Integrand size = 159, antiderivative size = 23 \[ \int \frac {\left (e^5 x^2+e^5 x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )+\left (-16 x-4 x^2+(-8-2 x) \log (8)+\left (8 x+2 x^2+(8+2 x) \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )\right ) \log \left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )+\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right ) \log ^2\left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )}{\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )} \, dx=(4+x) \left (e^5+\log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right )\right ) \]
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\[ \int \frac {\left (e^5 x^2+e^5 x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )+\left (-16 x-4 x^2+(-8-2 x) \log (8)+\left (8 x+2 x^2+(8+2 x) \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )\right ) \log \left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )+\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right ) \log ^2\left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )}{\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )} \, dx=\int \frac {\left (e^5 x^2+e^5 x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )+\left (-16 x-4 x^2+(-8-2 x) \log (8)+\left (8 x+2 x^2+(8+2 x) \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )\right ) \log \left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )+\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right ) \log ^2\left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )}{\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\left (e^5 x^2+e^5 x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )+\left (-16 x-4 x^2+(-8-2 x) \log (8)+\left (8 x+2 x^2+(8+2 x) \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )\right ) \log \left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )+\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right ) \log ^2\left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )}{x (x+\log (8)) \log \left (-12 x^2-12 x \log (8)\right )} \, dx \\ & = \int \frac {e^5 x^2+e^5 x \log (8)+\frac {2 (4+x) (-2 x-\log (8)+(x+\log (8)) \log (-12 x (x+\log (8)))) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (-12 x (x+\log (8)))}+x (x+\log (8)) \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x (x+\log (8))} \, dx \\ & = \int \left (e^5+\frac {2 (4+x) (-2 x-\log (8)+x \log (-12 x (x+\log (8)))+\log (8) \log (-12 x (x+\log (8)))) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x (x+\log (8)) \log (-12 x (x+\log (8)))}+\log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right )\right ) \, dx \\ & = e^5 x+2 \int \frac {(4+x) (-2 x-\log (8)+x \log (-12 x (x+\log (8)))+\log (8) \log (-12 x (x+\log (8)))) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x (x+\log (8)) \log (-12 x (x+\log (8)))} \, dx+\int \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx \\ & = e^5 x+2 \int \frac {(4+x) (-2 x-\log (8)+(x+\log (8)) \log (-12 x (x+\log (8)))) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x (x+\log (8)) \log (-12 x (x+\log (8)))} \, dx+\int \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx \\ & = e^5 x+2 \int \left (\frac {4 (-2 x-\log (8)+x \log (-12 x (x+\log (8)))+\log (8) \log (-12 x (x+\log (8)))) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x \log (8) \log (-12 x (x+\log (8)))}+\frac {(-4+\log (8)) (-2 x-\log (8)+x \log (-12 x (x+\log (8)))+\log (8) \log (-12 x (x+\log (8)))) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (8) (x+\log (8)) \log (-12 x (x+\log (8)))}\right ) \, dx+\int \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx \\ & = e^5 x+\frac {8 \int \frac {(-2 x-\log (8)+x \log (-12 x (x+\log (8)))+\log (8) \log (-12 x (x+\log (8)))) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x \log (-12 x (x+\log (8)))} \, dx}{\log (8)}+\frac {(2 (-4+\log (8))) \int \frac {(-2 x-\log (8)+x \log (-12 x (x+\log (8)))+\log (8) \log (-12 x (x+\log (8)))) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx}{\log (8)}+\int \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx \\ & = e^5 x+\frac {8 \int \frac {(-2 x-\log (8)+(x+\log (8)) \log (-12 x (x+\log (8)))) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x \log (-12 x (x+\log (8)))} \, dx}{\log (8)}+\frac {(2 (-4+\log (8))) \int \frac {(-2 x-\log (8)+(x+\log (8)) \log (-12 x (x+\log (8)))) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx}{\log (8)}+\int \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx \\ & = e^5 x+\frac {8 \int \left (\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )+\frac {\log (8) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x}-\frac {2 \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (-12 x (x+\log (8)))}-\frac {\log (8) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x \log (-12 x (x+\log (8)))}\right ) \, dx}{\log (8)}+\frac {(2 (-4+\log (8))) \int \left (\frac {x \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x+\log (8)}+\frac {\log (8) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x+\log (8)}-\frac {2 x \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))}-\frac {\log (8) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))}\right ) \, dx}{\log (8)}+\int \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx \\ & = e^5 x+8 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x} \, dx-8 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x \log (-12 x (x+\log (8)))} \, dx+(2 (-4+\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x+\log (8)} \, dx-(2 (-4+\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx+\frac {8 \int \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx}{\log (8)}-\frac {16 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (-12 x (x+\log (8)))} \, dx}{\log (8)}+\frac {(2 (-4+\log (8))) \int \frac {x \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x+\log (8)} \, dx}{\log (8)}-\frac {(4 (-4+\log (8))) \int \frac {x \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx}{\log (8)}+\int \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx \\ & = e^5 x+\frac {8 x \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (8)}+8 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x} \, dx-8 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x \log (-12 x (x+\log (8)))} \, dx+(2 (-4+\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x+\log (8)} \, dx-(2 (-4+\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx-\frac {8 \int \frac {-2 x-\log (8)+(x+\log (8)) \log (-12 x (x+\log (8)))}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx}{\log (8)}-\frac {16 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (-12 x (x+\log (8)))} \, dx}{\log (8)}+\frac {(2 (-4+\log (8))) \int \left (\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )-\frac {\log (8) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x+\log (8)}\right ) \, dx}{\log (8)}-\frac {(4 (-4+\log (8))) \int \left (\frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (-12 x (x+\log (8)))}-\frac {\log (8) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))}\right ) \, dx}{\log (8)}+\int \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx \\ & = e^5 x+\frac {8 x \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (8)}+8 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x} \, dx-8 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x \log (-12 x (x+\log (8)))} \, dx-(4 (4-\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx-(2 (-4+\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx-\frac {8 \int \left (1+\frac {-2 x-\log (8)}{(x+\log (8)) \log (-12 x (x+\log (8)))}\right ) \, dx}{\log (8)}-\frac {16 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (-12 x (x+\log (8)))} \, dx}{\log (8)}+\frac {(2 (-4+\log (8))) \int \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx}{\log (8)}-\frac {(4 (-4+\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (-12 x (x+\log (8)))} \, dx}{\log (8)}+\int \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx \\ & = e^5 x-\frac {8 x}{\log (8)}+\frac {8 x \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (8)}-\frac {2 x (4-\log (8)) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (8)}+8 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x} \, dx-8 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x \log (-12 x (x+\log (8)))} \, dx-(4 (4-\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx-(2 (-4+\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx-\frac {8 \int \frac {-2 x-\log (8)}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx}{\log (8)}-\frac {16 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (-12 x (x+\log (8)))} \, dx}{\log (8)}-\frac {(2 (-4+\log (8))) \int \frac {-2 x-\log (8)+(x+\log (8)) \log (-12 x (x+\log (8)))}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx}{\log (8)}-\frac {(4 (-4+\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (-12 x (x+\log (8)))} \, dx}{\log (8)}+\int \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx \\ & = e^5 x-\frac {8 x}{\log (8)}+\frac {8 x \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (8)}-\frac {2 x (4-\log (8)) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (8)}+8 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x} \, dx-8 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x \log (-12 x (x+\log (8)))} \, dx-(4 (4-\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx-(2 (-4+\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx-\frac {8 \int \frac {-2 x-\log (8)}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx}{\log (8)}-\frac {16 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (-12 x (x+\log (8)))} \, dx}{\log (8)}-\frac {(2 (-4+\log (8))) \int \left (1+\frac {-2 x-\log (8)}{(x+\log (8)) \log (-12 x (x+\log (8)))}\right ) \, dx}{\log (8)}-\frac {(4 (-4+\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (-12 x (x+\log (8)))} \, dx}{\log (8)}+\int \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx \\ & = e^5 x-\frac {8 x}{\log (8)}+\frac {2 x (4-\log (8))}{\log (8)}+\frac {8 x \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (8)}-\frac {2 x (4-\log (8)) \log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (8)}+8 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x} \, dx-8 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{x \log (-12 x (x+\log (8)))} \, dx-(4 (4-\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx-(2 (-4+\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx-\frac {8 \int \frac {-2 x-\log (8)}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx}{\log (8)}-\frac {16 \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (-12 x (x+\log (8)))} \, dx}{\log (8)}-\frac {(2 (-4+\log (8))) \int \frac {-2 x-\log (8)}{(x+\log (8)) \log (-12 x (x+\log (8)))} \, dx}{\log (8)}-\frac {(4 (-4+\log (8))) \int \frac {\log \left (\frac {x}{\log (-12 x (x+\log (8)))}\right )}{\log (-12 x (x+\log (8)))} \, dx}{\log (8)}+\int \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \, dx \\ \end{align*}
Time = 0.72 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.09 \[ \int \frac {\left (e^5 x^2+e^5 x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )+\left (-16 x-4 x^2+(-8-2 x) \log (8)+\left (8 x+2 x^2+(8+2 x) \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )\right ) \log \left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )+\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right ) \log ^2\left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )}{\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )} \, dx=e^5 x+(4+x) \log ^2\left (\frac {x}{\log (-12 x (x+\log (8)))}\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. \(49\) vs. \(2(24)=48\).
Time = 1.88 (sec) , antiderivative size = 50, normalized size of antiderivative = 2.17
method | result | size |
parallelrisch | \(\ln \left (\frac {x}{\ln \left (-12 x \left (3 \ln \left (2\right )+x \right )\right )}\right )^{2} x -6 \,{\mathrm e}^{5} \ln \left (2\right )+x \,{\mathrm e}^{5}+4 \ln \left (\frac {x}{\ln \left (-12 x \left (3 \ln \left (2\right )+x \right )\right )}\right )^{2}\) | \(50\) |
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none
Time = 0.26 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.22 \[ \int \frac {\left (e^5 x^2+e^5 x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )+\left (-16 x-4 x^2+(-8-2 x) \log (8)+\left (8 x+2 x^2+(8+2 x) \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )\right ) \log \left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )+\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right ) \log ^2\left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )}{\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )} \, dx={\left (x + 4\right )} \log \left (\frac {x}{\log \left (-12 \, x^{2} - 36 \, x \log \left (2\right )\right )}\right )^{2} + x e^{5} \]
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Time = 0.41 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.17 \[ \int \frac {\left (e^5 x^2+e^5 x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )+\left (-16 x-4 x^2+(-8-2 x) \log (8)+\left (8 x+2 x^2+(8+2 x) \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )\right ) \log \left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )+\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right ) \log ^2\left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )}{\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )} \, dx=x e^{5} + \left (x + 4\right ) \log {\left (\frac {x}{\log {\left (- 12 x^{2} - 36 x \log {\left (2 \right )} \right )}} \right )}^{2} \]
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Result contains complex when optimal does not.
