Integrand size = 51, antiderivative size = 25 \[ \int \frac {30+3 x^2-24 x^3+\left (-24-6 x+36 x^2\right ) \log (9)-12 \log ^2(9)}{2 x^2-4 x \log (9)+2 \log ^2(9)} \, dx=\frac {3}{2} (-5+4 x) \left (-1+\frac {-2+x^2}{-x+\log (9)}\right ) \]
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Time = 0.04 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.72, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.059, Rules used = {27, 12, 1864} \[ \int \frac {30+3 x^2-24 x^3+\left (-24-6 x+36 x^2\right ) \log (9)-12 \log ^2(9)}{2 x^2-4 x \log (9)+2 \log ^2(9)} \, dx=-6 x^2-\frac {3 (5-4 \log (9)) \left (2-\log ^2(9)\right )}{2 (x-\log (9))}+\frac {3}{2} x (1-4 \log (9)) \]
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Rule 12
Rule 27
Rule 1864
Rubi steps \begin{align*} \text {integral}& = \int \frac {30+3 x^2-24 x^3+\left (-24-6 x+36 x^2\right ) \log (9)-12 \log ^2(9)}{2 (x-\log (9))^2} \, dx \\ & = \frac {1}{2} \int \frac {30+3 x^2-24 x^3+\left (-24-6 x+36 x^2\right ) \log (9)-12 \log ^2(9)}{(x-\log (9))^2} \, dx \\ & = \frac {1}{2} \int \left (-24 x-3 (-1+4 \log (9))+\frac {3 (5-4 \log (9)) \left (2-\log ^2(9)\right )}{(x-\log (9))^2}\right ) \, dx \\ & = -6 x^2+\frac {3}{2} x (1-4 \log (9))-\frac {3 (5-4 \log (9)) \left (2-\log ^2(9)\right )}{2 (x-\log (9))} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.80 \[ \int \frac {30+3 x^2-24 x^3+\left (-24-6 x+36 x^2\right ) \log (9)-12 \log ^2(9)}{2 x^2-4 x \log (9)+2 \log ^2(9)} \, dx=-\frac {3}{2} \left (4 x^2+x (-1+4 \log (9))+\frac {10-8 \log (9)-5 \log ^2(9)+4 \log ^3(9)}{x-\log (9)}\right ) \]
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Time = 0.60 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.32
method | result | size |
gosper | \(-\frac {3 \left (-4 x^{3}+x^{2}-10+16 \ln \left (3\right )^{2}+16 \ln \left (3\right )\right )}{2 \left (2 \ln \left (3\right )-x \right )}\) | \(33\) |
norman | \(\frac {-\frac {3 x^{2}}{2}+6 x^{3}+15-24 \ln \left (3\right )^{2}-24 \ln \left (3\right )}{2 \ln \left (3\right )-x}\) | \(34\) |
parallelrisch | \(-\frac {-12 x^{3}+48 \ln \left (3\right )^{2}-30+3 x^{2}+48 \ln \left (3\right )}{2 \left (2 \ln \left (3\right )-x \right )}\) | \(35\) |
default | \(-6 x^{2}-12 x \ln \left (3\right )+\frac {3 x}{2}-\frac {3 \left (32 \ln \left (3\right )^{3}-20 \ln \left (3\right )^{2}-16 \ln \left (3\right )+10\right )}{2 \left (-2 \ln \left (3\right )+x \right )}\) | \(43\) |
risch | \(-12 x \ln \left (3\right )-6 x^{2}+\frac {3 x}{2}+\frac {24 \ln \left (3\right )^{3}}{\ln \left (3\right )-\frac {x}{2}}-\frac {15 \ln \left (3\right )^{2}}{\ln \left (3\right )-\frac {x}{2}}-\frac {12 \ln \left (3\right )}{\ln \left (3\right )-\frac {x}{2}}+\frac {15}{2 \left (\ln \left (3\right )-\frac {x}{2}\right )}\) | \(65\) |
