 \left (5 \log ^4(5)-2 \log ^2(5) (24-5 \log (25))-32 \log (25)-3 \log ^3(5) (5+\log (25))+4 \log (5) (6+7 \log (25))\right )\right ) \int \frac {1}{\left (-8+4 e^x-3 x^2+e^x x^2+e^x x \log (5)-x \log (25)\right )^2} \, dx+\left (3 \left (2-\log ^2(5)+\log (625)\right )\right ) \int \frac {1}{-8+4 e^x-3 x^2+e^x x^2+e^x x \log (5)-x \log (25)} \, dx \\ & = \text {Too large to display} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(207\) vs. \(2(31)=62\).
Time = 0.37 (sec) , antiderivative size = 207, normalized size of antiderivative = 6.68 \[ \int \frac {96+96 x-36 x^2+12 x^2 \log (5)+e^x \left (-96-96 x+30 x^2-6 x^3-3 x^4-12 x^2 \log (5)\right )+e^{2 x} \left (24+24 x-6 x^2+3 x^2 \log (5)\right )}{64+48 x^2+9 x^4+\left (32 x+12 x^3\right ) \log (5)+4 x^2 \log ^2(5)+e^x \left (-64-40 x^2-6 x^4+\left (-32 x-10 x^3\right ) \log (5)-4 x^2 \log ^2(5)\right )+e^{2 x} \left (16+8 x^2+x^4+\left (8 x+2 x^3\right ) \log (5)+x^2 \log ^2(5)\right )} \, dx=\frac {3 \left (256+3 x^6+96 x (-2+\log (25))+x^5 (-12+9 \log (5)+\log (25))+4 x^2 \left (56+4 \log (5) (-3+\log (25))-5 \log (25)+\log ^2(25)\right )+x^4 (44-4 \log (25)+\log (5) (-13+6 \log (25)))+x^3 \left (-88-4 \log ^2(5)+20 \log (25)+\log (5) \left (60-3 \log (25)+\log ^2(25)\right )\right )-e^x (4+x (-2+\log (5))) \left (32+3 x^4+x^2 (20+\log (5) (-1+\log (25)))+x^3 \log (3125)+2 x (-4+\log (390625))\right )\right )}{\left (-8-3 x^2+e^x \left (4+x^2+x \log (5)\right )-x \log (25)\right ) \left (32+3 x^4+x^2 (20+\log (5) (-1+\log (25)))+x^3 \log (3125)+2 x (-4+\log (390625))\right )} \]
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Time = 0.43 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.97
method | result | size |
norman | \(\frac {-12 \,{\mathrm e}^{x}+3 x^{2}+\left (-12+6 \ln \left (5\right )\right ) x +\left (-3 \ln \left (5\right )+6\right ) x \,{\mathrm e}^{x}+24}{x \,{\mathrm e}^{x} \ln \left (5\right )+{\mathrm e}^{x} x^{2}-2 x \ln \left (5\right )-3 x^{2}+4 \,{\mathrm e}^{x}-8}\) | \(61\) |
parallelrisch | \(\frac {24-3 x \,{\mathrm e}^{x} \ln \left (5\right )+6 x \ln \left (5\right )+3 x^{2}+6 \,{\mathrm e}^{x} x -12 x -12 \,{\mathrm e}^{x}}{x \,{\mathrm e}^{x} \ln \left (5\right )+{\mathrm e}^{x} x^{2}-2 x \ln \left (5\right )-3 x^{2}+4 \,{\mathrm e}^{x}-8}\) | \(63\) |
risch | \(\frac {\left (-3 \ln \left (5\right )+6\right ) x -12}{x \ln \left (5\right )+x^{2}+4}+\frac {3 \left (2+x \right ) x^{3}}{\left (x \ln \left (5\right )+x^{2}+4\right ) \left (x \,{\mathrm e}^{x} \ln \left (5\right )+{\mathrm e}^{x} x^{2}-2 x \ln \left (5\right )-3 x^{2}+4 \,{\mathrm e}^{x}-8\right )}\) | \(73\) |
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Time = 0.26 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.77 \[ \int \frac {96+96 x-36 x^2+12 x^2 \log (5)+e^x \left (-96-96 x+30 x^2-6 x^3-3 x^4-12 x^2 \log (5)\right )+e^{2 x} \left (24+24 x-6 x^2+3 x^2 \log (5)\right )}{64+48 x^2+9 x^4+\left (32 x+12 x^3\right ) \log (5)+4 x^2 \log ^2(5)+e^x \left (-64-40 x^2-6 x^4+\left (-32 x-10 x^3\right ) \log (5)-4 x^2 \log ^2(5)\right )+e^{2 x} \left (16+8 x^2+x^4+\left (8 x+2 x^3\right ) \log (5)+x^2 \log ^2(5)\right )} \, dx=-\frac {3 \, {\left (x^{2} - {\left (x \log \left (5\right ) - 2 \, x + 4\right )} e^{x} + 2 \, x \log \left (5\right ) - 4 \, x + 8\right )}}{3 \, x^{2} - {\left (x^{2} + x \log \left (5\right ) + 4\right )} e^{x} + 2 \, x \log \left (5\right ) + 8} \]
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Leaf count of result is larger than twice the leaf count of optimal. 104 vs. \(2 (24) = 48\).
