\(\int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{(x^2+5 x^3+(x+10 x^2) \log (x)+5 x \log ^2(x)) \log ^2(\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)})} \, dx\) [6709]

   Optimal result
   Rubi [F]
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [A] (verification not implemented)
   Sympy [A] (verification not implemented)
   Maxima [A] (verification not implemented)
   Giac [A] (verification not implemented)
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 76, antiderivative size = 25 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=2+\log (2)+\frac {256}{\log \left (\frac {1}{2} \left (5 x+\frac {x}{x+\log (x)}\right )\right )} \]

[Out]

ln(2)+2+256/ln(5/2*x+1/2*x/(x+ln(x)))

Rubi [F]

\[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=\int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx \]

[In]

Int[(256 - 1280*x^2 + (-256 - 2560*x)*Log[x] - 1280*Log[x]^2)/((x^2 + 5*x^3 + (x + 10*x^2)*Log[x] + 5*x*Log[x]
^2)*Log[(x + 5*x^2 + 5*x*Log[x])/(2*x + 2*Log[x])]^2),x]

[Out]

256*Defer[Int][1/(x*(x + 5*x^2 + Log[x] + 10*x*Log[x] + 5*Log[x]^2)*Log[(x*(1 + 5*x + 5*Log[x]))/(2*(x + Log[x
]))]^2), x] - 1280*Defer[Int][x/((x + 5*x^2 + Log[x] + 10*x*Log[x] + 5*Log[x]^2)*Log[(x*(1 + 5*x + 5*Log[x]))/
(2*(x + Log[x]))]^2), x] - 2560*Defer[Int][Log[x]/((x + 5*x^2 + Log[x] + 10*x*Log[x] + 5*Log[x]^2)*Log[(x*(1 +
 5*x + 5*Log[x]))/(2*(x + Log[x]))]^2), x] - 256*Defer[Int][Log[x]/(x*(x + 5*x^2 + Log[x] + 10*x*Log[x] + 5*Lo
g[x]^2)*Log[(x*(1 + 5*x + 5*Log[x]))/(2*(x + Log[x]))]^2), x] - 1280*Defer[Int][Log[x]^2/(x*(x + 5*x^2 + Log[x
] + 10*x*Log[x] + 5*Log[x]^2)*Log[(x*(1 + 5*x + 5*Log[x]))/(2*(x + Log[x]))]^2), x]

Rubi steps \begin{align*} \text {integral}& = \int \frac {256 \left (1-5 x^2-\log (x)-10 x \log (x)-5 \log ^2(x)\right )}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 (x+\log (x))}\right )} \, dx \\ & = 256 \int \frac {1-5 x^2-\log (x)-10 x \log (x)-5 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 (x+\log (x))}\right )} \, dx \\ & = 256 \int \left (\frac {1}{x \left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )}-\frac {5 x}{\left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )}-\frac {10 \log (x)}{\left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )}-\frac {\log (x)}{x \left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )}-\frac {5 \log ^2(x)}{x \left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )}\right ) \, dx \\ & = 256 \int \frac {1}{x \left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )} \, dx-256 \int \frac {\log (x)}{x \left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )} \, dx-1280 \int \frac {x}{\left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )} \, dx-1280 \int \frac {\log ^2(x)}{x \left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )} \, dx-2560 \int \frac {\log (x)}{\left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )} \, dx \\ \end{align*}

Mathematica [A] (verified)

Time = 0.31 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.00 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=\frac {256}{\log \left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )} \]

[In]

Integrate[(256 - 1280*x^2 + (-256 - 2560*x)*Log[x] - 1280*Log[x]^2)/((x^2 + 5*x^3 + (x + 10*x^2)*Log[x] + 5*x*
Log[x]^2)*Log[(x + 5*x^2 + 5*x*Log[x])/(2*x + 2*Log[x])]^2),x]

[Out]

256/Log[(x*(1 + 5*x + 5*Log[x]))/(2*(x + Log[x]))]

Maple [A] (verified)

