\(\int \frac {1}{144} (143-e^x-576 e^{3+4 e^x+x}) \, dx\) [6047]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [A] (verification not implemented)
   Sympy [A] (verification not implemented)
   Maxima [A] (verification not implemented)
   Giac [A] (verification not implemented)
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 23, antiderivative size = 27 \[ \int \frac {1}{144} \left (143-e^x-576 e^{3+4 e^x+x}\right ) \, dx=1-e^{3+4 e^x}+\frac {1}{144} \left (-e^x-x\right )+x \]

[Out]

1-1/144*exp(x)+143/144*x-exp(4*exp(x)+3)

Rubi [A] (verified)

Time = 0.01 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.89, number of steps used = 5, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.130, Rules used = {12, 2225, 2320} \[ \int \frac {1}{144} \left (143-e^x-576 e^{3+4 e^x+x}\right ) \, dx=\frac {143 x}{144}-e^{4 e^x+3}-\frac {e^x}{144} \]

[In]

Int[(143 - E^x - 576*E^(3 + 4*E^x + x))/144,x]

[Out]

-E^(3 + 4*E^x) - E^x/144 + (143*x)/144

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 2225

Int[((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.), x_Symbol] :> Simp[(F^(c*(a + b*x)))^n/(b*c*n*Log[F]), x] /; Fre
eQ[{F, a, b, c, n}, x]

Rule 2320

Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Dist[v/D[v, x], Subst[Int[FunctionOfExponentialFu
nction[u, x]/x, x], x, v], x]] /; FunctionOfExponentialQ[u, x] &&  !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; F
reeQ[{a, m, n}, x] && IntegerQ[m*n]] &&  !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x))*(F_)[v_] /; FreeQ[{a, b, c}, x
] && InverseFunctionQ[F[x]]]

Rubi steps \begin{align*} \text {integral}& = \frac {1}{144} \int \left (143-e^x-576 e^{3+4 e^x+x}\right ) \, dx \\ & = \frac {143 x}{144}-\frac {\int e^x \, dx}{144}-4 \int e^{3+4 e^x+x} \, dx \\ & = -\frac {e^x}{144}+\frac {143 x}{144}-4 \text {Subst}\left (\int e^{3+4 x} \, dx,x,e^x\right ) \\ & = -e^{3+4 e^x}-\frac {e^x}{144}+\frac {143 x}{144} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.02 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.89 \[ \int \frac {1}{144} \left (143-e^x-576 e^{3+4 e^x+x}\right ) \, dx=\frac {1}{144} \left (-144 e^{3+4 e^x}-e^x+143 x\right ) \]

[In]

Integrate[(143 - E^x - 576*E^(3 + 4*E^x + x))/144,x]

[Out]

(-144*E^(3 + 4*E^x) - E^x + 143*x)/144

Maple [A] (verified)

Time = 0.38 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.67

method result size
default \(\frac {143 x}{144}-{\mathrm e}^{4 \,{\mathrm e}^{x}+3}-\frac {{\mathrm e}^{x}}{144}\) \(18\)
norman \(\frac {143 x}{144}-{\mathrm e}^{4 \,{\mathrm e}^{x}+3}-\frac {{\mathrm e}^{x}}{144}\) \(18\)
risch \(\frac {143 x}{144}-{\mathrm e}^{4 \,{\mathrm e}^{x}+3}-\frac {{\mathrm e}^{x}}{144}\) \(18\)
parallelrisch \(\frac {143 x}{144}-{\mathrm e}^{4 \,{\mathrm e}^{x}+3}-\frac {{\mathrm e}^{x}}{144}\) \(18\)
parts \(\frac {143 x}{144}-{\mathrm e}^{4 \,{\mathrm e}^{x}+3}-\frac {{\mathrm e}^{x}}{144}\) \(18\)
derivativedivides \(\frac {143 \ln \left (4 \,{\mathrm e}^{x}\right )}{144}-\frac {{\mathrm e}^{x}}{144}-\frac {1}{192}-{\mathrm e}^{4 \,{\mathrm e}^{x}+3}\) \(23\)

[In]

int(-4*exp(x)*exp(4*exp(x)+3)-1/144*exp(x)+143/144,x,method=_RETURNVERBOSE)

[Out]

143/144*x-exp(4*exp(x)+3)-1/144*exp(x)

Fricas [A] (verification not implemented)

none

Time = 0.25 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.04 \[ \int \frac {1}{144} \left (143-e^x-576 e^{3+4 e^x+x}\right ) \, dx=\frac {1}{144} \, {\left (143 \, x e^{x} - e^{\left (2 \, x\right )} - 144 \, e^{\left (x + 4 \, e^{x} + 3\right )}\right )} e^{\left (-x\right )} \]

[In]

integrate(-4*exp(x)*exp(4*exp(x)+3)-1/144*exp(x)+143/144,x, algorithm="fricas")

[Out]

1/144*(143*x*e^x - e^(2*x) - 144*e^(x + 4*e^x + 3))*e^(-x)

Sympy [A] (verification not implemented)

Time = 0.07 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.63 \[ \int \frac {1}{144} \left (143-e^x-576 e^{3+4 e^x+x}\right ) \, dx=\frac {143 x}{144} - \frac {e^{x}}{144} - e^{4 e^{x} + 3} \]

[In]

integrate(-4*exp(x)*exp(4*exp(x)+3)-1/144*exp(x)+143/144,x)

[Out]

143*x/144 - exp(x)/144 - exp(4*exp(x) + 3)

Maxima [A] (verification not implemented)

none

Time = 0.19 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.63 \[ \int \frac {1}{144} \left (143-e^x-576 e^{3+4 e^x+x}\right ) \, dx=\frac {143}{144} \, x - \frac {1}{144} \, e^{x} - e^{\left (4 \, e^{x} + 3\right )} \]

[In]

integrate(-4*exp(x)*exp(4*exp(x)+3)-1/144*exp(x)+143/144,x, algorithm="maxima")

[Out]

143/144*x - 1/144*e^x - e^(4*e^x + 3)

Giac [A] (verification not implemented)

none

Time = 0.27 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.63 \[ \int \frac {1}{144} \left (143-e^x-576 e^{3+4 e^x+x}\right ) \, dx=\frac {143}{144} \, x - \frac {1}{144} \, e^{x} - e^{\left (4 \, e^{x} + 3\right )} \]

[In]

integrate(-4*exp(x)*exp(4*exp(x)+3)-1/144*exp(x)+143/144,x, algorithm="giac")

[Out]

143/144*x - 1/144*e^x - e^(4*e^x + 3)

Mupad [B] (verification not implemented)

Time = 0.07 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.63 \[ \int \frac {1}{144} \left (143-e^x-576 e^{3+4 e^x+x}\right ) \, dx=\frac {143\,x}{144}-\frac {{\mathrm {e}}^x}{144}-{\mathrm {e}}^3\,{\mathrm {e}}^{4\,{\mathrm {e}}^x} \]

[In]

int(143/144 - 4*exp(4*exp(x) + 3)*exp(x) - exp(x)/144,x)

[Out]

(143*x)/144 - exp(x)/144 - exp(3)*exp(4*exp(x))