Integrand size = 320, antiderivative size = 30 \[ \int \frac {-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (20 x \log (3)+e^{3-e^x} \left (-x \log (3)-e^x x^2 \log (3)\right )\right )+\left (-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400 \log (3)+e^{6-2 e^x} \log (3)-40 e^{3-e^x} \log (3)\right )\right ) \log \left (e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}}-x\right )}{e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400+e^{6-2 e^x}-40 e^{3-e^x}\right )-400 x-e^{6-2 e^x} x+40 e^{3-e^x} x} \, dx=x \log (3) \log \left (e^{4+\frac {x}{20-e^{3-e^x}}}-x\right ) \]
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Timed out. \[ \int \frac {-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (20 x \log (3)+e^{3-e^x} \left (-x \log (3)-e^x x^2 \log (3)\right )\right )+\left (-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400 \log (3)+e^{6-2 e^x} \log (3)-40 e^{3-e^x} \log (3)\right )\right ) \log \left (e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}}-x\right )}{e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400+e^{6-2 e^x}-40 e^{3-e^x}\right )-400 x-e^{6-2 e^x} x+40 e^{3-e^x} x} \, dx=\text {\$Aborted} \]
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Rubi steps Aborted
Time = 3.96 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.23 \[ \int \frac {-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (20 x \log (3)+e^{3-e^x} \left (-x \log (3)-e^x x^2 \log (3)\right )\right )+\left (-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400 \log (3)+e^{6-2 e^x} \log (3)-40 e^{3-e^x} \log (3)\right )\right ) \log \left (e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}}-x\right )}{e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400+e^{6-2 e^x}-40 e^{3-e^x}\right )-400 x-e^{6-2 e^x} x+40 e^{3-e^x} x} \, dx=x \log (3) \log \left (e^{\frac {1}{20} \left (80+x-\frac {e^3 x}{e^3-20 e^{e^x}}\right )}-x\right ) \]
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Time = 157.76 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.20
method | result | size |
risch | \(\ln \left (3\right ) \ln \left ({\mathrm e}^{-\frac {-4 \,{\mathrm e}^{-{\mathrm e}^{x}+3}+x +80}{{\mathrm e}^{-{\mathrm e}^{x}+3}-20}}-x \right ) x\) | \(36\) |
parallelrisch | \(\ln \left (3\right ) x \ln \left ({\mathrm e}^{\frac {4 \,{\mathrm e}^{-{\mathrm e}^{x}+3}-x -80}{{\mathrm e}^{-{\mathrm e}^{x}+3}-20}}-x \right )\) | \(37\) |
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Time = 0.26 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.17 \[ \int \frac {-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (20 x \log (3)+e^{3-e^x} \left (-x \log (3)-e^x x^2 \log (3)\right )\right )+\left (-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400 \log (3)+e^{6-2 e^x} \log (3)-40 e^{3-e^x} \log (3)\right )\right ) \log \left (e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}}-x\right )}{e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400+e^{6-2 e^x}-40 e^{3-e^x}\right )-400 x-e^{6-2 e^x} x+40 e^{3-e^x} x} \, dx=x \log \left (3\right ) \log \left (-x + e^{\left (-\frac {x - 4 \, e^{\left (-e^{x} + 3\right )} + 80}{e^{\left (-e^{x} + 3\right )} - 20}\right )}\right ) \]
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Timed out. \[ \int \frac {-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (20 x \log (3)+e^{3-e^x} \left (-x \log (3)-e^x x^2 \log (3)\right )\right )+\left (-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400 \log (3)+e^{6-2 e^x} \log (3)-40 e^{3-e^x} \log (3)\right )\right ) \log \left (e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}}-x\right )}{e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400+e^{6-2 e^x}-40 e^{3-e^x}\right )-400 x-e^{6-2 e^x} x+40 e^{3-e^x} x} \, dx=\text {Timed out} \]
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Leaf count of result is larger than twice the leaf count of optimal. 88 vs. \(2 (26) = 52\).
Time = 0.63 (sec) , antiderivative size = 88, normalized size of antiderivative = 2.93 \[ \int \frac {-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (20 x \log (3)+e^{3-e^x} \left (-x \log (3)-e^x x^2 \log (3)\right )\right )+\left (-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400 \log (3)+e^{6-2 e^x} \log (3)-40 e^{3-e^x} \log (3)\right )\right ) \log \left (e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}}-x\right )}{e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400+e^{6-2 e^x}-40 e^{3-e^x}\right )-400 x-e^{6-2 e^x} x+40 e^{3-e^x} x} \, dx=\frac {4 \, x e^{3} \log \left (3\right ) + {\left (x e^{3} \log \left (3\right ) - 20 \, x e^{\left (e^{x}\right )} \log \left (3\right )\right )} \log \left (-x e^{\left (-\frac {4 \, e^{3}}{e^{3} - 20 \, e^{\left (e^{x}\right )}}\right )} + e^{\left (-\frac {x e^{\left (e^{x}\right )}}{e^{3} - 20 \, e^{\left (e^{x}\right )}} - \frac {80 \, e^{\left (e^{x}\right )}}{e^{3} - 20 \, e^{\left (e^{x}\right )}}\right )}\right )}{e^{3} - 20 \, e^{\left (e^{x}\right )}} \]
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Timed out. \[ \int \frac {-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (20 x \log (3)+e^{3-e^x} \left (-x \log (3)-e^x x^2 \log (3)\right )\right )+\left (-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400 \log (3)+e^{6-2 e^x} \log (3)-40 e^{3-e^x} \log (3)\right )\right ) \log \left (e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}}-x\right )}{e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400+e^{6-2 e^x}-40 e^{3-e^x}\right )-400 x-e^{6-2 e^x} x+40 e^{3-e^x} x} \, dx=\text {Timed out} \]
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Time = 12.74 (sec) , antiderivative size = 63, normalized size of antiderivative = 2.10 \[ \int \frac {-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (20 x \log (3)+e^{3-e^x} \left (-x \log (3)-e^x x^2 \log (3)\right )\right )+\left (-400 x \log (3)-e^{6-2 e^x} x \log (3)+40 e^{3-e^x} x \log (3)+e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400 \log (3)+e^{6-2 e^x} \log (3)-40 e^{3-e^x} \log (3)\right )\right ) \log \left (e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}}-x\right )}{e^{\frac {-80+4 e^{3-e^x}-x}{-20+e^{3-e^x}}} \left (400+e^{6-2 e^x}-40 e^{3-e^x}\right )-400 x-e^{6-2 e^x} x+40 e^{3-e^x} x} \, dx=x\,\ln \left ({\mathrm {e}}^{-\frac {x}{{\mathrm {e}}^3\,{\mathrm {e}}^{-{\mathrm {e}}^x}-20}}\,{\mathrm {e}}^{-\frac {80}{{\mathrm {e}}^3\,{\mathrm {e}}^{-{\mathrm {e}}^x}-20}}\,{\mathrm {e}}^{\frac {4\,{\mathrm {e}}^3\,{\mathrm {e}}^{-{\mathrm {e}}^x}}{{\mathrm {e}}^3\,{\mathrm {e}}^{-{\mathrm {e}}^x}-20}}-x\right )\,\ln \left (3\right ) \]
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