Integrand size = 139, antiderivative size = 30 \[ \int \frac {e^{\frac {e^{16-x} \log ^2(x)}{-x \log (5)+x \log \left (\frac {16}{x^2}\right )}} \left (\left (-2 e^{16-x} \log (5)+2 e^{16-x} \log \left (\frac {16}{x^2}\right )\right ) \log (x)+\left (e^{16-x} (2+(1+x) \log (5))+e^{16-x} (-1-x) \log \left (\frac {16}{x^2}\right )\right ) \log ^2(x)\right )}{x^2 \log ^2(5)-2 x^2 \log (5) \log \left (\frac {16}{x^2}\right )+x^2 \log ^2\left (\frac {16}{x^2}\right )} \, dx=e^{\frac {e^{16-x} \log ^2(x)}{x \left (-\log (5)+\log \left (\frac {16}{x^2}\right )\right )}} \]
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\[ \int \frac {e^{\frac {e^{16-x} \log ^2(x)}{-x \log (5)+x \log \left (\frac {16}{x^2}\right )}} \left (\left (-2 e^{16-x} \log (5)+2 e^{16-x} \log \left (\frac {16}{x^2}\right )\right ) \log (x)+\left (e^{16-x} (2+(1+x) \log (5))+e^{16-x} (-1-x) \log \left (\frac {16}{x^2}\right )\right ) \log ^2(x)\right )}{x^2 \log ^2(5)-2 x^2 \log (5) \log \left (\frac {16}{x^2}\right )+x^2 \log ^2\left (\frac {16}{x^2}\right )} \, dx=\int \frac {e^{\frac {e^{16-x} \log ^2(x)}{-x \log (5)+x \log \left (\frac {16}{x^2}\right )}} \left (\left (-2 e^{16-x} \log (5)+2 e^{16-x} \log \left (\frac {16}{x^2}\right )\right ) \log (x)+\left (e^{16-x} (2+(1+x) \log (5))+e^{16-x} (-1-x) \log \left (\frac {16}{x^2}\right )\right ) \log ^2(x)\right )}{x^2 \log ^2(5)-2 x^2 \log (5) \log \left (\frac {16}{x^2}\right )+x^2 \log ^2\left (\frac {16}{x^2}\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \log (x) \left (-2 \log (5)+(2+\log (5)+x \log (5)) \log (x)-\log \left (\frac {16}{x^2}\right ) (-2+(1+x) \log (x))\right )}{x^2 \log ^2\left (\frac {16}{5 x^2}\right )} \, dx \\ & = \int \left (\frac {2 e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \log (x)}{x^2 \log \left (\frac {16}{5 x^2}\right )}+\frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \left (2 \left (1+\frac {\log (5)}{2}\right )+x \log (5)-\log \left (\frac {16}{x^2}\right )-x \log \left (\frac {16}{x^2}\right )\right ) \log ^2(x)}{x^2 \log ^2\left (\frac {16}{5 x^2}\right )}\right ) \, dx \\ & = 2 \int \frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \log (x)}{x^2 \log \left (\frac {16}{5 x^2}\right )} \, dx+\int \frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \left (2 \left (1+\frac {\log (5)}{2}\right )+x \log (5)-\log \left (\frac {16}{x^2}\right )-x \log \left (\frac {16}{x^2}\right )\right ) \log ^2(x)}{x^2 \log ^2\left (\frac {16}{5 x^2}\right )} \, dx \\ & = 2 \int \frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \log (x)}{x^2 \log \left (\frac {16}{5 x^2}\right )} \, dx+\int \left (\frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \log (5) \log ^2(x)}{x \log ^2\left (\frac {16}{5 x^2}\right )}+\frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} (2+\log (5)) \log ^2(x)}{x^2 \log ^2\left (\frac {16}{5 x^2}\right )}-\frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \log \left (\frac {16}{x^2}\right ) \log ^2(x)}{x^2 \log ^2\left (\frac {16}{5 x^2}\right )}-\frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \log \left (\frac {16}{x^2}\right ) \log ^2(x)}{x \log ^2\left (\frac {16}{5 x^2}\right )}\right ) \, dx \\ & = 2 \int \frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \log (x)}{x^2 \log \left (\frac {16}{5 x^2}\right )} \, dx+\log (5) \int \frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \log ^2(x)}{x \log ^2\left (\frac {16}{5 x^2}\right )} \, dx+(2+\log (5)) \int \frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \log ^2(x)}{x^2 \log ^2\left (\frac {16}{5 x^2}\right )} \, dx-\int \frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \log \left (\frac {16}{x^2}\right ) \log ^2(x)}{x^2 \log ^2\left (\frac {16}{5 x^2}\right )} \, dx-\int \frac {e^{16-x+\frac {e^{16-x} \log ^2(x)}{x \log \left (\frac {16}{5 x^2}\right )}} \log \left (\frac {16}{x^2}\right ) \log ^2(x)}{x \log ^2\left (\frac {16}{5 x^2}\right )} \, dx \\ \end{align*}
\[ \int \frac {e^{\frac {e^{16-x} \log ^2(x)}{-x \log (5)+x \log \left (\frac {16}{x^2}\right )}} \left (\left (-2 e^{16-x} \log (5)+2 e^{16-x} \log \left (\frac {16}{x^2}\right )\right ) \log (x)+\left (e^{16-x} (2+(1+x) \log (5))+e^{16-x} (-1-x) \log \left (\frac {16}{x^2}\right )\right ) \log ^2(x)\right )}{x^2 \log ^2(5)-2 x^2 \log (5) \log \left (\frac {16}{x^2}\right )+x^2 \log ^2\left (\frac {16}{x^2}\right )} \, dx=\int \frac {e^{\frac {e^{16-x} \log ^2(x)}{-x \log (5)+x \log \left (\frac {16}{x^2}\right )}} \left (\left (-2 e^{16-x} \log (5)+2 e^{16-x} \log \left (\frac {16}{x^2}\right )\right ) \log (x)+\left (e^{16-x} (2+(1+x) \log (5))+e^{16-x} (-1-x) \log \left (\frac {16}{x^2}\right )\right ) \log ^2(x)\right )}{x^2 \log ^2(5)-2 x^2 \log (5) \log \left (\frac {16}{x^2}\right )+x^2 \log ^2\left (\frac {16}{x^2}\right )} \, dx \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 0.58 (sec) , antiderivative size = 81, normalized size of antiderivative = 2.70
\[{\mathrm e}^{\frac {2 \,{\mathrm e}^{16-x} \ln \left (x \right )^{2}}{x \left (i \pi \operatorname {csgn}\left (i x^{2}\right )^{3}-2 i \pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i x^{2}\right )^{2}+i \pi \operatorname {csgn}\left (i x \right )^{2} \operatorname {csgn}\left (i x^{2}\right )-2 \ln \left (5\right )+8 \ln \left (2\right )-4 \ln \left (x \right )\right )}}\]
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Leaf count of result is larger than twice the leaf count of optimal. 63 vs. \(2 (29) = 58\).
Time = 0.24 (sec) , antiderivative size = 63, normalized size of antiderivative = 2.10 \[ \int \frac {e^{\frac {e^{16-x} \log ^2(x)}{-x \log (5)+x \log \left (\frac {16}{x^2}\right )}} \left (\left (-2 e^{16-x} \log (5)+2 e^{16-x} \log \left (\frac {16}{x^2}\right )\right ) \log (x)+\left (e^{16-x} (2+(1+x) \log (5))+e^{16-x} (-1-x) \log \left (\frac {16}{x^2}\right )\right ) \log ^2(x)\right )}{x^2 \log ^2(5)-2 x^2 \log (5) \log \left (\frac {16}{x^2}\right )+x^2 \log ^2\left (\frac {16}{x^2}\right )} \, dx=e^{\left (-\frac {16 \, e^{\left (-x + 16\right )} \log \left (2\right )^{2} - 8 \, e^{\left (-x + 16\right )} \log \left (2\right ) \log \left (\frac {16}{x^{2}}\right ) + e^{\left (-x + 16\right )} \log \left (\frac {16}{x^{2}}\right )^{2}}{4 \, {\left (x \log \left (5\right ) - x \log \left (\frac {16}{x^{2}}\right )\right )}}\right )} \]
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Time = 0.98 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.87 \[ \int \frac {e^{\frac {e^{16-x} \log ^2(x)}{-x \log (5)+x \log \left (\frac {16}{x^2}\right )}} \left (\left (-2 e^{16-x} \log (5)+2 e^{16-x} \log \left (\frac {16}{x^2}\right )\right ) \log (x)+\left (e^{16-x} (2+(1+x) \log (5))+e^{16-x} (-1-x) \log \left (\frac {16}{x^2}\right )\right ) \log ^2(x)\right )}{x^2 \log ^2(5)-2 x^2 \log (5) \log \left (\frac {16}{x^2}\right )+x^2 \log ^2\left (\frac {16}{x^2}\right )} \, dx=e^{\frac {e^{16 - x} \log {\left (x \right )}^{2}}{x \left (- 2 \log {\left (x \right )} + \log {\left (16 \right )}\right ) - x \log {\left (5 \right )}}} \]
