Integrand size = 2, antiderivative size = 20 \[ \int \log (2) \, dx=-4+\log (2) \left (4+x+\log \left (e^3+e^{10 e^2}\right )\right ) \]
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Time = 0.00 (sec) , antiderivative size = 4, normalized size of antiderivative = 0.20, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {8} \[ \int \log (2) \, dx=x \log (2) \]
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Rule 8
Rubi steps \begin{align*} \text {integral}& = x \log (2) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 4, normalized size of antiderivative = 0.20 \[ \int \log (2) \, dx=x \log (2) \]
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Time = 0.04 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.25
method | result | size |
default | \(x \ln \left (2\right )\) | \(5\) |
norman | \(x \ln \left (2\right )\) | \(5\) |
risch | \(x \ln \left (2\right )\) | \(5\) |
parallelrisch | \(x \ln \left (2\right )\) | \(5\) |
parts | \(x \ln \left (2\right )\) | \(5\) |
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none
Time = 0.23 (sec) , antiderivative size = 4, normalized size of antiderivative = 0.20 \[ \int \log (2) \, dx=x \log \left (2\right ) \]
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Time = 0.02 (sec) , antiderivative size = 3, normalized size of antiderivative = 0.15 \[ \int \log (2) \, dx=x \log {\left (2 \right )} \]
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none
Time = 0.19 (sec) , antiderivative size = 4, normalized size of antiderivative = 0.20 \[ \int \log (2) \, dx=x \log \left (2\right ) \]
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none
Time = 0.27 (sec) , antiderivative size = 4, normalized size of antiderivative = 0.20 \[ \int \log (2) \, dx=x \log \left (2\right ) \]
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Time = 0.00 (sec) , antiderivative size = 4, normalized size of antiderivative = 0.20 \[ \int \log (2) \, dx=x\,\ln \left (2\right ) \]
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