Integrand size = 78, antiderivative size = 24 \[ \int \frac {24 x+4 e^{\frac {-3+x^2}{x}} x-8 x^2+\left (-2 x^2+e^{\frac {-3+x^2}{x}} \left (3+x^2\right )\right ) \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )}{x^2 \log \left (\frac {x^4}{16}\right )} \, dx=\left (6+e^{-\frac {3}{x}+x}-2 x\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right ) \]
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Leaf count is larger than twice the leaf count of optimal. \(97\) vs. \(2(24)=48\).
Time = 0.74 (sec) , antiderivative size = 97, normalized size of antiderivative = 4.04, number of steps used = 14, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {6874, 6820, 2395, 2337, 2209, 2339, 29, 2600, 2326} \[ \int \frac {24 x+4 e^{\frac {-3+x^2}{x}} x-8 x^2+\left (-2 x^2+e^{\frac {-3+x^2}{x}} \left (3+x^2\right )\right ) \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )}{x^2 \log \left (\frac {x^4}{16}\right )} \, dx=-2 x \log \left (\log \left (\frac {x^4}{16}\right )\right )+6 \log \left (\log \left (\frac {x^4}{16}\right )\right )+\frac {e^{x-\frac {3}{x}} \left (3 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )+x^2 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )\right )}{\left (\frac {3}{x^2}+1\right ) x^2 \log \left (\frac {x^4}{16}\right )} \]
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Rule 29
Rule 2209
Rule 2326
Rule 2337
Rule 2339
Rule 2395
Rule 2600
Rule 6820
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {2 \left (-12+4 x+x \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )\right )}{x \log \left (\frac {x^4}{16}\right )}+\frac {e^{-\frac {3}{x}+x} \left (4 x+3 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )+x^2 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )\right )}{x^2 \log \left (\frac {x^4}{16}\right )}\right ) \, dx \\ & = -\left (2 \int \frac {-12+4 x+x \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )}{x \log \left (\frac {x^4}{16}\right )} \, dx\right )+\int \frac {e^{-\frac {3}{x}+x} \left (4 x+3 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )+x^2 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )\right )}{x^2 \log \left (\frac {x^4}{16}\right )} \, dx \\ & = \frac {e^{-\frac {3}{x}+x} \left (3 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )+x^2 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )\right )}{\left (1+\frac {3}{x^2}\right ) x^2 \log \left (\frac {x^4}{16}\right )}-2 \int \left (\frac {4 (-3+x)}{x \log \left (\frac {x^4}{16}\right )}+\log \left (\log \left (\frac {x^4}{16}\right )\right )\right ) \, dx \\ & = \frac {e^{-\frac {3}{x}+x} \left (3 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )+x^2 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )\right )}{\left (1+\frac {3}{x^2}\right ) x^2 \log \left (\frac {x^4}{16}\right )}-2 \int \log \left (\log \left (\frac {x^4}{16}\right )\right ) \, dx-8 \int \frac {-3+x}{x \log \left (\frac {x^4}{16}\right )} \, dx \\ & = -2 x \log \left (\log \left (\frac {x^4}{16}\right )\right )+\frac {e^{-\frac {3}{x}+x} \left (3 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )+x^2 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )\right )}{\left (1+\frac {3}{x^2}\right ) x^2 \log \left (\frac {x^4}{16}\right )}-8 \int \left (\frac {1}{\log \left (\frac {x^4}{16}\right )}-\frac {3}{x \log \left (\frac {x^4}{16}\right )}\right ) \, dx+8 \int \frac {1}{\log \left (\frac {x^4}{16}\right )} \, dx \\ & = -2 x \log \left (\log \left (\frac {x^4}{16}\right )\right )+\frac {e^{-\frac {3}{x}+x} \left (3 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )+x^2 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )\right )}{\left (1+\frac {3}{x^2}\right ) x^2 \log \left (\frac {x^4}{16}\right )}-8 \int \frac {1}{\log \left (\frac {x^4}{16}\right )} \, dx+24 \int \frac {1}{x \log \left (\frac {x^4}{16}\right )} \, dx+\frac {(4 x) \text {Subst}\left (\int \frac {e^{x/4}}{x} \, dx,x,\log \left (\frac {x^4}{16}\right )\right )}{\sqrt [4]{x^4}} \\ & = \frac {4 x \text {Ei}\left (\frac {1}{4} \log \left (\frac {x^4}{16}\right )\right )}{\sqrt [4]{x^4}}-2 x \log \left (\log \left (\frac {x^4}{16}\right )\right )+\frac {e^{-\frac {3}{x}+x} \left (3 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )+x^2 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )\right )}{\left (1+\frac {3}{x^2}\right ) x^2 \log \left (\frac {x^4}{16}\right )}+6 \text {Subst}\left (\int \frac {1}{x} \, dx,x,\log \left (\frac {x^4}{16}\right )\right )-\frac {(4 x) \text {Subst}\left (\int \frac {e^{x/4}}{x} \, dx,x,\log \left (\frac {x^4}{16}\right )\right )}{\sqrt [4]{x^4}} \\ & = 6 \log \left (\log \left (\frac {x^4}{16}\right )\right )-2 x \log \left (\log \left (\frac {x^4}{16}\right )\right )+\frac {e^{-\frac {3}{x}+x} \left (3 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )+x^2 \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )\right )}{\left (1+\frac {3}{x^2}\right ) x^2 \log \left (\frac {x^4}{16}\right )} \\ \end{align*}
Time = 3.39 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00 \[ \int \frac {24 x+4 e^{\frac {-3+x^2}{x}} x-8 x^2+\left (-2 x^2+e^{\frac {-3+x^2}{x}} \left (3+x^2\right )\right ) \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )}{x^2 \log \left (\frac {x^4}{16}\right )} \, dx=\left (6+e^{-\frac {3}{x}+x}-2 x\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right ) \]
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Time = 3.64 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.62
method | result | size |
parallelrisch | \(-2 \ln \left (\ln \left (\frac {x^{4}}{16}\right )\right ) x +\ln \left (\ln \left (\frac {x^{4}}{16}\right )\right ) {\mathrm e}^{\frac {x^{2}-3}{x}}+6 \ln \left (\ln \left (\frac {x^{4}}{16}\right )\right )\) | \(39\) |
risch | \(\left (-2 x +{\mathrm e}^{\frac {x^{2}-3}{x}}\right ) \ln \left (-4 \ln \left (2\right )+4 \ln \left (x \right )-\frac {i \pi \,\operatorname {csgn}\left (i x^{2}\right ) {\left (-\operatorname {csgn}\left (i x^{2}\right )+\operatorname {csgn}\left (i x \right )\right )}^{2}}{2}-\frac {i \pi \,\operatorname {csgn}\left (i x^{3}\right ) \left (-\operatorname {csgn}\left (i x^{3}\right )+\operatorname {csgn}\left (i x^{2}\right )\right ) \left (-\operatorname {csgn}\left (i x^{3}\right )+\operatorname {csgn}\left (i x \right )\right )}{2}-\frac {i \pi \,\operatorname {csgn}\left (i x^{4}\right ) \left (-\operatorname {csgn}\left (i x^{4}\right )+\operatorname {csgn}\left (i x^{3}\right )\right ) \left (-\operatorname {csgn}\left (i x^{4}\right )+\operatorname {csgn}\left (i x \right )\right )}{2}\right )+6 \ln \left (\ln \left (x \right )-\frac {i \left (\pi \operatorname {csgn}\left (i x \right )^{2} \operatorname {csgn}\left (i x^{2}\right )-2 \pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i x^{2}\right )^{2}+\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i x^{2}\right ) \operatorname {csgn}\left (i x^{3}\right )-\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i x^{3}\right )^{2}+\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i x^{3}\right ) \operatorname {csgn}\left (i x^{4}\right )-\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i x^{4}\right )^{2}+\pi \operatorname {csgn}\left (i x^{2}\right )^{3}-\pi \,\operatorname {csgn}\left (i x^{2}\right ) \operatorname {csgn}\left (i x^{3}\right )^{2}+\pi \operatorname {csgn}\left (i x^{3}\right )^{3}-\pi \,\operatorname {csgn}\left (i x^{3}\right ) \operatorname {csgn}\left (i x^{4}\right )^{2}+\pi \operatorname {csgn}\left (i x^{4}\right )^{3}-8 i \ln \left (2\right )\right )}{8}\right )\) | \(336\) |
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Time = 0.25 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {24 x+4 e^{\frac {-3+x^2}{x}} x-8 x^2+\left (-2 x^2+e^{\frac {-3+x^2}{x}} \left (3+x^2\right )\right ) \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )}{x^2 \log \left (\frac {x^4}{16}\right )} \, dx=-{\left (2 \, x - e^{\left (\frac {x^{2} - 3}{x}\right )} - 6\right )} \log \left (\log \left (\frac {1}{16} \, x^{4}\right )\right ) \]
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Time = 5.77 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.54 \[ \int \frac {24 x+4 e^{\frac {-3+x^2}{x}} x-8 x^2+\left (-2 x^2+e^{\frac {-3+x^2}{x}} \left (3+x^2\right )\right ) \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )}{x^2 \log \left (\frac {x^4}{16}\right )} \, dx=- 2 x \log {\left (\log {\left (\frac {x^{4}}{16} \right )} \right )} + e^{\frac {x^{2} - 3}{x}} \log {\left (\log {\left (\frac {x^{4}}{16} \right )} \right )} + 6 \log {\left (\log {\left (\frac {x^{4}}{16} \right )} \right )} \]
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Time = 0.30 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.79 \[ \int \frac {24 x+4 e^{\frac {-3+x^2}{x}} x-8 x^2+\left (-2 x^2+e^{\frac {-3+x^2}{x}} \left (3+x^2\right )\right ) \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )}{x^2 \log \left (\frac {x^4}{16}\right )} \, dx=-4 \, x \log \left (2\right ) + 2 \, e^{\left (x - \frac {3}{x}\right )} \log \left (2\right ) - {\left (2 \, x - e^{\left (x - \frac {3}{x}\right )} - 6\right )} \log \left (-\log \left (2\right ) + \log \left (x\right )\right ) \]
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\[ \int \frac {24 x+4 e^{\frac {-3+x^2}{x}} x-8 x^2+\left (-2 x^2+e^{\frac {-3+x^2}{x}} \left (3+x^2\right )\right ) \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )}{x^2 \log \left (\frac {x^4}{16}\right )} \, dx=\int { -\frac {{\left (2 \, x^{2} - {\left (x^{2} + 3\right )} e^{\left (\frac {x^{2} - 3}{x}\right )}\right )} \log \left (\frac {1}{16} \, x^{4}\right ) \log \left (\log \left (\frac {1}{16} \, x^{4}\right )\right ) + 8 \, x^{2} - 4 \, x e^{\left (\frac {x^{2} - 3}{x}\right )} - 24 \, x}{x^{2} \log \left (\frac {1}{16} \, x^{4}\right )} \,d x } \]
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Timed out. \[ \int \frac {24 x+4 e^{\frac {-3+x^2}{x}} x-8 x^2+\left (-2 x^2+e^{\frac {-3+x^2}{x}} \left (3+x^2\right )\right ) \log \left (\frac {x^4}{16}\right ) \log \left (\log \left (\frac {x^4}{16}\right )\right )}{x^2 \log \left (\frac {x^4}{16}\right )} \, dx=\int \frac {24\,x+4\,x\,{\mathrm {e}}^{\frac {x^2-3}{x}}-8\,x^2+\ln \left (\ln \left (\frac {x^4}{16}\right )\right )\,\ln \left (\frac {x^4}{16}\right )\,\left ({\mathrm {e}}^{\frac {x^2-3}{x}}\,\left (x^2+3\right )-2\,x^2\right )}{x^2\,\ln \left (\frac {x^4}{16}\right )} \,d x \]
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