Integrand size = 243, antiderivative size = 26 \[ \int \frac {\left (8 e^{10} x+4 x^2+14 x^3+16 x^4+8 x^5+e^5 \left (2 x+16 x^2+16 x^3\right )\right ) \log \left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )+\left (-2 x^2-10 x^3-14 x^4-4 x^5+2 x^6+e^{10} \left (-8 x+2 x^2\right )+e^5 \left (-2 x-16 x^2-12 x^3+4 x^4\right )\right ) \log ^2\left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )}{e^{10} (-4+x)-x-5 x^2-7 x^3-2 x^4+x^5+e^5 \left (-1-8 x-6 x^2+2 x^3\right )} \, dx=x^2 \log ^2\left (\frac {4-x+\frac {1}{e^5+x+x^2}}{x}\right ) \]
[Out]
Time = 134.73 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.81, number of steps used = 103, number of rules used = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.107, Rules used = {6874, 2608, 2603, 6860, 648, 632, 210, 642, 2125, 2106, 2104, 814, 2604, 2465, 2441, 2352, 2437, 2338, 2440, 2438, 2092, 2090, 719, 31, 1642, 2605} \[ \int \frac {\left (8 e^{10} x+4 x^2+14 x^3+16 x^4+8 x^5+e^5 \left (2 x+16 x^2+16 x^3\right )\right ) \log \left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )+\left (-2 x^2-10 x^3-14 x^4-4 x^5+2 x^6+e^{10} \left (-8 x+2 x^2\right )+e^5 \left (-2 x-16 x^2-12 x^3+4 x^4\right )\right ) \log ^2\left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )}{e^{10} (-4+x)-x-5 x^2-7 x^3-2 x^4+x^5+e^5 \left (-1-8 x-6 x^2+2 x^3\right )} \, dx=x^2 \log ^2\left (\frac {-x^3+3 x^2+\left (4-e^5\right ) x+4 e^5+1}{x \left (x^2+x+e^5\right )}\right ) \]
[In]
[Out]
Rule 31
Rule 210
Rule 632
Rule 642
Rule 648
Rule 719
Rule 814
Rule 1642
Rule 2090
Rule 2092
Rule 2104
Rule 2106
Rule 2125
Rule 2338
Rule 2352
Rule 2437
Rule 2438
Rule 2440
Rule 2441
Rule 2465
Rule 2603
Rule 2604
Rule 2605
Rule 2608
Rule 6860
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {2 x \left (-e^5 \left (1+4 e^5\right )-2 \left (1+4 e^5\right ) x-\left (7+8 e^5\right ) x^2-8 x^3-4 x^4\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{\left (e^5+x+x^2\right ) \left (1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3\right )}+2 x \log ^2\left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )\right ) \, dx \\ & = 2 \int \frac {x \left (-e^5 \left (1+4 e^5\right )-2 \left (1+4 e^5\right ) x-\left (7+8 e^5\right ) x^2-8 x^3-4 x^4\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{\left (e^5+x+x^2\right ) \left (1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3\right )} \, dx+2 \int x \log ^2\left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right ) \, dx \\ & = x^2 \log ^2\left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )-2 \int \frac {x \left (-e^5 \left (1+4 e^5\right )-2 \left (1+4 e^5\right ) x-\left (7+8 e^5\right ) x^2-8 x^3-4 x^4\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{\left (e^5+x+x^2\right ) \left (1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3\right )} \, dx+2 \int \left (4 \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )+\frac {\left (-e^5-\left (1-2 e^5\right ) x\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{e^5+x+x^2}+\frac {\left (-3 \left (1+4 e^5\right )-3 \left (5+3 e^5\right ) x-\left (17-2 e^5\right ) x^2\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}\right ) \, dx \\ & = x^2 \log ^2\left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )+2 \int \frac {\left (-e^5-\left (1-2 e^5\right ) x\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{e^5+x+x^2} \, dx+2 \int \frac {\left (-3 \left (1+4 e^5\right )-3 \left (5+3 e^5\right ) x-\left (17-2 e^5\right ) x^2\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx-2 \int \left (4 \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )+\frac {\left (-e^5-\left (1-2 e^5\right ) x\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{e^5+x+x^2}+\frac {\left (-3 \left (1+4 e^5\right )-3 \left (5+3 e^5\right ) x-\left (17-2 e^5\right ) x^2\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}\right ) \, dx+8 \int \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right ) \, dx \\ & = 8 x \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )+x^2 \log ^2\left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )-2 \int \frac {\left (-e^5-\left (1-2 e^5\right ) x\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{e^5+x+x^2} \, dx-2 \int \frac {\left (-3 \left (1+4 e^5\right )-3 \left (5+3 e^5\right ) x-\left (17-2 e^5\right ) x^2\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx+2 \int \left (\frac {\left (-1+2 e^5+i \sqrt {-1+4 e^5}\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1-i \sqrt {-1+4 e^5}+2 x}+\frac {\left (-1+2 e^5-i \sqrt {-1+4 e^5}\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+i \sqrt {-1+4 e^5}+2 x}\right ) \, dx+2 \int \left (\frac {3 \left (-1-4 e^5\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}+\frac {3 \left (-5-3 e^5\right ) x \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}+\frac {\left (-17+2 e^5\right ) x^2 \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}\right ) \, dx-8 \int \frac {-e^5 \left (1+4 e^5\right )-2 \left (1+4 e^5\right ) x-\left (7+8 e^5\right ) x^2-8 x^3-4 x^4}{\left (e^5+x+x^2\right ) \left (1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3\right )} \, dx-8 \int \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right ) \, dx \\ & = x^2 \log ^2\left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )-2 \int \left (\frac {\left (-1+2 e^5+i \sqrt {-1+4 e^5}\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1-i \sqrt {-1+4 e^5}+2 x}+\frac {\left (-1+2 e^5-i \sqrt {-1+4 e^5}\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+i \sqrt {-1+4 e^5}+2 x}\right ) \, dx-2 \int \left (\frac {3 \left (-1-4 e^5\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}+\frac {3 \left (-5-3 e^5\right ) x \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}+\frac {\left (-17+2 e^5\right ) x^2 \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}\right ) \, dx+8 \int \frac {-e^5 \left (1+4 e^5\right )-2 \left (1+4 e^5\right ) x-\left (7+8 e^5\right ) x^2-8 x^3-4 x^4}{\left (e^5+x+x^2\right ) \left (1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3\right )} \, dx-8 \int \left (\frac {2 e^5+x}{e^5+x+x^2}+\frac {-3 \left (1+4 e^5\right )-2 \left (4-e^5\right ) x-3 x^2}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}\right ) \, dx-\left (2 \left (17-2 e^5\right )\right ) \int \frac {x^2 \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx-\left (6 \left (5+3 e^5\right )\right ) \int \frac {x \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx-\left (6 \left (1+4 e^5\right )\right ) \int \frac {\log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx-\left (2 \left (1-2 e^5-i \sqrt {-1+4 e^5}\right )\right ) \int \frac {\log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1-i \sqrt {-1+4 e^5}+2 x} \, dx-\left (2 \left (1-2 e^5+i \sqrt {-1+4 e^5}\right )\right ) \int \frac {\log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+i \sqrt {-1+4 e^5}+2 x} \, dx \\ & = -\left (\left (1-2 e^5-i \sqrt {-1+4 e^5}\right ) \log \left (1-i \sqrt {-1+4 e^5}+2 x\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )\right )-\left (1-2 e^5+i \sqrt {-1+4 e^5}\right ) \log \left (1+i \sqrt {-1+4 e^5}+2 x\right ) \log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )+x^2 \log ^2\left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )-8 \int \frac {2 e^5+x}{e^5+x+x^2} \, dx-8 \int \frac {-3 \left (1+4 e^5\right )-2 \left (4-e^5\right ) x-3 x^2}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx+8 \int \left (\frac {2 e^5+x}{e^5+x+x^2}+\frac {-3 \left (1+4 e^5\right )-2 \left (4-e^5\right ) x-3 x^2}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}\right ) \, dx+\left (2 \left (1-2 e^5-i \sqrt {-1+4 e^5}\right )\right ) \int \frac {\log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1-i \sqrt {-1+4 e^5}+2 x} \, dx-\left (-1+2 e^5-i \sqrt {-1+4 e^5}\right ) \int \frac {x \left (e^5+x+x^2\right ) \left (\frac {4-e^5+6 x-3 x^2}{x \left (e^5+x+x^2\right )}-\frac {(1+2 x) \left (1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3\right )}{x \left (e^5+x+x^2\right )^2}-\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x^2 \left (e^5+x+x^2\right )}\right ) \log \left (1+i \sqrt {-1+4 e^5}+2 x\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx+\left (2 \left (1-2 e^5+i \sqrt {-1+4 e^5}\right )\right ) \int \frac {\log \left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )}{1+i \sqrt {-1+4 e^5}+2 x} \, dx-\left (-1+2 e^5+i \sqrt {-1+4 e^5}\right ) \int \frac {x \left (e^5+x+x^2\right ) \left (\frac {4-e^5+6 x-3 x^2}{x \left (e^5+x+x^2\right )}-\frac {(1+2 x) \left (1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3\right )}{x \left (e^5+x+x^2\right )^2}-\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x^2 \left (e^5+x+x^2\right )}\right ) \log \left (1-i \sqrt {-1+4 e^5}+2 x\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx \\ & = -8 \log \left (1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3\right )+x^2 \log ^2\left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )+\frac {8}{3} \int \frac {3 \left (7+11 e^5\right )+6 \left (7-e^5\right ) x}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx-4 \int \frac {1+2 x}{e^5+x+x^2} \, dx+8 \int \frac {2 e^5+x}{e^5+x+x^2} \, dx+8 \int \frac {-3 \left (1+4 e^5\right )-2 \left (4-e^5\right ) x-3 x^2}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx+\left (4 \left (1-4 e^5\right )\right ) \int \frac {1}{e^5+x+x^2} \, dx+\left (-1+2 e^5-i \sqrt {-1+4 e^5}\right ) \int \frac {x \left (e^5+x+x^2\right ) \left (\frac {4-e^5+6 x-3 x^2}{x \left (e^5+x+x^2\right )}-\frac {(1+2 x) \left (1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3\right )}{x \left (e^5+x+x^2\right )^2}-\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x^2 \left (e^5+x+x^2\right )}\right ) \log \left (1+i \sqrt {-1+4 e^5}+2 x\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx-\left (-1+2 e^5-i \sqrt {-1+4 e^5}\right ) \int \left (-\frac {\log \left (1+i \sqrt {-1+4 e^5}+2 x\right )}{x}+\frac {(-1-2 