Time = 0.36 (sec) , antiderivative size = 94, normalized size of antiderivative = 4.09 \[ \int \frac {\left (e^5 x^2+e^5 x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )+\left (-16 x-4 x^2+(-8-2 x) \log (8)+\left (8 x+2 x^2+(8+2 x) \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )\right ) \log \left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )+\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right ) \log ^2\left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )}{\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )} \, dx={\left (x + 4\right )} \log \left (i \, \pi + \log \left (3\right ) + 2 \, \log \left (2\right ) + \log \left (x + 3 \, \log \left (2\right )\right ) + \log \left (x\right )\right )^{2} + 3 \, e^{5} \log \left (2\right ) \log \left (x + 3 \, \log \left (2\right )\right ) - 2 \, {\left (x + 4\right )} \log \left (i \, \pi + \log \left (3\right ) + 2 \, \log \left (2\right ) + \log \left (x + 3 \, \log \left (2\right )\right ) + \log \left (x\right )\right ) \log \left (x\right ) + {\left (x + 4\right )} \log \left (x\right )^{2} - {\left (3 \, \log \left (2\right ) \log \left (x + 3 \, \log \left (2\right )\right ) - x\right )} e^{5} \]
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\[ \int \frac {\left (e^5 x^2+e^5 x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )+\left (-16 x-4 x^2+(-8-2 x) \log (8)+\left (8 x+2 x^2+(8+2 x) \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )\right ) \log \left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )+\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right ) \log ^2\left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )}{\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )} \, dx=\int { \frac {{\left (x^{2} + 3 \, x \log \left (2\right )\right )} \log \left (-12 \, x^{2} - 36 \, x \log \left (2\right )\right ) \log \left (\frac {x}{\log \left (-12 \, x^{2} - 36 \, x \log \left (2\right )\right )}\right )^{2} + {\left (x^{2} e^{5} + 3 \, x e^{5} \log \left (2\right )\right )} \log \left (-12 \, x^{2} - 36 \, x \log \left (2\right )\right ) - 2 \, {\left (2 \, x^{2} + 3 \, {\left (x + 4\right )} \log \left (2\right ) - {\left (x^{2} + 3 \, {\left (x + 4\right )} \log \left (2\right ) + 4 \, x\right )} \log \left (-12 \, x^{2} - 36 \, x \log \left (2\right )\right ) + 8 \, x\right )} \log \left (\frac {x}{\log \left (-12 \, x^{2} - 36 \, x \log \left (2\right )\right )}\right )}{{\left (x^{2} + 3 \, x \log \left (2\right )\right )} \log \left (-12 \, x^{2} - 36 \, x \log \left (2\right )\right )} \,d x } \]
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Timed out. \[ \int \frac {\left (e^5 x^2+e^5 x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )+\left (-16 x-4 x^2+(-8-2 x) \log (8)+\left (8 x+2 x^2+(8+2 x) \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )\right ) \log \left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )+\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right ) \log ^2\left (\frac {x}{\log \left (-12 x^2-12 x \log (8)\right )}\right )}{\left (x^2+x \log (8)\right ) \log \left (-12 x^2-12 x \log (8)\right )} \, dx=\int \frac {\ln \left (-12\,x^2-36\,\ln \left (2\right )\,x\right )\,\left (x^2+3\,\ln \left (2\right )\,x\right )\,{\ln \left (\frac {x}{\ln \left (-12\,x^2-36\,\ln \left (2\right )\,x\right )}\right )}^2+\left (\ln \left (-12\,x^2-36\,\ln \left (2\right )\,x\right )\,\left (8\,x+3\,\ln \left (2\right )\,\left (2\,x+8\right )+2\,x^2\right )-3\,\ln \left (2\right )\,\left (2\,x+8\right )-16\,x-4\,x^2\right )\,\ln \left (\frac {x}{\ln \left (-12\,x^2-36\,\ln \left (2\right )\,x\right )}\right )+\ln \left (-12\,x^2-36\,\ln \left (2\right )\,x\right )\,\left ({\mathrm {e}}^5\,x^2+3\,{\mathrm {e}}^5\,\ln \left (2\right )\,x\right )}{\ln \left (-12\,x^2-36\,\ln \left (2\right )\,x\right )\,\left (x^2+3\,\ln \left (2\right )\,x\right )} \,d x \]
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