Integrand size = 56, antiderivative size = 23 \[ \int \frac {-60 e^{\frac {19}{9}+\frac {20 e^2}{x}}+x^2}{3 \sqrt [9]{e} x^2+3 e^{\frac {1}{9}+\frac {20 e^2}{x}} x^2+x^3} \, dx=\log \left (\sqrt [9]{e} \left (3+3 e^{\frac {20 e^2}{x}}\right )+x\right ) \]
[Out]
\[ \int \frac {-60 e^{\frac {19}{9}+\frac {20 e^2}{x}}+x^2}{3 \sqrt [9]{e} x^2+3 e^{\frac {1}{9}+\frac {20 e^2}{x}} x^2+x^3} \, dx=\int \frac {-60 e^{\frac {19}{9}+\frac {20 e^2}{x}}+x^2}{3 \sqrt [9]{e} x^2+3 e^{\frac {1}{9}+\frac {20 e^2}{x}} x^2+x^3} \, dx \]
[In]
[Out]
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {20 e^2}{x^2}+\frac {60 e^{19/9}+20 e^2 x+x^2}{x^2 \left (3 \sqrt [9]{e}+3 e^{\frac {1}{9}+\frac {20 e^2}{x}}+x\right )}\right ) \, dx \\ & = \frac {20 e^2}{x}+\int \frac {60 e^{19/9}+20 e^2 x+x^2}{x^2 \left (3 \sqrt [9]{e}+3 e^{\frac {1}{9}+\frac {20 e^2}{x}}+x\right )} \, dx \\ & = \frac {20 e^2}{x}+\int \left (\frac {1}{3 \sqrt [9]{e}+3 e^{\frac {1}{9}+\frac {20 e^2}{x}}+x}+\frac {60 e^{19/9}}{x^2 \left (3 \sqrt [9]{e}+3 e^{\frac {1}{9}+\frac {20 e^2}{x}}+x\right )}+\frac {20 e^2}{x \left (3 \sqrt [9]{e}+3 e^{\frac {1}{9}+\frac {20 e^2}{x}}+x\right )}\right ) \, dx \\ & = \frac {20 e^2}{x}+\left (20 e^2\right ) \int \frac {1}{x \left (3 \sqrt [9]{e}+3 e^{\frac {1}{9}+\frac {20 e^2}{x}}+x\right )} \, dx+\left (60 e^{19/9}\right ) \int \frac {1}{x^2 \left (3 \sqrt [9]{e}+3 e^{\frac {1}{9}+\frac {20 e^2}{x}}+x\right )} \, dx+\int \frac {1}{3 \sqrt [9]{e}+3 e^{\frac {1}{9}+\frac {20 e^2}{x}}+x} \, dx \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.13 \[ \int \frac {-60 e^{\frac {19}{9}+\frac {20 e^2}{x}}+x^2}{3 \sqrt [9]{e} x^2+3 e^{\frac {1}{9}+\frac {20 e^2}{x}} x^2+x^3} \, dx=\log \left (3 \sqrt [9]{e}+3 e^{\frac {1}{9}+\frac {20 e^2}{x}}+x\right ) \]
[In]
[Out]
Time = 1.47 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.74
method | result | size |
risch | \(\ln \left ({\mathrm e}^{\frac {20 \,{\mathrm e}^{2}}{x}}+1+\frac {{\mathrm e}^{-\frac {1}{9}} x}{3}\right )\) | \(17\) |
norman | \(\ln \left (3 \,{\mathrm e}^{\frac {1}{9}} {\mathrm e}^{\frac {20 \,{\mathrm e}^{2}}{x}}+3 \,{\mathrm e}^{\frac {1}{9}}+x \right )\) | \(20\) |
parallelrisch | \(\ln \left (3 \,{\mathrm e}^{\frac {1}{9}} {\mathrm e}^{\frac {20 \,{\mathrm e}^{2}}{x}}+3 \,{\mathrm e}^{\frac {1}{9}}+x \right )\) | \(20\) |
[In]
[Out]
none
Time = 0.22 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.13 \[ \int \frac {-60 e^{\frac {19}{9}+\frac {20 e^2}{x}}+x^2}{3 \sqrt [9]{e} x^2+3 e^{\frac {1}{9}+\frac {20 e^2}{x}} x^2+x^3} \, dx=\log \left (x e^{2} + 3 \, e^{\frac {19}{9}} + 3 \, e^{\left (\frac {19 \, x + 180 \, e^{2}}{9 \, x}\right )}\right ) \]
[In]
[Out]
Time = 0.11 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.04 \[ \int \frac {-60 e^{\frac {19}{9}+\frac {20 e^2}{x}}+x^2}{3 \sqrt [9]{e} x^2+3 e^{\frac {1}{9}+\frac {20 e^2}{x}} x^2+x^3} \, dx=\log {\left (\frac {x + 3 e^{\frac {1}{9}}}{3 e^{\frac {1}{9}}} + e^{\frac {20 e^{2}}{x}} \right )} \]
[In]
[Out]
none
Time = 0.22 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.00 \[ \int \frac {-60 e^{\frac {19}{9}+\frac {20 e^2}{x}}+x^2}{3 \sqrt [9]{e} x^2+3 e^{\frac {1}{9}+\frac {20 e^2}{x}} x^2+x^3} \, dx=\log \left (\frac {1}{3} \, {\left (x + 3 \, e^{\frac {1}{9}} + 3 \, e^{\left (\frac {20 \, e^{2}}{x} + \frac {1}{9}\right )}\right )} e^{\left (-\frac {1}{9}\right )}\right ) \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 44 vs. \(2 (17) = 34\).
Time = 0.28 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.91 \[ \int \frac {-60 e^{\frac {19}{9}+\frac {20 e^2}{x}}+x^2}{3 \sqrt [9]{e} x^2+3 e^{\frac {1}{9}+\frac {20 e^2}{x}} x^2+x^3} \, dx={\left (e^{2} \log \left (\frac {3 \, e^{2}}{x} + \frac {3 \, e^{\left (\frac {20 \, e^{2}}{x} + 2\right )}}{x} + e^{\frac {17}{9}}\right ) - e^{2} \log \left (\frac {e^{2}}{x}\right )\right )} e^{\left (-2\right )} \]
[In]
[Out]
Time = 13.09 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.30 \[ \int \frac {-60 e^{\frac {19}{9}+\frac {20 e^2}{x}}+x^2}{3 \sqrt [9]{e} x^2+3 e^{\frac {1}{9}+\frac {20 e^2}{x}} x^2+x^3} \, dx=\ln \left (\frac {x+3\,{\mathrm {e}}^{1/9}+3\,{\mathrm {e}}^{\frac {20\,{\mathrm {e}}^2}{x}}\,{\mathrm {e}}^{1/9}}{x}\right )-\ln \left (\frac {1}{x}\right ) \]
[In]
[Out]