Integrand size = 105, antiderivative size = 19 \[ \int \frac {e^{179 x/3} (-6-349 x)+e^x \left (-12-6 x+3 x^2\right )}{24 x^3+3 e^{176 x} x^3+36 x^4+18 x^5+3 x^6+e^{352 x/3} \left (18 x^3+9 x^4\right )+e^{176 x/3} \left (36 x^3+36 x^4+9 x^5\right )} \, dx=\frac {e^x}{x^2 \left (2+e^{176 x/3}+x\right )^2} \]
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\[ \int \frac {e^{179 x/3} (-6-349 x)+e^x \left (-12-6 x+3 x^2\right )}{24 x^3+3 e^{176 x} x^3+36 x^4+18 x^5+3 x^6+e^{352 x/3} \left (18 x^3+9 x^4\right )+e^{176 x/3} \left (36 x^3+36 x^4+9 x^5\right )} \, dx=\int \frac {e^{179 x/3} (-6-349 x)+e^x \left (-12-6 x+3 x^2\right )}{24 x^3+3 e^{176 x} x^3+36 x^4+18 x^5+3 x^6+e^{352 x/3} \left (18 x^3+9 x^4\right )+e^{176 x/3} \left (36 x^3+36 x^4+9 x^5\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {e^x \left (-12-6 x+3 x^2-e^{176 x/3} (6+349 x)\right )}{3 x^3 \left (2+e^{176 x/3}+x\right )^3} \, dx \\ & = \frac {1}{3} \int \frac {e^x \left (-12-6 x+3 x^2-e^{176 x/3} (6+349 x)\right )}{x^3 \left (2+e^{176 x/3}+x\right )^3} \, dx \\ & = \frac {1}{3} \int \left (\frac {2 e^x (349+176 x)}{x^2 \left (2+e^{176 x/3}+x\right )^3}-\frac {e^x (6+349 x)}{x^3 \left (2+e^{176 x/3}+x\right )^2}\right ) \, dx \\ & = -\left (\frac {1}{3} \int \frac {e^x (6+349 x)}{x^3 \left (2+e^{176 x/3}+x\right )^2} \, dx\right )+\frac {2}{3} \int \frac {e^x (349+176 x)}{x^2 \left (2+e^{176 x/3}+x\right )^3} \, dx \\ & = -\left (\frac {1}{3} \int \left (\frac {6 e^x}{x^3 \left (2+e^{176 x/3}+x\right )^2}+\frac {349 e^x}{x^2 \left (2+e^{176 x/3}+x\right )^2}\right ) \, dx\right )+\frac {2}{3} \int \left (\frac {349 e^x}{x^2 \left (2+e^{176 x/3}+x\right )^3}+\frac {176 e^x}{x \left (2+e^{176 x/3}+x\right )^3}\right ) \, dx \\ & = -\left (2 \int \frac {e^x}{x^3 \left (2+e^{176 x/3}+x\right )^2} \, dx\right )-\frac {349}{3} \int \frac {e^x}{x^2 \left (2+e^{176 x/3}+x\right )^2} \, dx+\frac {352}{3} \int \frac {e^x}{x \left (2+e^{176 x/3}+x\right )^3} \, dx+\frac {698}{3} \int \frac {e^x}{x^2 \left (2+e^{176 x/3}+x\right )^3} \, dx \\ \end{align*}
Time = 1.79 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00 \[ \int \frac {e^{179 x/3} (-6-349 x)+e^x \left (-12-6 x+3 x^2\right )}{24 x^3+3 e^{176 x} x^3+36 x^4+18 x^5+3 x^6+e^{352 x/3} \left (18 x^3+9 x^4\right )+e^{176 x/3} \left (36 x^3+36 x^4+9 x^5\right )} \, dx=\frac {e^x}{x^2 \left (2+e^{176 x/3}+x\right )^2} \]
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Time = 0.56 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.84
method | result | size |
risch | \(\frac {{\mathrm e}^{x}}{x^{2} \left ({\mathrm e}^{\frac {176 x}{3}}+x +2\right )^{2}}\) | \(16\) |
parallelrisch | \(\frac {{\mathrm e}^{x}}{x^{2} \left ({\mathrm e}^{\frac {352 x}{3}}+2 \,{\mathrm e}^{\frac {176 x}{3}} x +x^{2}+4 \,{\mathrm e}^{\frac {176 x}{3}}+4 x +4\right )}\) | \(40\) |
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Leaf count of result is larger than twice the leaf count of optimal. 42 vs. \(2 (15) = 30\).
