Integrand size = 82, antiderivative size = 29 \[ \int \frac {7 x^2-4 x^3-14 x^4+\left (-3-6 x^2\right ) \log (4)+\left (-2 x-7 x^2-3 \log (4)\right ) \log \left (\frac {-2 x-7 x^2-3 \log (4)}{3 x}\right )}{2 x^3+7 x^4+3 x^2 \log (4)} \, dx=-2 x+\frac {\log \left (\frac {1}{3} (-2-x)-2 x-\frac {\log (4)}{x}\right )}{x} \]
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Leaf count is larger than twice the leaf count of optimal. \(107\) vs. \(2(29)=58\).
Time = 0.47 (sec) , antiderivative size = 107, normalized size of antiderivative = 3.69, number of steps used = 16, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.098, Rules used = {1608, 6860, 1642, 648, 632, 210, 642, 2605} \[ \int \frac {7 x^2-4 x^3-14 x^4+\left (-3-6 x^2\right ) \log (4)+\left (-2 x-7 x^2-3 \log (4)\right ) \log \left (\frac {-2 x-7 x^2-3 \log (4)}{3 x}\right )}{2 x^3+7 x^4+3 x^2 \log (4)} \, dx=\frac {\sqrt {7 \log (64)-1} \log (4096) \arctan \left (\frac {7 x+1}{\sqrt {7 \log (64)-1}}\right )}{\log ^2(64)}+\frac {\left (\log (4) (6-21 \log (64))-7 \log ^2(64)\right ) \arctan \left (\frac {7 x+1}{\sqrt {7 \log (64)-1}}\right )}{\log ^2(64) \sqrt {7 \log (64)-1}}-2 x+\frac {\log \left (-\frac {7 x}{3}-\frac {\log (4)}{x}-\frac {2}{3}\right )}{x} \]
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Rule 210
Rule 632
Rule 642
Rule 648
Rule 1608
Rule 1642
Rule 2605
Rule 6860
Rubi steps \begin{align*} \text {integral}& = \int \frac {7 x^2-4 x^3-14 x^4+\left (-3-6 x^2\right ) \log (4)+\left (-2 x-7 x^2-3 \log (4)\right ) \log \left (\frac {-2 x-7 x^2-3 \log (4)}{3 x}\right )}{x^2 \left (2 x+7 x^2+3 \log (4)\right )} \, dx \\ & = \int \left (\frac {-4 x^3-14 x^4+x^2 (7-6 \log (4))-3 \log (4)}{x^2 \left (2 x+7 x^2+\log (64)\right )}-\frac {\log \left (-\frac {2}{3}-\frac {7 x}{3}-\frac {\log (4)}{x}\right )}{x^2}\right ) \, dx \\ & = \int \frac {-4 x^3-14 x^4+x^2 (7-6 \log (4))-3 \log (4)}{x^2 \left (2 x+7 x^2+\log (64)\right )} \, dx-\int \frac {\log \left (-\frac {2}{3}-\frac {7 x}{3}-\frac {\log (4)}{x}\right )}{x^2} \, dx \\ & = \frac {\log \left (-\frac {2}{3}-\frac {7 x}{3}-\frac {\log (4)}{x}\right )}{x}-\int \frac {7 x^2-3 \log (4)}{x^2 \left (2 x+7 x^2+\log (64)\right )} \, dx+\int \left (-2-\frac {1}{x^2}+\frac {6 \log (4)}{x \log ^2(64)}+\frac {-12 \log (4)-42 x \log (4)+21 \log (4) \log (64)+7 \log ^2(64)-6 \log (4) \log ^2(64)+\log ^2(64) \log (4096)}{\log ^2(64) \left (2 x+7 x^2+\log (64)\right )}\right ) \, dx \\ & = \frac {1}{x}-2 x+\frac {6 \log (4) \log (x)}{\log ^2(64)}+\frac {\log \left (-\frac {2}{3}-\frac {7 x}{3}-\frac {\log (4)}{x}\right )}{x}+\frac {\int \frac {-12 \log (4)-42 x \log (4)+21 \log (4) \log (64)+7 \log ^2(64)-6 \log (4) \log ^2(64)+\log ^2(64) \log (4096)}{2 x+7 x^2+\log (64)} \, dx}{\log ^2(64)}-\int \left (-\frac {1}{x^2}+\frac {6 \log (4)}{x \log ^2(64)}+\frac {-12 \log (4)-42 x \log (4)+21 \log (4) \log (64)+7 \log ^2(64)}{\log ^2(64) \left (2 x+7 x^2+\log (64)\right )}\right ) \, dx \\ & = -2 x+\frac {\log \left (-\frac {2}{3}-\frac {7 x}{3}-\frac {\log (4)}{x}\right )}{x}-\frac {\int \frac {-12 \log (4)-42 x \log (4)+21 \log (4) \log (64)+7 \log ^2(64)}{2 x+7 x^2+\log (64)} \, dx}{\log ^2(64)}-\frac {(3 \log (4)) \int \frac {2+14 x}{2 x+7 x^2+\log (64)} \, dx}{\log ^2(64)}+\frac {\left (7 \log ^2(64)-\log (4096)+\log (64) \log (4398046511104)\right ) \int \frac {1}{2 