Integrand size = 96, antiderivative size = 29 \[ \int \frac {-8 x-4 x^2+(8+4 x) \log (3)+(-8 x-4 x \log (3)) \log (x)+\left (-4 x-2 x^2+(4+2 x) \log (3)\right ) \log \left (\frac {x^2-2 x \log (3)+\log ^2(3)}{4+4 x+x^2}\right )}{-2 x^2-x^3+\left (2 x+x^2\right ) \log (3)} \, dx=2 \left (1+\log (x)-\log (x) \left (-1-\log \left (\frac {(x-\log (3))^2}{(2+x)^2}\right )\right )\right ) \]
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Result contains higher order function than in optimal. Order 4 vs. order 3 in optimal.
Time = 0.20 (sec) , antiderivative size = 153, normalized size of antiderivative = 5.28, number of steps used = 13, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.073, Rules used = {6820, 2404, 2354, 2438, 2353, 2352, 2546} \[ \int \frac {-8 x-4 x^2+(8+4 x) \log (3)+(-8 x-4 x \log (3)) \log (x)+\left (-4 x-2 x^2+(4+2 x) \log (3)\right ) \log \left (\frac {x^2-2 x \log (3)+\log ^2(3)}{4+4 x+x^2}\right )}{-2 x^2-x^3+\left (2 x+x^2\right ) \log (3)} \, dx=4 \operatorname {PolyLog}\left (2,-\frac {x}{2}\right )-\frac {(8+\log (81)) \operatorname {PolyLog}\left (2,-\frac {x}{2}\right )}{2+\log (3)}-\frac {(8+\log (81)) \operatorname {PolyLog}\left (2,1-\frac {x}{\log (3)}\right )}{2+\log (3)}+4 \operatorname {PolyLog}\left (2,1-\frac {x}{\log (3)}\right )-\frac {(8+\log (81)) \log \left (\frac {x}{2}+1\right ) \log (x)}{2+\log (3)}+4 \log \left (\frac {x}{2}+1\right ) \log (x)+2 \left (\log \left (\frac {(x-\log (3))^2}{(x+2)^2}\right )+2\right ) \log (x)+\frac {(8+\log (81)) \log (\log (3)) \log (x-\log (3))}{2+\log (3)}-4 \log (\log (3)) \log (x-\log (3)) \]
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Rule 2352
Rule 2353
Rule 2354
Rule 2404
Rule 2438
Rule 2546
Rule 6820
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {(8+\log (81)) \log (x)}{(2+x) (x-\log (3))}+\frac {2 \left (2+\log \left (\frac {(x-\log (3))^2}{(2+x)^2}\right )\right )}{x}\right ) \, dx \\ & = 2 \int \frac {2+\log \left (\frac {(x-\log (3))^2}{(2+x)^2}\right )}{x} \, dx+(8+\log (81)) \int \frac {\log (x)}{(2+x) (x-\log (3))} \, dx \\ & = 2 \log (x) \left (2+\log \left (\frac {(x-\log (3))^2}{(2+x)^2}\right )\right )+4 \int \frac {\log (x)}{2+x} \, dx-4 \int \frac {\log (x)}{x-\log (3)} \, dx+(8+\log (81)) \int \left (-\frac {\log (x)}{(2+x) (2+\log (3))}+\frac {\log (x)}{(x-\log (3)) (2+\log (3))}\right ) \, dx \\ & = 4 \log \left (1+\frac {x}{2}\right ) \log (x)+2 \log (x) \left (2+\log \left (\frac {(x-\log (3))^2}{(2+x)^2}\right )\right )-4 \log (x-\log (3)) \log (\log (3))-4 \int \frac {\log \left (1+\frac {x}{2}\right )}{x} \, dx-4 \int \frac {\log \left (\frac {x}{\log (3)}\right )}{x-\log (3)} \, dx-\frac {(8+\log (81)) \int \frac {\log (x)}{2+x} \, dx}{2+\log (3)}+\frac {(8+\log (81)) \int \frac {\log (x)}{x-\log (3)} \, dx}{2+\log (3)} \\ & = 4 \log \left (1+\frac {x}{2}\right ) \log (x)-\frac {(8+\log (81)) \log \left (1+\frac {x}{2}\right ) \log (x)}{2+\log (3)}+2 \log (x) \left (2+\log \left (\frac {(x-\log (3))^2}{(2+x)^2}\right )\right )-4 \log (x-\log (3)) \log (\log (3))+\frac {(8+\log (81)) \log (x-\log (3)) \log (\log (3))}{2+\log (3)}+4 \operatorname {PolyLog}\left (2,-\frac {x}{2}\right )+4 \operatorname {PolyLog}\left (2,1-\frac {x}{\log (3)}\right )+\frac {(8+\log (81)) \int \frac {\log \left (1+\frac {x}{2}\right )}{x} \, dx}{2+\log (3)}+\frac {(8+\log (81)) \int \frac {\log \left (\frac {x}{\log (3)}\right )}{x-\log (3)} \, dx}{2+\log (3)} \\ & = 