Integrand size = 196, antiderivative size = 30 \[ \int \frac {e^{x^4 \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )} \left (\left (-10 x^5+20 x^6-10 x^7+\sqrt [5]{\frac {1}{x}} \left (12 x^3-22 x^4\right )\right ) \log \left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )+\left (-20 x^5+40 x^6-20 x^7+\sqrt [5]{\frac {1}{x}} \left (-20 x^3+20 x^4\right )\right ) \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )\right )}{-5 x^2+10 x^3-5 x^4+\sqrt [5]{\frac {1}{x}} (-5+5 x)} \, dx=e^{x^4 \log ^2\left (-x+\frac {\sqrt [5]{\frac {1}{x}}}{-x+x^2}\right )} \]
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Timed out. \[ \int \frac {e^{x^4 \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )} \left (\left (-10 x^5+20 x^6-10 x^7+\sqrt [5]{\frac {1}{x}} \left (12 x^3-22 x^4\right )\right ) \log \left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )+\left (-20 x^5+40 x^6-20 x^7+\sqrt [5]{\frac {1}{x}} \left (-20 x^3+20 x^4\right )\right ) \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )\right )}{-5 x^2+10 x^3-5 x^4+\sqrt [5]{\frac {1}{x}} (-5+5 x)} \, dx=\text {\$Aborted} \]
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Rubi steps Aborted
\[ \int \frac {e^{x^4 \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )} \left (\left (-10 x^5+20 x^6-10 x^7+\sqrt [5]{\frac {1}{x}} \left (12 x^3-22 x^4\right )\right ) \log \left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )+\left (-20 x^5+40 x^6-20 x^7+\sqrt [5]{\frac {1}{x}} \left (-20 x^3+20 x^4\right )\right ) \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )\right )}{-5 x^2+10 x^3-5 x^4+\sqrt [5]{\frac {1}{x}} (-5+5 x)} \, dx=\int \frac {e^{x^4 \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )} \left (\left (-10 x^5+20 x^6-10 x^7+\sqrt [5]{\frac {1}{x}} \left (12 x^3-22 x^4\right )\right ) \log \left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )+\left (-20 x^5+40 x^6-20 x^7+\sqrt [5]{\frac {1}{x}} \left (-20 x^3+20 x^4\right )\right ) \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )\right )}{-5 x^2+10 x^3-5 x^4+\sqrt [5]{\frac {1}{x}} (-5+5 x)} \, dx \]
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\[\int \frac {\left (\left (\left (20 x^{4}-20 x^{3}\right ) \left (\frac {1}{x}\right )^{\frac {1}{5}}-20 x^{7}+40 x^{6}-20 x^{5}\right ) \ln \left (\frac {\left (\frac {1}{x}\right )^{\frac {1}{5}}-x^{3}+x^{2}}{x^{2}-x}\right )^{2}+\left (\left (-22 x^{4}+12 x^{3}\right ) \left (\frac {1}{x}\right )^{\frac {1}{5}}-10 x^{7}+20 x^{6}-10 x^{5}\right ) \ln \left (\frac {\left (\frac {1}{x}\right )^{\frac {1}{5}}-x^{3}+x^{2}}{x^{2}-x}\right )\right ) {\mathrm e}^{x^{4} \ln \left (\frac {\left (\frac {1}{x}\right )^{\frac {1}{5}}-x^{3}+x^{2}}{x^{2}-x}\right )^{2}}}{\left (5 x -5\right ) \left (\frac {1}{x}\right )^{\frac {1}{5}}-5 x^{4}+10 x^{3}-5 x^{2}}d x\]
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none
Time = 0.38 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.17 \[ \int \frac {e^{x^4 \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )} \left (\left (-10 x^5+20 x^6-10 x^7+\sqrt [5]{\frac {1}{x}} \left (12 x^3-22 x^4\right )\right ) \log \left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )+\left (-20 x^5+40 x^6-20 x^7+\sqrt [5]{\frac {1}{x}} \left (-20 x^3+20 x^4\right )\right ) \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )\right )}{-5 x^2+10 x^3-5 x^4+\sqrt [5]{\frac {1}{x}} (-5+5 x)} \, dx=e^{\left (x^{4} \log \left (-\frac {x^{4} - x^{3} - x^{\frac {4}{5}}}{x^{3} - x^{2}}\right )^{2}\right )} \]
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Timed out. \[ \int \frac {e^{x^4 \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )} \left (\left (-10 x^5+20 x^6-10 x^7+\sqrt [5]{\frac {1}{x}} \left (12 x^3-22 x^4\right )\right ) \log \left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )+\left (-20 x^5+40 x^6-20 x^7+\sqrt [5]{\frac {1}{x}} \left (-20 x^3+20 x^4\right )\right ) \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )\right )}{-5 x^2+10 x^3-5 x^4+\sqrt [5]{\frac {1}{x}} (-5+5 x)} \, dx=\text {Timed out} \]
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Leaf count of result is larger than twice the leaf count of optimal. 193 vs. \(2 (25) = 50\).