Time = 1.64 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.96

method result size
parallelrisch \(\frac {256}{\ln \left (\frac {x \left (5 \ln \left (x \right )+5 x +1\right )}{2 x +2 \ln \left (x \right )}\right )}\) \(24\)
default \(\frac {512 i}{\pi \,\operatorname {csgn}\left (\frac {i}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (i \left (\ln \left (x \right )+x +\frac {1}{5}\right )\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )-\pi \,\operatorname {csgn}\left (\frac {i}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}-\pi \,\operatorname {csgn}\left (i \left (\ln \left (x \right )+x +\frac {1}{5}\right )\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}+\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )-\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}+\pi \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{3}-\pi \,\operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}+\pi \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{3}+2 i \ln \left (x \right )+2 i \ln \left (\ln \left (x \right )+x +\frac {1}{5}\right )-2 i \ln \left (x +\ln \left (x \right )\right )-2 i \ln \left (2\right )+2 i \ln \left (5\right )}\) \(273\)
risch \(\frac {512 i}{\pi \,\operatorname {csgn}\left (\frac {i}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (i \left (\ln \left (x \right )+x +\frac {1}{5}\right )\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )-\pi \,\operatorname {csgn}\left (\frac {i}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}-\pi \,\operatorname {csgn}\left (i \left (\ln \left (x \right )+x +\frac {1}{5}\right )\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}+\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )-\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}+\pi \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{3}-\pi \,\operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}+\pi \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{3}+2 i \ln \left (x \right )+2 i \ln \left (\ln \left (x \right )+x +\frac {1}{5}\right )-2 i \ln \left (x +\ln \left (x \right )\right )-2 i \ln \left (2\right )+2 i \ln \left (5\right )}\) \(273\)

[In]

int((-1280*ln(x)^2+(-2560*x-256)*ln(x)-1280*x^2+256)/(5*x*ln(x)^2+(10*x^2+x)*ln(x)+5*x^3+x^2)/ln((5*x*ln(x)+5*
x^2+x)/(2*x+2*ln(x)))^2,x,method=_RETURNVERBOSE)

[Out]

256/ln(1/2*x*(5*ln(x)+5*x+1)/(x+ln(x)))

Fricas [A] (verification not implemented)

none

Time = 0.34 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.00 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=\frac {256}{\log \left (\frac {5 \, x^{2} + 5 \, x \log \left (x\right ) + x}{2 \, {\left (x + \log \left (x\right )\right )}}\right )} \]

[In]

integrate((-1280*log(x)^2+(-2560*x-256)*log(x)-1280*x^2+256)/(5*x*log(x)^2+(10*x^2+x)*log(x)+5*x^3+x^2)/log((5
*x*log(x)+5*x^2+x)/(2*x+2*log(x)))^2,x, algorithm="fricas")

[Out]

256/log(1/2*(5*x^2 + 5*x*log(x) + x)/(x + log(x)))

Sympy [A] (verification not implemented)

Time = 0.16 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.96 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=\frac {256}{\log {\left (\frac {5 x^{2} + 5 x \log {\left (x \right )} + x}{2 x + 2 \log {\left (x \right )}} \right )}} \]

[In]

integrate((-1280*ln(x)**2+(-2560*x-256)*ln(x)-1280*x**2+256)/(5*x*ln(x)**2+(10*x**2+x)*ln(x)+5*x**3+x**2)/ln((
5*x*ln(x)+5*x**2+x)/(2*x+2*ln(x)))**2,x)

[Out]

256/log((5*x**2 + 5*x*log(x) + x)/(2*x + 2*log(x)))

Maxima [A] (verification not implemented)

none

Time = 0.33 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=-\frac {256}{\log \left (2\right ) - \log \left (5 \, x + 5 \, \log \left (x\right ) + 1\right ) + \log \left (x + \log \left (x\right )\right ) - \log \left (x\right )} \]

[In]

integrate((-1280*log(x)^2+(-2560*x-256)*log(x)-1280*x^2+256)/(5*x*log(x)^2+(10*x^2+x)*log(x)+5*x^3+x^2)/log((5
*x*log(x)+5*x^2+x)/(2*x+2*log(x)))^2,x, algorithm="maxima")

[Out]

-256/(log(2) - log(5*x + 5*log(x) + 1) + log(x + log(x)) - log(x))

Giac [A] (verification not implemented)

none

Time = 0.36 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=\frac {256}{\log \left (5 \, x + 5 \, \log \left (x\right ) + 1\right ) - \log \left (2 \, x + 2 \, \log \left (x\right )\right ) + \log \left (x\right )} \]

[In]

integrate((-1280*log(x)^2+(-2560*x-256)*log(x)-1280*x^2+256)/(5*x*log(x)^2+(10*x^2+x)*log(x)+5*x^3+x^2)/log((5
*x*log(x)+5*x^2+x)/(2*x+2*log(x)))^2,x, algorithm="giac")

[Out]

256/(log(5*x + 5*log(x) + 1) - log(2*x + 2*log(x)) + log(x))

Mupad [B] (verification not implemented)

Time = 12.88 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=\frac {256}{\ln \left (\frac {x+5\,x\,\ln \left (x\right )+5\,x^2}{2\,x+2\,\ln \left (x\right )}\right )} \]

[In]

int(-(1280*log(x)^2 + log(x)*(2560*x + 256) + 1280*x^2 - 256)/(log((x + 5*x*log(x) + 5*x^2)/(2*x + 2*log(x)))^
2*(5*x*log(x)^2 + log(x)*(x + 10*x^2) + x^2 + 5*x^3)),x)

[Out]

256/log((x + 5*x*log(x) + 5*x^2)/(2*x + 2*log(x)))