Integrand size = 41, antiderivative size = 20 \[ \int \frac {4+e^{2 x} x+144 x^2+\left (-4+144 x^2+2 e^{2 x} x^2\right ) \log (x)}{144 x^2} \, dx=\left (\frac {1}{144} \left (e^{2 x}+\frac {4}{x}\right )+x\right ) \log (x) \]
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Time = 0.06 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.25, number of steps used = 10, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.098, Rules used = {12, 14, 2326, 2372} \[ \int \frac {4+e^{2 x} x+144 x^2+\left (-4+144 x^2+2 e^{2 x} x^2\right ) \log (x)}{144 x^2} \, dx=\frac {1}{144} e^{2 x} \log (x)+x \log (x)+\frac {\log (x)}{36 x} \]
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Rule 12
Rule 14
Rule 2326
Rule 2372
Rubi steps \begin{align*} \text {integral}& = \frac {1}{144} \int \frac {4+e^{2 x} x+144 x^2+\left (-4+144 x^2+2 e^{2 x} x^2\right ) \log (x)}{x^2} \, dx \\ & = \frac {1}{144} \int \left (\frac {e^{2 x} (1+2 x \log (x))}{x}+\frac {4 \left (1+36 x^2-\log (x)+36 x^2 \log (x)\right )}{x^2}\right ) \, dx \\ & = \frac {1}{144} \int \frac {e^{2 x} (1+2 x \log (x))}{x} \, dx+\frac {1}{36} \int \frac {1+36 x^2-\log (x)+36 x^2 \log (x)}{x^2} \, dx \\ & = \frac {1}{144} e^{2 x} \log (x)+\frac {1}{36} \int \left (\frac {1+36 x^2}{x^2}+\frac {\left (-1+36 x^2\right ) \log (x)}{x^2}\right ) \, dx \\ & = \frac {1}{144} e^{2 x} \log (x)+\frac {1}{36} \int \frac {1+36 x^2}{x^2} \, dx+\frac {1}{36} \int \frac {\left (-1+36 x^2\right ) \log (x)}{x^2} \, dx \\ & = \frac {1}{144} e^{2 x} \log (x)+\frac {\log (x)}{36 x}+x \log (x) \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.25 \[ \int \frac {4+e^{2 x} x+144 x^2+\left (-4+144 x^2+2 e^{2 x} x^2\right ) \log (x)}{144 x^2} \, dx=\frac {1}{144} \left (e^{2 x} \log (x)+\frac {4 \log (x)}{x}+144 x \log (x)\right ) \]
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Time = 0.10 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.05
method | result | size |
default | \(\frac {{\mathrm e}^{2 x} \ln \left (x \right )}{144}+x \ln \left (x \right )+\frac {\ln \left (x \right )}{36 x}\) | \(21\) |
risch | \(\frac {\left (x \,{\mathrm e}^{2 x}+144 x^{2}+4\right ) \ln \left (x \right )}{144 x}\) | \(21\) |
parts | \(\frac {{\mathrm e}^{2 x} \ln \left (x \right )}{144}+x \ln \left (x \right )+\frac {\ln \left (x \right )}{36 x}\) | \(21\) |
norman | \(\frac {x^{2} \ln \left (x \right )+\frac {{\mathrm e}^{2 x} \ln \left (x \right ) x}{144}+\frac {\ln \left (x \right )}{36}}{x}\) | \(25\) |
parallelrisch | \(-\frac {-{\mathrm e}^{2 x} \ln \left (x \right ) x -144 x^{2} \ln \left (x \right )-4 \ln \left (x \right )}{144 x}\) | \(27\) |
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Time = 0.25 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.00 \[ \int \frac {4+e^{2 x} x+144 x^2+\left (-4+144 x^2+2 e^{2 x} x^2\right ) \log (x)}{144 x^2} \, dx=\frac {{\left (144 \, x^{2} + x e^{\left (2 \, x\right )} + 4\right )} \log \left (x\right )}{144 \, x} \]
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Time = 0.14 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.10 \[ \int \frac {4+e^{2 x} x+144 x^2+\left (-4+144 x^2+2 e^{2 x} x^2\right ) \log (x)}{144 x^2} \, dx=\frac {e^{2 x} \log {\left (x \right )}}{144} + \frac {\left (36 x^{2} + 1\right ) \log {\left (x \right )}}{36 x} \]
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Time = 0.22 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.00 \[ \int \frac {4+e^{2 x} x+144 x^2+\left (-4+144 x^2+2 e^{2 x} x^2\right ) \log (x)}{144 x^2} \, dx=x \log \left (x\right ) + \frac {1}{144} \, e^{\left (2 \, x\right )} \log \left (x\right ) + \frac {\log \left (x\right )}{36 \, x} \]
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Time = 0.29 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.25 \[ \int \frac {4+e^{2 x} x+144 x^2+\left (-4+144 x^2+2 e^{2 x} x^2\right ) \log (x)}{144 x^2} \, dx=\frac {144 \, x^{2} \log \left (x\right ) + x e^{\left (2 \, x\right )} \log \left (x\right ) + 4 \, \log \left (x\right )}{144 \, x} \]
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Time = 12.71 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.00 \[ \int \frac {4+e^{2 x} x+144 x^2+\left (-4+144 x^2+2 e^{2 x} x^2\right ) \log (x)}{144 x^2} \, dx=\frac {\ln \left (x\right )\,\left (x\,{\mathrm {e}}^{2\,x}+144\,x^2+4\right )}{144\,x} \]
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