\(\int \frac {e^{-2+e^{5 e^x}} (-50 x^2+50 e^{-3+x} x^2)+e^{-4+2 e^{5 e^x}} (50 e^{-3+x} x-50 x^2+e^{5 e^x+x} (250 e^{-3+x} x^2-250 x^3)) \log (e^{-3+x}-x) \log (\log (e^{-3+x}-x))+(-50 x^2+50 e^{-3+x} x^2+e^{-2+e^{5 e^x}} (100 e^{-3+x} x-100 x^2+e^{5 e^x+x} (250 e^{-3+x} x^2-250 x^3)) \log (e^{-3+x}-x) \log (\log (e^{-3+x}-x))) \log (\log (\log (e^{-3+x}-x)))+(50 e^{-3+x} x-50 x^2) \log (e^{-3+x}-x) \log (\log (e^{-3+x}-x)) \log ^2(\log (\log (e^{-3+x}-x)))}{(e^{-3+x}-x) \log (e^{-3+x}-x) \log (\log (e^{-3+x}-x))} \, dx\) [6817]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [B] (verified)
   Fricas [B] (verification not implemented)
   Sympy [F(-1)]
   Maxima [B] (verification not implemented)
   Giac [F]
   Mupad [F(-1)]

Optimal result

Integrand size = 293, antiderivative size = 31 \[ \int \frac {e^{-2+e^{5 e^x}} \left (-50 x^2+50 e^{-3+x} x^2\right )+e^{-4+2 e^{5 e^x}} \left (50 e^{-3+x} x-50 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )+\left (-50 x^2+50 e^{-3+x} x^2+e^{-2+e^{5 e^x}} \left (100 e^{-3+x} x-100 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )\right ) \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )+\left (50 e^{-3+x} x-50 x^2\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right ) \log ^2\left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )}{\left (e^{-3+x}-x\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )} \, dx=25 x^2 \left (e^{-2+e^{5 e^x}}+\log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )\right )^2 \]

[Out]

25*x^2*(exp(exp(5*exp(x))-2)+ln(ln(ln(exp(-3+x)-x))))^2

Rubi [A] (verified)

Time = 2.37 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.16, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.010, Rules used = {6820, 12, 6819} \[ \int \frac {e^{-2+e^{5 e^x}} \left (-50 x^2+50 e^{-3+x} x^2\right )+e^{-4+2 e^{5 e^x}} \left (50 e^{-3+x} x-50 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )+\left (-50 x^2+50 e^{-3+x} x^2+e^{-2+e^{5 e^x}} \left (100 e^{-3+x} x-100 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )\right ) \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )+\left (50 e^{-3+x} x-50 x^2\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right ) \log ^2\left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )}{\left (e^{-3+x}-x\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )} \, dx=\frac {25 x^2 \left (e^{e^{5 e^x}}+e^2 \log \left (\log \left (\log \left (e^{x-3}-x\right )\right )\right )\right )^2}{e^4} \]

[In]

Int[(E^(-2 + E^(5*E^x))*(-50*x^2 + 50*E^(-3 + x)*x^2) + E^(-4 + 2*E^(5*E^x))*(50*E^(-3 + x)*x - 50*x^2 + E^(5*
E^x + x)*(250*E^(-3 + x)*x^2 - 250*x^3))*Log[E^(-3 + x) - x]*Log[Log[E^(-3 + x) - x]] + (-50*x^2 + 50*E^(-3 +
x)*x^2 + E^(-2 + E^(5*E^x))*(100*E^(-3 + x)*x - 100*x^2 + E^(5*E^x + x)*(250*E^(-3 + x)*x^2 - 250*x^3))*Log[E^
(-3 + x) - x]*Log[Log[E^(-3 + x) - x]])*Log[Log[Log[E^(-3 + x) - x]]] + (50*E^(-3 + x)*x - 50*x^2)*Log[E^(-3 +
 x) - x]*Log[Log[E^(-3 + x) - x]]*Log[Log[Log[E^(-3 + x) - x]]]^2)/((E^(-3 + x) - x)*Log[E^(-3 + x) - x]*Log[L
og[E^(-3 + x) - x]]),x]

