Integrand size = 39, antiderivative size = 32 \[ \int \frac {-9-24 x^2+4 x^3+e^{x^2} \left (-3+6 x^2\right )-24 x^2 \log (x)}{24 x^2} \, dx=\frac {1}{4} \left (\frac {3+e^{x^2}}{2 x}+\frac {x^2}{3}\right )-x \log (x) \]
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Time = 0.05 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {12, 14, 2326, 2332} \[ \int \frac {-9-24 x^2+4 x^3+e^{x^2} \left (-3+6 x^2\right )-24 x^2 \log (x)}{24 x^2} \, dx=\frac {x^2}{12}+\frac {e^{x^2}}{8 x}+\frac {3}{8 x}-x \log (x) \]
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Rule 12
Rule 14
Rule 2326
Rule 2332
Rubi steps \begin{align*} \text {integral}& = \frac {1}{24} \int \frac {-9-24 x^2+4 x^3+e^{x^2} \left (-3+6 x^2\right )-24 x^2 \log (x)}{x^2} \, dx \\ & = \frac {1}{24} \int \left (\frac {3 e^{x^2} \left (-1+2 x^2\right )}{x^2}+\frac {-9-24 x^2+4 x^3-24 x^2 \log (x)}{x^2}\right ) \, dx \\ & = \frac {1}{24} \int \frac {-9-24 x^2+4 x^3-24 x^2 \log (x)}{x^2} \, dx+\frac {1}{8} \int \frac {e^{x^2} \left (-1+2 x^2\right )}{x^2} \, dx \\ & = \frac {e^{x^2}}{8 x}+\frac {1}{24} \int \left (\frac {-9-24 x^2+4 x^3}{x^2}-24 \log (x)\right ) \, dx \\ & = \frac {e^{x^2}}{8 x}+\frac {1}{24} \int \frac {-9-24 x^2+4 x^3}{x^2} \, dx-\int \log (x) \, dx \\ & = \frac {e^{x^2}}{8 x}+x-x \log (x)+\frac {1}{24} \int \left (-24-\frac {9}{x^2}+4 x\right ) \, dx \\ & = \frac {3}{8 x}+\frac {e^{x^2}}{8 x}+\frac {x^2}{12}-x \log (x) \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.94 \[ \int \frac {-9-24 x^2+4 x^3+e^{x^2} \left (-3+6 x^2\right )-24 x^2 \log (x)}{24 x^2} \, dx=\frac {1}{24} \left (\frac {9}{x}+\frac {3 e^{x^2}}{x}+2 x^2-24 x \log (x)\right ) \]
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Time = 0.08 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.78
method | result | size |
norman | \(\frac {\frac {3}{8}+\frac {x^{3}}{12}-x^{2} \ln \left (x \right )+\frac {{\mathrm e}^{x^{2}}}{8}}{x}\) | \(25\) |
risch | \(-x \ln \left (x \right )+\frac {2 x^{3}+3 \,{\mathrm e}^{x^{2}}+9}{24 x}\) | \(25\) |
default | \(\frac {x^{2}}{12}+\frac {3}{8 x}+\frac {{\mathrm e}^{x^{2}}}{8 x}-x \ln \left (x \right )\) | \(26\) |
parallelrisch | \(\frac {-24 x^{2} \ln \left (x \right )+2 x^{3}+3 \,{\mathrm e}^{x^{2}}+9}{24 x}\) | \(26\) |
parts | \(\frac {x^{2}}{12}+\frac {3}{8 x}+\frac {{\mathrm e}^{x^{2}}}{8 x}-x \ln \left (x \right )\) | \(26\) |
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Time = 0.23 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.78 \[ \int \frac {-9-24 x^2+4 x^3+e^{x^2} \left (-3+6 x^2\right )-24 x^2 \log (x)}{24 x^2} \, dx=\frac {2 \, x^{3} - 24 \, x^{2} \log \left (x\right ) + 3 \, e^{\left (x^{2}\right )} + 9}{24 \, x} \]
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Time = 0.10 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.69 \[ \int \frac {-9-24 x^2+4 x^3+e^{x^2} \left (-3+6 x^2\right )-24 x^2 \log (x)}{24 x^2} \, dx=\frac {x^{2}}{12} - x \log {\left (x \right )} + \frac {e^{x^{2}}}{8 x} + \frac {3}{8 x} \]
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Result contains higher order function than in optimal. Order 4 vs. order 3.
Time = 0.22 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.38 \[ \int \frac {-9-24 x^2+4 x^3+e^{x^2} \left (-3+6 x^2\right )-24 x^2 \log (x)}{24 x^2} \, dx=\frac {1}{12} \, x^{2} - x \log \left (x\right ) - \frac {1}{8} i \, \sqrt {\pi } \operatorname {erf}\left (i \, x\right ) + \frac {\sqrt {-x^{2}} \Gamma \left (-\frac {1}{2}, -x^{2}\right )}{16 \, x} + \frac {3}{8 \, x} \]
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Time = 0.28 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.78 \[ \int \frac {-9-24 x^2+4 x^3+e^{x^2} \left (-3+6 x^2\right )-24 x^2 \log (x)}{24 x^2} \, dx=\frac {2 \, x^{3} - 24 \, x^{2} \log \left (x\right ) + 3 \, e^{\left (x^{2}\right )} + 9}{24 \, x} \]
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Time = 12.24 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.72 \[ \int \frac {-9-24 x^2+4 x^3+e^{x^2} \left (-3+6 x^2\right )-24 x^2 \log (x)}{24 x^2} \, dx=\frac {\frac {{\mathrm {e}}^{x^2}}{8}+\frac {3}{8}}{x}-x\,\ln \left (x\right )+\frac {x^2}{12} \]
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