x+7 x^2+\log (64)} \, dx}{\log ^2(64)} \\ & = -2 x+\frac {\log \left (-\frac {2}{3}-\frac {7 x}{3}-\frac {\log (4)}{x}\right )}{x}-\frac {3 \log (4) \log \left (2 x+7 x^2+\log (64)\right )}{\log ^2(64)}-\left (7-\frac {3 \log (4) (2-7 \log (64))}{\log ^2(64)}\right ) \int \frac {1}{2 x+7 x^2+\log (64)} \, dx+\frac {(3 \log (4)) \int \frac {2+14 x}{2 x+7 x^2+\log (64)} \, dx}{\log ^2(64)}-\frac {\left (2 \left (7 \log ^2(64)-\log (4096)+\log (64) \log (4398046511104)\right )\right ) \text {Subst}\left (\int \frac {1}{-x^2+4 (1-7 \log (64))} \, dx,x,2+14 x\right )}{\log ^2(64)} \\ & = -2 x+\frac {\tan ^{-1}\left (\frac {1+7 x}{\sqrt {-1+7 \log (64)}}\right ) \sqrt {-1+7 \log (64)} \log (4096)}{\log ^2(64)}+\frac {\log \left (-\frac {2}{3}-\frac {7 x}{3}-\frac {\log (4)}{x}\right )}{x}+\left (2 \left (7-\frac {3 \log (4) (2-7 \log (64))}{\log ^2(64)}\right )\right ) \text {Subst}\left (\int \frac {1}{-x^2+4 (1-7 \log (64))} \, dx,x,2+14 x\right ) \\ & = -2 x-\frac {\tan ^{-1}\left (\frac {1+7 x}{\sqrt {-1+7 \log (64)}}\right ) \left (7-\frac {3 \log (4) (2-7 \log (64))}{\log ^2(64)}\right )}{\sqrt {-1+7 \log (64)}}+\frac {\tan ^{-1}\left (\frac {1+7 x}{\sqrt {-1+7 \log (64)}}\right ) \sqrt {-1+7 \log (64)} \log (4096)}{\log ^2(64)}+\frac {\log \left (-\frac {2}{3}-\frac {7 x}{3}-\frac {\log (4)}{x}\right )}{x} \\ \end{align*}
Time = 0.26 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.14 \[ \int \frac {7 x^2-4 x^3-14 x^4+\left (-3-6 x^2\right ) \log (4)+\left (-2 x-7 x^2-3 \log (4)\right ) \log \left (\frac {-2 x-7 x^2-3 \log (4)}{3 x}\right )}{2 x^3+7 x^4+3 x^2 \log (4)} \, dx=-\frac {\log (3)+\frac {x^2 \log (4096)}{\log (64)}-\log \left (-2-7 x-\frac {\log (64)}{x}\right )}{x} \]
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Time = 0.20 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.97
method | result | size |
risch | \(\frac {\ln \left (\frac {-6 \ln \left (2\right )-7 x^{2}-2 x}{3 x}\right )}{x}-2 x\) | \(28\) |
norman | \(\frac {-2 x^{2}+\ln \left (\frac {-6 \ln \left (2\right )-7 x^{2}-2 x}{3 x}\right )}{x}\) | \(30\) |
parallelrisch | \(-\frac {98 x^{2}-56 x -49 \ln \left (-\frac {7 x^{2}+6 \ln \left (2\right )+2 x}{3 x}\right )}{49 x}\) | \(36\) |
default | \(-\frac {\ln \left (3\right )}{x}+\frac {\ln \left (\frac {-6 \ln \left (2\right )-7 x^{2}-2 x}{x}\right )}{x}-\frac {-\frac {\ln \left (7 x^{2}+6 \ln \left (2\right )+2 x \right )}{2}+\sqrt {-1+42 \ln \left (2\right )}\, \arctan \left (\frac {14 x +2}{2 \sqrt {-1+42 \ln \left (2\right )}}\right )}{3 \ln \left (2\right )}-2 x -\frac {\frac {\ln \left (7 x^{2}+6 \ln \left (2\right )+2 x \right )}{2}+\frac {\left (1-42 \ln \left (2\right )\right ) \arctan \left (\frac {14 x +2}{2 \sqrt {-1+42 \ln \left (2\right )}}\right )}{\sqrt {-1+42 \ln \left (2\right )}}}{3 \ln \left (2\right )}\) | \(136\) |
parts | \(-\frac {\ln \left (3\right )}{x}+\frac {\ln \left (\frac {-6 \ln \left (2\right )-7 x^{2}-2 x}{x}\right )}{x}-\frac {-\frac {\ln \left (7 x^{2}+6 \ln \left (2\right )+2 x \right )}{2}+\sqrt {-1+42 \ln \left (2\right )}\, \arctan \left (\frac {14 x +2}{2 \sqrt {-1+42 \ln \left (2\right )}}\right )}{3 \ln \left (2\right )}-2 x -\frac {\frac {\ln \left (7 x^{2}+6 \ln \left (2\right )+2 x \right )}{2}+\frac {\left (1-42 \ln \left (2\right )\right ) \arctan \left (\frac {14 x +2}{2 \sqrt {-1+42 \ln \left (2\right )}}\right )}{\sqrt {-1+42 \ln \left (2\right )}}}{3 \ln \left (2\right )}\) | \(136\) |
