Integrand size = 120, antiderivative size = 24 \[ \int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \left (20 x^3-20 x \log ^4(7)+\left (20 e^5 x^2-20 x^3+\left (20 e^5-20 x\right ) \log ^4(7)\right ) \log \left (-e^5+x\right )\right )}{e^5 x^4-x^5+\left (-2 e^5 x^2+2 x^3\right ) \log ^4(7)+\left (e^5-x\right ) \log ^8(7)} \, dx=\left (-e^5+x\right )^{\frac {20}{-x+\frac {\log ^4(7)}{x}}} \]
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\[ \int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \left (20 x^3-20 x \log ^4(7)+\left (20 e^5 x^2-20 x^3+\left (20 e^5-20 x\right ) \log ^4(7)\right ) \log \left (-e^5+x\right )\right )}{e^5 x^4-x^5+\left (-2 e^5 x^2+2 x^3\right ) \log ^4(7)+\left (e^5-x\right ) \log ^8(7)} \, dx=\int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \left (20 x^3-20 x \log ^4(7)+\left (20 e^5 x^2-20 x^3+\left (20 e^5-20 x\right ) \log ^4(7)\right ) \log \left (-e^5+x\right )\right )}{e^5 x^4-x^5+\left (-2 e^5 x^2+2 x^3\right ) \log ^4(7)+\left (e^5-x\right ) \log ^8(7)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {20 \left (-e^5+x\right )^{-1+\frac {20 x}{-x^2+\log ^4(7)}} \left (-x^3+x \log ^4(7)-\left (e^5-x\right ) \left (x^2+\log ^4(7)\right ) \log \left (-e^5+x\right )\right )}{\left (x^2-\log ^4(7)\right )^2} \, dx \\ & = 20 \int \frac {\left (-e^5+x\right )^{-1+\frac {20 x}{-x^2+\log ^4(7)}} \left (-x^3+x \log ^4(7)-\left (e^5-x\right ) \left (x^2+\log ^4(7)\right ) \log \left (-e^5+x\right )\right )}{\left (x^2-\log ^4(7)\right )^2} \, dx \\ & = 20 \int \left (-\frac {x \left (-e^5+x\right )^{-1+\frac {20 x}{-x^2+\log ^4(7)}}}{x^2-\log ^4(7)}+\frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \left (x^2+\log ^4(7)\right ) \log \left (-e^5+x\right )}{\left (x^2-\log ^4(7)\right )^2}\right ) \, dx \\ & = -\left (20 \int \frac {x \left (-e^5+x\right )^{-1+\frac {20 x}{-x^2+\log ^4(7)}}}{x^2-\log ^4(7)} \, dx\right )+20 \int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \left (x^2+\log ^4(7)\right ) \log \left (-e^5+x\right )}{\left (x^2-\log ^4(7)\right )^2} \, dx \\ & = -\left (20 \int \left (\frac {\left (-e^5+x\right )^{-1+\frac {20 x}{-x^2+\log ^4(7)}}}{2 \left (x-\log ^2(7)\right )}+\frac {\left (-e^5+x\right )^{-1+\frac {20 x}{-x^2+\log ^4(7)}}}{2 \left (x+\log ^2(7)\right )}\right ) \, dx\right )+20 \int \left (\frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \log \left (-e^5+x\right )}{2 \left (x-\log ^2(7)\right )^2}+\frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \log \left (-e^5+x\right )}{2 \left (x+\log ^2(7)\right )^2}\right ) \, dx \\ & = -\left (10 \int \frac {\left (-e^5+x\right )^{-1+\frac {20 x}{-x^2+\log ^4(7)}}}{x-\log ^2(7)} \, dx\right )-10 \int \frac {\left (-e^5+x\right )^{-1+\frac {20 x}{-x^2+\log ^4(7)}}}{x+\log ^2(7)} \, dx+10 \int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \log \left (-e^5+x\right )}{\left (x-\log ^2(7)\right )^2} \, dx+10 \int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \log \left (-e^5+x\right )}{\left (x+\log ^2(7)\right )^2} \, dx \\ & = \frac {\left (-e^5+x\right )^{-\frac {20 x}{x^2-\log ^4(7)}} \, _2F_1\left (1,-\frac {20 x}{x^2-\log ^4(7)};1-\frac {20 x}{x^2-\log ^4(7)};\frac {e^5-x}{e^5-\log ^2(7)}\right ) \left (x^2-\log ^4(7)\right )}{2 x \left (e^5-\log ^2(7)\right )}+\frac {\left (-e^5+x\right )^{-\frac {20 x}{x^2-\log ^4(7)}} \, _2F_1\left (1,-\frac {20 x}{x^2-\log ^4(7)};1-\frac {20 x}{x^2-\log ^4(7)};\frac {e^5-x}{e^5+\log ^2(7)}\right ) \left (x^2-\log ^4(7)\right )}{2 x \left (e^5+\log ^2(7)\right )}+10 \int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \log \left (-e^5+x\right )}{\left (x-\log ^2(7)\right )^2} \, dx+10 \int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \log \left (-e^5+x\right )}{\left (x+\log ^2(7)\right )^2} \, dx \\ \end{align*}
