Integrand size = 135, antiderivative size = 34 \[ \int \frac {100-160 x-20 x^2+6 x^3+e^x \left (150 x+30 x^2-10 x^3\right )}{\left (-25 x+30 x^2-x^4+e^x \left (-25 x^2+5 x^3\right )\right ) \log ^2\left (\frac {25 x^4-50 x^5+15 x^6+25 e^{2 x} x^6+10 x^7+x^8+e^x \left (50 x^5-50 x^6-10 x^7\right )}{625-250 x+25 x^2}\right )} \, dx=\frac {1}{\log \left (\frac {x^2 \left (-x+\left (1-e^x+\frac {x}{5}\right ) x^2\right )^2}{(-5+x)^2}\right )} \]
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\[ \int \frac {100-160 x-20 x^2+6 x^3+e^x \left (150 x+30 x^2-10 x^3\right )}{\left (-25 x+30 x^2-x^4+e^x \left (-25 x^2+5 x^3\right )\right ) \log ^2\left (\frac {25 x^4-50 x^5+15 x^6+25 e^{2 x} x^6+10 x^7+x^8+e^x \left (50 x^5-50 x^6-10 x^7\right )}{625-250 x+25 x^2}\right )} \, dx=\int \frac {100-160 x-20 x^2+6 x^3+e^x \left (150 x+30 x^2-10 x^3\right )}{\left (-25 x+30 x^2-x^4+e^x \left (-25 x^2+5 x^3\right )\right ) \log ^2\left (\frac {25 x^4-50 x^5+15 x^6+25 e^{2 x} x^6+10 x^7+x^8+e^x \left (50 x^5-50 x^6-10 x^7\right )}{625-250 x+25 x^2}\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {2 \left (-50+\left (80-75 e^x\right ) x-5 \left (-2+3 e^x\right ) x^2+\left (-3+5 e^x\right ) x^3\right )}{(5-x) x \left (5+5 \left (-1+e^x\right ) x-x^2\right ) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )} \, dx \\ & = 2 \int \frac {-50+\left (80-75 e^x\right ) x-5 \left (-2+3 e^x\right ) x^2+\left (-3+5 e^x\right ) x^3}{(5-x) x \left (5+5 \left (-1+e^x\right ) x-x^2\right ) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )} \, dx \\ & = 2 \int \left (\frac {15+3 x-x^2}{(-5+x) x \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )}+\frac {-5-5 x+4 x^2+x^3}{x \left (-5+5 x-5 e^x x+x^2\right ) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )}\right ) \, dx \\ & = 2 \int \frac {15+3 x-x^2}{(-5+x) x \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )} \, dx+2 \int \frac {-5-5 x+4 x^2+x^3}{x \left (-5+5 x-5 e^x x+x^2\right ) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )} \, dx \\ & = 2 \int \left (-\frac {1}{\log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )}+\frac {1}{(-5+x) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )}-\frac {3}{x \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )}\right ) \, dx+2 \int \left (-\frac {5}{\left (-5+5 x-5 e^x x+x^2\right ) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )}-\frac {5}{x \left (-5+5 x-5 e^x x+x^2\right ) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )}+\frac {4 x}{\left (-5+5 x-5 e^x x+x^2\right ) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )}+\frac {x^2}{\left (-5+5 x-5 e^x x+x^2\right ) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )}\right ) \, dx \\ & = -\left (2 \int \frac {1}{\log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )} \, dx\right )+2 \int \frac {1}{(-5+x) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )} \, dx+2 \int \frac {x^2}{\left (-5+5 x-5 e^x x+x^2\right ) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )} \, dx-6 \int \frac {1}{x \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )} \, dx+8 \int \frac {x}{\left (-5+5 x-5 e^x x+x^2\right ) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )} \, dx-10 \int \frac {1}{\left (-5+5 x-5 e^x x+x^2\right ) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )} \, dx-10 \int \frac {1}{x \left (-5+5 x-5 e^x x+x^2\right ) \log ^2\left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )} \, dx \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.88 \[ \int \frac {100-160 x-20 x^2+6 x^3+e^x \left (150 x+30 x^2-10 x^3\right )}{\left (-25 x+30 x^2-x^4+e^x \left (-25 x^2+5 x^3\right )\right ) \log ^2\left (\frac {25 x^4-50 x^5+15 x^6+25 e^{2 x} x^6+10 x^7+x^8+e^x \left (50 x^5-50 x^6-10 x^7\right )}{625-250 x+25 x^2}\right )} \, dx=\frac {1}{\log \left (\frac {x^4 \left (-5-5 \left (-1+e^x\right ) x+x^2\right )^2}{25 (-5+x)^2}\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(67\) vs. \(2(31)=62\).
Time = 1.83 (sec) , antiderivative size = 68, normalized size of antiderivative = 2.00
method | result | size |
parallelrisch | \(\frac {1}{\ln \left (\frac {25 \,{\mathrm e}^{2 x} x^{6}+\left (-10 x^{7}-50 x^{6}+50 x^{5}\right ) {\mathrm e}^{x}+x^{8}+10 x^{7}+15 x^{6}-50 x^{5}+25 x^{4}}{25 x^{2}-250 x +625}\right )}\) | \(68\) |
risch | \(\text {Expression too large to display}\) | \(818\) |
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Leaf count of result is larger than twice the leaf count of optimal. 66 vs. \(2 (30) = 60\).