4 \log \left (1+\frac {x}{2}\right ) \log (x)-\frac {(8+\log (81)) \log \left (1+\frac {x}{2}\right ) \log (x)}{2+\log (3)}+2 \log (x) \left (2+\log \left (\frac {(x-\log (3))^2}{(2+x)^2}\right )\right )-4 \log (x-\log (3)) \log (\log (3))+\frac {(8+\log (81)) \log (x-\log (3)) \log (\log (3))}{2+\log (3)}+4 \operatorname {PolyLog}\left (2,-\frac {x}{2}\right )-\frac {(8+\log (81)) \operatorname {PolyLog}\left (2,-\frac {x}{2}\right )}{2+\log (3)}+4 \operatorname {PolyLog}\left (2,1-\frac {x}{\log (3)}\right )-\frac {(8+\log (81)) \operatorname {PolyLog}\left (2,1-\frac {x}{\log (3)}\right )}{2+\log (3)} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.31 \[ \int \frac {-8 x-4 x^2+(8+4 x) \log (3)+(-8 x-4 x \log (3)) \log (x)+\left (-4 x-2 x^2+(4+2 x) \log (3)\right ) \log \left (\frac {x^2-2 x \log (3)+\log ^2(3)}{4+4 x+x^2}\right )}{-2 x^2-x^3+\left (2 x+x^2\right ) \log (3)} \, dx=\frac {\log (x) \left (8+\log (81)+(4+\log (9)) \log \left (\frac {x^2+\log ^2(3)-x \log (9)}{(2+x)^2}\right )\right )}{2+\log (3)} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 0.32 (sec) , antiderivative size = 310, normalized size of antiderivative = 10.69
method | result | size |
risch | \(4 \ln \left (x \right ) \ln \left (\ln \left (3\right )-x \right )-i \ln \left (x \right ) \pi \,\operatorname {csgn}\left (\frac {i}{\left (2+x \right )^{2}}\right ) \operatorname {csgn}\left (i \left (\ln \left (3\right )-x \right )^{2}\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (3\right )-x \right )^{2}}{\left (2+x \right )^{2}}\right )+i \ln \left (x \right ) \pi \,\operatorname {csgn}\left (\frac {i}{\left (2+x \right )^{2}}\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (3\right )-x \right )^{2}}{\left (2+x \right )^{2}}\right )^{2}+i \ln \left (x \right ) \pi \operatorname {csgn}\left (i \left (2+x \right )\right )^{2} \operatorname {csgn}\left (i \left (2+x \right )^{2}\right )-2 i \ln \left (x \right ) \pi \,\operatorname {csgn}\left (i \left (2+x \right )\right ) \operatorname {csgn}\left (i \left (2+x \right )^{2}\right )^{2}+i \ln \left (x \right ) \pi \operatorname {csgn}\left (i \left (2+x \right )^{2}\right )^{3}-i \ln \left (x \right ) \pi \operatorname {csgn}\left (i \left (\ln \left (3\right )-x \right )\right )^{2} \operatorname {csgn}\left (i \left (\ln \left (3\right )-x \right )^{2}\right )+2 i \ln \left (x \right ) \pi \,\operatorname {csgn}\left (i \left (\ln \left (3\right )-x \right )\right ) \operatorname {csgn}\left (i \left (\ln \left (3\right )-x \right )^{2}\right )^{2}-i \ln \left (x \right ) \pi \operatorname {csgn}\left (i \left (\ln \left (3\right )-x \right )^{2}\right )^{3}+i \ln \left (x \right ) \pi \,\operatorname {csgn}\left (i \left (\ln \left (3\right )-x \right )^{2}\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (3\right )-x \right )^{2}}{\left (2+x \right )^{2}}\right )^{2}-i \ln \left (x \right ) \pi \operatorname {csgn}\left (\frac {i \left (\ln \left (3\right )-x \right )^{2}}{\left (2+x \right )^{2}}\right )^{3}-4 \ln \left (x \right ) \ln \left (2+x \right )+4 \ln \left (x \right )\) | \(310\) |