Time = 1.53 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.96 \[ \int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \left (20 x^3-20 x \log ^4(7)+\left (20 e^5 x^2-20 x^3+\left (20 e^5-20 x\right ) \log ^4(7)\right ) \log \left (-e^5+x\right )\right )}{e^5 x^4-x^5+\left (-2 e^5 x^2+2 x^3\right ) \log ^4(7)+\left (e^5-x\right ) \log ^8(7)} \, dx=\left (-e^5+x\right )^{-\frac {20 x}{x^2-\log ^4(7)}} \]
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Time = 17.72 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.04
method | result | size |
risch | \(\left (-{\mathrm e}^{5}+x \right )^{\frac {20 x}{\ln \left (7\right )^{4}-x^{2}}}\) | \(25\) |
parallelrisch | \({\mathrm e}^{\frac {20 x \ln \left (-{\mathrm e}^{5}+x \right )}{\ln \left (7\right )^{4}-x^{2}}}\) | \(26\) |
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Time = 0.30 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.92 \[ \int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \left (20 x^3-20 x \log ^4(7)+\left (20 e^5 x^2-20 x^3+\left (20 e^5-20 x\right ) \log ^4(7)\right ) \log \left (-e^5+x\right )\right )}{e^5 x^4-x^5+\left (-2 e^5 x^2+2 x^3\right ) \log ^4(7)+\left (e^5-x\right ) \log ^8(7)} \, dx={\left (x - e^{5}\right )}^{\frac {20 \, x}{\log \left (7\right )^{4} - x^{2}}} \]
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Time = 0.31 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.79 \[ \int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \left (20 x^3-20 x \log ^4(7)+\left (20 e^5 x^2-20 x^3+\left (20 e^5-20 x\right ) \log ^4(7)\right ) \log \left (-e^5+x\right )\right )}{e^5 x^4-x^5+\left (-2 e^5 x^2+2 x^3\right ) \log ^4(7)+\left (e^5-x\right ) \log ^8(7)} \, dx=e^{\frac {20 x \log {\left (x - e^{5} \right )}}{- x^{2} + \log {\left (7 \right )}^{4}}} \]
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Time = 0.43 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.58 \[ \int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \left (20 x^3-20 x \log ^4(7)+\left (20 e^5 x^2-20 x^3+\left (20 e^5-20 x\right ) \log ^4(7)\right ) \log \left (-e^5+x\right )\right )}{e^5 x^4-x^5+\left (-2 e^5 x^2+2 x^3\right ) \log ^4(7)+\left (e^5-x\right ) \log ^8(7)} \, dx=e^{\left (-\frac {10 \, \log \left (x - e^{5}\right )}{\log \left (7\right )^{2} + x} + \frac {10 \, \log \left (x - e^{5}\right )}{\log \left (7\right )^{2} - x}\right )} \]
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\[ \int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \left (20 x^3-20 x \log ^4(7)+\left (20 e^5 x^2-20 x^3+\left (20 e^5-20 x\right ) \log ^4(7)\right ) \log \left (-e^5+x\right )\right )}{e^5 x^4-x^5+\left (-2 e^5 x^2+2 x^3\right ) \log ^4(7)+\left (e^5-x\right ) \log ^8(7)} \, dx=\int { \frac {20 \, {\left (x \log \left (7\right )^{4} - x^{3} + {\left ({\left (x - e^{5}\right )} \log \left (7\right )^{4} + x^{3} - x^{2} e^{5}\right )} \log \left (x - e^{5}\right )\right )} {\left (x - e^{5}\right )}^{\frac {20 \, x}{\log \left (7\right )^{4} - x^{2}}}}{{\left (x - e^{5}\right )} \log \left (7\right )^{8} + x^{5} - x^{4} e^{5} - 2 \, {\left (x^{3} - x^{2} e^{5}\right )} \log \left (7\right )^{4}} \,d x } \]
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Time = 12.00 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.92 \[ \int \frac {\left (-e^5+x\right )^{\frac {20 x}{-x^2+\log ^4(7)}} \left (20 x^3-20 x \log ^4(7)+\left (20 e^5 x^2-20 x^3+\left (20 e^5-20 x\right ) \log ^4(7)\right ) \log \left (-e^5+x\right )\right )}{e^5 x^4-x^5+\left (-2 e^5 x^2+2 x^3\right ) \log ^4(7)+\left (e^5-x\right ) \log ^8(7)} \, dx={\left (x-{\mathrm {e}}^5\right )}^{\frac {20\,x}{{\ln \left (7\right )}^4-x^2}} \]
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