Integrand size = 82, antiderivative size = 20 \[ \int \frac {e^x \left (-8 x+4 x^2+28 x^6-4 x^7-12 x^{11}+x^{12}+\log (4)\right )}{16 x^4-32 x^9+24 x^{14}-8 x^{19}+x^{24}+\left (8 x^2-8 x^7+2 x^{12}\right ) \log (4)+\log ^2(4)} \, dx=\frac {e^x}{x^2 \left (-2+x^5\right )^2+\log (4)} \]
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Leaf count is larger than twice the leaf count of optimal. \(68\) vs. \(2(20)=40\).
Time = 0.63 (sec) , antiderivative size = 68, normalized size of antiderivative = 3.40, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.012, Rules used = {2326} \[ \int \frac {e^x \left (-8 x+4 x^2+28 x^6-4 x^7-12 x^{11}+x^{12}+\log (4)\right )}{16 x^4-32 x^9+24 x^{14}-8 x^{19}+x^{24}+\left (8 x^2-8 x^7+2 x^{12}\right ) \log (4)+\log ^2(4)} \, dx=\frac {e^x \left (x^{12}-4 x^7+4 x^2+\log (4)\right )}{x^{24}-8 x^{19}+24 x^{14}-32 x^9+16 x^4+2 \left (x^{12}-4 x^7+4 x^2\right ) \log (4)+\log ^2(4)} \]
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Rule 2326
Rubi steps \begin{align*} \text {integral}& = \frac {e^x \left (4 x^2-4 x^7+x^{12}+\log (4)\right )}{16 x^4-32 x^9+24 x^{14}-8 x^{19}+x^{24}+2 \left (4 x^2-4 x^7+x^{12}\right ) \log (4)+\log ^2(4)} \\ \end{align*}
Time = 0.96 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.10 \[ \int \frac {e^x \left (-8 x+4 x^2+28 x^6-4 x^7-12 x^{11}+x^{12}+\log (4)\right )}{16 x^4-32 x^9+24 x^{14}-8 x^{19}+x^{24}+\left (8 x^2-8 x^7+2 x^{12}\right ) \log (4)+\log ^2(4)} \, dx=\frac {e^x}{4 x^2-4 x^7+x^{12}+\log (4)} \]
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Time = 2.92 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.20
method | result | size |
gosper | \(\frac {{\mathrm e}^{x}}{x^{12}-4 x^{7}+4 x^{2}+2 \ln \left (2\right )}\) | \(24\) |
risch | \(\frac {{\mathrm e}^{x}}{x^{12}-4 x^{7}+4 x^{2}+2 \ln \left (2\right )}\) | \(24\) |
parallelrisch | \(\frac {{\mathrm e}^{x}}{x^{12}-4 x^{7}+4 x^{2}+2 \ln \left (2\right )}\) | \(24\) |
default | \(\text {Expression too large to display}\) | \(2854\) |
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Time = 0.26 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.15 \[ \int \frac {e^x \left (-8 x+4 x^2+28 x^6-4 x^7-12 x^{11}+x^{12}+\log (4)\right )}{16 x^4-32 x^9+24 x^{14}-8 x^{19}+x^{24}+\left (8 x^2-8 x^7+2 x^{12}\right ) \log (4)+\log ^2(4)} \, dx=\frac {e^{x}}{x^{12} - 4 \, x^{7} + 4 \, x^{2} + 2 \, \log \left (2\right )} \]
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Time = 0.12 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.00 \[ \int \frac {e^x \left (-8 x+4 x^2+28 x^6-4 x^7-12 x^{11}+x^{12}+\log (4)\right )}{16 x^4-32 x^9+24 x^{14}-8 x^{19}+x^{24}+\left (8 x^2-8 x^7+2 x^{12}\right ) \log (4)+\log ^2(4)} \, dx=\frac {e^{x}}{x^{12} - 4 x^{7} + 4 x^{2} + 2 \log {\left (2 \right )}} \]
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Time = 0.31 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.15 \[ \int \frac {e^x \left (-8 x+4 x^2+28 x^6-4 x^7-12 x^{11}+x^{12}+\log (4)\right )}{16 x^4-32 x^9+24 x^{14}-8 x^{19}+x^{24}+\left (8 x^2-8 x^7+2 x^{12}\right ) \log (4)+\log ^2(4)} \, dx=\frac {e^{x}}{x^{12} - 4 \, x^{7} + 4 \, x^{2} + 2 \, \log \left (2\right )} \]
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Time = 0.49 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.15 \[ \int \frac {e^x \left (-8 x+4 x^2+28 x^6-4 x^7-12 x^{11}+x^{12}+\log (4)\right )}{16 x^4-32 x^9+24 x^{14}-8 x^{19}+x^{24}+\left (8 x^2-8 x^7+2 x^{12}\right ) \log (4)+\log ^2(4)} \, dx=\frac {e^{x}}{x^{12} - 4 \, x^{7} + 4 \, x^{2} + 2 \, \log \left (2\right )} \]
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Time = 12.28 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.05 \[ \int \frac {e^x \left (-8 x+4 x^2+28 x^6-4 x^7-12 x^{11}+x^{12}+\log (4)\right )}{16 x^4-32 x^9+24 x^{14}-8 x^{19}+x^{24}+\left (8 x^2-8 x^7+2 x^{12}\right ) \log (4)+\log ^2(4)} \, dx=\frac {{\mathrm {e}}^x}{x^{12}-4\,x^7+4\,x^2+\ln \left (4\right )} \]
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