[Out]

(25*x^2*(E^E^(5*E^x) + E^2*Log[Log[Log[E^(-3 + x) - x]]])^2)/E^4

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 6819

Int[(u_)*(y_)^(m_.)*(z_)^(n_.), x_Symbol] :> With[{q = DerivativeDivides[y*z, u*z^(n - m), x]}, Simp[q*y^(m +
1)*(z^(m + 1)/(m + 1)), x] /;  !FalseQ[q]] /; FreeQ[{m, n}, x] && NeQ[m, -1]

Rule 6820

Int[u_, x_Symbol] :> With[{v = SimplifyIntegrand[u, x]}, Int[v, x] /; SimplerIntegrandQ[v, u, x]]

Rubi steps \begin{align*} \text {integral}& = \int \frac {50 x \left (e^{e^{5 e^x}}+e^2 \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )\right ) \left (-e^5 x+e^{2+x} x+\left (e^x-e^3 x\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right ) \left (e^{e^{5 e^x}} \left (1+5 e^{5 e^x+x} x\right )+e^2 \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )\right )\right )}{e^4 \left (e^x-e^3 x\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )} \, dx \\ & = \frac {50 \int \frac {x \left (e^{e^{5 e^x}}+e^2 \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )\right ) \left (-e^5 x+e^{2+x} x+\left (e^x-e^3 x\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right ) \left (e^{e^{5 e^x}} \left (1+5 e^{5 e^x+x} x\right )+e^2 \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )\right )\right )}{\left (e^x-e^3 x\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )} \, dx}{e^4} \\ & = \frac {25 x^2 \left (e^{e^{5 e^x}}+e^2 \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )\right )^2}{e^4} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.27 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.16 \[ \int \frac {e^{-2+e^{5 e^x}} \left (-50 x^2+50 e^{-3+x} x^2\right )+e^{-4+2 e^{5 e^x}} \left (50 e^{-3+x} x-50 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )+\left (-50 x^2+50 e^{-3+x} x^2+e^{-2+e^{5 e^x}} \left (100 e^{-3+x} x-100 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )\right ) \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )+\left (50 e^{-3+x} x-50 x^2\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right ) \log ^2\left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )}{\left (e^{-3+x}-x\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )} \, dx=\frac {25 x^2 \left (e^{e^{5 e^x}}+e^2 \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )\right )^2}{e^4} \]

[In]

Integrate[(E^(-2 + E^(5*E^x))*(-50*x^2 + 50*E^(-3 + x)*x^2) + E^(-4 + 2*E^(5*E^x))*(50*E^(-3 + x)*x - 50*x^2 +
 E^(5*E^x + x)*(250*E^(-3 + x)*x^2 - 250*x^3))*Log[E^(-3 + x) - x]*Log[Log[E^(-3 + x) - x]] + (-50*x^2 + 50*E^
(-3 + x)*x^2 + E^(-2 + E^(5*E^x))*(100*E^(-3 + x)*x - 100*x^2 + E^(5*E^x + x)*(250*E^(-3 + x)*x^2 - 250*x^3))*
Log[E^(-3 + x) - x]*Log[Log[E^(-3 + x) - x]])*Log[Log[Log[E^(-3 + x) - x]]] + (50*E^(-3 + x)*x - 50*x^2)*Log[E
^(-3 + x) - x]*Log[Log[E^(-3 + x) - x]]*Log[Log[Log[E^(-3 + x) - x]]]^2)/((E^(-3 + x) - x)*Log[E^(-3 + x) - x]
*Log[Log[E^(-3 + x) - x]]),x]

[Out]

(25*x^2*(E^E^(5*E^x) + E^2*Log[Log[Log[E^(-3 + x) - x]]])^2)/E^4

Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(58\) vs. \(2(27)=54\).

