Integrand size = 76, antiderivative size = 25 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=2+\log (2)+\frac {256}{\log \left (\frac {1}{2} \left (5 x+\frac {x}{x+\log (x)}\right )\right )} \]
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\[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=\int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {256 \left (1-5 x^2-\log (x)-10 x \log (x)-5 \log ^2(x)\right )}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 (x+\log (x))}\right )} \, dx \\ & = 256 \int \frac {1-5 x^2-\log (x)-10 x \log (x)-5 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 (x+\log (x))}\right )} \, dx \\ & = 256 \int \left (\frac {1}{x \left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )}-\frac {5 x}{\left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )}-\frac {10 \log (x)}{\left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )}-\frac {\log (x)}{x \left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )}-\frac {5 \log ^2(x)}{x \left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )}\right ) \, dx \\ & = 256 \int \frac {1}{x \left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )} \, dx-256 \int \frac {\log (x)}{x \left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )} \, dx-1280 \int \frac {x}{\left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )} \, dx-1280 \int \frac {\log ^2(x)}{x \left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )} \, dx-2560 \int \frac {\log (x)}{\left (x+5 x^2+\log (x)+10 x \log (x)+5 \log ^2(x)\right ) \log ^2\left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )} \, dx \\ \end{align*}
Time = 0.31 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.00 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=\frac {256}{\log \left (\frac {x (1+5 x+5 \log (x))}{2 (x+\log (x))}\right )} \]
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Time = 1.64 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.96
method | result | size |
parallelrisch | \(\frac {256}{\ln \left (\frac {x \left (5 \ln \left (x \right )+5 x +1\right )}{2 x +2 \ln \left (x \right )}\right )}\) | \(24\) |
default | \(\frac {512 i}{\pi \,\operatorname {csgn}\left (\frac {i}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (i \left (\ln \left (x \right )+x +\frac {1}{5}\right )\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )-\pi \,\operatorname {csgn}\left (\frac {i}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}-\pi \,\operatorname {csgn}\left (i \left (\ln \left (x \right )+x +\frac {1}{5}\right )\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}+\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )-\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}+\pi \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{3}-\pi \,\operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}+\pi \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{3}+2 i \ln \left (x \right )+2 i \ln \left (\ln \left (x \right )+x +\frac {1}{5}\right )-2 i \ln \left (x +\ln \left (x \right )\right )-2 i \ln \left (2\right )+2 i \ln \left (5\right )}\) | \(273\) |
risch | \(\frac {512 i}{\pi \,\operatorname {csgn}\left (\frac {i}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (i \left (\ln \left (x \right )+x +\frac {1}{5}\right )\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )-\pi \,\operatorname {csgn}\left (\frac {i}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}-\pi \,\operatorname {csgn}\left (i \left (\ln \left (x \right )+x +\frac {1}{5}\right )\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}+\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )-\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}+\pi \operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{3}-\pi \,\operatorname {csgn}\left (\frac {i \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right ) \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{2}+\pi \operatorname {csgn}\left (\frac {i x \left (\ln \left (x \right )+x +\frac {1}{5}\right )}{x +\ln \left (x \right )}\right )^{3}+2 i \ln \left (x \right )+2 i \ln \left (\ln \left (x \right )+x +\frac {1}{5}\right )-2 i \ln \left (x +\ln \left (x \right )\right )-2 i \ln \left (2\right )+2 i \ln \left (5\right )}\) | \(273\) |
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Time = 0.34 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.00 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=\frac {256}{\log \left (\frac {5 \, x^{2} + 5 \, x \log \left (x\right ) + x}{2 \, {\left (x + \log \left (x\right )\right )}}\right )} \]
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Time = 0.16 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.96 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=\frac {256}{\log {\left (\frac {5 x^{2} + 5 x \log {\left (x \right )} + x}{2 x + 2 \log {\left (x \right )}} \right )}} \]
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Time = 0.33 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=-\frac {256}{\log \left (2\right ) - \log \left (5 \, x + 5 \, \log \left (x\right ) + 1\right ) + \log \left (x + \log \left (x\right )\right ) - \log \left (x\right )} \]
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Time = 0.36 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=\frac {256}{\log \left (5 \, x + 5 \, \log \left (x\right ) + 1\right ) - \log \left (2 \, x + 2 \, \log \left (x\right )\right ) + \log \left (x\right )} \]
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Time = 12.88 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {256-1280 x^2+(-256-2560 x) \log (x)-1280 \log ^2(x)}{\left (x^2+5 x^3+\left (x+10 x^2\right ) \log (x)+5 x \log ^2(x)\right ) \log ^2\left (\frac {x+5 x^2+5 x \log (x)}{2 x+2 \log (x)}\right )} \, dx=\frac {256}{\ln \left (\frac {x+5\,x\,\ln \left (x\right )+5\,x^2}{2\,x+2\,\ln \left (x\right )}\right )} \]
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