Integrand size = 102, antiderivative size = 28 \[ \int \frac {e^{\frac {4}{x+\log (x)}} (-4-4 x)-2 x^2-x^3+x^4+\left (-4 x-4 x^2+2 x^3+2 x^4\right ) \log (x)+\left (-2-5 x+x^2+4 x^3\right ) \log ^2(x)+\left (-2+2 x^2\right ) \log ^3(x)}{x^3+2 x^2 \log (x)+x \log ^2(x)} \, dx=1+e^{\frac {4}{x+\log (x)}}-x-\log (x) \left (2-x^2+\log (x)\right ) \]
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Time = 1.85 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.07, number of steps used = 31, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.069, Rules used = {6820, 6874, 6838, 14, 2404, 2338, 2341} \[ \int \frac {e^{\frac {4}{x+\log (x)}} (-4-4 x)-2 x^2-x^3+x^4+\left (-4 x-4 x^2+2 x^3+2 x^4\right ) \log (x)+\left (-2-5 x+x^2+4 x^3\right ) \log ^2(x)+\left (-2+2 x^2\right ) \log ^3(x)}{x^3+2 x^2 \log (x)+x \log ^2(x)} \, dx=x^2 \log (x)-x-\log ^2(x)+e^{\frac {4}{x+\log (x)}}-2 \log (x) \]
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Rule 14
Rule 2338
Rule 2341
Rule 2404
Rule 6820
Rule 6838
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \frac {(1+x) \left (-4 e^{\frac {4}{x+\log (x)}}+(-2+x) x^2+2 x \left (-2+x^2\right ) \log (x)+\left (-2-3 x+4 x^2\right ) \log ^2(x)+2 (-1+x) \log ^3(x)\right )}{x (x+\log (x))^2} \, dx \\ & = \int \left (-\frac {4 e^{\frac {4}{x+\log (x)}} (1+x)}{x (x+\log (x))^2}+\frac {(-2+x) x (1+x)}{(x+\log (x))^2}+\frac {2 (1+x) \left (-2+x^2\right ) \log (x)}{(x+\log (x))^2}+\frac {(1+x) \left (-2-3 x+4 x^2\right ) \log ^2(x)}{x (x+\log (x))^2}+\frac {2 (-1+x) (1+x) \log ^3(x)}{x (x+\log (x))^2}\right ) \, dx \\ & = 2 \int \frac {(1+x) \left (-2+x^2\right ) \log (x)}{(x+\log (x))^2} \, dx+2 \int \frac {(-1+x) (1+x) \log ^3(x)}{x (x+\log (x))^2} \, dx-4 \int \frac {e^{\frac {4}{x+\log (x)}} (1+x)}{x (x+\log (x))^2} \, dx+\int \frac {(-2+x) x (1+x)}{(x+\log (x))^2} \, dx+\int \frac {(1+x) \left (-2-3 x+4 x^2\right ) \log ^2(x)}{x (x+\log (x))^2} \, dx \\ & = e^{\frac {4}{x+\log (x)}}+2 \int \left (-\frac {x \left (-2-2 x+x^2+x^3\right )}{(x+\log (x))^2}+\frac {(1+x) \left (-2+x^2\right )}{x+\log (x)}\right ) \, dx+2 \int \left (-2 \left (-1+x^2\right )+\frac {(-1+x) (1+x) \log (x)}{x}+\frac {x^2 \left (1-x^2\right )}{(x+\log (x))^2}+\frac {3 x \left (-1+x^2\right )}{x+\log (x)}\right ) \, dx+\int \left (-\frac {2 x}{(x+\log (x))^2}-\frac {x^2}{(x+\log (x))^2}+\frac {x^3}{(x+\log (x))^2}\right ) \, dx+\int \left (\frac {-2-5 x+x^2+4 x^3}{x}+\frac {x \left (-2-5 x+x^2+4 x^3\right )}{(x+\log (x))^2}-\frac {2 \left (-2-5 x+x^2+4 x^3\right )}{x+\log (x)}\right ) \, dx \\ & = e^{\frac {4}{x+\log (x)}}+2 \int \frac {(-1+x) (1+x) \log (x)}{x} \, dx-2 \int \frac {x}{(x+\log (x))^2} \, dx+2 \int \frac {x^2 \left (1-x^2\right )}{(x+\log (x))^2} \, dx-2 \int \frac {x \left (-2-2 x+x^2+x^3\right )}{(x+\log (x))^2} \, dx+2 \int \frac {(1+x) \left (-2+x^2\right )}{x+\log (x)} \, dx-2 \int \frac {-2-5 x+x^2+4 x^3}{x+\log (x)} \, dx-4 \int \left (-1+x^2\right ) \, dx+6 \int \frac {x \left (-1+x^2\right )}{x+\log (x)} \, dx+\int \frac {-2-5 x+x^2+4 x^3}{x} \, dx-\int \frac {x^2}{(x+\log (x))^2} \, dx+\int \frac {x^3}{(x+\log (x))^2} \, dx+\int \frac {x \left (-2-5 x+x^2+4 x^3\right )}{(x+\log (x))^2} \, dx \\ & = e^{\frac {4}{x+\log (x)}}+4 x-\frac {4 x^3}{3}-2 \int \frac {x}{(x+\log (x))^2} \, dx+2 \int \left (-\frac {\log (x)}{x}+x \log (x)\right ) \, dx+2 \int \left (\frac {x^2}{(x+\log (x))^2}-\frac {x^4}{(x+\log (x))^2}\right ) \, dx-2 \int \left (-\frac {2 x}{(x+\log (x))^2}-\frac {2 x^2}{(x+\log (x))^2}+\frac {x^3}{(x+\log (x))^2}+\frac {x^4}{(x+\log (x))^2}\right ) \, dx+2 \int \left (-\frac {2}{x+\log (x)}-\frac {2 x}{x+\log (x)}+\frac {x^2}{x+\log (x)}+\frac {x^3}{x+\log (x)}\right ) \, dx-2 \int \left (-\frac {2}{x+\log (x)}-\frac {5 x}{x+\log (x)}+\frac {x^2}{x+\log (x)}+\frac {4 x^3}{x+\log (x)}\right ) \, dx+6 \int \left (-\frac {x}{x+\log (x)}+\frac {x^3}{x+\log (x)}\right ) \, dx+\int \left (-5-\frac {2}{x}+x+4 x^2\right ) \, dx-\int \frac {x^2}{(x+\log (x))^2} \, dx+\int \frac {x^3}{(x+\log (x))^2} \, dx+\int \left (-\frac {2 x}{(x+\log (x))^2}-\frac {5 x^2}{(x+\log (x))^2}+\frac {x^3}{(x+\log (x))^2}+\frac {4 x^4}{(x+\log (x))^2}\right ) \, dx \\ & = e^{\frac {4}{x+\log (x)}}-x+\frac {x^2}{2}-2 \log (x)-2 \int \frac {\log (x)}{x} \, dx+2 \int x \log (x) \, dx-2 \left (2 \int \frac {x}{(x+\log (x))^2} \, dx\right )+2 \int \frac {x^2}{(x+\log (x))^2} \, dx-2 \int \frac {x^3}{(x+\log (x))^2} \, dx-2 \left (2 \int \frac {x^4}{(x+\log (x))^2} \, dx\right )+2 \int \frac {x^3}{x+\log (x)} \, dx+4 \int \frac {x}{(x+\log (x))^2} \, dx+4 \int \frac {x^2}{(x+\log (x))^2} \, dx+4 \int \frac {x^4}{(x+\log (x))^2} \, dx-4 \int \frac {x}{x+\log (x)} \, dx-5 \int \frac {x^2}{(x+\log (x))^2} \, dx-6 \int \frac {x}{x+\log (x)} \, dx+6 \int \frac {x^3}{x+\log (x)} \, dx-8 \int \frac {x^3}{x+\log (x)} \, dx+10 \int \frac {x}{x+\log (x)} \, dx-\int \frac {x^2}{(x+\log (x))^2} \, dx+2 \int \frac {x^3}{(x+\log (x))^2} \, dx \\ & = e^{\frac {4}{x+\log (x)}}-x-2 \log (x)+x^2 \log (x)-\log ^2(x)-2 \left (2 \int \frac {x}{(x+\log (x))^2} \, dx\right )+2 \int \frac {x^2}{(x+\log (x))^2} \, dx-2 \int \frac {x^3}{(x+\log (x))^2} \, dx-2 \left (2 \int \frac {x^4}{(x+\log (x))^2} \, dx\right )+2 \int \frac {x^3}{x+\log (x)} \, dx+4 \int \frac {x}{(x+\log (x))^2} \, dx+4 \int \frac {x^2}{(x+\log (x))^2} \, dx+4 \int \frac {x^4}{(x+\log (x))^2} \, dx-4 \int \frac {x}{x+\log (x)} \, dx-5 \int \frac {x^2}{(x+\log (x))^2} \, dx-6 \int \frac {x}{x+\log (x)} \, dx+6 \int \frac {x^3}{x+\log (x)} \, dx-8 \int \frac {x^3}{x+\log (x)} \, dx+10 \int \frac {x}{x+\log (x)} \, dx-\int \frac {x^2}{(x+\log (x))^2} \, dx+2 \int \frac {x^3}{(x+\log (x))^2} \, dx \\ \end{align*}
Time = 0.41 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.07 \[ \int \frac {e^{\frac {4}{x+\log (x)}} (-4-4 x)-2 x^2-x^3+x^4+\left (-4 x-4 x^2+2 x^3+2 x^4\right ) \log (x)+\left (-2-5 x+x^2+4 x^3\right ) \log ^2(x)+\left (-2+2 x^2\right ) \log ^3(x)}{x^3+2 x^2 \log (x)+x \log ^2(x)} \, dx=e^{\frac {4}{x+\log (x)}}-x-2 \log (x)+x^2 \log (x)-\log ^2(x) \]