Time = 0.76 (sec) , antiderivative size = 59, normalized size of antiderivative = 1.90

\[25 x^{2} {\mathrm e}^{2 \,{\mathrm e}^{5 \,{\mathrm e}^{x}}-4}+50 x^{2} {\mathrm e}^{{\mathrm e}^{5 \,{\mathrm e}^{x}}-2} \ln \left (\ln \left (\ln \left ({\mathrm e}^{-3+x}-x \right )\right )\right )+25 {\ln \left (\ln \left (\ln \left ({\mathrm e}^{-3+x}-x \right )\right )\right )}^{2} x^{2}\]

[In]

int(((50*x*exp(-3+x)-50*x^2)*ln(exp(-3+x)-x)*ln(ln(exp(-3+x)-x))*ln(ln(ln(exp(-3+x)-x)))^2+(((250*x^2*exp(-3+x
)-250*x^3)*exp(x)*exp(5*exp(x))+100*x*exp(-3+x)-100*x^2)*ln(exp(-3+x)-x)*exp(exp(5*exp(x))-2)*ln(ln(exp(-3+x)-
x))+50*x^2*exp(-3+x)-50*x^2)*ln(ln(ln(exp(-3+x)-x)))+((250*x^2*exp(-3+x)-250*x^3)*exp(x)*exp(5*exp(x))+50*x*ex
p(-3+x)-50*x^2)*ln(exp(-3+x)-x)*exp(exp(5*exp(x))-2)^2*ln(ln(exp(-3+x)-x))+(50*x^2*exp(-3+x)-50*x^2)*exp(exp(5
*exp(x))-2))/(exp(-3+x)-x)/ln(exp(-3+x)-x)/ln(ln(exp(-3+x)-x)),x)

[Out]

25*x^2*exp(2*exp(5*exp(x))-4)+50*x^2*exp(exp(5*exp(x))-2)*ln(ln(ln(exp(-3+x)-x)))+25*ln(ln(ln(exp(-3+x)-x)))^2
*x^2

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 87 vs. \(2 (27) = 54\).

Time = 0.26 (sec) , antiderivative size = 87, normalized size of antiderivative = 2.81 \[ \int \frac {e^{-2+e^{5 e^x}} \left (-50 x^2+50 e^{-3+x} x^2\right )+e^{-4+2 e^{5 e^x}} \left (50 e^{-3+x} x-50 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )+\left (-50 x^2+50 e^{-3+x} x^2+e^{-2+e^{5 e^x}} \left (100 e^{-3+x} x-100 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )\right ) \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )+\left (50 e^{-3+x} x-50 x^2\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right ) \log ^2\left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )}{\left (e^{-3+x}-x\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )} \, dx=50 \, x^{2} e^{\left ({\left (e^{\left (x + 5 \, e^{x}\right )} - 2 \, e^{x}\right )} e^{\left (-x\right )}\right )} \log \left (\log \left (\log \left (-{\left (x e^{3} - e^{x}\right )} e^{\left (-3\right )}\right )\right )\right ) + 25 \, x^{2} \log \left (\log \left (\log \left (-{\left (x e^{3} - e^{x}\right )} e^{\left (-3\right )}\right )\right )\right )^{2} + 25 \, x^{2} e^{\left (2 \, {\left (e^{\left (x + 5 \, e^{x}\right )} - 2 \, e^{x}\right )} e^{\left (-x\right )}\right )} \]