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Time = 0.26 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.10 \[ \int \frac {7 x^2-4 x^3-14 x^4+\left (-3-6 x^2\right ) \log (4)+\left (-2 x-7 x^2-3 \log (4)\right ) \log \left (\frac {-2 x-7 x^2-3 \log (4)}{3 x}\right )}{2 x^3+7 x^4+3 x^2 \log (4)} \, dx=-\frac {2 \, x^{2} - \log \left (-\frac {7 \, x^{2} + 2 \, x + 6 \, \log \left (2\right )}{3 \, x}\right )}{x} \]
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Time = 0.10 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.90 \[ \int \frac {7 x^2-4 x^3-14 x^4+\left (-3-6 x^2\right ) \log (4)+\left (-2 x-7 x^2-3 \log (4)\right ) \log \left (\frac {-2 x-7 x^2-3 \log (4)}{3 x}\right )}{2 x^3+7 x^4+3 x^2 \log (4)} \, dx=- 2 x + \frac {\log {\left (\frac {- \frac {7 x^{2}}{3} - \frac {2 x}{3} - 2 \log {\left (2 \right )}}{x} \right )}}{x} \]
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Leaf count of result is larger than twice the leaf count of optimal. 170 vs. \(2 (21) = 42\).
Time = 0.74 (sec) , antiderivative size = 170, normalized size of antiderivative = 5.86 \[ \int \frac {7 x^2-4 x^3-14 x^4+\left (-3-6 x^2\right ) \log (4)+\left (-2 x-7 x^2-3 \log (4)\right ) \log \left (\frac {-2 x-7 x^2-3 \log (4)}{3 x}\right )}{2 x^3+7 x^4+3 x^2 \log (4)} \, dx=\frac {1}{6} \, {\left (\frac {2 \, {\left (21 \, \log \left (2\right ) - 1\right )} \arctan \left (\frac {7 \, x + 1}{\sqrt {42 \, \log \left (2\right ) - 1}}\right )}{\sqrt {42 \, \log \left (2\right ) - 1} \log \left (2\right )^{2}} - \frac {\log \left (7 \, x^{2} + 2 \, x + 6 \, \log \left (2\right )\right )}{\log \left (2\right )^{2}} + \frac {2 \, \log \left (x\right )}{\log \left (2\right )^{2}} + \frac {6}{x \log \left (2\right )}\right )} \log \left (2\right ) - \frac {{\left (21 \, \log \left (2\right ) - 1\right )} \arctan \left (\frac {7 \, x + 1}{\sqrt {42 \, \log \left (2\right ) - 1}}\right )}{3 \, \sqrt {42 \, \log \left (2\right ) - 1} \log \left (2\right )} - \frac {12 \, x^{2} \log \left (2\right ) + 6 \, {\left (\log \left (3\right ) + 1\right )} \log \left (2\right ) - {\left (x + 6 \, \log \left (2\right )\right )} \log \left (-7 \, x^{2} - 2 \, x - 6 \, \log \left (2\right )\right ) + 2 \, {\left (x + 3 \, \log \left (2\right )\right )} \log \left (x\right )}{6 \, x \log \left (2\right )} \]
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Time = 0.28 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.07 \[ \int \frac {7 x^2-4 x^3-14 x^4+\left (-3-6 x^2\right ) \log (4)+\left (-2 x-7 x^2-3 \log (4)\right ) \log \left (\frac {-2 x-7 x^2-3 \log (4)}{3 x}\right )}{2 x^3+7 x^4+3 x^2 \log (4)} \, dx=-2 \, x + \frac {\log \left (-7 \, x^{2} - 2 \, x - 6 \, \log \left (2\right )\right )}{x} - \frac {\log \left (3 \, x\right )}{x} \]
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Time = 12.96 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.86 \[ \int \frac {7 x^2-4 x^3-14 x^4+\left (-3-6 x^2\right ) \log (4)+\left (-2 x-7 x^2-3 \log (4)\right ) \log \left (\frac {-2 x-7 x^2-3 \log (4)}{3 x}\right )}{2 x^3+7 x^4+3 x^2 \log (4)} \, dx=\frac {\ln \left (-\frac {\frac {7\,x^2}{3}+\frac {2\,x}{3}+\ln \left (4\right )}{x}\right )}{x}-2\,x \]
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