x) \log \left (1+i \sqrt {-1+4 e^5}+2 x\right )}{e^5+x+x^2}+\frac {\left (4-e^5+6 x-3 x^2\right ) \log \left (1+i \sqrt {-1+4 e^5}+2 x\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}\right ) \, dx+\left (-1+2 e^5+i \sqrt {-1+4 e^5}\right ) \int \frac {x \left (e^5+x+x^2\right ) \left (\frac {4-e^5+6 x-3 x^2}{x \left (e^5+x+x^2\right )}-\frac {(1+2 x) \left (1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3\right )}{x \left (e^5+x+x^2\right )^2}-\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x^2 \left (e^5+x+x^2\right )}\right ) \log \left (1-i \sqrt {-1+4 e^5}+2 x\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx-\left (-1+2 e^5+i \sqrt {-1+4 e^5}\right ) \int \left (-\frac {\log \left (1-i \sqrt {-1+4 e^5}+2 x\right )}{x}+\frac {(-1-2 x) \log \left (1-i \sqrt {-1+4 e^5}+2 x\right )}{e^5+x+x^2}+\frac {\left (4-e^5+6 x-3 x^2\right ) \log \left (1-i \sqrt {-1+4 e^5}+2 x\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}\right ) \, dx \\ & = -4 \log \left (e^5+x+x^2\right )+x^2 \log ^2\left (\frac {1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}{x \left (e^5+x+x^2\right )}\right )-\frac {8}{3} \int \frac {3 \left (7+11 e^5\right )+6 \left (7-e^5\right ) x}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx+\frac {8}{3} \text {Subst}\left (\int \frac {\frac {1}{3} \left (18 \left (7-e^5\right )+9 \left (7+11 e^5\right )\right )+6 \left (7-e^5\right ) x}{7+3 e^5+\left (7-e^5\right ) x-x^3} \, dx,x,-1+x\right )+4 \int \frac {1+2 x}{e^5+x+x^2} \, dx-\left (4 \left (1-4 e^5\right )\right ) \int \frac {1}{e^5+x+x^2} \, dx-\left (8 \left (1-4 e^5\right )\right ) \text {Subst}\left (\int \frac {1}{1-4 e^5-x^2} \, dx,x,1+2 x\right )-\left (1-2 e^5-i \sqrt {-1+4 e^5}\right ) \int \frac {\log \left (1-i \sqrt {-1+4 e^5}+2 x\right )}{x} \, dx-\left (-1+2 e^5-i \sqrt {-1+4 e^5}\right ) \int \frac {(-1-2 x) \log \left (1+i \sqrt {-1+4 e^5}+2 x\right )}{e^5+x+x^2} \, dx-\left (-1+2 e^5-i \sqrt {-1+4 e^5}\right ) \int \frac {\left (4-e^5+6 x-3 x^2\right ) \log \left (1+i \sqrt {-1+4 e^5}+2 x\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx+\left (-1+2 e^5-i \sqrt {-1+4 e^5}\right ) \int \left (-\frac {\log \left (1+i \sqrt {-1+4 e^5}+2 x\right )}{x}+\frac {(-1-2 x) \log \left (1+i \sqrt {-1+4 e^5}+2 x\right )}{e^5+x+x^2}+\frac {\left (4-e^5+6 x-3 x^2\right ) \log \left (1+i \sqrt {-1+4 e^5}+2 x\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}\right ) \, dx-\left (1-2 e^5+i \sqrt {-1+4 e^5}\right ) \int \frac {\log \left (1+i \sqrt {-1+4 e^5}+2 x\right )}{x} \, dx-\left (-1+2 e^5+i \sqrt {-1+4 e^5}\right ) \int \frac {(-1-2 x) \log \left (1-i \sqrt {-1+4 e^5}+2 x\right )}{e^5+x+x^2} \, dx-\left (-1+2 e^5+i \sqrt {-1+4 e^5}\right ) \int \frac {\left (4-e^5+6 x-3 x^2\right ) \log \left (1-i \sqrt {-1+4 e^5}+2 x\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3} \, dx+\left (-1+2 e^5+i \sqrt {-1+4 e^5}\right ) \int \left (-\frac {\log \left (1-i \sqrt {-1+4 e^5}+2 x\right )}{x}+\frac {(-1-2 x) \log \left (1-i \sqrt {-1+4 e^5}+2 x\right )}{e^5+x+x^2}+\frac {\left (4-e^5+6 x-3 x^2\right ) \log \left (1-i \sqrt {-1+4 e^5}+2 x\right )}{1+4 e^5+\left (4-e^5\right ) x+3 x^2-x^3}\right ) \, dx \\ & = \text {Too large to display} \\ \end{align*}
Result contains higher order function than in optimal. Order 9 vs. order 3 in optimal.
