Integrand size = 83, antiderivative size = 21 \[ \int \frac {-18 x^3+9 x^4+2 x^5+e^{\frac {1+2 x \log (6+x)+x^2 \log ^2(6+x)}{x^2}} \left (-12-2 x+2 x^2+\left (-12 x-2 x^2+2 x^3\right ) \log (6+x)\right )}{6 x^3+x^4} \, dx=e^{\left (\frac {1}{x}+\log (6+x)\right )^2}-(3-x) x \]
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\[ \int \frac {-18 x^3+9 x^4+2 x^5+e^{\frac {1+2 x \log (6+x)+x^2 \log ^2(6+x)}{x^2}} \left (-12-2 x+2 x^2+\left (-12 x-2 x^2+2 x^3\right ) \log (6+x)\right )}{6 x^3+x^4} \, dx=\int \frac {-18 x^3+9 x^4+2 x^5+e^{\frac {1+2 x \log (6+x)+x^2 \log ^2(6+x)}{x^2}} \left (-12-2 x+2 x^2+\left (-12 x-2 x^2+2 x^3\right ) \log (6+x)\right )}{6 x^3+x^4} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {-18 x^3+9 x^4+2 x^5+e^{\frac {1+2 x \log (6+x)+x^2 \log ^2(6+x)}{x^2}} \left (-12-2 x+2 x^2+\left (-12 x-2 x^2+2 x^3\right ) \log (6+x)\right )}{x^3 (6+x)} \, dx \\ & = \int \left (-3+2 x+\frac {2 e^{\frac {1}{x^2}+\log ^2(6+x)} (-3+x) (2+x) (6+x)^{-1+\frac {2}{x}} (1+x \log (6+x))}{x^3}\right ) \, dx \\ & = -3 x+x^2+2 \int \frac {e^{\frac {1}{x^2}+\log ^2(6+x)} (-3+x) (2+x) (6+x)^{-1+\frac {2}{x}} (1+x \log (6+x))}{x^3} \, dx \\ & = -3 x+x^2+2 \int \left (\frac {e^{\frac {1}{x^2}+\log ^2(6+x)} (-3+x) (2+x) (6+x)^{-1+\frac {2}{x}}}{x^3}+\frac {e^{\frac {1}{x^2}+\log ^2(6+x)} (-3+x) (2+x) (6+x)^{-1+\frac {2}{x}} \log (6+x)}{x^2}\right ) \, dx \\ & = -3 x+x^2+2 \int \frac {e^{\frac {1}{x^2}+\log ^2(6+x)} (-3+x) (2+x) (6+x)^{-1+\frac {2}{x}}}{x^3} \, dx+2 \int \frac {e^{\frac {1}{x^2}+\log ^2(6+x)} (-3+x) (2+x) (6+x)^{-1+\frac {2}{x}} \log (6+x)}{x^2} \, dx \\ & = -3 x+x^2+2 \int \left (-\frac {6 e^{\frac {1}{x^2}+\log ^2(6+x)} (6+x)^{-1+\frac {2}{x}}}{x^3}-\frac {e^{\frac {1}{x^2}+\log ^2(6+x)} (6+x)^{-1+\frac {2}{x}}}{x^2}+\frac {e^{\frac {1}{x^2}+\log ^2(6+x)} (6+x)^{-1+\frac {2}{x}}}{x}\right ) \, dx+2 \int \left (e^{\frac {1}{x^2}+\log ^2(6+x)} (6+x)^{-1+\frac {2}{x}} \log (6+x)-\frac {6 e^{\frac {1}{x^2}+\log ^2(6+x)} (6+x)^{-1+\frac {2}{x}} \log (6+x)}{x^2}-\frac {e^{\frac {1}{x^2}+\log ^2(6+x)} (6+x)^{-1+\frac {2}{x}} \log (6+x)}{x}\right ) \, dx \\ & = -3 x+x^2-2 \int \frac {e^{\frac {1}{x^2}+\log ^2(6+x)} (6+x)^{-1+\frac {2}{x}}}{x^2} \, dx+2 \int \frac {e^{\frac {1}{x^2}+\log ^2(6+x)} (6+x)^{-1+\frac {2}{x}}}{x} \, dx+2 \int e^{\frac {1}{x^2}+\log ^2(6+x)} (6+x)^{-1+\frac {2}{x}} \log (6+x) \, dx-2 \int \frac {e^{\frac {1}{x^2}+\log ^2(6+x)} (6+x)^{-1+\frac {2}{x}} \log (6+x)}{x} \, dx-12 \int \frac {e^{\frac {1}{x^2}+\log ^2(6+x)} (6+x)^{-1+\frac {2}{x}}}{x^3} \, dx-12 \int \frac {e^{\frac {1}{x^2}+\log ^2(6+x)} (6+x)^{-1+\frac {2}{x}} \log (6+x)}{x^2} \, dx \\ \end{align*}
Time = 0.83 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.38 \[ \int \frac {-18 x^3+9 x^4+2 x^5+e^{\frac {1+2 x \log (6+x)+x^2 \log ^2(6+x)}{x^2}} \left (-12-2 x+2 x^2+\left (-12 x-2 x^2+2 x^3\right ) \log (6+x)\right )}{6 x^3+x^4} \, dx=-3 x+x^2+e^{\frac {1}{x^2}+\log ^2(6+x)} (6+x)^{2/x} \]
