Integrand size = 61, antiderivative size = 23 \[ \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} \left (230400 e^x-103680 x\right )}{1600 e^{2 x}-720 e^x x^2+81 x^4} \, dx=e^{-1+\frac {40}{-\frac {5 e^x}{18}+\frac {x^2}{16}}} \]
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\[ \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} \left (230400 e^x-103680 x\right )}{1600 e^{2 x}-720 e^x x^2+81 x^4} \, dx=\int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} \left (230400 e^x-103680 x\right )}{1600 e^{2 x}-720 e^x x^2+81 x^4} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {11520 e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} \left (20 e^x-9 x\right )}{\left (40 e^x-9 x^2\right )^2} \, dx \\ & = 11520 \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} \left (20 e^x-9 x\right )}{\left (40 e^x-9 x^2\right )^2} \, dx \\ & = 11520 \int \left (\frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}}}{2 \left (40 e^x-9 x^2\right )}+\frac {9 e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} (-2+x) x}{2 \left (-40 e^x+9 x^2\right )^2}\right ) \, dx \\ & = 5760 \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}}}{40 e^x-9 x^2} \, dx+51840 \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} (-2+x) x}{\left (-40 e^x+9 x^2\right )^2} \, dx \\ & = 5760 \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}}}{40 e^x-9 x^2} \, dx+51840 \int \left (-\frac {2 e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} x}{\left (-40 e^x+9 x^2\right )^2}+\frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} x^2}{\left (-40 e^x+9 x^2\right )^2}\right ) \, dx \\ & = 5760 \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}}}{40 e^x-9 x^2} \, dx+51840 \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} x^2}{\left (-40 e^x+9 x^2\right )^2} \, dx-103680 \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} x}{\left (-40 e^x+9 x^2\right )^2} \, dx \\ \end{align*}
Time = 0.62 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.83 \[ \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} \left (230400 e^x-103680 x\right )}{1600 e^{2 x}-720 e^x x^2+81 x^4} \, dx=e^{-1-\frac {5760}{40 e^x-9 x^2}} \]
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Time = 0.88 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.17
method | result | size |
risch | \({\mathrm e}^{-\frac {-9 x^{2}+40 \,{\mathrm e}^{x}+5760}{40 \,{\mathrm e}^{x}-9 x^{2}}}\) | \(27\) |
parallelrisch | \({\mathrm e}^{-\frac {-9 x^{2}+40 \,{\mathrm e}^{x}+5760}{40 \,{\mathrm e}^{x}-9 x^{2}}}\) | \(27\) |
norman | \(\frac {9 x^{2} {\mathrm e}^{\frac {-40 \,{\mathrm e}^{x}+9 x^{2}-5760}{40 \,{\mathrm e}^{x}-9 x^{2}}}-40 \,{\mathrm e}^{x} {\mathrm e}^{\frac {-40 \,{\mathrm e}^{x}+9 x^{2}-5760}{40 \,{\mathrm e}^{x}-9 x^{2}}}}{9 x^{2}-40 \,{\mathrm e}^{x}}\) | \(74\) |
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Time = 0.23 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.13 \[ \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} \left (230400 e^x-103680 x\right )}{1600 e^{2 x}-720 e^x x^2+81 x^4} \, dx=e^{\left (-\frac {9 \, x^{2} - 40 \, e^{x} - 5760}{9 \, x^{2} - 40 \, e^{x}}\right )} \]
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Time = 0.16 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.96 \[ \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} \left (230400 e^x-103680 x\right )}{1600 e^{2 x}-720 e^x x^2+81 x^4} \, dx=e^{\frac {9 x^{2} - 40 e^{x} - 5760}{- 9 x^{2} + 40 e^{x}}} \]
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Time = 1.41 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.74 \[ \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} \left (230400 e^x-103680 x\right )}{1600 e^{2 x}-720 e^x x^2+81 x^4} \, dx=e^{\left (\frac {5760}{9 \, x^{2} - 40 \, e^{x}} - 1\right )} \]
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\[ \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} \left (230400 e^x-103680 x\right )}{1600 e^{2 x}-720 e^x x^2+81 x^4} \, dx=\int { -\frac {11520 \, {\left (9 \, x - 20 \, e^{x}\right )} e^{\left (-\frac {9 \, x^{2} - 40 \, e^{x} - 5760}{9 \, x^{2} - 40 \, e^{x}}\right )}}{81 \, x^{4} - 720 \, x^{2} e^{x} + 1600 \, e^{\left (2 \, x\right )}} \,d x } \]
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Time = 11.05 (sec) , antiderivative size = 51, normalized size of antiderivative = 2.22 \[ \int \frac {e^{\frac {-5760-40 e^x+9 x^2}{40 e^x-9 x^2}} \left (230400 e^x-103680 x\right )}{1600 e^{2 x}-720 e^x x^2+81 x^4} \, dx={\mathrm {e}}^{\frac {9\,x^2}{40\,{\mathrm {e}}^x-9\,x^2}}\,{\mathrm {e}}^{-\frac {40\,{\mathrm {e}}^x}{40\,{\mathrm {e}}^x-9\,x^2}}\,{\mathrm {e}}^{-\frac {5760}{40\,{\mathrm {e}}^x-9\,x^2}} \]
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