[In]

integrate(((50*x*exp(-3+x)-50*x^2)*log(exp(-3+x)-x)*log(log(exp(-3+x)-x))*log(log(log(exp(-3+x)-x)))^2+(((250*
x^2*exp(-3+x)-250*x^3)*exp(x)*exp(5*exp(x))+100*x*exp(-3+x)-100*x^2)*log(exp(-3+x)-x)*exp(exp(5*exp(x))-2)*log
(log(exp(-3+x)-x))+50*x^2*exp(-3+x)-50*x^2)*log(log(log(exp(-3+x)-x)))+((250*x^2*exp(-3+x)-250*x^3)*exp(x)*exp
(5*exp(x))+50*x*exp(-3+x)-50*x^2)*log(exp(-3+x)-x)*exp(exp(5*exp(x))-2)^2*log(log(exp(-3+x)-x))+(50*x^2*exp(-3
+x)-50*x^2)*exp(exp(5*exp(x))-2))/(exp(-3+x)-x)/log(exp(-3+x)-x)/log(log(exp(-3+x)-x)),x, algorithm="fricas")

[Out]

50*x^2*e^((e^(x + 5*e^x) - 2*e^x)*e^(-x))*log(log(log(-(x*e^3 - e^x)*e^(-3)))) + 25*x^2*log(log(log(-(x*e^3 -
e^x)*e^(-3))))^2 + 25*x^2*e^(2*(e^(x + 5*e^x) - 2*e^x)*e^(-x))

Sympy [F(-1)]

Timed out. \[ \int \frac {e^{-2+e^{5 e^x}} \left (-50 x^2+50 e^{-3+x} x^2\right )+e^{-4+2 e^{5 e^x}} \left (50 e^{-3+x} x-50 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )+\left (-50 x^2+50 e^{-3+x} x^2+e^{-2+e^{5 e^x}} \left (100 e^{-3+x} x-100 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )\right ) \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )+\left (50 e^{-3+x} x-50 x^2\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right ) \log ^2\left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )}{\left (e^{-3+x}-x\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )} \, dx=\text {Timed out} \]

[In]

integrate(((50*x*exp(-3+x)-50*x**2)*ln(exp(-3+x)-x)*ln(ln(exp(-3+x)-x))*ln(ln(ln(exp(-3+x)-x)))**2+(((250*x**2
*exp(-3+x)-250*x**3)*exp(x)*exp(5*exp(x))+100*x*exp(-3+x)-100*x**2)*ln(exp(-3+x)-x)*exp(exp(5*exp(x))-2)*ln(ln
(exp(-3+x)-x))+50*x**2*exp(-3+x)-50*x**2)*ln(ln(ln(exp(-3+x)-x)))+((250*x**2*exp(-3+x)-250*x**3)*exp(x)*exp(5*
exp(x))+50*x*exp(-3+x)-50*x**2)*ln(exp(-3+x)-x)*exp(exp(5*exp(x))-2)**2*ln(ln(exp(-3+x)-x))+(50*x**2*exp(-3+x)
-50*x**2)*exp(exp(5*exp(x))-2))/(exp(-3+x)-x)/ln(exp(-3+x)-x)/ln(ln(exp(-3+x)-x)),x)

[Out]

Timed out

Maxima [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 64 vs. \(2 (27) = 54\).

Time = 0.44 (sec) , antiderivative size = 64, normalized size of antiderivative = 2.06 \[ \int \frac {e^{-2+e^{5 e^x}} \left (-50 x^2+50 e^{-3+x} x^2\right )+e^{-4+2 e^{5 e^x}} \left (50 e^{-3+x} x-50 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )+\left (-50 x^2+50 e^{-3+x} x^2+e^{-2+e^{5 e^x}} \left (100 e^{-3+x} x-100 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )\right ) \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )+\left (50 e^{-3+x} x-50 x^2\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right ) \log ^2\left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )}{\left (e^{-3+x}-x\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )} \, dx=25 \, {\left (x^{2} e^{4} \log \left (\log \left (\log \left (-x e^{3} + e^{x}\right ) - 3\right )\right )^{2} + 2 \, x^{2} e^{\left (e^{\left (5 \, e^{x}\right )} + 2\right )} \log \left (\log \left (\log \left (-x e^{3} + e^{x}\right ) - 3\right )\right ) + x^{2} e^{\left (2 \, e^{\left (5 \, e^{x}\right )}\right )}\right )} e^{\left (-4\right )} \]