Time = 0.26 (sec) , antiderivative size = 66, normalized size of antiderivative = 1.94 \[ \int \frac {100-160 x-20 x^2+6 x^3+e^x \left (150 x+30 x^2-10 x^3\right )}{\left (-25 x+30 x^2-x^4+e^x \left (-25 x^2+5 x^3\right )\right ) \log ^2\left (\frac {25 x^4-50 x^5+15 x^6+25 e^{2 x} x^6+10 x^7+x^8+e^x \left (50 x^5-50 x^6-10 x^7\right )}{625-250 x+25 x^2}\right )} \, dx=\frac {1}{\log \left (\frac {x^{8} + 10 \, x^{7} + 25 \, x^{6} e^{\left (2 \, x\right )} + 15 \, x^{6} - 50 \, x^{5} + 25 \, x^{4} - 10 \, {\left (x^{7} + 5 \, x^{6} - 5 \, x^{5}\right )} e^{x}}{25 \, {\left (x^{2} - 10 \, x + 25\right )}}\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 65 vs. \(2 (26) = 52\).
Time = 0.29 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.91 \[ \int \frac {100-160 x-20 x^2+6 x^3+e^x \left (150 x+30 x^2-10 x^3\right )}{\left (-25 x+30 x^2-x^4+e^x \left (-25 x^2+5 x^3\right )\right ) \log ^2\left (\frac {25 x^4-50 x^5+15 x^6+25 e^{2 x} x^6+10 x^7+x^8+e^x \left (50 x^5-50 x^6-10 x^7\right )}{625-250 x+25 x^2}\right )} \, dx=\frac {1}{\log {\left (\frac {x^{8} + 10 x^{7} + 25 x^{6} e^{2 x} + 15 x^{6} - 50 x^{5} + 25 x^{4} + \left (- 10 x^{7} - 50 x^{6} + 50 x^{5}\right ) e^{x}}{25 x^{2} - 250 x + 625} \right )}} \]
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Time = 0.55 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.97 \[ \int \frac {100-160 x-20 x^2+6 x^3+e^x \left (150 x+30 x^2-10 x^3\right )}{\left (-25 x+30 x^2-x^4+e^x \left (-25 x^2+5 x^3\right )\right ) \log ^2\left (\frac {25 x^4-50 x^5+15 x^6+25 e^{2 x} x^6+10 x^7+x^8+e^x \left (50 x^5-50 x^6-10 x^7\right )}{625-250 x+25 x^2}\right )} \, dx=-\frac {1}{2 \, {\left (\log \left (5\right ) - \log \left (-x^{2} + 5 \, x e^{x} - 5 \, x + 5\right ) + \log \left (x - 5\right ) - 2 \, \log \left (x\right )\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 69 vs. \(2 (30) = 60\).
Time = 1.51 (sec) , antiderivative size = 69, normalized size of antiderivative = 2.03 \[ \int \frac {100-160 x-20 x^2+6 x^3+e^x \left (150 x+30 x^2-10 x^3\right )}{\left (-25 x+30 x^2-x^4+e^x \left (-25 x^2+5 x^3\right )\right ) \log ^2\left (\frac {25 x^4-50 x^5+15 x^6+25 e^{2 x} x^6+10 x^7+x^8+e^x \left (50 x^5-50 x^6-10 x^7\right )}{625-250 x+25 x^2}\right )} \, dx=\frac {1}{\log \left (\frac {x^{8} - 10 \, x^{7} e^{x} + 10 \, x^{7} + 25 \, x^{6} e^{\left (2 \, x\right )} - 50 \, x^{6} e^{x} + 15 \, x^{6} + 50 \, x^{5} e^{x} - 50 \, x^{5} + 25 \, x^{4}}{25 \, {\left (x^{2} - 10 \, x + 25\right )}}\right )} \]
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Time = 12.81 (sec) , antiderivative size = 69, normalized size of antiderivative = 2.03 \[ \int \frac {100-160 x-20 x^2+6 x^3+e^x \left (150 x+30 x^2-10 x^3\right )}{\left (-25 x+30 x^2-x^4+e^x \left (-25 x^2+5 x^3\right )\right ) \log ^2\left (\frac {25 x^4-50 x^5+15 x^6+25 e^{2 x} x^6+10 x^7+x^8+e^x \left (50 x^5-50 x^6-10 x^7\right )}{625-250 x+25 x^2}\right )} \, dx=\frac {1}{\ln \left (\frac {25\,x^6\,{\mathrm {e}}^{2\,x}-{\mathrm {e}}^x\,\left (10\,x^7+50\,x^6-50\,x^5\right )+25\,x^4-50\,x^5+15\,x^6+10\,x^7+x^8}{25\,x^2-250\,x+625}\right )} \]
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