Integrand size = 68, antiderivative size = 22 \[ \int \frac {e^{\frac {x+(24-6 x+(-12+3 x) \log (5)) \log ^2(5 x)}{(-12+3 x) \log ^2(5 x)}} (8-2 x-4 \log (5 x))}{\left (48-24 x+3 x^2\right ) \log ^3(5 x)} \, dx=5 e^{-2+\frac {x}{3 (-4+x) \log ^2(5 x)}} \]
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\[ \int \frac {e^{\frac {x+(24-6 x+(-12+3 x) \log (5)) \log ^2(5 x)}{(-12+3 x) \log ^2(5 x)}} (8-2 x-4 \log (5 x))}{\left (48-24 x+3 x^2\right ) \log ^3(5 x)} \, dx=\int \frac {\exp \left (\frac {x+(24-6 x+(-12+3 x) \log (5)) \log ^2(5 x)}{(-12+3 x) \log ^2(5 x)}\right ) (8-2 x-4 \log (5 x))}{\left (48-24 x+3 x^2\right ) \log ^3(5 x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\exp \left (\frac {x+(24-6 x+(-12+3 x) \log (5)) \log ^2(5 x)}{(-12+3 x) \log ^2(5 x)}\right ) (8-2 x-4 \log (5 x))}{3 (-4+x)^2 \log ^3(5 x)} \, dx \\ & = \frac {1}{3} \int \frac {\exp \left (\frac {x+(24-6 x+(-12+3 x) \log (5)) \log ^2(5 x)}{(-12+3 x) \log ^2(5 x)}\right ) (8-2 x-4 \log (5 x))}{(-4+x)^2 \log ^3(5 x)} \, dx \\ & = \frac {1}{3} \int \frac {10 e^{-2+\frac {x}{3 (-4+x) \log ^2(5 x)}} (4-x-2 \log (5 x))}{(4-x)^2 \log ^3(5 x)} \, dx \\ & = \frac {10}{3} \int \frac {e^{-2+\frac {x}{3 (-4+x) \log ^2(5 x)}} (4-x-2 \log (5 x))}{(4-x)^2 \log ^3(5 x)} \, dx \\ & = \frac {10}{3} \int \left (-\frac {e^{-2+\frac {x}{3 (-4+x) \log ^2(5 x)}}}{(-4+x) \log ^3(5 x)}-\frac {2 e^{-2+\frac {x}{3 (-4+x) \log ^2(5 x)}}}{(-4+x)^2 \log ^2(5 x)}\right ) \, dx \\ & = -\left (\frac {10}{3} \int \frac {e^{-2+\frac {x}{3 (-4+x) \log ^2(5 x)}}}{(-4+x) \log ^3(5 x)} \, dx\right )-\frac {20}{3} \int \frac {e^{-2+\frac {x}{3 (-4+x) \log ^2(5 x)}}}{(-4+x)^2 \log ^2(5 x)} \, dx \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00 \[ \int \frac {e^{\frac {x+(24-6 x+(-12+3 x) \log (5)) \log ^2(5 x)}{(-12+3 x) \log ^2(5 x)}} (8-2 x-4 \log (5 x))}{\left (48-24 x+3 x^2\right ) \log ^3(5 x)} \, dx=5 e^{-2+\frac {x}{3 (-4+x) \log ^2(5 x)}} \]
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Time = 1.24 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.73
method | result | size |
parallelrisch | \({\mathrm e}^{\frac {\left (\left (3 x -12\right ) \ln \left (5\right )-6 x +24\right ) \ln \left (5 x \right )^{2}+x}{\left (3 x -12\right ) \ln \left (5 x \right )^{2}}}\) | \(38\) |
risch | \(5^{\frac {x}{x -4}} \left (\frac {1}{625}\right )^{\frac {1}{x -4}} {\mathrm e}^{-\frac {6 x \ln \left (5 x \right )^{2}-24 \ln \left (5 x \right )^{2}-x}{3 \left (x -4\right ) \ln \left (5 x \right )^{2}}}\) | \(53\) |
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Time = 0.31 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.59 \[ \int \frac {e^{\frac {x+(24-6 x+(-12+3 x) \log (5)) \log ^2(5 x)}{(-12+3 x) \log ^2(5 x)}} (8-2 x-4 \log (5 x))}{\left (48-24 x+3 x^2\right ) \log ^3(5 x)} \, dx=e^{\left (\frac {3 \, {\left ({\left (x - 4\right )} \log \left (5\right ) - 2 \, x + 8\right )} \log \left (5 \, x\right )^{2} + x}{3 \, {\left (x - 4\right )} \log \left (5 \, x\right )^{2}}\right )} \]
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Time = 0.40 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.55 \[ \int \frac {e^{\frac {x+(24-6 x+(-12+3 x) \log (5)) \log ^2(5 x)}{(-12+3 x) \log ^2(5 x)}} (8-2 x-4 \log (5 x))}{\left (48-24 x+3 x^2\right ) \log ^3(5 x)} \, dx=e^{\frac {x + \left (- 6 x + \left (3 x - 12\right ) \log {\left (5 \right )} + 24\right ) \log {\left (5 x \right )}^{2}}{\left (3 x - 12\right ) \log {\left (5 x \right )}^{2}}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 62 vs. \(2 (19) = 38\).