[In]

integrate(((50*x*exp(-3+x)-50*x^2)*log(exp(-3+x)-x)*log(log(exp(-3+x)-x))*log(log(log(exp(-3+x)-x)))^2+(((250*
x^2*exp(-3+x)-250*x^3)*exp(x)*exp(5*exp(x))+100*x*exp(-3+x)-100*x^2)*log(exp(-3+x)-x)*exp(exp(5*exp(x))-2)*log
(log(exp(-3+x)-x))+50*x^2*exp(-3+x)-50*x^2)*log(log(log(exp(-3+x)-x)))+((250*x^2*exp(-3+x)-250*x^3)*exp(x)*exp
(5*exp(x))+50*x*exp(-3+x)-50*x^2)*log(exp(-3+x)-x)*exp(exp(5*exp(x))-2)^2*log(log(exp(-3+x)-x))+(50*x^2*exp(-3
+x)-50*x^2)*exp(exp(5*exp(x))-2))/(exp(-3+x)-x)/log(exp(-3+x)-x)/log(log(exp(-3+x)-x)),x, algorithm="maxima")

[Out]

25*(x^2*e^4*log(log(log(-x*e^3 + e^x) - 3))^2 + 2*x^2*e^(e^(5*e^x) + 2)*log(log(log(-x*e^3 + e^x) - 3)) + x^2*
e^(2*e^(5*e^x)))*e^(-4)

Giac [F]

\[ \int \frac {e^{-2+e^{5 e^x}} \left (-50 x^2+50 e^{-3+x} x^2\right )+e^{-4+2 e^{5 e^x}} \left (50 e^{-3+x} x-50 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )+\left (-50 x^2+50 e^{-3+x} x^2+e^{-2+e^{5 e^x}} \left (100 e^{-3+x} x-100 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )\right ) \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )+\left (50 e^{-3+x} x-50 x^2\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right ) \log ^2\left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )}{\left (e^{-3+x}-x\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )} \, dx=\int { \frac {50 \, {\left ({\left (x^{2} - x e^{\left (x - 3\right )}\right )} \log \left (-x + e^{\left (x - 3\right )}\right ) \log \left (\log \left (-x + e^{\left (x - 3\right )}\right )\right ) \log \left (\log \left (\log \left (-x + e^{\left (x - 3\right )}\right )\right )\right )^{2} + {\left (x^{2} + 5 \, {\left (x^{3} - x^{2} e^{\left (x - 3\right )}\right )} e^{\left (x + 5 \, e^{x}\right )} - x e^{\left (x - 3\right )}\right )} e^{\left (2 \, e^{\left (5 \, e^{x}\right )} - 4\right )} \log \left (-x + e^{\left (x - 3\right )}\right ) \log \left (\log \left (-x + e^{\left (x - 3\right )}\right )\right ) - {\left (x^{2} e^{\left (x - 3\right )} - x^{2}\right )} e^{\left (e^{\left (5 \, e^{x}\right )} - 2\right )} + {\left ({\left (2 \, x^{2} + 5 \, {\left (x^{3} - x^{2} e^{\left (x - 3\right )}\right )} e^{\left (x + 5 \, e^{x}\right )} - 2 \, x e^{\left (x - 3\right )}\right )} e^{\left (e^{\left (5 \, e^{x}\right )} - 2\right )} \log \left (-x + e^{\left (x - 3\right )}\right ) \log \left (\log \left (-x + e^{\left (x - 3\right )}\right )\right ) - x^{2} e^{\left (x - 3\right )} + x^{2}\right )} \log \left (\log \left (\log \left (-x + e^{\left (x - 3\right )}\right )\right )\right )\right )}}{{\left (x - e^{\left (x - 3\right )}\right )} \log \left (-x + e^{\left (x - 3\right )}\right ) \log \left (\log \left (-x + e^{\left (x - 3\right )}\right )\right )} \,d x } \]

