Integrand size = 178, antiderivative size = 30 \[ \int \frac {e^{\frac {192+96 x^2+12 x^4+e^{2 x^2} \left (12 x^2-4 e^4 x^2\right )+e^4 \left (-64-32 x^2-4 x^4\right )+e^{x^2} \left (96 x+24 x^3+e^4 \left (-32 x-8 x^3\right )\right )}{x^4}} \left (-768-192 x^2+e^4 \left (256+64 x^2\right )+e^{2 x^2} \left (-24 x^2+48 x^4+e^4 \left (8 x^2-16 x^4\right )\right )+e^{x^2} \left (-288 x+168 x^3+48 x^5+e^4 \left (96 x-56 x^3-16 x^5\right )\right )\right )}{x^5} \, dx=5+e^{\frac {4 \left (3-e^4\right ) \left (e^{x^2}+\frac {4}{x}+x\right )^2}{x^2}} \]
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Time = 3.03 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.93, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.017, Rules used = {6820, 12, 6838} \[ \int \frac {e^{\frac {192+96 x^2+12 x^4+e^{2 x^2} \left (12 x^2-4 e^4 x^2\right )+e^4 \left (-64-32 x^2-4 x^4\right )+e^{x^2} \left (96 x+24 x^3+e^4 \left (-32 x-8 x^3\right )\right )}{x^4}} \left (-768-192 x^2+e^4 \left (256+64 x^2\right )+e^{2 x^2} \left (-24 x^2+48 x^4+e^4 \left (8 x^2-16 x^4\right )\right )+e^{x^2} \left (-288 x+168 x^3+48 x^5+e^4 \left (96 x-56 x^3-16 x^5\right )\right )\right )}{x^5} \, dx=e^{\frac {4 \left (3-e^4\right ) \left (x^2+e^{x^2} x+4\right )^2}{x^4}} \]
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Rule 12
Rule 6820
Rule 6838
Rubi steps \begin{align*} \text {integral}& = \int \frac {8 e^{-\frac {4 \left (-3+e^4\right ) \left (4+e^{x^2} x+x^2\right )^2}{x^4}} \left (3-e^4\right ) \left (-8 \left (4+x^2\right )+e^{2 x^2} x^2 \left (-1+2 x^2\right )+e^{x^2} x \left (-12+7 x^2+2 x^4\right )\right )}{x^5} \, dx \\ & = \left (8 \left (3-e^4\right )\right ) \int \frac {e^{-\frac {4 \left (-3+e^4\right ) \left (4+e^{x^2} x+x^2\right )^2}{x^4}} \left (-8 \left (4+x^2\right )+e^{2 x^2} x^2 \left (-1+2 x^2\right )+e^{x^2} x \left (-12+7 x^2+2 x^4\right )\right )}{x^5} \, dx \\ & = e^{\frac {4 \left (3-e^4\right ) \left (4+e^{x^2} x+x^2\right )^2}{x^4}} \\ \end{align*}
Time = 5.02 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.87 \[ \int \frac {e^{\frac {192+96 x^2+12 x^4+e^{2 x^2} \left (12 x^2-4 e^4 x^2\right )+e^4 \left (-64-32 x^2-4 x^4\right )+e^{x^2} \left (96 x+24 x^3+e^4 \left (-32 x-8 x^3\right )\right )}{x^4}} \left (-768-192 x^2+e^4 \left (256+64 x^2\right )+e^{2 x^2} \left (-24 x^2+48 x^4+e^4 \left (8 x^2-16 x^4\right )\right )+e^{x^2} \left (-288 x+168 x^3+48 x^5+e^4 \left (96 x-56 x^3-16 x^5\right )\right )\right )}{x^5} \, dx=e^{-\frac {4 \left (-3+e^4\right ) \left (4+e^{x^2} x+x^2\right )^2}{x^4}} \]
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Time = 10.84 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.57
method | result | size |
risch | \({\mathrm e}^{-\frac {4 \left ({\mathrm e}^{4}-3\right ) \left (2 x^{3} {\mathrm e}^{x^{2}}+x^{4}+{\mathrm e}^{2 x^{2}} x^{2}+8 \,{\mathrm e}^{x^{2}} x +8 x^{2}+16\right )}{x^{4}}}\) | \(47\) |
parallelrisch | \({\mathrm e}^{\frac {\left (-4 x^{2} {\mathrm e}^{4}+12 x^{2}\right ) {\mathrm e}^{2 x^{2}}+\left (\left (-8 x^{3}-32 x \right ) {\mathrm e}^{4}+24 x^{3}+96 x \right ) {\mathrm e}^{x^{2}}+\left (-4 x^{4}-32 x^{2}-64\right ) {\mathrm e}^{4}+12 x^{4}+96 x^{2}+192}{x^{4}}}\) | \(79\) |
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Leaf count of result is larger than twice the leaf count of optimal. 78 vs. \(2 (25) = 50\).
