Integrand size = 88, antiderivative size = 32 \[ \int \frac {e^x (3+3 x)+e^{x-2 e x+2 e^4 x} \left (-x^2+x^3+2 e x^3-2 e^4 x^3\right )}{9+6 e^{-2 e x+2 e^4 x} x^2+e^{-4 e x+4 e^4 x} x^4} \, dx=1+\frac {e^x x}{3+e^{-2 x+2 \left (1-e+e^4\right ) x} x^2} \]
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\[ \int \frac {e^x (3+3 x)+e^{x-2 e x+2 e^4 x} \left (-x^2+x^3+2 e x^3-2 e^4 x^3\right )}{9+6 e^{-2 e x+2 e^4 x} x^2+e^{-4 e x+4 e^4 x} x^4} \, dx=\int \frac {e^x (3+3 x)+e^{x-2 e x+2 e^4 x} \left (-x^2+x^3+2 e x^3-2 e^4 x^3\right )}{9+6 e^{-2 e x+2 e^4 x} x^2+e^{-4 e x+4 e^4 x} x^4} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {e^{4 e x} \left (e^x (3+3 x)+e^{x-2 e x+2 e^4 x} \left (-x^2+x^3+2 e x^3-2 e^4 x^3\right )\right )}{\left (3 e^{2 e x}+e^{2 e^4 x} x^2\right )^2} \, dx \\ & = \int \left (\frac {6 e^{x+4 e x} \left (1-e \left (1-e^3\right ) x\right )}{\left (3 e^{2 e x}+e^{2 e^4 x} x^2\right )^2}+\frac {e^{(1-2 e) x+4 e x} \left (-1+\left (1+2 e-2 e^4\right ) x\right )}{3 e^{2 e x}+e^{2 e^4 x} x^2}\right ) \, dx \\ & = 6 \int \frac {e^{x+4 e x} \left (1-e \left (1-e^3\right ) x\right )}{\left (3 e^{2 e x}+e^{2 e^4 x} x^2\right )^2} \, dx+\int \frac {e^{(1-2 e) x+4 e x} \left (-1+\left (1+2 e-2 e^4\right ) x\right )}{3 e^{2 e x}+e^{2 e^4 x} x^2} \, dx \\ & = 6 \int \frac {e^{(1+4 e) x} \left (1-e \left (1-e^3\right ) x\right )}{\left (3 e^{2 e x}+e^{2 e^4 x} x^2\right )^2} \, dx+\int \frac {e^{(1+2 e) x} \left (-1+\left (1+2 e-2 e^4\right ) x\right )}{3 e^{2 e x}+e^{2 e^4 x} x^2} \, dx \\ & = 6 \int \left (\frac {e^{(1+4 e) x}}{\left (3 e^{2 e x}+e^{2 e^4 x} x^2\right )^2}+\frac {e^{1+(1+4 e) x} \left (-1+e^3\right ) x}{\left (3 e^{2 e x}+e^{2 e^4 x} x^2\right )^2}\right ) \, dx+\int \left (-\frac {e^{(1+2 e) x}}{3 e^{2 e x}+e^{2 e^4 x} x^2}-\frac {e^{(1+2 e) x} \left (-1-2 e+2 e^4\right ) x}{3 e^{2 e x}+e^{2 e^4 x} x^2}\right ) \, dx \\ & = 6 \int \frac {e^{(1+4 e) x}}{\left (3 e^{2 e x}+e^{2 e^4 x} x^2\right )^2} \, dx-\left (6 \left (1-e^3\right )\right ) \int \frac {e^{1+(1+4 e) x} x}{\left (3 e^{2 e x}+e^{2 e^4 x} x^2\right )^2} \, dx+\left (1+2 e-2 e^4\right ) \int \frac {e^{(1+2 e) x} x}{3 e^{2 e x}+e^{2 e^4 x} x^2} \, dx-\int \frac {e^{(1+2 e) x}}{3 e^{2 e x}+e^{2 e^4 x} x^2} \, dx \\ \end{align*}
Time = 4.80 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.06 \[ \int \frac {e^x (3+3 x)+e^{x-2 e x+2 e^4 x} \left (-x^2+x^3+2 e x^3-2 e^4 x^3\right )}{9+6 e^{-2 e x+2 e^4 x} x^2+e^{-4 e x+4 e^4 x} x^4} \, dx=\frac {e^{(1+2 e) x} x}{3 e^{2 e x}+e^{2 e^4 x} x^2} \]