Time = 0.58 (sec) , antiderivative size = 104, normalized size of antiderivative = 3.35 \[ \int \frac {96+96 x-36 x^2+12 x^2 \log (5)+e^x \left (-96-96 x+30 x^2-6 x^3-3 x^4-12 x^2 \log (5)\right )+e^{2 x} \left (24+24 x-6 x^2+3 x^2 \log (5)\right )}{64+48 x^2+9 x^4+\left (32 x+12 x^3\right ) \log (5)+4 x^2 \log ^2(5)+e^x \left (-64-40 x^2-6 x^4+\left (-32 x-10 x^3\right ) \log (5)-4 x^2 \log ^2(5)\right )+e^{2 x} \left (16+8 x^2+x^4+\left (8 x+2 x^3\right ) \log (5)+x^2 \log ^2(5)\right )} \, dx=\frac {3 x^{4} + 6 x^{3}}{- 3 x^{4} - 5 x^{3} \log {\left (5 \right )} - 20 x^{2} - 2 x^{2} \log {\left (5 \right )}^{2} - 16 x \log {\left (5 \right )} + \left (x^{4} + 2 x^{3} \log {\left (5 \right )} + x^{2} \log {\left (5 \right )}^{2} + 8 x^{2} + 8 x \log {\left (5 \right )} + 16\right ) e^{x} - 32} - \frac {x \left (-6 + 3 \log {\left (5 \right )}\right ) + 12}{x^{2} + x \log {\left (5 \right )} + 4} \]
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Time = 0.37 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.71 \[ \int \frac {96+96 x-36 x^2+12 x^2 \log (5)+e^x \left (-96-96 x+30 x^2-6 x^3-3 x^4-12 x^2 \log (5)\right )+e^{2 x} \left (24+24 x-6 x^2+3 x^2 \log (5)\right )}{64+48 x^2+9 x^4+\left (32 x+12 x^3\right ) \log (5)+4 x^2 \log ^2(5)+e^x \left (-64-40 x^2-6 x^4+\left (-32 x-10 x^3\right ) \log (5)-4 x^2 \log ^2(5)\right )+e^{2 x} \left (16+8 x^2+x^4+\left (8 x+2 x^3\right ) \log (5)+x^2 \log ^2(5)\right )} \, dx=-\frac {3 \, {\left (x^{2} + 2 \, x {\left (\log \left (5\right ) - 2\right )} - {\left (x {\left (\log \left (5\right ) - 2\right )} + 4\right )} e^{x} + 8\right )}}{3 \, x^{2} - {\left (x^{2} + x \log \left (5\right ) + 4\right )} e^{x} + 2 \, x \log \left (5\right ) + 8} \]
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Time = 0.38 (sec) , antiderivative size = 62, normalized size of antiderivative = 2.00 \[ \int \frac {96+96 x-36 x^2+12 x^2 \log (5)+e^x \left (-96-96 x+30 x^2-6 x^3-3 x^4-12 x^2 \log (5)\right )+e^{2 x} \left (24+24 x-6 x^2+3 x^2 \log (5)\right )}{64+48 x^2+9 x^4+\left (32 x+12 x^3\right ) \log (5)+4 x^2 \log ^2(5)+e^x \left (-64-40 x^2-6 x^4+\left (-32 x-10 x^3\right ) \log (5)-4 x^2 \log ^2(5)\right )+e^{2 x} \left (16+8 x^2+x^4+\left (8 x+2 x^3\right ) \log (5)+x^2 \log ^2(5)\right )} \, dx=-\frac {3 \, {\left (x e^{x} \log \left (5\right ) - x^{2} - 2 \, x e^{x} - 2 \, x \log \left (5\right ) + 4 \, x + 4 \, e^{x} - 8\right )}}{x^{2} e^{x} + x e^{x} \log \left (5\right ) - 3 \, x^{2} - 2 \, x \log \left (5\right ) + 4 \, e^{x} - 8} \]
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Timed out. \[ \int \frac {96+96 x-36 x^2+12 x^2 \log (5)+e^x \left (-96-96 x+30 x^2-6 x^3-3 x^4-12 x^2 \log (5)\right )+e^{2 x} \left (24+24 x-6 x^2+3 x^2 \log (5)\right )}{64+48 x^2+9 x^4+\left (32 x+12 x^3\right ) \log (5)+4 x^2 \log ^2(5)+e^x \left (-64-40 x^2-6 x^4+\left (-32 x-10 x^3\right ) \log (5)-4 x^2 \log ^2(5)\right )+e^{2 x} \left (16+8 x^2+x^4+\left (8 x+2 x^3\right ) \log (5)+x^2 \log ^2(5)\right )} \, dx=\int \frac {96\,x+12\,x^2\,\ln \left (5\right )+{\mathrm {e}}^{2\,x}\,\left (24\,x+3\,x^2\,\ln \left (5\right )-6\,x^2+24\right )-{\mathrm {e}}^x\,\left (96\,x+12\,x^2\,\ln \left (5\right )-30\,x^2+6\,x^3+3\,x^4+96\right )-36\,x^2+96}{4\,x^2\,{\ln \left (5\right )}^2+\ln \left (5\right )\,\left (12\,x^3+32\,x\right )+{\mathrm {e}}^{2\,x}\,\left (x^2\,{\ln \left (5\right )}^2+\ln \left (5\right )\,\left (2\,x^3+8\,x\right )+8\,x^2+x^4+16\right )-{\mathrm {e}}^x\,\left (4\,x^2\,{\ln \left (5\right )}^2+\ln \left (5\right )\,\left (10\,x^3+32\,x\right )+40\,x^2+6\,x^4+64\right )+48\,x^2+9\,x^4+64} \,d x \]
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