Time = 0.38 (sec) , antiderivative size = 42, normalized size of antiderivative = 2.21 \[ \int \frac {e^{179 x/3} (-6-349 x)+e^x \left (-12-6 x+3 x^2\right )}{24 x^3+3 e^{176 x} x^3+36 x^4+18 x^5+3 x^6+e^{352 x/3} \left (18 x^3+9 x^4\right )+e^{176 x/3} \left (36 x^3+36 x^4+9 x^5\right )} \, dx=\frac {e^{x}}{x^{4} + 4 \, x^{3} + x^{2} e^{\left (\frac {352}{3} \, x\right )} + 4 \, x^{2} + 2 \, {\left (x^{3} + 2 \, x^{2}\right )} e^{\left (\frac {176}{3} \, x\right )}} \]
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Timed out. \[ \int \frac {e^{179 x/3} (-6-349 x)+e^x \left (-12-6 x+3 x^2\right )}{24 x^3+3 e^{176 x} x^3+36 x^4+18 x^5+3 x^6+e^{352 x/3} \left (18 x^3+9 x^4\right )+e^{176 x/3} \left (36 x^3+36 x^4+9 x^5\right )} \, dx=\text {Timed out} \]
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Leaf count of result is larger than twice the leaf count of optimal. 42 vs. \(2 (15) = 30\).
Time = 1.27 (sec) , antiderivative size = 42, normalized size of antiderivative = 2.21 \[ \int \frac {e^{179 x/3} (-6-349 x)+e^x \left (-12-6 x+3 x^2\right )}{24 x^3+3 e^{176 x} x^3+36 x^4+18 x^5+3 x^6+e^{352 x/3} \left (18 x^3+9 x^4\right )+e^{176 x/3} \left (36 x^3+36 x^4+9 x^5\right )} \, dx=\frac {e^{x}}{x^{4} + 4 \, x^{3} + x^{2} e^{\left (\frac {352}{3} \, x\right )} + 4 \, x^{2} + 2 \, {\left (x^{3} + 2 \, x^{2}\right )} e^{\left (\frac {176}{3} \, x\right )}} \]
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\[ \int \frac {e^{179 x/3} (-6-349 x)+e^x \left (-12-6 x+3 x^2\right )}{24 x^3+3 e^{176 x} x^3+36 x^4+18 x^5+3 x^6+e^{352 x/3} \left (18 x^3+9 x^4\right )+e^{176 x/3} \left (36 x^3+36 x^4+9 x^5\right )} \, dx=\int { -\frac {{\left (349 \, x + 6\right )} e^{\left (\frac {179}{3} \, x\right )} - 3 \, {\left (x^{2} - 2 \, x - 4\right )} e^{x}}{3 \, {\left (x^{6} + 6 \, x^{5} + 12 \, x^{4} + x^{3} e^{\left (176 \, x\right )} + 8 \, x^{3} + 3 \, {\left (x^{4} + 2 \, x^{3}\right )} e^{\left (\frac {352}{3} \, x\right )} + 3 \, {\left (x^{5} + 4 \, x^{4} + 4 \, x^{3}\right )} e^{\left (\frac {176}{3} \, x\right )}\right )}} \,d x } \]
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Timed out. \[ \int \frac {e^{179 x/3} (-6-349 x)+e^x \left (-12-6 x+3 x^2\right )}{24 x^3+3 e^{176 x} x^3+36 x^4+18 x^5+3 x^6+e^{352 x/3} \left (18 x^3+9 x^4\right )+e^{176 x/3} \left (36 x^3+36 x^4+9 x^5\right )} \, dx=\int -\frac {{\mathrm {e}}^x\,\left (-3\,x^2+6\,x+12\right )+{\mathrm {e}}^{\frac {176\,x}{3}}\,{\mathrm {e}}^x\,\left (349\,x+6\right )}{{\mathrm {e}}^{\frac {352\,x}{3}}\,\left (9\,x^4+18\,x^3\right )+3\,x^3\,{\mathrm {e}}^{176\,x}+{\mathrm {e}}^{\frac {176\,x}{3}}\,\left (9\,x^5+36\,x^4+36\,x^3\right )+24\,x^3+36\,x^4+18\,x^5+3\,x^6} \,d x \]
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