Time = 15.81 (sec) , antiderivative size = 146774, normalized size of antiderivative = 5645.15 \[ \int \frac {\left (8 e^{10} x+4 x^2+14 x^3+16 x^4+8 x^5+e^5 \left (2 x+16 x^2+16 x^3\right )\right ) \log \left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )+\left (-2 x^2-10 x^3-14 x^4-4 x^5+2 x^6+e^{10} \left (-8 x+2 x^2\right )+e^5 \left (-2 x-16 x^2-12 x^3+4 x^4\right )\right ) \log ^2\left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )}{e^{10} (-4+x)-x-5 x^2-7 x^3-2 x^4+x^5+e^5 \left (-1-8 x-6 x^2+2 x^3\right )} \, dx=\text {Result too large to show} \]
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Time = 3.09 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.73
method | result | size |
norman | \(x^{2} \ln \left (\frac {\left (-x +4\right ) {\mathrm e}^{5}-x^{3}+3 x^{2}+4 x +1}{x \,{\mathrm e}^{5}+x^{3}+x^{2}}\right )^{2}\) | \(45\) |
risch | \(x^{2} \ln \left (\frac {\left (-x +4\right ) {\mathrm e}^{5}-x^{3}+3 x^{2}+4 x +1}{x \,{\mathrm e}^{5}+x^{3}+x^{2}}\right )^{2}\) | \(45\) |
parallelrisch | \(-\frac {\left (-16 x^{2} \ln \left (\frac {\left (-x +4\right ) {\mathrm e}^{5}-x^{3}+3 x^{2}+4 x +1}{x \left (x^{2}+{\mathrm e}^{5}+x \right )}\right )^{2} {\mathrm e}^{20}-8 \,{\mathrm e}^{15} x^{2} \ln \left (\frac {\left (-x +4\right ) {\mathrm e}^{5}-x^{3}+3 x^{2}+4 x +1}{x \left (x^{2}+{\mathrm e}^{5}+x \right )}\right )^{2}-{\mathrm e}^{10} x^{2} \ln \left (\frac {\left (-x +4\right ) {\mathrm e}^{5}-x^{3}+3 x^{2}+4 x +1}{x \left (x^{2}+{\mathrm e}^{5}+x \right )}\right )^{2}\right ) {\mathrm e}^{-10}}{\left (4 \,{\mathrm e}^{5}+1\right )^{2}}\) | \(160\) |
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Time = 0.25 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.58 \[ \int \frac {\left (8 e^{10} x+4 x^2+14 x^3+16 x^4+8 x^5+e^5 \left (2 x+16 x^2+16 x^3\right )\right ) \log \left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )+\left (-2 x^2-10 x^3-14 x^4-4 x^5+2 x^6+e^{10} \left (-8 x+2 x^2\right )+e^5 \left (-2 x-16 x^2-12 x^3+4 x^4\right )\right ) \log ^2\left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )}{e^{10} (-4+x)-x-5 x^2-7 x^3-2 x^4+x^5+e^5 \left (-1-8 x-6 x^2+2 x^3\right )} \, dx=x^{2} \log \left (-\frac {x^{3} - 3 \, x^{2} + {\left (x - 4\right )} e^{5} - 4 \, x - 1}{x^{3} + x^{2} + x e^{5}}\right )^{2} \]
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Time = 0.21 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.42 \[ \int \frac {\left (8 e^{10} x+4 x^2+14 x^3+16 x^4+8 x^5+e^5 \left (2 x+16 x^2+16 x^3\right )\right ) \log \left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )+\left (-2 x^2-10 x^3-14 x^4-4 x^5+2 x^6+e^{10} \left (-8 x+2 x^2\right )+e^5 \left (-2 x-16 x^2-12 x^3+4 x^4\right )\right ) \log ^2\left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )}{e^{10} (-4+x)-x-5 x^2-7 x^3-2 x^4+x^5+e^5 \left (-1-8 x-6 x^2+2 x^3\right )} \, dx=x^{2} \log {\left (\frac {- x^{3} + 3 x^{2} + 4 x + \left (4 - x\right ) e^{5} + 1}{x^{3} + x^{2} + x e^{5}} \right )}^{2} \]
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Leaf count of result is larger than twice the leaf count of optimal. 113 vs. \(2 (26) = 52\).
