Integrand size = 30, antiderivative size = 19 \[ \int \left (40+32 x+\left (-60 x^2-64 x^3\right ) \log ^2(4)+24 x^5 \log ^4(4)\right ) \, dx=\left (-3+2 \left (-1-2 x+x^3 \log ^2(4)\right )\right )^2 \]
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Time = 0.01 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.89, number of steps used = 2, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \left (40+32 x+\left (-60 x^2-64 x^3\right ) \log ^2(4)+24 x^5 \log ^4(4)\right ) \, dx=4 x^6 \log ^4(4)-16 x^4 \log ^2(4)-20 x^3 \log ^2(4)+16 x^2+40 x \]
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Rubi steps \begin{align*} \text {integral}& = 40 x+16 x^2+4 x^6 \log ^4(4)+\log ^2(4) \int \left (-60 x^2-64 x^3\right ) \, dx \\ & = 40 x+16 x^2-20 x^3 \log ^2(4)-16 x^4 \log ^2(4)+4 x^6 \log ^4(4) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.89 \[ \int \left (40+32 x+\left (-60 x^2-64 x^3\right ) \log ^2(4)+24 x^5 \log ^4(4)\right ) \, dx=40 x+16 x^2-20 x^3 \log ^2(4)-16 x^4 \log ^2(4)+4 x^6 \log ^4(4) \]
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Time = 0.28 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.89
method | result | size |
default | \(\left (8 x^{3} \ln \left (2\right )^{2}-4 x -5\right )^{2}\) | \(17\) |
gosper | \(8 x \left (8 x^{5} \ln \left (2\right )^{4}-8 x^{3} \ln \left (2\right )^{2}-10 x^{2} \ln \left (2\right )^{2}+2 x +5\right )\) | \(36\) |
norman | \(40 x +16 x^{2}-80 x^{3} \ln \left (2\right )^{2}-64 x^{4} \ln \left (2\right )^{2}+64 x^{6} \ln \left (2\right )^{4}\) | \(37\) |
risch | \(40 x +16 x^{2}-80 x^{3} \ln \left (2\right )^{2}-64 x^{4} \ln \left (2\right )^{2}+64 x^{6} \ln \left (2\right )^{4}\) | \(37\) |
parallelrisch | \(40 x +16 x^{2}-80 x^{3} \ln \left (2\right )^{2}-64 x^{4} \ln \left (2\right )^{2}+64 x^{6} \ln \left (2\right )^{4}\) | \(37\) |
parts | \(40 x +16 x^{2}-80 x^{3} \ln \left (2\right )^{2}-64 x^{4} \ln \left (2\right )^{2}+64 x^{6} \ln \left (2\right )^{4}\) | \(37\) |
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Leaf count of result is larger than twice the leaf count of optimal. 35 vs. \(2 (16) = 32\).
Time = 0.30 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.84 \[ \int \left (40+32 x+\left (-60 x^2-64 x^3\right ) \log ^2(4)+24 x^5 \log ^4(4)\right ) \, dx=64 \, x^{6} \log \left (2\right )^{4} - 16 \, {\left (4 \, x^{4} + 5 \, x^{3}\right )} \log \left (2\right )^{2} + 16 \, x^{2} + 40 \, x \]
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Leaf count of result is larger than twice the leaf count of optimal. 37 vs. \(2 (15) = 30\).
Time = 0.02 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.95 \[ \int \left (40+32 x+\left (-60 x^2-64 x^3\right ) \log ^2(4)+24 x^5 \log ^4(4)\right ) \, dx=64 x^{6} \log {\left (2 \right )}^{4} - 64 x^{4} \log {\left (2 \right )}^{2} - 80 x^{3} \log {\left (2 \right )}^{2} + 16 x^{2} + 40 x \]
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Leaf count of result is larger than twice the leaf count of optimal. 35 vs. \(2 (16) = 32\).
Time = 0.19 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.84 \[ \int \left (40+32 x+\left (-60 x^2-64 x^3\right ) \log ^2(4)+24 x^5 \log ^4(4)\right ) \, dx=64 \, x^{6} \log \left (2\right )^{4} - 16 \, {\left (4 \, x^{4} + 5 \, x^{3}\right )} \log \left (2\right )^{2} + 16 \, x^{2} + 40 \, x \]
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Leaf count of result is larger than twice the leaf count of optimal. 35 vs. \(2 (16) = 32\).
Time = 0.27 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.84 \[ \int \left (40+32 x+\left (-60 x^2-64 x^3\right ) \log ^2(4)+24 x^5 \log ^4(4)\right ) \, dx=64 \, x^{6} \log \left (2\right )^{4} - 16 \, {\left (4 \, x^{4} + 5 \, x^{3}\right )} \log \left (2\right )^{2} + 16 \, x^{2} + 40 \, x \]
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Time = 11.78 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.89 \[ \int \left (40+32 x+\left (-60 x^2-64 x^3\right ) \log ^2(4)+24 x^5 \log ^4(4)\right ) \, dx=64\,{\ln \left (2\right )}^4\,x^6-64\,{\ln \left (2\right )}^2\,x^4-80\,{\ln \left (2\right )}^2\,x^3+16\,x^2+40\,x \]
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