[In]

integrate(((50*x*exp(-3+x)-50*x^2)*log(exp(-3+x)-x)*log(log(exp(-3+x)-x))*log(log(log(exp(-3+x)-x)))^2+(((250*
x^2*exp(-3+x)-250*x^3)*exp(x)*exp(5*exp(x))+100*x*exp(-3+x)-100*x^2)*log(exp(-3+x)-x)*exp(exp(5*exp(x))-2)*log
(log(exp(-3+x)-x))+50*x^2*exp(-3+x)-50*x^2)*log(log(log(exp(-3+x)-x)))+((250*x^2*exp(-3+x)-250*x^3)*exp(x)*exp
(5*exp(x))+50*x*exp(-3+x)-50*x^2)*log(exp(-3+x)-x)*exp(exp(5*exp(x))-2)^2*log(log(exp(-3+x)-x))+(50*x^2*exp(-3
+x)-50*x^2)*exp(exp(5*exp(x))-2))/(exp(-3+x)-x)/log(exp(-3+x)-x)/log(log(exp(-3+x)-x)),x, algorithm="giac")

[Out]

integrate(50*((x^2 - x*e^(x - 3))*log(-x + e^(x - 3))*log(log(-x + e^(x - 3)))*log(log(log(-x + e^(x - 3))))^2
 + (x^2 + 5*(x^3 - x^2*e^(x - 3))*e^(x + 5*e^x) - x*e^(x - 3))*e^(2*e^(5*e^x) - 4)*log(-x + e^(x - 3))*log(log
(-x + e^(x - 3))) - (x^2*e^(x - 3) - x^2)*e^(e^(5*e^x) - 2) + ((2*x^2 + 5*(x^3 - x^2*e^(x - 3))*e^(x + 5*e^x)
- 2*x*e^(x - 3))*e^(e^(5*e^x) - 2)*log(-x + e^(x - 3))*log(log(-x + e^(x - 3))) - x^2*e^(x - 3) + x^2)*log(log
(log(-x + e^(x - 3)))))/((x - e^(x - 3))*log(-x + e^(x - 3))*log(log(-x + e^(x - 3)))), x)

Mupad [F(-1)]

