Integrand size = 21, antiderivative size = 21 \[ \int \left (2+e^{\frac {1}{2} \left (3+e^2\right )+x} (-2-2 x)\right ) \, dx=-2 \left (-x+e^{\frac {1}{2} \left (3+e^2\right )+x} x\right ) \]
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Time = 0.02 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.76, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {2207, 2225} \[ \int \left (2+e^{\frac {1}{2} \left (3+e^2\right )+x} (-2-2 x)\right ) \, dx=2 x+2 e^{x+\frac {1}{2} \left (3+e^2\right )}-2 e^{x+\frac {1}{2} \left (3+e^2\right )} (x+1) \]
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Rule 2207
Rule 2225
Rubi steps \begin{align*} \text {integral}& = 2 x+\int e^{\frac {1}{2} \left (3+e^2\right )+x} (-2-2 x) \, dx \\ & = 2 x-2 e^{\frac {1}{2} \left (3+e^2\right )+x} (1+x)+2 \int e^{\frac {1}{2} \left (3+e^2\right )+x} \, dx \\ & = 2 e^{\frac {1}{2} \left (3+e^2\right )+x}+2 x-2 e^{\frac {1}{2} \left (3+e^2\right )+x} (1+x) \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.00 \[ \int \left (2+e^{\frac {1}{2} \left (3+e^2\right )+x} (-2-2 x)\right ) \, dx=2 x-2 e^{\frac {3}{2}+\frac {e^2}{2}+x} x \]
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Time = 0.11 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.76
method | result | size |
risch | \(-2 x \,{\mathrm e}^{\frac {{\mathrm e}^{2}}{2}+\frac {3}{2}+x}+2 x\) | \(16\) |
norman | \(-2 \,{\mathrm e}^{{\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x} x +2 x\) | \(22\) |
parallelrisch | \(-2 \,{\mathrm e}^{{\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x} x +2 x\) | \(22\) |
default | \(2 x -2 \,{\mathrm e}^{{\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x} \left ({\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x \right )+3 \,{\mathrm e}^{{\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x}+{\mathrm e}^{{\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x} {\mathrm e}^{2}\) | \(67\) |
parts | \(2 x -2 \,{\mathrm e}^{{\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x} \left ({\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x \right )+3 \,{\mathrm e}^{{\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x}+{\mathrm e}^{{\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x} {\mathrm e}^{2}\) | \(67\) |
derivativedivides | \(2 \,{\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+2 x -2 \,{\mathrm e}^{{\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x} \left ({\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x \right )+3 \,{\mathrm e}^{{\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x}+{\mathrm e}^{{\mathrm e}^{\ln \left ({\mathrm e}^{2}+3\right )-\ln \left (2\right )}+x} {\mathrm e}^{2}\) | \(80\) |
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Time = 0.26 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.71 \[ \int \left (2+e^{\frac {1}{2} \left (3+e^2\right )+x} (-2-2 x)\right ) \, dx=-2 \, x e^{\left (x + \frac {1}{2} \, e^{2} + \frac {3}{2}\right )} + 2 \, x \]
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Time = 0.05 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.81 \[ \int \left (2+e^{\frac {1}{2} \left (3+e^2\right )+x} (-2-2 x)\right ) \, dx=- 2 x e^{x + \frac {3}{2} + \frac {e^{2}}{2}} + 2 x \]
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Time = 0.21 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.76 \[ \int \left (2+e^{\frac {1}{2} \left (3+e^2\right )+x} (-2-2 x)\right ) \, dx=-2 \, {\left (x e^{\left (\frac {1}{2} \, e^{2} + \frac {3}{2}\right )} - e^{\left (\frac {1}{2} \, e^{2} + \frac {3}{2}\right )}\right )} e^{x} + 2 \, x - 2 \, e^{\left (x + \frac {1}{2} \, e^{2} + \frac {3}{2}\right )} \]
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Time = 0.27 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.00 \[ \int \left (2+e^{\frac {1}{2} \left (3+e^2\right )+x} (-2-2 x)\right ) \, dx=-2 \, x e^{\left (x + e^{\left (-\log \left (2\right ) + \log \left (e^{2} + 3\right )\right )}\right )} + 2 \, x \]
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Time = 0.08 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.71 \[ \int \left (2+e^{\frac {1}{2} \left (3+e^2\right )+x} (-2-2 x)\right ) \, dx=-2\,x\,\left ({\mathrm {e}}^{\frac {{\mathrm {e}}^2}{2}}\,{\mathrm {e}}^{3/2}\,{\mathrm {e}}^x-1\right ) \]
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