Integrand size = 59, antiderivative size = 17 \[ \int \frac {25 \sqrt [35]{e}+\left (1-10 \sqrt [35]{e}\right ) e^x+e^{\frac {1}{35}+2 x}}{25 \sqrt [35]{e}-10 e^{\frac {1}{35}+x}+e^{\frac {1}{35}+2 x}} \, dx=\frac {1}{\sqrt [35]{e} \left (5-e^x\right )}+x \]
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Time = 0.05 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.051, Rules used = {2320, 12, 907} \[ \int \frac {25 \sqrt [35]{e}+\left (1-10 \sqrt [35]{e}\right ) e^x+e^{\frac {1}{35}+2 x}}{25 \sqrt [35]{e}-10 e^{\frac {1}{35}+x}+e^{\frac {1}{35}+2 x}} \, dx=x+\frac {1}{\sqrt [35]{e} \left (5-e^x\right )} \]
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Rule 12
Rule 907
Rule 2320
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \frac {25 \sqrt [35]{e}+\left (1-10 \sqrt [35]{e}\right ) x+\sqrt [35]{e} x^2}{\sqrt [35]{e} (5-x)^2 x} \, dx,x,e^x\right ) \\ & = \frac {\text {Subst}\left (\int \frac {25 \sqrt [35]{e}+\left (1-10 \sqrt [35]{e}\right ) x+\sqrt [35]{e} x^2}{(5-x)^2 x} \, dx,x,e^x\right )}{\sqrt [35]{e}} \\ & = \frac {\text {Subst}\left (\int \left (\frac {1}{(-5+x)^2}+\frac {\sqrt [35]{e}}{x}\right ) \, dx,x,e^x\right )}{\sqrt [35]{e}} \\ & = \frac {1}{\sqrt [35]{e} \left (5-e^x\right )}+x \\ \end{align*}
Time = 0.19 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.47 \[ \int \frac {25 \sqrt [35]{e}+\left (1-10 \sqrt [35]{e}\right ) e^x+e^{\frac {1}{35}+2 x}}{25 \sqrt [35]{e}-10 e^{\frac {1}{35}+x}+e^{\frac {1}{35}+2 x}} \, dx=\frac {\frac {1}{\sqrt [35]{e}}+5 x-e^x x}{5-e^x} \]
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Time = 0.13 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.76
method | result | size |
risch | \(x -\frac {{\mathrm e}^{-\frac {1}{35}}}{{\mathrm e}^{x}-5}\) | \(13\) |
derivativedivides | \({\mathrm e}^{-\frac {1}{35}} \left (-\frac {1}{{\mathrm e}^{x}-5}+{\mathrm e}^{\frac {1}{35}} \ln \left ({\mathrm e}^{x}\right )\right )\) | \(21\) |
default | \({\mathrm e}^{-\frac {1}{35}} \left (-\frac {1}{{\mathrm e}^{x}-5}+{\mathrm e}^{\frac {1}{35}} \ln \left ({\mathrm e}^{x}\right )\right )\) | \(21\) |
norman | \(\frac {{\mathrm e}^{x} x -5 x -{\mathrm e}^{-\frac {1}{35}}}{{\mathrm e}^{x}-5}\) | \(22\) |
parallelrisch | \(\frac {\left (-1+{\mathrm e}^{\frac {1}{35}} x \,{\mathrm e}^{x}-5 \,{\mathrm e}^{\frac {1}{35}} x \right ) {\mathrm e}^{-\frac {1}{35}}}{{\mathrm e}^{x}-5}\) | \(25\) |
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Leaf count of result is larger than twice the leaf count of optimal. 28 vs. \(2 (12) = 24\).
Time = 0.33 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.65 \[ \int \frac {25 \sqrt [35]{e}+\left (1-10 \sqrt [35]{e}\right ) e^x+e^{\frac {1}{35}+2 x}}{25 \sqrt [35]{e}-10 e^{\frac {1}{35}+x}+e^{\frac {1}{35}+2 x}} \, dx=\frac {5 \, x e^{\frac {1}{35}} - x e^{\left (x + \frac {1}{35}\right )} + 1}{5 \, e^{\frac {1}{35}} - e^{\left (x + \frac {1}{35}\right )}} \]
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Time = 0.04 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00 \[ \int \frac {25 \sqrt [35]{e}+\left (1-10 \sqrt [35]{e}\right ) e^x+e^{\frac {1}{35}+2 x}}{25 \sqrt [35]{e}-10 e^{\frac {1}{35}+x}+e^{\frac {1}{35}+2 x}} \, dx=x - \frac {1}{e^{\frac {1}{35}} e^{x} - 5 e^{\frac {1}{35}}} \]
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Time = 0.19 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.88 \[ \int \frac {25 \sqrt [35]{e}+\left (1-10 \sqrt [35]{e}\right ) e^x+e^{\frac {1}{35}+2 x}}{25 \sqrt [35]{e}-10 e^{\frac {1}{35}+x}+e^{\frac {1}{35}+2 x}} \, dx=x + \frac {1}{5 \, e^{\frac {1}{35}} - e^{\left (x + \frac {1}{35}\right )}} \]
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Time = 0.30 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.71 \[ \int \frac {25 \sqrt [35]{e}+\left (1-10 \sqrt [35]{e}\right ) e^x+e^{\frac {1}{35}+2 x}}{25 \sqrt [35]{e}-10 e^{\frac {1}{35}+x}+e^{\frac {1}{35}+2 x}} \, dx=x - \frac {e^{\left (-\frac {1}{35}\right )}}{e^{x} - 5} \]
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Time = 11.68 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.88 \[ \int \frac {25 \sqrt [35]{e}+\left (1-10 \sqrt [35]{e}\right ) e^x+e^{\frac {1}{35}+2 x}}{25 \sqrt [35]{e}-10 e^{\frac {1}{35}+x}+e^{\frac {1}{35}+2 x}} \, dx=x-\frac {1}{{\mathrm {e}}^{x+\frac {1}{35}}-5\,{\mathrm {e}}^{1/35}} \]
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