default | \(4 \ln \left (x \right )-2 \ln \left (\frac {1}{2+x}\right ) \ln \left (\frac {\ln \left (3\right )^{2}}{\left (2+x \right )^{2}}+\frac {4 \ln \left (3\right )}{\left (2+x \right )^{2}}-\frac {2 \ln \left (3\right )}{2+x}+\frac {4}{\left (2+x \right )^{2}}-\frac {4}{2+x}+1\right )+4 \left (2+\ln \left (3\right )\right ) \left (\frac {\left (\ln \left (\frac {1}{2+x}\right )-\ln \left (\frac {2+\ln \left (3\right )}{2+x}\right )\right ) \ln \left (-\frac {2+\ln \left (3\right )}{2+x}+1\right )}{2+\ln \left (3\right )}-\frac {\operatorname {dilog}\left (\frac {2+\ln \left (3\right )}{2+x}\right )}{2+\ln \left (3\right )}\right )+2 \ln \left (-1+\frac {2}{2+x}\right ) \ln \left (\frac {\ln \left (3\right )^{2}}{\left (2+x \right )^{2}}+\frac {4 \ln \left (3\right )}{\left (2+x \right )^{2}}-\frac {2 \ln \left (3\right )}{2+x}+\frac {4}{\left (2+x \right )^{2}}-\frac {4}{2+x}+1\right )-2 \left (2 \ln \left (3\right )+4\right ) \left (\frac {\operatorname {dilog}\left (\frac {\left (2+\ln \left (3\right )\right ) \left (-1+\frac {2}{2+x}\right )+\ln \left (3\right )}{\ln \left (3\right )}\right )}{2+\ln \left (3\right )}+\frac {\ln \left (-1+\frac {2}{2+x}\right ) \ln \left (\frac {\left (2+\ln \left (3\right )\right ) \left (-1+\frac {2}{2+x}\right )+\ln \left (3\right )}{\ln \left (3\right )}\right )}{2+\ln \left (3\right )}\right )+\left (-4 \ln \left (3\right )-8\right ) \left (-\frac {\left (\ln \left (x \right )-\ln \left (\frac {x}{\ln \left (3\right )}\right )\right ) \ln \left (\frac {\ln \left (3\right )-x}{\ln \left (3\right )}\right )-\operatorname {dilog}\left (\frac {x}{\ln \left (3\right )}\right )}{2+\ln \left (3\right )}+\frac {\operatorname {dilog}\left (1+\frac {x}{2}\right )+\ln \left (x \right ) \ln \left (1+\frac {x}{2}\right )}{2+\ln \left (3\right )}\right )\) | \(336\) |
parts | \(4 \ln \left (x \right )-2 \ln \left (\frac {1}{2+x}\right ) \ln \left (\frac {\ln \left (3\right )^{2}}{\left (2+x \right )^{2}}+\frac {4 \ln \left (3\right )}{\left (2+x \right )^{2}}-\frac {2 \ln \left (3\right )}{2+x}+\frac {4}{\left (2+x \right )^{2}}-\frac {4}{2+x}+1\right )+4 \left (2+\ln \left (3\right )\right ) \left (\frac {\left (\ln \left (\frac {1}{2+x}\right )-\ln \left (\frac {2+\ln \left (3\right )}{2+x}\right )\right ) \ln \left (-\frac {2+\ln \left (3\right )}{2+x}+1\right )}{2+\ln \left (3\right )}-\frac {\operatorname {dilog}\left (\frac {2+\ln \left (3\right )}{2+x}\right )}{2+\ln \left (3\right )}\right )+2 \ln \left (-1+\frac {2}{2+x}\right ) \ln \left (\frac {\ln \left (3\right )^{2}}{\left (2+x \right )^{2}}+\frac {4 \ln \left (3\right )}{\left (2+x \right )^{2}}-\frac {2 \ln \left (3\right )}{2+x}+\frac {4}{\left (2+x \right )^{2}}-\frac {4}{2+x}+1\right )-2 \left (2 \ln \left (3\right )+4\right ) \left (\frac {\operatorname {dilog}\left (\frac {\left (2+\ln \left (3\right )\right ) \left (-1+\frac {2}{2+x}\right )+\ln \left (3\right )}{\ln \left (3\right )}\right )}{2+\ln \left (3\right )}+\frac {\ln \left (-1+\frac {2}{2+x}\right ) \ln \left (\frac {\left (2+\ln \left (3\right )\right ) \left (-1+\frac {2}{2+x}\right )+\ln \left (3\right )}{\ln \left (3\right )}\right )}{2+\ln \left (3\right )}\right )+\left (-4 \ln \left (3\right )-8\right ) \left (-\frac {\left (\ln \left (x \right )-\ln \left (\frac {x}{\ln \left (3\right )}\right )\right ) \ln \left (\frac {\ln \left (3\right )-x}{\ln \left (3\right )}\right )-\operatorname {dilog}\left (\frac {x}{\ln \left (3\right )}\right )}{2+\ln \left (3\right )}+\frac {\operatorname {dilog}\left (1+\frac {x}{2}\right )+\ln \left (x \right ) \ln \left (1+\frac {x}{2}\right )}{2+\ln \left (3\right )}\right )\) | \(336\) |
