Integrand size = 56, antiderivative size = 19 \[ \int \frac {-3+e^{-7+2 x-2 x^3} \left (1-2 x+6 x^3\right )}{9+e^{-14+4 x-4 x^3}-6 e^{-7+2 x-2 x^3}} \, dx=\frac {x}{-3+e^{-7+2 \left (x-x^3\right )}} \]
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\[ \int \frac {-3+e^{-7+2 x-2 x^3} \left (1-2 x+6 x^3\right )}{9+e^{-14+4 x-4 x^3}-6 e^{-7+2 x-2 x^3}} \, dx=\int \frac {-3+e^{-7+2 x-2 x^3} \left (1-2 x+6 x^3\right )}{9+e^{-14+4 x-4 x^3}-6 e^{-7+2 x-2 x^3}} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {1}{3}+\frac {2 e^{4 x} x \left (-1+3 x^2\right )}{3 \left (e^{2 x}-3 e^{7+2 x^3}\right )^2}-\frac {e^{2 x} \left (-1-2 x+6 x^3\right )}{3 \left (e^{2 x}-3 e^{7+2 x^3}\right )}\right ) \, dx \\ & = -\frac {x}{3}-\frac {1}{3} \int \frac {e^{2 x} \left (-1-2 x+6 x^3\right )}{e^{2 x}-3 e^{7+2 x^3}} \, dx+\frac {2}{3} \int \frac {e^{4 x} x \left (-1+3 x^2\right )}{\left (e^{2 x}-3 e^{7+2 x^3}\right )^2} \, dx \\ & = -\frac {x}{3}-\frac {1}{3} \int \left (-\frac {e^{2 x}}{e^{2 x}-3 e^{7+2 x^3}}-\frac {2 e^{2 x} x}{e^{2 x}-3 e^{7+2 x^3}}+\frac {6 e^{2 x} x^3}{e^{2 x}-3 e^{7+2 x^3}}\right ) \, dx+\frac {2}{3} \int \left (-\frac {e^{4 x} x}{\left (e^{2 x}-3 e^{7+2 x^3}\right )^2}+\frac {3 e^{4 x} x^3}{\left (e^{2 x}-3 e^{7+2 x^3}\right )^2}\right ) \, dx \\ & = -\frac {x}{3}+\frac {1}{3} \int \frac {e^{2 x}}{e^{2 x}-3 e^{7+2 x^3}} \, dx-\frac {2}{3} \int \frac {e^{4 x} x}{\left (e^{2 x}-3 e^{7+2 x^3}\right )^2} \, dx+\frac {2}{3} \int \frac {e^{2 x} x}{e^{2 x}-3 e^{7+2 x^3}} \, dx+2 \int \frac {e^{4 x} x^3}{\left (e^{2 x}-3 e^{7+2 x^3}\right )^2} \, dx-2 \int \frac {e^{2 x} x^3}{e^{2 x}-3 e^{7+2 x^3}} \, dx \\ \end{align*}
Time = 3.16 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.58 \[ \int \frac {-3+e^{-7+2 x-2 x^3} \left (1-2 x+6 x^3\right )}{9+e^{-14+4 x-4 x^3}-6 e^{-7+2 x-2 x^3}} \, dx=\frac {e^{7+2 x^3} x}{e^{2 x}-3 e^{7+2 x^3}} \]
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Time = 0.12 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.95
method | result | size |
norman | \(\frac {x}{{\mathrm e}^{-2 x^{3}+2 x -7}-3}\) | \(18\) |
risch | \(\frac {x}{{\mathrm e}^{-2 x^{3}+2 x -7}-3}\) | \(18\) |
parallelrisch | \(\frac {x}{{\mathrm e}^{-2 x^{3}+2 x -7}-3}\) | \(18\) |
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Time = 0.24 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.89 \[ \int \frac {-3+e^{-7+2 x-2 x^3} \left (1-2 x+6 x^3\right )}{9+e^{-14+4 x-4 x^3}-6 e^{-7+2 x-2 x^3}} \, dx=\frac {x}{e^{\left (-2 \, x^{3} + 2 \, x - 7\right )} - 3} \]
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Time = 0.09 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.74 \[ \int \frac {-3+e^{-7+2 x-2 x^3} \left (1-2 x+6 x^3\right )}{9+e^{-14+4 x-4 x^3}-6 e^{-7+2 x-2 x^3}} \, dx=\frac {x}{e^{- 2 x^{3} + 2 x - 7} - 3} \]
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Time = 0.26 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.58 \[ \int \frac {-3+e^{-7+2 x-2 x^3} \left (1-2 x+6 x^3\right )}{9+e^{-14+4 x-4 x^3}-6 e^{-7+2 x-2 x^3}} \, dx=-\frac {x e^{\left (2 \, x^{3} + 7\right )}}{3 \, e^{\left (2 \, x^{3} + 7\right )} - e^{\left (2 \, x\right )}} \]
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Time = 0.28 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.26 \[ \int \frac {-3+e^{-7+2 x-2 x^3} \left (1-2 x+6 x^3\right )}{9+e^{-14+4 x-4 x^3}-6 e^{-7+2 x-2 x^3}} \, dx=-\frac {x e^{7}}{3 \, e^{7} - e^{\left (-2 \, x^{3} + 2 \, x\right )}} \]
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Time = 11.90 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00 \[ \int \frac {-3+e^{-7+2 x-2 x^3} \left (1-2 x+6 x^3\right )}{9+e^{-14+4 x-4 x^3}-6 e^{-7+2 x-2 x^3}} \, dx=\frac {x}{{\mathrm {e}}^{2\,x}\,{\mathrm {e}}^{-7}\,{\mathrm {e}}^{-2\,x^3}-3} \]
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