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Time = 7.78 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.07
method | result | size |
risch | \(-\ln \left (x \right )^{2}+x^{2} \ln \left (x \right )-x -2 \ln \left (x \right )+{\mathrm e}^{\frac {4}{x +\ln \left (x \right )}}\) | \(30\) |
parallelrisch | \(-\ln \left (x \right )^{2}+x^{2} \ln \left (x \right )-x -2 \ln \left (x \right )+{\mathrm e}^{\frac {4}{x +\ln \left (x \right )}}\) | \(30\) |
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Time = 0.27 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.96 \[ \int \frac {e^{\frac {4}{x+\log (x)}} (-4-4 x)-2 x^2-x^3+x^4+\left (-4 x-4 x^2+2 x^3+2 x^4\right ) \log (x)+\left (-2-5 x+x^2+4 x^3\right ) \log ^2(x)+\left (-2+2 x^2\right ) \log ^3(x)}{x^3+2 x^2 \log (x)+x \log ^2(x)} \, dx={\left (x^{2} - 2\right )} \log \left (x\right ) - \log \left (x\right )^{2} - x + e^{\left (\frac {4}{x + \log \left (x\right )}\right )} \]
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Time = 0.19 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93 \[ \int \frac {e^{\frac {4}{x+\log (x)}} (-4-4 x)-2 x^2-x^3+x^4+\left (-4 x-4 x^2+2 x^3+2 x^4\right ) \log (x)+\left (-2-5 x+x^2+4 x^3\right ) \log ^2(x)+\left (-2+2 x^2\right ) \log ^3(x)}{x^3+2 x^2 \log (x)+x \log ^2(x)} \, dx=x^{2} \log {\left (x \right )} - x + e^{\frac {4}{x + \log {\left (x \right )}}} - \log {\left (x \right )}^{2} - 2 \log {\left (x \right )} \]
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Time = 0.22 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.96 \[ \int \frac {e^{\frac {4}{x+\log (x)}} (-4-4 x)-2 x^2-x^3+x^4+\left (-4 x-4 x^2+2 x^3+2 x^4\right ) \log (x)+\left (-2-5 x+x^2+4 x^3\right ) \log ^2(x)+\left (-2+2 x^2\right ) \log ^3(x)}{x^3+2 x^2 \log (x)+x \log ^2(x)} \, dx={\left (x^{2} - 2\right )} \log \left (x\right ) - \log \left (x\right )^{2} - x + e^{\left (\frac {4}{x + \log \left (x\right )}\right )} \]
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Time = 0.28 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.04 \[ \int \frac {e^{\frac {4}{x+\log (x)}} (-4-4 x)-2 x^2-x^3+x^4+\left (-4 x-4 x^2+2 x^3+2 x^4\right ) \log (x)+\left (-2-5 x+x^2+4 x^3\right ) \log ^2(x)+\left (-2+2 x^2\right ) \log ^3(x)}{x^3+2 x^2 \log (x)+x \log ^2(x)} \, dx=x^{2} \log \left (x\right ) - \log \left (x\right )^{2} - x + e^{\left (\frac {4}{x + \log \left (x\right )}\right )} - 2 \, \log \left (x\right ) \]
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Time = 14.32 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.04 \[ \int \frac {e^{\frac {4}{x+\log (x)}} (-4-4 x)-2 x^2-x^3+x^4+\left (-4 x-4 x^2+2 x^3+2 x^4\right ) \log (x)+\left (-2-5 x+x^2+4 x^3\right ) \log ^2(x)+\left (-2+2 x^2\right ) \log ^3(x)}{x^3+2 x^2 \log (x)+x \log ^2(x)} \, dx={\mathrm {e}}^{\frac {4}{x+\ln \left (x\right )}}-x-2\,\ln \left (x\right )+x^2\,\ln \left (x\right )-{\ln \left (x\right )}^2 \]
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