Integrand size = 75, antiderivative size = 21 \[ \int e^{(4+x)^{x^2} \left (-10 x+10 x^3\right )} (4+x)^{-1+x^2} \left (-40-10 x+120 x^2+20 x^3+10 x^5+\left (-80 x^2-20 x^3+80 x^4+20 x^5\right ) \log (4+x)\right ) \, dx=e^{5 (4+x)^{x^2} (-2+2 x) \left (x+x^2\right )} \]
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\[ \int e^{(4+x)^{x^2} \left (-10 x+10 x^3\right )} (4+x)^{-1+x^2} \left (-40-10 x+120 x^2+20 x^3+10 x^5+\left (-80 x^2-20 x^3+80 x^4+20 x^5\right ) \log (4+x)\right ) \, dx=\int e^{(4+x)^{x^2} \left (-10 x+10 x^3\right )} (4+x)^{-1+x^2} \left (-40-10 x+120 x^2+20 x^3+10 x^5+\left (-80 x^2-20 x^3+80 x^4+20 x^5\right ) \log (4+x)\right ) \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} (4+x)^{-1+x^2} \left (-40-10 x+120 x^2+20 x^3+10 x^5+\left (-80 x^2-20 x^3+80 x^4+20 x^5\right ) \log (4+x)\right ) \, dx \\ & = \int \left (-40 e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} (4+x)^{-1+x^2}-10 e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x (4+x)^{-1+x^2}+120 e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^2 (4+x)^{-1+x^2}+20 e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^3 (4+x)^{-1+x^2}+10 e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^5 (4+x)^{-1+x^2}+20 e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^2 (4+x)^{-1+x^2} \left (-4-x+4 x^2+x^3\right ) \log (4+x)\right ) \, dx \\ & = -\left (10 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x (4+x)^{-1+x^2} \, dx\right )+10 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^5 (4+x)^{-1+x^2} \, dx+20 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^3 (4+x)^{-1+x^2} \, dx+20 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^2 (4+x)^{-1+x^2} \left (-4-x+4 x^2+x^3\right ) \log (4+x) \, dx-40 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} (4+x)^{-1+x^2} \, dx+120 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^2 (4+x)^{-1+x^2} \, dx \\ & = -\left (10 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x (4+x)^{-1+x^2} \, dx\right )+10 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^5 (4+x)^{-1+x^2} \, dx+20 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^3 (4+x)^{-1+x^2} \, dx-20 \int \frac {-\int e^{10 x (4+x)^{x^2} \left (-1+x^2\right )} x^2 (4+x)^{x^2} \, dx+\int e^{10 x (4+x)^{x^2} \left (-1+x^2\right )} x^4 (4+x)^{x^2} \, dx}{4+x} \, dx-40 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} (4+x)^{-1+x^2} \, dx+120 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^2 (4+x)^{-1+x^2} \, dx-(20 \log (4+x)) \int e^{10 x (4+x)^{x^2} \left (-1+x^2\right )} x^2 (4+x)^{x^2} \, dx+(20 \log (4+x)) \int e^{10 x (4+x)^{x^2} \left (-1+x^2\right )} x^4 (4+x)^{x^2} \, dx \\ & = -\left (10 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x (4+x)^{-1+x^2} \, dx\right )+10 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^5 (4+x)^{-1+x^2} \, dx+20 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^3 (4+x)^{-1+x^2} \, dx-20 \int \left (-\frac {\int e^{10 x (4+x)^{x^2} \left (-1+x^2\right )} x^2 (4+x)^{x^2} \, dx}{4+x}+\frac {\int e^{10 x (4+x)^{x^2} \left (-1+x^2\right )} x^4 (4+x)^{x^2} \, dx}{4+x}\right ) \, dx-40 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} (4+x)^{-1+x^2} \, dx+120 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^2 (4+x)^{-1+x^2} \, dx-(20 \log (4+x)) \int e^{10 x (4+x)^{x^2} \left (-1+x^2\right )} x^2 (4+x)^{x^2} \, dx+(20 \log (4+x)) \int e^{10 x (4+x)^{x^2} \left (-1+x^2\right )} x^4 (4+x)^{x^2} \, dx \\ & = -\left (10 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x (4+x)^{-1+x^2} \, dx\right )+10 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^5 (4+x)^{-1+x^2} \, dx+20 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^3 (4+x)^{-1+x^2} \, dx+20 \int \frac {\int e^{10 x (4+x)^{x^2} \left (-1+x^2\right )} x^2 (4+x)^{x^2} \, dx}{4+x} \, dx-20 \int \frac {\int e^{10 x (4+x)^{x^2} \left (-1+x^2\right )} x^4 (4+x)^{x^2} \, dx}{4+x} \, dx-40 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} (4+x)^{-1+x^2} \, dx+120 \int e^{x (4+x)^{x^2} \left (-10+10 x^2\right )} x^2 (4+x)^{-1+x^2} \, dx-(20 \log (4+x)) \int e^{10 x (4+x)^{x^2} \left (-1+x^2\right )} x^2 (4+x)^{x^2} \, dx+(20 \log (4+x)) \int e^{10 x (4+x)^{x^2} \left (-1+x^2\right )} x^4 (4+x)^{x^2} \, dx \\ \end{align*}
Time = 5.05 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.81 \[ \int e^{(4+x)^{x^2} \left (-10 x+10 x^3\right )} (4+x)^{-1+x^2} \left (-40-10 x+120 x^2+20 x^3+10 x^5+\left (-80 x^2-20 x^3+80 x^4+20 x^5\right ) \log (4+x)\right ) \, dx=e^{10 x (4+x)^{x^2} \left (-1+x^2\right )} \]
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Time = 1.26 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.86
method | result | size |
risch | \({\mathrm e}^{10 x \left (-1+x \right ) \left (1+x \right ) \left (4+x \right )^{x^{2}}}\) | \(18\) |
parallelrisch | \({\mathrm e}^{\left (10 x^{3}-10 x \right ) {\mathrm e}^{x^{2} \ln \left (4+x \right )}}\) | \(21\) |
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Time = 0.24 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.81 \[ \int e^{(4+x)^{x^2} \left (-10 x+10 x^3\right )} (4+x)^{-1+x^2} \left (-40-10 x+120 x^2+20 x^3+10 x^5+\left (-80 x^2-20 x^3+80 x^4+20 x^5\right ) \log (4+x)\right ) \, dx=e^{\left (10 \, {\left (x^{3} - x\right )} {\left (x + 4\right )}^{\left (x^{2}\right )}\right )} \]
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Time = 0.91 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.90 \[ \int e^{(4+x)^{x^2} \left (-10 x+10 x^3\right )} (4+x)^{-1+x^2} \left (-40-10 x+120 x^2+20 x^3+10 x^5+\left (-80 x^2-20 x^3+80 x^4+20 x^5\right ) \log (4+x)\right ) \, dx=e^{\left (10 x^{3} - 10 x\right ) e^{x^{2} \log {\left (x + 4 \right )}}} \]
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Time = 0.28 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.14 \[ \int e^{(4+x)^{x^2} \left (-10 x+10 x^3\right )} (4+x)^{-1+x^2} \left (-40-10 x+120 x^2+20 x^3+10 x^5+\left (-80 x^2-20 x^3+80 x^4+20 x^5\right ) \log (4+x)\right ) \, dx=e^{\left (10 \, {\left (x + 4\right )}^{\left (x^{2}\right )} x^{3} - 10 \, {\left (x + 4\right )}^{\left (x^{2}\right )} x\right )} \]
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Timed out. \[ \int e^{(4+x)^{x^2} \left (-10 x+10 x^3\right )} (4+x)^{-1+x^2} \left (-40-10 x+120 x^2+20 x^3+10 x^5+\left (-80 x^2-20 x^3+80 x^4+20 x^5\right ) \log (4+x)\right ) \, dx=\text {Timed out} \]
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Time = 11.82 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.19 \[ \int e^{(4+x)^{x^2} \left (-10 x+10 x^3\right )} (4+x)^{-1+x^2} \left (-40-10 x+120 x^2+20 x^3+10 x^5+\left (-80 x^2-20 x^3+80 x^4+20 x^5\right ) \log (4+x)\right ) \, dx={\mathrm {e}}^{-10\,x\,{\left (x+4\right )}^{x^2}}\,{\mathrm {e}}^{10\,x^3\,{\left (x+4\right )}^{x^2}} \]
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