Integrand size = 280, antiderivative size = 38 \[ \int \frac {e^{\frac {x}{2-x+\log (2)}} (-2 x-x \log (2))+\frac {e^{450+\frac {x}{2-x+\log (2)}+50 \log ^2\left (x^2\right )} (-2 x-x \log (2))}{x^{600}}+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (600-600 x+150 x^2+(600-300 x) \log (2)+150 \log ^2(2)+e^{\frac {x}{2-x+\log (2)}} (4 x+2 x \log (2))+\left (-200+200 x-50 x^2+(-200+100 x) \log (2)-50 \log ^2(2)\right ) \log \left (x^2\right )\right )}{x^{300}}}{4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (-8 x+8 x^2-2 x^3+\left (-8 x+4 x^2\right ) \log (2)-2 x \log ^2(2)\right )}{x^{300}}+\frac {e^{450+50 \log ^2\left (x^2\right )} \left (4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)\right )}{x^{600}}} \, dx=-e^{\frac {x}{2-x+\log (2)}}+\frac {1}{2 \left (-1+e^{25 \left (3-\log \left (x^2\right )\right )^2}\right )} \]
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Timed out. \[ \int \frac {e^{\frac {x}{2-x+\log (2)}} (-2 x-x \log (2))+\frac {e^{450+\frac {x}{2-x+\log (2)}+50 \log ^2\left (x^2\right )} (-2 x-x \log (2))}{x^{600}}+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (600-600 x+150 x^2+(600-300 x) \log (2)+150 \log ^2(2)+e^{\frac {x}{2-x+\log (2)}} (4 x+2 x \log (2))+\left (-200+200 x-50 x^2+(-200+100 x) \log (2)-50 \log ^2(2)\right ) \log \left (x^2\right )\right )}{x^{300}}}{4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (-8 x+8 x^2-2 x^3+\left (-8 x+4 x^2\right ) \log (2)-2 x \log ^2(2)\right )}{x^{300}}+\frac {e^{450+50 \log ^2\left (x^2\right )} \left (4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)\right )}{x^{600}}} \, dx=\text {\$Aborted} \]
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Rubi steps Aborted
Timed out. \[ \int \frac {e^{\frac {x}{2-x+\log (2)}} (-2 x-x \log (2))+\frac {e^{450+\frac {x}{2-x+\log (2)}+50 \log ^2\left (x^2\right )} (-2 x-x \log (2))}{x^{600}}+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (600-600 x+150 x^2+(600-300 x) \log (2)+150 \log ^2(2)+e^{\frac {x}{2-x+\log (2)}} (4 x+2 x \log (2))+\left (-200+200 x-50 x^2+(-200+100 x) \log (2)-50 \log ^2(2)\right ) \log \left (x^2\right )\right )}{x^{300}}}{4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (-8 x+8 x^2-2 x^3+\left (-8 x+4 x^2\right ) \log (2)-2 x \log ^2(2)\right )}{x^{300}}+\frac {e^{450+50 \log ^2\left (x^2\right )} \left (4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)\right )}{x^{600}}} \, dx=\text {\$Aborted} \]
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Time = 29.72 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.87
method | result | size |
parallelrisch | \(\frac {1-2 \,{\mathrm e}^{25 \ln \left (x^{2}\right )^{2}-150 \ln \left (x^{2}\right )+225} {\mathrm e}^{\frac {x}{\ln \left (2\right )+2-x}}+2 \,{\mathrm e}^{\frac {x}{\ln \left (2\right )+2-x}}}{2 \,{\mathrm e}^{25 \ln \left (x^{2}\right )^{2}-150 \ln \left (x^{2}\right )+225}-2}\) | \(71\) |
risch | \(-{\mathrm e}^{\frac {x}{\ln \left (2\right )+2-x}}+\frac {1}{\frac {2 x^{-100 i \pi \,\operatorname {csgn}\left (i x^{2}\right )} x^{100 i \pi \,\operatorname {csgn}\left (i x \right )} {\mathrm e}^{100 \ln \left (x \right )^{2}+225} {\mathrm e}^{-\frac {25 \operatorname {csgn}\left (i x^{2}\right )^{6} \pi ^{2}}{4}} {\mathrm e}^{25 \operatorname {csgn}\left (i x^{2}\right )^{5} \operatorname {csgn}\left (i x \right ) \pi ^{2}} {\mathrm e}^{-\frac {75 \operatorname {csgn}\left (i x^{2}\right )^{4} \operatorname {csgn}\left (i x \right )^{2} \pi ^{2}}{2}} {\mathrm e}^{25 \operatorname {csgn}\left (i x^{2}\right )^{3} \operatorname {csgn}\left (i x \right )^{3} \pi ^{2}} {\mathrm e}^{-\frac {25 \operatorname {csgn}\left (i x^{2}\right )^{2} \operatorname {csgn}\left (i x \right )^{4} \pi ^{2}}{4}}}{x^{300}}-2}\) | \(162\) |
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Leaf count of result is larger than twice the leaf count of optimal. 71 vs. \(2 (33) = 66\).