Time = 0.74 (sec) , antiderivative size = 193, normalized size of antiderivative = 6.43 \[ \int \frac {e^{x^4 \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )} \left (\left (-10 x^5+20 x^6-10 x^7+\sqrt [5]{\frac {1}{x}} \left (12 x^3-22 x^4\right )\right ) \log \left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )+\left (-20 x^5+40 x^6-20 x^7+\sqrt [5]{\frac {1}{x}} \left (-20 x^3+20 x^4\right )\right ) \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )\right )}{-5 x^2+10 x^3-5 x^4+\sqrt [5]{\frac {1}{x}} (-5+5 x)} \, dx=e^{\left (x^{4} \log \left (-x^{\frac {16}{5}} + x^{\frac {11}{5}} + 1\right )^{2} - \frac {12}{5} \, x^{4} \log \left (-x^{\frac {16}{5}} + x^{\frac {11}{5}} + 1\right ) \log \left (x\right ) + \frac {36}{25} \, x^{4} \log \left (x\right )^{2} - 2 \, x^{4} \log \left (-x^{\frac {16}{5}} + x^{\frac {11}{5}} + 1\right ) \log \left (x^{\frac {4}{5}} + x^{\frac {3}{5}} + x^{\frac {2}{5}} + x^{\frac {1}{5}} + 1\right ) + \frac {12}{5} \, x^{4} \log \left (x\right ) \log \left (x^{\frac {4}{5}} + x^{\frac {3}{5}} + x^{\frac {2}{5}} + x^{\frac {1}{5}} + 1\right ) + x^{4} \log \left (x^{\frac {4}{5}} + x^{\frac {3}{5}} + x^{\frac {2}{5}} + x^{\frac {1}{5}} + 1\right )^{2} - 2 \, x^{4} \log \left (-x^{\frac {16}{5}} + x^{\frac {11}{5}} + 1\right ) \log \left (x^{\frac {1}{5}} - 1\right ) + \frac {12}{5} \, x^{4} \log \left (x\right ) \log \left (x^{\frac {1}{5}} - 1\right ) + 2 \, x^{4} \log \left (x^{\frac {4}{5}} + x^{\frac {3}{5}} + x^{\frac {2}{5}} + x^{\frac {1}{5}} + 1\right ) \log \left (x^{\frac {1}{5}} - 1\right ) + x^{4} \log \left (x^{\frac {1}{5}} - 1\right )^{2}\right )} \]
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\[ \int \frac {e^{x^4 \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )} \left (\left (-10 x^5+20 x^6-10 x^7+\sqrt [5]{\frac {1}{x}} \left (12 x^3-22 x^4\right )\right ) \log \left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )+\left (-20 x^5+40 x^6-20 x^7+\sqrt [5]{\frac {1}{x}} \left (-20 x^3+20 x^4\right )\right ) \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )\right )}{-5 x^2+10 x^3-5 x^4+\sqrt [5]{\frac {1}{x}} (-5+5 x)} \, dx=\int { \frac {2 \, {\left (10 \, {\left (x^{7} - 2 \, x^{6} + x^{5} - \frac {x^{4} - x^{3}}{x^{\frac {1}{5}}}\right )} \log \left (-\frac {x^{3} - x^{2} - \frac {1}{x^{\frac {1}{5}}}}{x^{2} - x}\right )^{2} + {\left (5 \, x^{7} - 10 \, x^{6} + 5 \, x^{5} + \frac {11 \, x^{4} - 6 \, x^{3}}{x^{\frac {1}{5}}}\right )} \log \left (-\frac {x^{3} - x^{2} - \frac {1}{x^{\frac {1}{5}}}}{x^{2} - x}\right )\right )} e^{\left (x^{4} \log \left (-\frac {x^{3} - x^{2} - \frac {1}{x^{\frac {1}{5}}}}{x^{2} - x}\right )^{2}\right )}}{5 \, {\left (x^{4} - 2 \, x^{3} + x^{2} - \frac {x - 1}{x^{\frac {1}{5}}}\right )}} \,d x } \]
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Timed out. \[ \int \frac {e^{x^4 \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )} \left (\left (-10 x^5+20 x^6-10 x^7+\sqrt [5]{\frac {1}{x}} \left (12 x^3-22 x^4\right )\right ) \log \left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )+\left (-20 x^5+40 x^6-20 x^7+\sqrt [5]{\frac {1}{x}} \left (-20 x^3+20 x^4\right )\right ) \log ^2\left (\frac {\sqrt [5]{\frac {1}{x}}+x^2-x^3}{-x+x^2}\right )\right )}{-5 x^2+10 x^3-5 x^4+\sqrt [5]{\frac {1}{x}} (-5+5 x)} \, dx=\int -\frac {{\mathrm {e}}^{x^4\,{\ln \left (-\frac {{\left (\frac {1}{x}\right )}^{1/5}+x^2-x^3}{x-x^2}\right )}^2}\,\left ({\ln \left (-\frac {{\left (\frac {1}{x}\right )}^{1/5}+x^2-x^3}{x-x^2}\right )}^2\,\left (\left (20\,x^3-20\,x^4\right )\,{\left (\frac {1}{x}\right )}^{1/5}+20\,x^5-40\,x^6+20\,x^7\right )-\ln \left (-\frac {{\left (\frac {1}{x}\right )}^{1/5}+x^2-x^3}{x-x^2}\right )\,\left (\left (12\,x^3-22\,x^4\right )\,{\left (\frac {1}{x}\right )}^{1/5}-10\,x^5+20\,x^6-10\,x^7\right )\right )}{\left (5\,x-5\right )\,{\left (\frac {1}{x}\right )}^{1/5}-5\,x^2+10\,x^3-5\,x^4} \,d x \]
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