Time = 0.26 (sec) , antiderivative size = 78, normalized size of antiderivative = 2.60 \[ \int \frac {e^{\frac {192+96 x^2+12 x^4+e^{2 x^2} \left (12 x^2-4 e^4 x^2\right )+e^4 \left (-64-32 x^2-4 x^4\right )+e^{x^2} \left (96 x+24 x^3+e^4 \left (-32 x-8 x^3\right )\right )}{x^4}} \left (-768-192 x^2+e^4 \left (256+64 x^2\right )+e^{2 x^2} \left (-24 x^2+48 x^4+e^4 \left (8 x^2-16 x^4\right )\right )+e^{x^2} \left (-288 x+168 x^3+48 x^5+e^4 \left (96 x-56 x^3-16 x^5\right )\right )\right )}{x^5} \, dx=e^{\left (\frac {4 \, {\left (3 \, x^{4} + 24 \, x^{2} - {\left (x^{4} + 8 \, x^{2} + 16\right )} e^{4} - {\left (x^{2} e^{4} - 3 \, x^{2}\right )} e^{\left (2 \, x^{2}\right )} + 2 \, {\left (3 \, x^{3} - {\left (x^{3} + 4 \, x\right )} e^{4} + 12 \, x\right )} e^{\left (x^{2}\right )} + 48\right )}}{x^{4}}\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 80 vs. \(2 (24) = 48\).
Time = 0.53 (sec) , antiderivative size = 80, normalized size of antiderivative = 2.67 \[ \int \frac {e^{\frac {192+96 x^2+12 x^4+e^{2 x^2} \left (12 x^2-4 e^4 x^2\right )+e^4 \left (-64-32 x^2-4 x^4\right )+e^{x^2} \left (96 x+24 x^3+e^4 \left (-32 x-8 x^3\right )\right )}{x^4}} \left (-768-192 x^2+e^4 \left (256+64 x^2\right )+e^{2 x^2} \left (-24 x^2+48 x^4+e^4 \left (8 x^2-16 x^4\right )\right )+e^{x^2} \left (-288 x+168 x^3+48 x^5+e^4 \left (96 x-56 x^3-16 x^5\right )\right )\right )}{x^5} \, dx=e^{\frac {12 x^{4} + 96 x^{2} + \left (- 4 x^{2} e^{4} + 12 x^{2}\right ) e^{2 x^{2}} + \left (24 x^{3} + 96 x + \left (- 8 x^{3} - 32 x\right ) e^{4}\right ) e^{x^{2}} + \left (- 4 x^{4} - 32 x^{2} - 64\right ) e^{4} + 192}{x^{4}}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 95 vs. \(2 (25) = 50\).
Time = 0.57 (sec) , antiderivative size = 95, normalized size of antiderivative = 3.17 \[ \int \frac {e^{\frac {192+96 x^2+12 x^4+e^{2 x^2} \left (12 x^2-4 e^4 x^2\right )+e^4 \left (-64-32 x^2-4 x^4\right )+e^{x^2} \left (96 x+24 x^3+e^4 \left (-32 x-8 x^3\right )\right )}{x^4}} \left (-768-192 x^2+e^4 \left (256+64 x^2\right )+e^{2 x^2} \left (-24 x^2+48 x^4+e^4 \left (8 x^2-16 x^4\right )\right )+e^{x^2} \left (-288 x+168 x^3+48 x^5+e^4 \left (96 x-56 x^3-16 x^5\right )\right )\right )}{x^5} \, dx=e^{\left (-\frac {8 \, e^{\left (x^{2} + 4\right )}}{x} + \frac {24 \, e^{\left (x^{2}\right )}}{x} - \frac {32 \, e^{4}}{x^{2}} + \frac {12 \, e^{\left (2 \, x^{2}\right )}}{x^{2}} - \frac {4 \, e^{\left (2 \, x^{2} + 4\right )}}{x^{2}} + \frac {96}{x^{2}} - \frac {32 \, e^{\left (x^{2} + 4\right )}}{x^{3}} + \frac {96 \, e^{\left (x^{2}\right )}}{x^{3}} - \frac {64 \, e^{4}}{x^{4}} + \frac {192}{x^{4}} - 4 \, e^{4} + 12\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 95 vs. \(2 (25) = 50\).