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Time = 0.73 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00 \[ \int \frac {e^{\frac {e^{16-x} \log ^2(x)}{-x \log (5)+x \log \left (\frac {16}{x^2}\right )}} \left (\left (-2 e^{16-x} \log (5)+2 e^{16-x} \log \left (\frac {16}{x^2}\right )\right ) \log (x)+\left (e^{16-x} (2+(1+x) \log (5))+e^{16-x} (-1-x) \log \left (\frac {16}{x^2}\right )\right ) \log ^2(x)\right )}{x^2 \log ^2(5)-2 x^2 \log (5) \log \left (\frac {16}{x^2}\right )+x^2 \log ^2\left (\frac {16}{x^2}\right )} \, dx=e^{\left (-\frac {e^{16} \log \left (x\right )^{2}}{x {\left (\log \left (5\right ) - 4 \, \log \left (2\right )\right )} e^{x} + 2 \, x e^{x} \log \left (x\right )}\right )} \]
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\[ \int \frac {e^{\frac {e^{16-x} \log ^2(x)}{-x \log (5)+x \log \left (\frac {16}{x^2}\right )}} \left (\left (-2 e^{16-x} \log (5)+2 e^{16-x} \log \left (\frac {16}{x^2}\right )\right ) \log (x)+\left (e^{16-x} (2+(1+x) \log (5))+e^{16-x} (-1-x) \log \left (\frac {16}{x^2}\right )\right ) \log ^2(x)\right )}{x^2 \log ^2(5)-2 x^2 \log (5) \log \left (\frac {16}{x^2}\right )+x^2 \log ^2\left (\frac {16}{x^2}\right )} \, dx=\int { -\frac {{\left ({\left ({\left (x + 1\right )} e^{\left (-x + 16\right )} \log \left (\frac {16}{x^{2}}\right ) - {\left ({\left (x + 1\right )} \log \left (5\right ) + 2\right )} e^{\left (-x + 16\right )}\right )} \log \left (x\right )^{2} + 2 \, {\left (e^{\left (-x + 16\right )} \log \left (5\right ) - e^{\left (-x + 16\right )} \log \left (\frac {16}{x^{2}}\right )\right )} \log \left (x\right )\right )} e^{\left (-\frac {e^{\left (-x + 16\right )} \log \left (x\right )^{2}}{x \log \left (5\right ) - x \log \left (\frac {16}{x^{2}}\right )}\right )}}{x^{2} \log \left (5\right )^{2} - 2 \, x^{2} \log \left (5\right ) \log \left (\frac {16}{x^{2}}\right ) + x^{2} \log \left (\frac {16}{x^{2}}\right )^{2}} \,d x } \]
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Timed out. \[ \int \frac {e^{\frac {e^{16-x} \log ^2(x)}{-x \log (5)+x \log \left (\frac {16}{x^2}\right )}} \left (\left (-2 e^{16-x} \log (5)+2 e^{16-x} \log \left (\frac {16}{x^2}\right )\right ) \log (x)+\left (e^{16-x} (2+(1+x) \log (5))+e^{16-x} (-1-x) \log \left (\frac {16}{x^2}\right )\right ) \log ^2(x)\right )}{x^2 \log ^2(5)-2 x^2 \log (5) \log \left (\frac {16}{x^2}\right )+x^2 \log ^2\left (\frac {16}{x^2}\right )} \, dx=-\int -\frac {{\mathrm {e}}^{-\frac {{\mathrm {e}}^{16-x}\,{\ln \left (x\right )}^2}{x\,\ln \left (5\right )-x\,\ln \left (\frac {16}{x^2}\right )}}\,\left ({\ln \left (x\right )}^2\,\left ({\mathrm {e}}^{16-x}\,\left (\ln \left (5\right )\,\left (x+1\right )+2\right )-{\mathrm {e}}^{16-x}\,\ln \left (\frac {16}{x^2}\right )\,\left (x+1\right )\right )-\ln \left (x\right )\,\left (2\,{\mathrm {e}}^{16-x}\,\ln \left (5\right )-2\,{\mathrm {e}}^{16-x}\,\ln \left (\frac {16}{x^2}\right )\right )\right )}{x^2\,{\ln \left (\frac {16}{x^2}\right )}^2-2\,\ln \left (5\right )\,x^2\,\ln \left (\frac {16}{x^2}\right )+{\ln \left (5\right )}^2\,x^2} \,d x \]
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