Time = 0.26 (sec) , antiderivative size = 113, normalized size of antiderivative = 4.35 \[ \int \frac {\left (8 e^{10} x+4 x^2+14 x^3+16 x^4+8 x^5+e^5 \left (2 x+16 x^2+16 x^3\right )\right ) \log \left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )+\left (-2 x^2-10 x^3-14 x^4-4 x^5+2 x^6+e^{10} \left (-8 x+2 x^2\right )+e^5 \left (-2 x-16 x^2-12 x^3+4 x^4\right )\right ) \log ^2\left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )}{e^{10} (-4+x)-x-5 x^2-7 x^3-2 x^4+x^5+e^5 \left (-1-8 x-6 x^2+2 x^3\right )} \, dx=x^{2} \log \left (-x^{3} + 3 \, x^{2} - x {\left (e^{5} - 4\right )} + 4 \, e^{5} + 1\right )^{2} + x^{2} \log \left (x^{2} + x + e^{5}\right )^{2} + 2 \, x^{2} \log \left (x^{2} + x + e^{5}\right ) \log \left (x\right ) + x^{2} \log \left (x\right )^{2} - 2 \, {\left (x^{2} \log \left (x^{2} + x + e^{5}\right ) + x^{2} \log \left (x\right )\right )} \log \left (-x^{3} + 3 \, x^{2} - x {\left (e^{5} - 4\right )} + 4 \, e^{5} + 1\right ) \]
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Time = 2.21 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.65 \[ \int \frac {\left (8 e^{10} x+4 x^2+14 x^3+16 x^4+8 x^5+e^5 \left (2 x+16 x^2+16 x^3\right )\right ) \log \left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )+\left (-2 x^2-10 x^3-14 x^4-4 x^5+2 x^6+e^{10} \left (-8 x+2 x^2\right )+e^5 \left (-2 x-16 x^2-12 x^3+4 x^4\right )\right ) \log ^2\left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )}{e^{10} (-4+x)-x-5 x^2-7 x^3-2 x^4+x^5+e^5 \left (-1-8 x-6 x^2+2 x^3\right )} \, dx=x^{2} \log \left (-\frac {x^{3} - 3 \, x^{2} + x e^{5} - 4 \, x - 4 \, e^{5} - 1}{x^{3} + x^{2} + x e^{5}}\right )^{2} \]
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Time = 12.55 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.65 \[ \int \frac {\left (8 e^{10} x+4 x^2+14 x^3+16 x^4+8 x^5+e^5 \left (2 x+16 x^2+16 x^3\right )\right ) \log \left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )+\left (-2 x^2-10 x^3-14 x^4-4 x^5+2 x^6+e^{10} \left (-8 x+2 x^2\right )+e^5 \left (-2 x-16 x^2-12 x^3+4 x^4\right )\right ) \log ^2\left (\frac {1+e^5 (4-x)+4 x+3 x^2-x^3}{e^5 x+x^2+x^3}\right )}{e^{10} (-4+x)-x-5 x^2-7 x^3-2 x^4+x^5+e^5 \left (-1-8 x-6 x^2+2 x^3\right )} \, dx=x^2\,{\ln \left (\frac {4\,x-{\mathrm {e}}^5\,\left (x-4\right )+3\,x^2-x^3+1}{x^3+x^2+{\mathrm {e}}^5\,x}\right )}^2 \]
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