Integrand size = 29, antiderivative size = 17 \[ \int e^{\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )} \left (1+3 e^x x\right ) \, dx=e^{-\frac {20}{3}-3 e^x (1-x)+x} \]
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\[ \int e^{\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )} \left (1+3 e^x x\right ) \, dx=\int e^{\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )} \left (1+3 e^x x\right ) \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (e^{\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )}+3 e^{x+\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )} x\right ) \, dx \\ & = 3 \int e^{x+\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )} x \, dx+\int e^{\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )} \, dx \\ & = 3 \int e^{\frac {1}{3} \left (-20-9 e^x+6 x+9 e^x x\right )} x \, dx+\int e^{\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )} \, dx \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.88 \[ \int e^{\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )} \left (1+3 e^x x\right ) \, dx=e^{-\frac {20}{3}+3 e^x (-1+x)+x} \]
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Time = 0.08 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.82
method | result | size |
derivativedivides | \({\mathrm e}^{\frac {\left (9 x -9\right ) {\mathrm e}^{x}}{3}+x -\frac {20}{3}}\) | \(14\) |
default | \({\mathrm e}^{\frac {\left (9 x -9\right ) {\mathrm e}^{x}}{3}+x -\frac {20}{3}}\) | \(14\) |
norman | \({\mathrm e}^{\frac {\left (9 x -9\right ) {\mathrm e}^{x}}{3}+x -\frac {20}{3}}\) | \(14\) |
risch | \({\mathrm e}^{3 \,{\mathrm e}^{x} x -3 \,{\mathrm e}^{x}+x -\frac {20}{3}}\) | \(14\) |
parallelrisch | \({\mathrm e}^{3 \,{\mathrm e}^{x} x -3 \,{\mathrm e}^{x}+x -\frac {20}{3}}\) | \(14\) |
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Time = 0.31 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.65 \[ \int e^{\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )} \left (1+3 e^x x\right ) \, dx=e^{\left (3 \, {\left (x - 1\right )} e^{x} + x - \frac {20}{3}\right )} \]
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Time = 0.10 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.82 \[ \int e^{\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )} \left (1+3 e^x x\right ) \, dx=e^{x + \left (3 x - 3\right ) e^{x} - \frac {20}{3}} \]
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Time = 0.27 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.76 \[ \int e^{\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )} \left (1+3 e^x x\right ) \, dx=e^{\left (3 \, x e^{x} + x - 3 \, e^{x} - \frac {20}{3}\right )} \]
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Time = 0.28 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.76 \[ \int e^{\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )} \left (1+3 e^x x\right ) \, dx=e^{\left (3 \, x e^{x} + x - 3 \, e^{x} - \frac {20}{3}\right )} \]
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Time = 0.08 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.94 \[ \int e^{\frac {1}{3} \left (-20+3 x+e^x (-9+9 x)\right )} \left (1+3 e^x x\right ) \, dx={\mathrm {e}}^{3\,x\,{\mathrm {e}}^x}\,{\mathrm {e}}^{-\frac {20}{3}}\,{\mathrm {e}}^{-3\,{\mathrm {e}}^x}\,{\mathrm {e}}^x \]
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