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Time = 1.18 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.75
method | result | size |
risch | \(\frac {x \,{\mathrm e}^{x}}{x^{2} {\mathrm e}^{-2 x \left ({\mathrm e}-{\mathrm e}^{4}\right )}+3}\) | \(24\) |
parallelrisch | \(\frac {{\mathrm e}^{x} x}{x^{2} {\mathrm e}^{2 x \left (-{\mathrm e}+{\mathrm e}^{4}\right )}+3}\) | \(25\) |
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Time = 0.25 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.50 \[ \int \frac {e^x (3+3 x)+e^{x-2 e x+2 e^4 x} \left (-x^2+x^3+2 e x^3-2 e^4 x^3\right )}{9+6 e^{-2 e x+2 e^4 x} x^2+e^{-4 e x+4 e^4 x} x^4} \, dx=\frac {x e^{\left (2 \, x e^{4} - 2 \, x e + x\right )}}{x^{2} e^{\left (4 \, x e^{4} - 4 \, x e\right )} + 3 \, e^{\left (2 \, x e^{4} - 2 \, x e\right )}} \]
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Timed out. \[ \int \frac {e^x (3+3 x)+e^{x-2 e x+2 e^4 x} \left (-x^2+x^3+2 e x^3-2 e^4 x^3\right )}{9+6 e^{-2 e x+2 e^4 x} x^2+e^{-4 e x+4 e^4 x} x^4} \, dx=\text {Timed out} \]
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Time = 0.27 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.97 \[ \int \frac {e^x (3+3 x)+e^{x-2 e x+2 e^4 x} \left (-x^2+x^3+2 e x^3-2 e^4 x^3\right )}{9+6 e^{-2 e x+2 e^4 x} x^2+e^{-4 e x+4 e^4 x} x^4} \, dx=\frac {x e^{\left (2 \, x e + x\right )}}{x^{2} e^{\left (2 \, x e^{4}\right )} + 3 \, e^{\left (2 \, x e\right )}} \]
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\[ \int \frac {e^x (3+3 x)+e^{x-2 e x+2 e^4 x} \left (-x^2+x^3+2 e x^3-2 e^4 x^3\right )}{9+6 e^{-2 e x+2 e^4 x} x^2+e^{-4 e x+4 e^4 x} x^4} \, dx=\int { -\frac {{\left (2 \, x^{3} e^{4} - 2 \, x^{3} e - x^{3} + x^{2}\right )} e^{\left (2 \, x e^{4} - 2 \, x e + x\right )} - 3 \, {\left (x + 1\right )} e^{x}}{x^{4} e^{\left (4 \, x e^{4} - 4 \, x e\right )} + 6 \, x^{2} e^{\left (2 \, x e^{4} - 2 \, x e\right )} + 9} \,d x } \]
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Time = 0.23 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.91 \[ \int \frac {e^x (3+3 x)+e^{x-2 e x+2 e^4 x} \left (-x^2+x^3+2 e x^3-2 e^4 x^3\right )}{9+6 e^{-2 e x+2 e^4 x} x^2+e^{-4 e x+4 e^4 x} x^4} \, dx=\frac {x^2\,{\mathrm {e}}^x-x^3\,\left ({\mathrm {e}}^{x+1}-{\mathrm {e}}^{x+4}\right )}{\left (x^2\,{\mathrm {e}}^{2\,x\,{\mathrm {e}}^4-2\,x\,\mathrm {e}}+3\right )\,\left (x-x^2\,\mathrm {e}+x^2\,{\mathrm {e}}^4\right )} \]
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