meijerg | \(-\frac {6 x}{1-\frac {x}{2 \ln \left (3\right )}}+\frac {15 x}{4 \ln \left (3\right )^{2} \left (1-\frac {x}{2 \ln \left (3\right )}\right )}-2 \left (36 \ln \left (3\right )+\frac {3}{2}\right ) \ln \left (3\right ) \left (-\frac {x \left (-\frac {3 x}{2 \ln \left (3\right )}+6\right )}{6 \ln \left (3\right ) \left (1-\frac {x}{2 \ln \left (3\right )}\right )}-2 \ln \left (1-\frac {x}{2 \ln \left (3\right )}\right )\right )-6 \ln \left (3\right ) \left (\frac {x}{2 \ln \left (3\right ) \left (1-\frac {x}{2 \ln \left (3\right )}\right )}+\ln \left (1-\frac {x}{2 \ln \left (3\right )}\right )\right )-48 \ln \left (3\right )^{2} \left (\frac {x \left (-\frac {x^{2}}{2 \ln \left (3\right )^{2}}-\frac {3 x}{\ln \left (3\right )}+12\right )}{8 \ln \left (3\right ) \left (1-\frac {x}{2 \ln \left (3\right )}\right )}+3 \ln \left (1-\frac {x}{2 \ln \left (3\right )}\right )\right )-\frac {6 x}{\ln \left (3\right ) \left (1-\frac {x}{2 \ln \left (3\right )}\right )}\) | \(190\) |
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Time = 0.25 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.84 \[ \int \frac {30+3 x^2-24 x^3+\left (-24-6 x+36 x^2\right ) \log (9)-12 \log ^2(9)}{2 x^2-4 x \log (9)+2 \log ^2(9)} \, dx=-\frac {3 \, {\left (4 \, x^{3} - 4 \, {\left (4 \, x + 5\right )} \log \left (3\right )^{2} + 32 \, \log \left (3\right )^{3} - x^{2} + 2 \, {\left (x - 8\right )} \log \left (3\right ) + 10\right )}}{2 \, {\left (x - 2 \, \log \left (3\right )\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 42 vs. \(2 (19) = 38\).
Time = 0.16 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.68 \[ \int \frac {30+3 x^2-24 x^3+\left (-24-6 x+36 x^2\right ) \log (9)-12 \log ^2(9)}{2 x^2-4 x \log (9)+2 \log ^2(9)} \, dx=- 6 x^{2} - x \left (- \frac {3}{2} + 12 \log {\left (3 \right )}\right ) - \frac {- 30 \log {\left (3 \right )}^{2} - 24 \log {\left (3 \right )} + 15 + 48 \log {\left (3 \right )}^{3}}{x - 2 \log {\left (3 \right )}} \]
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Time = 0.17 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.72 \[ \int \frac {30+3 x^2-24 x^3+\left (-24-6 x+36 x^2\right ) \log (9)-12 \log ^2(9)}{2 x^2-4 x \log (9)+2 \log ^2(9)} \, dx=-6 \, x^{2} - \frac {3}{2} \, x {\left (8 \, \log \left (3\right ) - 1\right )} - \frac {3 \, {\left (16 \, \log \left (3\right )^{3} - 10 \, \log \left (3\right )^{2} - 8 \, \log \left (3\right ) + 5\right )}}{x - 2 \, \log \left (3\right )} \]
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Time = 0.29 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.68 \[ \int \frac {30+3 x^2-24 x^3+\left (-24-6 x+36 x^2\right ) \log (9)-12 \log ^2(9)}{2 x^2-4 x \log (9)+2 \log ^2(9)} \, dx=-6 \, x^{2} - 12 \, x \log \left (3\right ) + \frac {3}{2} \, x - \frac {3 \, {\left (16 \, \log \left (3\right )^{3} - 10 \, \log \left (3\right )^{2} - 8 \, \log \left (3\right ) + 5\right )}}{x - 2 \, \log \left (3\right )} \]
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Time = 0.18 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.68 \[ \int \frac {30+3 x^2-24 x^3+\left (-24-6 x+36 x^2\right ) \log (9)-12 \log ^2(9)}{2 x^2-4 x \log (9)+2 \log ^2(9)} \, dx=\frac {24\,\ln \left (3\right )+30\,{\ln \left (3\right )}^2-48\,{\ln \left (3\right )}^3-15}{x-2\,\ln \left (3\right )}-6\,x^2-x\,\left (12\,\ln \left (3\right )-\frac {3}{2}\right ) \]
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