Time = 0.46 (sec) , antiderivative size = 62, normalized size of antiderivative = 2.82 \[ \int \frac {e^{\frac {x+(24-6 x+(-12+3 x) \log (5)) \log ^2(5 x)}{(-12+3 x) \log ^2(5 x)}} (8-2 x-4 \log (5 x))}{\left (48-24 x+3 x^2\right ) \log ^3(5 x)} \, dx=5 \, e^{\left (\frac {4}{3 \, {\left (x \log \left (5\right )^{2} + {\left (x - 4\right )} \log \left (x\right )^{2} - 4 \, \log \left (5\right )^{2} + 2 \, {\left (x \log \left (5\right ) - 4 \, \log \left (5\right )\right )} \log \left (x\right )\right )}} + \frac {1}{3 \, {\left (\log \left (5\right )^{2} + 2 \, \log \left (5\right ) \log \left (x\right ) + \log \left (x\right )^{2}\right )}} - 2\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 137 vs. \(2 (19) = 38\).
Time = 1.05 (sec) , antiderivative size = 137, normalized size of antiderivative = 6.23 \[ \int \frac {e^{\frac {x+(24-6 x+(-12+3 x) \log (5)) \log ^2(5 x)}{(-12+3 x) \log ^2(5 x)}} (8-2 x-4 \log (5 x))}{\left (48-24 x+3 x^2\right ) \log ^3(5 x)} \, dx=e^{\left (\frac {x \log \left (5\right ) \log \left (5 \, x\right )^{2}}{x \log \left (5 \, x\right )^{2} - 4 \, \log \left (5 \, x\right )^{2}} - \frac {2 \, x \log \left (5 \, x\right )^{2}}{x \log \left (5 \, x\right )^{2} - 4 \, \log \left (5 \, x\right )^{2}} - \frac {4 \, \log \left (5\right ) \log \left (5 \, x\right )^{2}}{x \log \left (5 \, x\right )^{2} - 4 \, \log \left (5 \, x\right )^{2}} + \frac {8 \, \log \left (5 \, x\right )^{2}}{x \log \left (5 \, x\right )^{2} - 4 \, \log \left (5 \, x\right )^{2}} + \frac {x}{3 \, {\left (x \log \left (5 \, x\right )^{2} - 4 \, \log \left (5 \, x\right )^{2}\right )}}\right )} \]
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Time = 12.01 (sec) , antiderivative size = 401, normalized size of antiderivative = 18.23 \[ \int \frac {e^{\frac {x+(24-6 x+(-12+3 x) \log (5)) \log ^2(5 x)}{(-12+3 x) \log ^2(5 x)}} (8-2 x-4 \log (5 x))}{\left (48-24 x+3 x^2\right ) \log ^3(5 x)} \, dx=\frac {5^{\frac {{\ln \left (x\right )}^2}{{\ln \left (x\right )}^2+2\,\ln \left (5\right )\,\ln \left (x\right )+{\ln \left (5\right )}^2}}\,{\mathrm {e}}^{\frac {3\,x\,{\ln \left (5\right )}^3}{3\,x\,{\ln \left (x\right )}^2-12\,{\ln \left (x\right )}^2+3\,x\,{\ln \left (5\right )}^2-24\,\ln \left (5\right )\,\ln \left (x\right )-12\,{\ln \left (5\right )}^2+6\,x\,\ln \left (5\right )\,\ln \left (x\right )}}\,{\mathrm {e}}^{-\frac {6\,x\,{\ln \left (5\right )}^2}{3\,x\,{\ln \left (x\right )}^2-12\,{\ln \left (x\right )}^2+3\,x\,{\ln \left (5\right )}^2-24\,\ln \left (5\right )\,\ln \left (x\right )-12\,{\ln \left (5\right )}^2+6\,x\,\ln \left (5\right )\,\ln \left (x\right )}}\,{\mathrm {e}}^{\frac {24\,{\ln \left (x\right )}^2}{3\,x\,{\ln \left (x\right )}^2-12\,{\ln \left (x\right )}^2+3\,x\,{\ln \left (5\right )}^2-24\,\ln \left (5\right )\,\ln \left (x\right )-12\,{\ln \left (5\right )}^2+6\,x\,\ln \left (5\right )\,\ln \left (x\right )}}\,{\mathrm {e}}^{\frac {x}{3\,x\,{\ln \left (x\right )}^2-12\,{\ln \left (x\right )}^2+3\,x\,{\ln \left (5\right )}^2-24\,\ln \left (5\right )\,\ln \left (x\right )-12\,{\ln \left (5\right )}^2+6\,x\,\ln \left (5\right )\,\ln \left (x\right )}}\,{\mathrm {e}}^{-\frac {6\,x\,{\ln \left (x\right )}^2}{3\,x\,{\ln \left (x\right )}^2-12\,{\ln \left (x\right )}^2+3\,x\,{\ln \left (5\right )}^2-24\,\ln \left (5\right )\,\ln \left (x\right )-12\,{\ln \left (5\right )}^2+6\,x\,\ln \left (5\right )\,\ln \left (x\right )}}\,{\mathrm {e}}^{-\frac {12\,{\ln \left (5\right )}^3}{3\,x\,{\ln \left (x\right )}^2-12\,{\ln \left (x\right )}^2+3\,x\,{\ln \left (5\right )}^2-24\,\ln \left (5\right )\,\ln \left (x\right )-12\,{\ln \left (5\right )}^2+6\,x\,\ln \left (5\right )\,\ln \left (x\right )}}\,{\mathrm {e}}^{\frac {24\,{\ln \left (5\right )}^2}{3\,x\,{\ln \left (x\right )}^2-12\,{\ln \left (x\right )}^2+3\,x\,{\ln \left (5\right )}^2-24\,\ln \left (5\right )\,\ln \left (x\right )-12\,{\ln \left (5\right )}^2+6\,x\,\ln \left (5\right )\,\ln \left (x\right )}}}{x^{\frac {2\,\left (2\,\ln \left (5\right )-{\ln \left (5\right )}^2\right )}{{\ln \left (x\right )}^2+2\,\ln \left (5\right )\,\ln \left (x\right )+{\ln \left (5\right )}^2}}} \]
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