Time = 0.56 (sec) , antiderivative size = 95, normalized size of antiderivative = 3.17 \[ \int \frac {e^{\frac {192+96 x^2+12 x^4+e^{2 x^2} \left (12 x^2-4 e^4 x^2\right )+e^4 \left (-64-32 x^2-4 x^4\right )+e^{x^2} \left (96 x+24 x^3+e^4 \left (-32 x-8 x^3\right )\right )}{x^4}} \left (-768-192 x^2+e^4 \left (256+64 x^2\right )+e^{2 x^2} \left (-24 x^2+48 x^4+e^4 \left (8 x^2-16 x^4\right )\right )+e^{x^2} \left (-288 x+168 x^3+48 x^5+e^4 \left (96 x-56 x^3-16 x^5\right )\right )\right )}{x^5} \, dx=e^{\left (-\frac {8 \, e^{\left (x^{2} + 4\right )}}{x} + \frac {24 \, e^{\left (x^{2}\right )}}{x} - \frac {32 \, e^{4}}{x^{2}} + \frac {12 \, e^{\left (2 \, x^{2}\right )}}{x^{2}} - \frac {4 \, e^{\left (2 \, x^{2} + 4\right )}}{x^{2}} + \frac {96}{x^{2}} - \frac {32 \, e^{\left (x^{2} + 4\right )}}{x^{3}} + \frac {96 \, e^{\left (x^{2}\right )}}{x^{3}} - \frac {64 \, e^{4}}{x^{4}} + \frac {192}{x^{4}} - 4 \, e^{4} + 12\right )} \]
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Time = 12.81 (sec) , antiderivative size = 106, normalized size of antiderivative = 3.53 \[ \int \frac {e^{\frac {192+96 x^2+12 x^4+e^{2 x^2} \left (12 x^2-4 e^4 x^2\right )+e^4 \left (-64-32 x^2-4 x^4\right )+e^{x^2} \left (96 x+24 x^3+e^4 \left (-32 x-8 x^3\right )\right )}{x^4}} \left (-768-192 x^2+e^4 \left (256+64 x^2\right )+e^{2 x^2} \left (-24 x^2+48 x^4+e^4 \left (8 x^2-16 x^4\right )\right )+e^{x^2} \left (-288 x+168 x^3+48 x^5+e^4 \left (96 x-56 x^3-16 x^5\right )\right )\right )}{x^5} \, dx={\mathrm {e}}^{-\frac {32\,{\mathrm {e}}^4}{x^2}}\,{\mathrm {e}}^{-\frac {64\,{\mathrm {e}}^4}{x^4}}\,{\mathrm {e}}^{-4\,{\mathrm {e}}^4}\,{\mathrm {e}}^{\frac {12\,{\mathrm {e}}^{2\,x^2}}{x^2}}\,{\mathrm {e}}^{-\frac {8\,{\mathrm {e}}^{x^2}\,{\mathrm {e}}^4}{x}}\,{\mathrm {e}}^{-\frac {32\,{\mathrm {e}}^{x^2}\,{\mathrm {e}}^4}{x^3}}\,{\mathrm {e}}^{12}\,{\mathrm {e}}^{\frac {96}{x^2}}\,{\mathrm {e}}^{\frac {192}{x^4}}\,{\mathrm {e}}^{-\frac {4\,{\mathrm {e}}^4\,{\mathrm {e}}^{2\,x^2}}{x^2}}\,{\mathrm {e}}^{\frac {24\,{\mathrm {e}}^{x^2}}{x}}\,{\mathrm {e}}^{\frac {96\,{\mathrm {e}}^{x^2}}{x^3}} \]
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