Time = 0.25 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.87 \[ \int \frac {e^{\frac {x}{2-x+\log (2)}} (-2 x-x \log (2))+\frac {e^{450+\frac {x}{2-x+\log (2)}+50 \log ^2\left (x^2\right )} (-2 x-x \log (2))}{x^{600}}+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (600-600 x+150 x^2+(600-300 x) \log (2)+150 \log ^2(2)+e^{\frac {x}{2-x+\log (2)}} (4 x+2 x \log (2))+\left (-200+200 x-50 x^2+(-200+100 x) \log (2)-50 \log ^2(2)\right ) \log \left (x^2\right )\right )}{x^{300}}}{4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (-8 x+8 x^2-2 x^3+\left (-8 x+4 x^2\right ) \log (2)-2 x \log ^2(2)\right )}{x^{300}}+\frac {e^{450+50 \log ^2\left (x^2\right )} \left (4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)\right )}{x^{600}}} \, dx=-\frac {2 \, e^{\left (25 \, \log \left (x^{2}\right )^{2} - \frac {x}{x - \log \left (2\right ) - 2} - 150 \, \log \left (x^{2}\right ) + 225\right )} - 2 \, e^{\left (-\frac {x}{x - \log \left (2\right ) - 2}\right )} - 1}{2 \, {\left (e^{\left (25 \, \log \left (x^{2}\right )^{2} - 150 \, \log \left (x^{2}\right ) + 225\right )} - 1\right )}} \]
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Time = 0.56 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.82 \[ \int \frac {e^{\frac {x}{2-x+\log (2)}} (-2 x-x \log (2))+\frac {e^{450+\frac {x}{2-x+\log (2)}+50 \log ^2\left (x^2\right )} (-2 x-x \log (2))}{x^{600}}+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (600-600 x+150 x^2+(600-300 x) \log (2)+150 \log ^2(2)+e^{\frac {x}{2-x+\log (2)}} (4 x+2 x \log (2))+\left (-200+200 x-50 x^2+(-200+100 x) \log (2)-50 \log ^2(2)\right ) \log \left (x^2\right )\right )}{x^{300}}}{4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (-8 x+8 x^2-2 x^3+\left (-8 x+4 x^2\right ) \log (2)-2 x \log ^2(2)\right )}{x^{300}}+\frac {e^{450+50 \log ^2\left (x^2\right )} \left (4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)\right )}{x^{600}}} \, dx=\frac {x^{300}}{- 2 x^{300} + 2 e^{25 \log {\left (x^{2} \right )}^{2} + 225}} - e^{\frac {x}{- x + \log {\left (2 \right )} + 2}} \]
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Timed out. \[ \int \frac {e^{\frac {x}{2-x+\log (2)}} (-2 x-x \log (2))+\frac {e^{450+\frac {x}{2-x+\log (2)}+50 \log ^2\left (x^2\right )} (-2 x-x \log (2))}{x^{600}}+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (600-600 x+150 x^2+(600-300 x) \log (2)+150 \log ^2(2)+e^{\frac {x}{2-x+\log (2)}} (4 x+2 x \log (2))+\left (-200+200 x-50 x^2+(-200+100 x) \log (2)-50 \log ^2(2)\right ) \log \left (x^2\right )\right )}{x^{300}}}{4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (-8 x+8 x^2-2 x^3+\left (-8 x+4 x^2\right ) \log (2)-2 x \log ^2(2)\right )}{x^{300}}+\frac {e^{450+50 \log ^2\left (x^2\right )} \left (4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)\right )}{x^{600}}} \, dx=\text {Timed out} \]
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Exception generated. \[ \int \frac {e^{\frac {x}{2-x+\log (2)}} (-2 x-x \log (2))+\frac {e^{450+\frac {x}{2-x+\log (2)}+50 \log ^2\left (x^2\right )} (-2 x-x \log (2))}{x^{600}}+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (600-600 x+150 x^2+(600-300 x) \log (2)+150 \log ^2(2)+e^{\frac {x}{2-x+\log (2)}} (4 x+2 x \log (2))+\left (-200+200 x-50 x^2+(-200+100 x) \log (2)-50 \log ^2(2)\right ) \log \left (x^2\right )\right )}{x^{300}}}{4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (-8 x+8 x^2-2 x^3+\left (-8 x+4 x^2\right ) \log (2)-2 x \log ^2(2)\right )}{x^{300}}+\frac {e^{450+50 \log ^2\left (x^2\right )} \left (4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)\right )}{x^{600}}} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {e^{\frac {x}{2-x+\log (2)}} (-2 x-x \log (2))+\frac {e^{450+\frac {x}{2-x+\log (2)}+50 \log ^2\left (x^2\right )} (-2 x-x \log (2))}{x^{600}}+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (600-600 x+150 x^2+(600-300 x) \log (2)+150 \log ^2(2)+e^{\frac {x}{2-x+\log (2)}} (4 x+2 x \log (2))+\left (-200+200 x-50 x^2+(-200+100 x) \log (2)-50 \log ^2(2)\right ) \log \left (x^2\right )\right )}{x^{300}}}{4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)+\frac {e^{225+25 \log ^2\left (x^2\right )} \left (-8 x+8 x^2-2 x^3+\left (-8 x+4 x^2\right ) \log (2)-2 x \log ^2(2)\right )}{x^{300}}+\frac {e^{450+50 \log ^2\left (x^2\right )} \left (4 x-4 x^2+x^3+\left (4 x-2 x^2\right ) \log (2)+x \log ^2(2)\right )}{x^{600}}} \, dx=\text {Hanged} \]
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