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Time = 0.27 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.17 \[ \int \frac {-8 x-4 x^2+(8+4 x) \log (3)+(-8 x-4 x \log (3)) \log (x)+\left (-4 x-2 x^2+(4+2 x) \log (3)\right ) \log \left (\frac {x^2-2 x \log (3)+\log ^2(3)}{4+4 x+x^2}\right )}{-2 x^2-x^3+\left (2 x+x^2\right ) \log (3)} \, dx=2 \, \log \left (x\right ) \log \left (\frac {x^{2} - 2 \, x \log \left (3\right ) + \log \left (3\right )^{2}}{x^{2} + 4 \, x + 4}\right ) + 4 \, \log \left (x\right ) \]
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Time = 0.18 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.17 \[ \int \frac {-8 x-4 x^2+(8+4 x) \log (3)+(-8 x-4 x \log (3)) \log (x)+\left (-4 x-2 x^2+(4+2 x) \log (3)\right ) \log \left (\frac {x^2-2 x \log (3)+\log ^2(3)}{4+4 x+x^2}\right )}{-2 x^2-x^3+\left (2 x+x^2\right ) \log (3)} \, dx=2 \log {\left (x \right )} \log {\left (\frac {x^{2} - 2 x \log {\left (3 \right )} + \log {\left (3 \right )}^{2}}{x^{2} + 4 x + 4} \right )} + 4 \log {\left (x \right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 127 vs. \(2 (27) = 54\).
Time = 0.30 (sec) , antiderivative size = 127, normalized size of antiderivative = 4.38 \[ \int \frac {-8 x-4 x^2+(8+4 x) \log (3)+(-8 x-4 x \log (3)) \log (x)+\left (-4 x-2 x^2+(4+2 x) \log (3)\right ) \log \left (\frac {x^2-2 x \log (3)+\log ^2(3)}{4+4 x+x^2}\right )}{-2 x^2-x^3+\left (2 x+x^2\right ) \log (3)} \, dx=-4 \, {\left (\frac {2 \, \log \left (x - \log \left (3\right )\right )}{\log \left (3\right )^{2} + 2 \, \log \left (3\right )} + \frac {\log \left (x + 2\right )}{\log \left (3\right ) + 2} - \frac {\log \left (x\right )}{\log \left (3\right )}\right )} \log \left (3\right ) - 4 \, {\left (\frac {\log \left (x - \log \left (3\right )\right )}{\log \left (3\right ) + 2} - \frac {\log \left (x + 2\right )}{\log \left (3\right ) + 2}\right )} \log \left (3\right ) + 4 \, \log \left (x - \log \left (3\right )\right ) \log \left (x\right ) - 4 \, \log \left (x + 2\right ) \log \left (x\right ) + \frac {4 \, \log \left (3\right ) \log \left (x - \log \left (3\right )\right )}{\log \left (3\right ) + 2} + \frac {8 \, \log \left (x - \log \left (3\right )\right )}{\log \left (3\right ) + 2} \]
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Time = 0.36 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.24 \[ \int \frac {-8 x-4 x^2+(8+4 x) \log (3)+(-8 x-4 x \log (3)) \log (x)+\left (-4 x-2 x^2+(4+2 x) \log (3)\right ) \log \left (\frac {x^2-2 x \log (3)+\log ^2(3)}{4+4 x+x^2}\right )}{-2 x^2-x^3+\left (2 x+x^2\right ) \log (3)} \, dx=2 \, \log \left (x^{2} - 2 \, x \log \left (3\right ) + \log \left (3\right )^{2}\right ) \log \left (x\right ) - 2 \, \log \left (x^{2} + 4 \, x + 4\right ) \log \left (x\right ) + 4 \, \log \left (x\right ) \]
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Timed out. \[ \int \frac {-8 x-4 x^2+(8+4 x) \log (3)+(-8 x-4 x \log (3)) \log (x)+\left (-4 x-2 x^2+(4+2 x) \log (3)\right ) \log \left (\frac {x^2-2 x \log (3)+\log ^2(3)}{4+4 x+x^2}\right )}{-2 x^2-x^3+\left (2 x+x^2\right ) \log (3)} \, dx=\int \frac {8\,x-\ln \left (3\right )\,\left (4\,x+8\right )+\ln \left (\frac {x^2-2\,\ln \left (3\right )\,x+{\ln \left (3\right )}^2}{x^2+4\,x+4}\right )\,\left (4\,x-\ln \left (3\right )\,\left (2\,x+4\right )+2\,x^2\right )+\ln \left (x\right )\,\left (8\,x+4\,x\,\ln \left (3\right )\right )+4\,x^2}{2\,x^2+x^3-\ln \left (3\right )\,\left (x^2+2\,x\right )} \,d x \]
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