Timed out. \[ \int \frac {e^{-2+e^{5 e^x}} \left (-50 x^2+50 e^{-3+x} x^2\right )+e^{-4+2 e^{5 e^x}} \left (50 e^{-3+x} x-50 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )+\left (-50 x^2+50 e^{-3+x} x^2+e^{-2+e^{5 e^x}} \left (100 e^{-3+x} x-100 x^2+e^{5 e^x+x} \left (250 e^{-3+x} x^2-250 x^3\right )\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )\right ) \log \left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )+\left (50 e^{-3+x} x-50 x^2\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right ) \log ^2\left (\log \left (\log \left (e^{-3+x}-x\right )\right )\right )}{\left (e^{-3+x}-x\right ) \log \left (e^{-3+x}-x\right ) \log \left (\log \left (e^{-3+x}-x\right )\right )} \, dx=-\int \frac {\ln \left (\ln \left ({\mathrm {e}}^{x-3}-x\right )\right )\,\ln \left ({\mathrm {e}}^{x-3}-x\right )\,\left (50\,x\,{\mathrm {e}}^{x-3}-50\,x^2\right )\,{\ln \left (\ln \left (\ln \left ({\mathrm {e}}^{x-3}-x\right )\right )\right )}^2+\left (50\,x^2\,{\mathrm {e}}^{x-3}-50\,x^2+\ln \left (\ln \left ({\mathrm {e}}^{x-3}-x\right )\right )\,{\mathrm {e}}^{{\mathrm {e}}^{5\,{\mathrm {e}}^x}-2}\,\ln \left ({\mathrm {e}}^{x-3}-x\right )\,\left (100\,x\,{\mathrm {e}}^{x-3}-100\,x^2+{\mathrm {e}}^{x+5\,{\mathrm {e}}^x}\,\left (250\,x^2\,{\mathrm {e}}^{x-3}-250\,x^3\right )\right )\right )\,\ln \left (\ln \left (\ln \left ({\mathrm {e}}^{x-3}-x\right )\right )\right )+{\mathrm {e}}^{{\mathrm {e}}^{5\,{\mathrm {e}}^x}-2}\,\left (50\,x^2\,{\mathrm {e}}^{x-3}-50\,x^2\right )+\ln \left (\ln \left ({\mathrm {e}}^{x-3}-x\right )\right )\,{\mathrm {e}}^{2\,{\mathrm {e}}^{5\,{\mathrm {e}}^x}-4}\,\ln \left ({\mathrm {e}}^{x-3}-x\right )\,\left (50\,x\,{\mathrm {e}}^{x-3}-50\,x^2+{\mathrm {e}}^{x+5\,{\mathrm {e}}^x}\,\left (250\,x^2\,{\mathrm {e}}^{x-3}-250\,x^3\right )\right )}{\ln \left (\ln \left ({\mathrm {e}}^{x-3}-x\right )\right )\,\ln \left ({\mathrm {e}}^{x-3}-x\right )\,\left (x-{\mathrm {e}}^{x-3}\right )} \,d x \]

[In]

int(-(log(log(log(exp(x - 3) - x)))*(50*x^2*exp(x - 3) - 50*x^2 + log(log(exp(x - 3) - x))*exp(exp(5*exp(x)) -
 2)*log(exp(x - 3) - x)*(100*x*exp(x - 3) - 100*x^2 + exp(5*exp(x))*exp(x)*(250*x^2*exp(x - 3) - 250*x^3))) +
exp(exp(5*exp(x)) - 2)*(50*x^2*exp(x - 3) - 50*x^2) + log(log(exp(x - 3) - x))*log(log(log(exp(x - 3) - x)))^2
*log(exp(x - 3) - x)*(50*x*exp(x - 3) - 50*x^2) + log(log(exp(x - 3) - x))*exp(2*exp(5*exp(x)) - 4)*log(exp(x
- 3) - x)*(50*x*exp(x - 3) - 50*x^2 + exp(5*exp(x))*exp(x)*(250*x^2*exp(x - 3) - 250*x^3)))/(log(log(exp(x - 3
) - x))*log(exp(x - 3) - x)*(x - exp(x - 3))),x)

[Out]

-int((log(log(log(exp(x - 3) - x)))*(50*x^2*exp(x - 3) - 50*x^2 + log(log(exp(x - 3) - x))*exp(exp(5*exp(x)) -
 2)*log(exp(x - 3) - x)*(100*x*exp(x - 3) - 100*x^2 + exp(x + 5*exp(x))*(250*x^2*exp(x - 3) - 250*x^3))) + exp
(exp(5*exp(x)) - 2)*(50*x^2*exp(x - 3) - 50*x^2) + log(log(exp(x - 3) - x))*log(log(log(exp(x - 3) - x)))^2*lo
g(exp(x - 3) - x)*(50*x*exp(x - 3) - 50*x^2) + log(log(exp(x - 3) - x))*exp(2*exp(5*exp(x)) - 4)*log(exp(x - 3
) - x)*(50*x*exp(x - 3) - 50*x^2 + exp(x + 5*exp(x))*(250*x^2*exp(x - 3) - 250*x^3)))/(log(log(exp(x - 3) - x)
)*log(exp(x - 3) - x)*(x - exp(x - 3))), x)