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Time = 0.24 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.10
method | result | size |
risch | \(-3 x +{\mathrm e}^{\frac {\left (x \ln \left (6+x \right )+1\right )^{2}}{x^{2}}}+x^{2}\) | \(23\) |
default | \(-3 x +{\mathrm e}^{\frac {x^{2} \ln \left (6+x \right )^{2}+2 x \ln \left (6+x \right )+1}{x^{2}}}+x^{2}\) | \(32\) |
parts | \(-3 x +{\mathrm e}^{\frac {x^{2} \ln \left (6+x \right )^{2}+2 x \ln \left (6+x \right )+1}{x^{2}}}+x^{2}\) | \(32\) |
parallelrisch | \(x^{2}-3 x +{\mathrm e}^{\frac {x^{2} \ln \left (6+x \right )^{2}+2 x \ln \left (6+x \right )+1}{x^{2}}}+9\) | \(33\) |
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Time = 0.26 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.48 \[ \int \frac {-18 x^3+9 x^4+2 x^5+e^{\frac {1+2 x \log (6+x)+x^2 \log ^2(6+x)}{x^2}} \left (-12-2 x+2 x^2+\left (-12 x-2 x^2+2 x^3\right ) \log (6+x)\right )}{6 x^3+x^4} \, dx=x^{2} - 3 \, x + e^{\left (\frac {x^{2} \log \left (x + 6\right )^{2} + 2 \, x \log \left (x + 6\right ) + 1}{x^{2}}\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 31 vs. \(2 (15) = 30\).
Time = 0.16 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.48 \[ \int \frac {-18 x^3+9 x^4+2 x^5+e^{\frac {1+2 x \log (6+x)+x^2 \log ^2(6+x)}{x^2}} \left (-12-2 x+2 x^2+\left (-12 x-2 x^2+2 x^3\right ) \log (6+x)\right )}{6 x^3+x^4} \, dx=x^{2} - 3 x + e^{\frac {x^{2} \log {\left (x + 6 \right )}^{2} + 2 x \log {\left (x + 6 \right )} + 1}{x^{2}}} \]
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Time = 0.28 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.29 \[ \int \frac {-18 x^3+9 x^4+2 x^5+e^{\frac {1+2 x \log (6+x)+x^2 \log ^2(6+x)}{x^2}} \left (-12-2 x+2 x^2+\left (-12 x-2 x^2+2 x^3\right ) \log (6+x)\right )}{6 x^3+x^4} \, dx=x^{2} - 3 \, x + e^{\left (\log \left (x + 6\right )^{2} + \frac {2 \, \log \left (x + 6\right )}{x} + \frac {1}{x^{2}}\right )} \]
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Time = 0.40 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.29 \[ \int \frac {-18 x^3+9 x^4+2 x^5+e^{\frac {1+2 x \log (6+x)+x^2 \log ^2(6+x)}{x^2}} \left (-12-2 x+2 x^2+\left (-12 x-2 x^2+2 x^3\right ) \log (6+x)\right )}{6 x^3+x^4} \, dx=x^{2} - 3 \, x + e^{\left (\log \left (x + 6\right )^{2} + \frac {2 \, \log \left (x + 6\right )}{x} + \frac {1}{x^{2}}\right )} \]
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Time = 7.54 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.33 \[ \int \frac {-18 x^3+9 x^4+2 x^5+e^{\frac {1+2 x \log (6+x)+x^2 \log ^2(6+x)}{x^2}} \left (-12-2 x+2 x^2+\left (-12 x-2 x^2+2 x^3\right ) \log (6+x)\right )}{6 x^3+x^4} \, dx=x^2-3\,x+{\mathrm {e}}^{{\ln \left (x+6\right )}^2}\,{\mathrm {e}}^{\frac {1}{x^2}}\,{\left (x+6\right )}^{2/x} \]
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